Inferring Evolutionary Relationships from Sequences
Hidden inside every cell is a record of ancestry written in four DNA letters and twenty amino acids. The more recently two species shared an ancestor, the more of that code they still share, and the fewer differences, the closer the kinship. In this investigation you become a molecular detective, comparing real-style sequences to work out who is related to whom and to draw the family tree that the molecules reveal.
Orient yourself
Make a prediction, scan the goals and the key terms, and see which misconception this lesson is built to fix.
Before You Read
warm-upYou compare the same short stretch of DNA in three species. Species A and B differ at 2 positions; species A and C differ at 11 positions.
Before reading: which pair is more closely related, A&B or A&C? Explain your reasoning. What is your one assumption about how differences build up over time?
Learning Intentions
goalsKnow
- That DNA and amino-acid sequences carry a record of common ancestry
- How to count differences between aligned sequences
- What a phylogenetic tree shows
Understand
- Why fewer sequence differences imply a more recent common ancestor
- The assumption that mutations accumulate roughly over time
- Why molecular data can be more reliable than appearance
Can Do
- Compare sequences and tabulate the number of differences
- Infer relative relatedness from the data
- Draw a simple phylogenetic tree from a difference matrix
Scan these before reading
vocabMatch each term to its meaning: use the Key Terms card above.
- Sequence alignment
- Phylogenetic tree
- Common ancestor
- Conserved sequence
- Molecular clock
- A part of a gene or protein that changes very little because it is essential to function
- Lining the same gene or protein from different species up position by position
- The idea that mutations accumulate at a roughly steady rate over time
- A species from which two or more later species both descend
- A branching diagram of inferred relationships, whose shared branch points are ancestors
Misconceptions To Fix
watch outSequences Record Ancestry
The principle behind molecular phylogenetics
Core Content
Sequences Record Ancestry
+5 XPThe principle behind molecular phylogenetics
When two species split from a common ancestor, their DNA slowly accumulates separate mutations, so the longer ago they split, the more their sequences differ.
The core principle: the fewer differences there are between the DNA or amino-acid sequences of two species, the more recently they shared a common ancestor, so the more closely related they are. This works because random mutations build up over time after two lineages separate; closely related species have had little time to differ, distantly related species much more.
Amino-acid sequences (the order of amino acids in a protein) are read the same way, fewer amino-acid differences mean a closer relationship. Comparing a conserved gene or protein (one that all the species have and that changes slowly) lets us compare even very different organisms on the same scale.
Pause, copy the highlighted principle into your book before moving on.
The fewer differences between two species' DNA sequences, the more _____ their common ancestor is (more closely related).
The Investigation, Counting Differences
Aligning sequences and building a difference matrix
The Investigation, Counting Differences
+5 XPAligning sequences and building a difference matrix
We just saw that differences track time since divergence. That raises a question: how do we turn raw sequences into a statement about relatedness? This card answers it → align the sequences, count differences, and tabulate them.
The method is straightforward: take the same gene or protein from each species, line them up, count the positions that differ for each pair, and record the totals in a table.
Method: (1) Obtain the same DNA or amino-acid sequence from several species (in class, from a provided dataset or an online database such as a public sequence library). (2) Align them so the same positions line up. (3) For each pair of species, count the number of positions where they differ. (4) Record the counts in a difference matrix. (5) Infer that pairs with the fewest differences are the most closely related, and use the pattern to draw a phylogenetic tree.
Text description
- Aligned sequences: Sp1 A C G T A C G; Sp2 A C G T A C G; Sp3 A T G T G C A. The positions where Sp3 differs from Sp1 are highlighted (positions 2, 5 and 7).
- Sp3 differs from Sp1 at 3 positions; Sp1 and Sp2 are identical (0).
- Difference matrix: Sp1–Sp2 0, Sp1–Sp3 3, Sp2–Sp3 3.
- Sp1 and Sp2 are closest (0 differences); Sp3 is the most distant.
Method: get the same gene/protein from each species → align → count differing positions for every pair → record in a difference matrix → the pair with the fewest differences is most closely related → build a phylogenetic tree from the pattern. Assumption: mutations accumulate roughly steadily over time (a molecular clock).
Pause, copy the five method steps and the difference-matrix idea into your book.
A real, checkable dataset to practise on. Cytochrome c is a small respiratory protein of about 104 amino acids found in almost every aerobic organism, which makes it the classic conserved sequence for comparisons across very distant groups. The number of amino acid differences from the human sequence is roughly: chimpanzee 0, rhesus monkey 1, horse 12, tuna 21, baker's yeast 44. Read down that list and the ordering is exactly the relatedness biologists infer from anatomy and from the fossil record, which is why the agreement between independent methods matters so much (Lesson 18).
Notice what a difference of 0 does and does not mean. Chimpanzee cytochrome c being identical to ours does not make a chimpanzee a human; it means this particular protein is so constrained by its function that it has accumulated no changes since the two lineages split. A conserved sequence resolves deep relationships well and recent ones poorly, which is a limitation worth stating.
In a difference matrix, the pair of species with the SMALLEST number of differences is:
Apply it: Build the Tree from the Data
Work the activity in your own book before you read on. This is the first point where you are on your own.
Activity 1
Build the Tree from the Data
Pattern B, Work with data
Amino-acid differences in a conserved protein, compared to humans, are: chimpanzee 0, gorilla 1, mouse 9, chicken 18. Rank the four species from most to least closely related to humans, explain how the numbers justify your ranking, and sketch a simple tree (in words) showing the branching order from the human lineage.
Reading the Tree & Its Limits
From matrix to tree, and what the method assumes
Reading the Tree & Its Limits
+5 XPFrom matrix to tree, and what the method assumes
We just built a difference matrix. That raises a question: how does that become a tree, and how far can we trust it? This card answers it → species sharing the most code branch together, but the method rests on assumptions.
A phylogenetic tree turns the pattern of differences into branch points: the more similar two species are, the more recently their branches join.
To build the tree, the two species with the fewest differences are joined at a recent branch point (a recent common ancestor); species with more differences join further back. The result is a branching diagram in which shared branch points represent shared ancestors and branch length can suggest time since divergence.
Important limits: the method assumes mutations accumulate at a roughly steady rate (the molecular clock), which is not perfectly true for every gene. Using a single short sequence can give a misleading tree, so reliability improves when several genes or proteins are compared and the trees agree. To improve validity, compare the same conserved sequence in each species and align carefully; to improve reliability, repeat with additional sequences.
Build the tree by joining the least-different species at recent branch points; more-different species branch earlier. Shared branch points = shared ancestors. Limits: assumes a roughly steady molecular clock; one short sequence can mislead, so compare several genes/proteins. Validity = same conserved sequence, careful alignment; reliability = repeat with more sequences.
Add the tree-building rule and the two main limitations to your notes before the check below.
In a phylogenetic tree, a shared branch point represents a common ancestor of the species above it.
Comparing several genes or proteins gives a more reliable tree than relying on one short sequence.
Species that look the most alike are always the most closely related according to their DNA.
See where it lands in the real world
Why this matters: tracing viruses and classifying life
Why this matters: tracing viruses and classifying life
The same sequence-comparison method you used drives front-line science. During disease outbreaks, researchers sequence a virus from many patients and build phylogenetic trees to trace how it spread and mutated, this is how new variants are detected and tracked. Molecular phylogenetics has also rewritten the tree of life, reclassifying organisms whose true relationships appearance had hidden, and it guides conservation by revealing which populations are genetically distinct. The molecules really do tell the story.
Two truths, one lie: three of these statements about the card above are correct. Which one is the lie?
Describe how you would use amino acid sequences of the same protein from four species to infer their evolutionary relationships.
Describe asks for the characteristics and features of the method. It must be specific enough that another student could follow it, and it must say what is done with the numbers, not only how they are obtained.
5 marks. State why the same protein is used, then the alignment and counting, then the matrix, then the tree, then the reading rule.
Use the same protein from all four species, and a protein present across a wide range of organisms because it performs an essential function, so that the sequences are homologous, meaning they descend from one ancestral gene. Comparing different proteins, or unrelated sequences, would produce differences that reflect the proteins rather than the species. A highly conserved protein is preferred because most of its sequence is constrained by function, so the differences that do accumulate are informative rather than random noise.
Write the four sequences one beneath another and align them position by position, inserting gaps where necessary so that corresponding positions line up. Then compare each pair of species and count the number of positions at which their amino acids differ. This gives a difference count for every possible pair.
Record the counts in a difference matrix, a table with the species along both axes and the number of differences in each cell. This makes the pattern visible: the smallest counts identify the most similar pairs and the largest counts the most divergent.
Interpret the counts using the principle that differences accumulate over time since two lineages diverged: the fewer the differences between two species, the more recently they shared a common ancestor. Rank the pairs from fewest differences to most, and build a tree by joining the most similar pair first, then attaching the next most similar species to that group, and so on, so that the species most different from all the others joins the tree last and at its base.
Finally, check the tree reproduces the matrix: species grouped closely together should have small counts between them, and a species placed at the base should have large counts against every other. The method assumes that differences accumulate at a broadly similar rate across the lineages compared, and that the positions counted are changing independently rather than being constrained together, so the inferred tree should be treated as a hypothesis to be tested against other proteins and against anatomical evidence.
Use the same protein from all four species, choosing one present across a wide range of organisms because it performs an essential function, so that the sequences are homologous and descend from a single ancestral gene; comparing different proteins would produce differences reflecting the proteins rather than the species, and a highly conserved protein is preferable because most of its sequence is constrained by function, so the differences that do accumulate are informative rather than noise. Write the four sequences one beneath another and align them position by position, inserting gaps where necessary so corresponding positions line up, then compare each pair of species and count the positions at which their amino acids differ, giving a count for every possible pair. Record these in a difference matrix, a table with the species on both axes and the number of differences in each cell, which makes the pattern visible, with the smallest counts identifying the most similar pairs and the largest the most divergent. Interpret the counts using the principle that differences accumulate over time since two lineages diverged, so that the fewer the differences between two species the more recently they shared a common ancestor: rank the pairs from fewest differences to most, then build a tree by joining the most similar pair first, attaching the next most similar species to that group, and continuing, so that the species most different from all the others joins last and at the base. Finally, check that the tree reproduces the matrix, since species grouped closely should show small counts between them and a species at the base should show large counts against every other. The method assumes that differences accumulate at a broadly similar rate across the lineages compared and that the positions counted change independently rather than being constrained together, so the inferred tree should be treated as a hypothesis to be tested against other proteins and against anatomical evidence.
In a hypothetical 100-amino-acid protein, species W differs from species X at 3 positions, from species Y at 18 positions and from species Z at 41 positions. Independent fossil evidence dates the divergence of W and X at 15 million years ago. Deduce the approximate divergence times of Y and Z from W, and state the assumptions you have made.
Deduce asks you to reach a conclusion by reasoning from given information. The reasoning must be shown, and because the question asks for assumptions, an answer without them is incomplete however good the arithmetic.
5 marks. Establish the rate from the calibration point, apply it to each unknown, state the answers with appropriate precision, check they are plausible, then state the assumptions.
W and X differ at 3 positions and are known from fossil evidence to have diverged 15 million years ago. The rate of accumulation of differences is therefore 3 differences divided by 15 million years, which is 0.2 differences per million years.
It matters that the rate was calibrated from a pairwise count and is being applied to pairwise counts. Differences accumulate independently along both lineages after they diverge, so the number of differences between two living species reflects change on two branches, not one, and is proportional to roughly twice the time since divergence. Because the calibration was made the same way, that factor is already inside the 0.2 figure and cancels out. Taking a per-lineage mutation rate from elsewhere and applying it to a pairwise count would overestimate every divergence time by about a factor of two, and nothing in the arithmetic would reveal the error.
W and Y differ at 18 positions. Dividing 18 differences by the rate of 0.2 differences per million years gives 18 divided by 0.2, which is 90 million years. The divergence of Y from W is therefore estimated at approximately 90 million years ago.
W and Z differ at 41 positions. Dividing 41 by 0.2 gives 205 million years, so the divergence of Z from W is estimated at approximately 205 million years ago. The order of relatedness is therefore X most closely related to W, then Y, then Z most distantly, which matches the order of the difference counts as it must.
The figures should be checked for plausibility before being reported. Divergences of 90 and 205 million years are within the range spanned by vertebrate groups, so both are possible. Two results would not be: a divergence time greater than the age of life on Earth, or one exceeding the age of the group the species belong to, and a divergence estimate older than the oldest fossil of the whole lineage would indicate an error in the rate or the counts rather than a discovery. Note also that 41 differences in a 100-position protein means the sequences are 59 per cent identical, so the count is well short of the point at which so many positions have changed that the relationship is no longer readable.
The deduction assumes that differences have accumulated at an approximately constant rate over the whole period and in all four lineages, which is the molecular clock assumption and is only approximately true, since rates vary between proteins, between lineages and over time; that the fossil calibration of 15 million years is itself accurate, so any error in it scales all the derived dates; that each counted position has changed only once, which becomes unsafe as counts rise; and that the sequences are homologous and correctly aligned. Because of these, the figures should be reported as estimates of order of magnitude rather than as precise dates, and they would be far more secure if the same calculation were repeated using several independent proteins.
W and X differ at 3 positions and diverged 15 million years ago on fossil evidence, so the rate of accumulation is 3 differences divided by 15 million years, or 0.2 differences per million years. It matters that this rate was calibrated from a pairwise count and is applied to pairwise counts: differences accumulate independently along both lineages after divergence, so a count between two living species reflects change on two branches and is proportional to roughly twice the time since divergence, but because the calibration was made the same way that factor is already inside the 0.2 figure and cancels. Taking a per-lineage mutation rate from elsewhere and applying it to pairwise counts would overestimate every date by about a factor of two, with nothing in the arithmetic revealing it. Applying the rate, W and Y differ at 18 positions, and 18 divided by 0.2 gives 90 million years, so Y diverged from W approximately 90 million years ago; W and Z differ at 41 positions, and 41 divided by 0.2 gives 205 million years, so Z diverged approximately 205 million years ago. The order of relatedness is therefore X, then Y, then Z, matching the order of the raw counts as it must. Checking plausibility, divergences of 90 and 205 million years lie within the range spanned by vertebrate groups and are possible, whereas a date exceeding the age of life on Earth or older than the oldest fossil of the lineage would indicate an error in the rate or the counts rather than a discovery; and 41 differences in a 100-position protein leaves the sequences 59 per cent identical, well short of the saturation point at which positions change more than once and the clock begins to underestimate. The deduction assumes an approximately constant rate over the whole period and in all four lineages, which is only approximately true since rates vary between proteins, lineages and times; that the 15-million-year fossil calibration is accurate, since any error in it scales every derived date; that each counted position has changed only once, which becomes unsafe as counts rise; and that the sequences are homologous and correctly aligned. The figures should therefore be reported as order-of-magnitude estimates rather than precise dates, and would be far more secure if the calculation were repeated across several independent proteins.
Practise independently
Answer every question in your own words first. The model answers are for checking against, not for copying.
Multiple Choice
+5 XPA fresh set drawn from this lesson's question bank, feedback shown immediately. +5 XP per correct · +25 XP all correct
Pick your answer, then rate your confidence, that tells the system what to drill next.
Short Answer, 12 marks
+5 XPAnalyseBand 5(5 marks) 1. Describe how you could use DNA or amino-acid sequences to infer the evolutionary relationships between three species, and explain one assumption and one limitation of the method.
2 marks: clear method (align same sequence, count differences, tabulate, infer relatedness) · 1 mark: correct inference rule (fewer differences = closer) · 1 mark: assumption (molecular clock) · 1 mark: limitation (single short sequence / uneven mutation rate)
AnalyseBand 5(3 marks) 2. Amino acid differences in cytochrome c compared with the human sequence are: chimpanzee 0, rhesus monkey 1, horse 12, tuna 21, yeast 44. Rank these species from most to least closely related to humans and explain how the data justify the ranking.
1 mark: correct ranking, chimpanzee, rhesus monkey, horse, tuna, yeast · 1 mark: states the inference rule, fewer differences means less time since the common ancestor · 1 mark: explains that the differences accumulate after two lineages separate, so the count estimates divergence time
EvaluateBand 5-6(5 marks) 3. A student builds a phylogenetic tree from one short DNA sequence and presents it as settled. Evaluate the reliability and validity of that conclusion, and describe two changes that would improve it.
1 mark: identifies the molecular clock assumption and that mutation rates are not uniform between genes or lineages · 1 mark: identifies that a short sequence gives few informative positions, so chance differences carry too much weight · 1 mark: one improvement that raises reliability, comparing several genes or proteins and checking the trees agree · 1 mark: one improvement that raises validity, using a conserved sequence present in all the species and aligning it carefully · 1 mark: reaches a judgement that the tree is a hypothesis supported to a stated degree rather than a settled result
Show all answers
Multiple choice
MC answers and full explanations are shown inline as you complete each question. Use the retry button to attempt a fresh set from the lesson bank.
Short Answer Model Answer
Q1 (5 marks): To infer evolutionary relationships, obtain the same conserved DNA or amino-acid sequence from each of the three species (for example from a public sequence database), align the sequences so the same positions line up, then for each pair count the number of positions at which they differ and record the totals in a difference matrix. Interpret the data using the rule that the pair with the fewest differences shares the most recent common ancestor and is therefore the most closely related, while pairs with more differences diverged longer ago; this pattern is then used to draw a phylogenetic tree. One key assumption is the molecular clock, that mutations accumulate at a roughly steady rate over time, so the number of differences reflects the time since divergence. One limitation is that a single short sequence can give a misleading result because mutation rates are not perfectly constant between genes or lineages; comparing several genes or proteins, and using a conserved sequence with careful alignment, improves the reliability and validity of the inferred tree.
Q2 (3 marks): From most to least closely related to humans: chimpanzee (0 differences), rhesus monkey (1), horse (12), tuna (21), yeast (44) [1]. The inference rule is that the fewer differences there are between the same protein in two species, the more recently they shared a common ancestor, so the count is used as a measure of relatedness [1]. This works because once two lineages separate they no longer exchange genes, and each accumulates its own mutations independently; the longer they have been separate, the more positions will have changed in one lineage or the other, so the number of differences estimates the time since divergence [1].
Q3 (5 marks): The conclusion rests on the molecular clock assumption, that mutations accumulate at a roughly steady rate, and that assumption is only approximately true: different genes are under different functional constraints and mutation rates differ between lineages, so a difference count converts to time only loosely [1]. A short sequence compounds the problem, because it contains few positions that differ at all, and with few informative positions a small number of chance differences, or a single misaligned region, can change which species pair joins first [1]. To improve reliability, compare several independent genes or proteins from the same species and check whether the resulting trees agree; a branching order that recurs across several independent sequences is far better supported than one that appears in a single short one [1]. To improve validity, make sure the sequence chosen is genuinely comparable: use a conserved gene or protein that all the species possess, align it carefully so that the same positions are being compared, and check that any gaps in the alignment are handled consistently, since a misalignment compares positions that are not equivalent and measures nothing meaningful [1]. My judgement is that a tree from one short sequence should be presented as a hypothesis with a stated level of support, not as a settled result. It is legitimate evidence, and it becomes strong evidence when several sequences and independent lines such as comparative anatomy and the fossil record converge on the same branching order [1].
Retrieve and reflect
Do the spaced-review set from memory first, then look back at the prediction you made before you read anything.
Check what actually stuck
A short spaced-review set drawn from this lesson and the lessons before it. Answer from memory first, that is what makes it stick.
Lock it in
bossYou can now compare sequences, build a difference matrix and infer a phylogenetic tree, while recognising the method's assumptions and limits. Next lesson steps back to weigh this biochemical evidence against the other major lines of evidence for evolution.
↩ Back to focus-area hubHow did your thinking change?
You compared three species: A and B differed at 2 positions, A and C at 11. A and B are more closely related, because fewer sequence differences mean less time has passed since they shared a common ancestor, mutations have had less time to accumulate. Your assumption was the molecular clock: that differences build up at a roughly steady rate over time, so the count of differences estimates relatedness.
If your first instinct was to judge relatedness by appearance, this investigation shows why molecules can overrule looks, convergent evolution can make unrelated species resemble one another, but the underlying sequence cannot fake a shared ancestry.