Chemistry Year 11 · Module 1 ⏱ ~45 min

Gravimetric Analysis and Choosing Techniques

Every time a water authority tests your tap water for mineral content, or a food manufacturer checks the salt level in a product, they are likely using gravimetric analysis. It is one of the oldest quantitative techniques in chemistry — and one of the most accurate.

⚗️

📝 Choose how you work: type answers below, or work in your book.

📚 Know

  • The principle of gravimetric analysis
  • The steps in a gravimetric analysis procedure
  • The properties of components that determine technique choice

🔗 Understand

  • Why precipitation is used in gravimetric analysis
  • How mass measurements allow quantitative determination
  • How to systematically match technique to mixture type

✅ Can Do

  • Describe and justify a gravimetric analysis procedure
  • Select and justify the appropriate separation technique for any mixture
  • Evaluate the effectiveness of different techniques for a scenario
📋

Key Definitions

gravimetric analysisA quantitative technique where the amount of a substance is determined by measuring the mass of a product formed in a chemical reaction (typically a precipitate).
precipitationThe formation of an insoluble solid (precipitate) when two solutions are mixed and a reaction produces a substance that is insoluble in the solvent.
precipitateAn insoluble solid formed from a reaction in solution. Can be separated from the solution by filtration.
stoichiometryThe quantitative relationship between reactants and products in a chemical reaction, based on the balanced equation.

Core Content

⚖️

Gravimetric Analysis

Principle

Gravimetric analysis is a quantitative method — it doesn't just detect a substance, it measures how much of it is present. The key idea: cause the target substance to form an insoluble precipitate with a known reagent, then collect, dry, and weigh the precipitate. Using stoichiometry (the molar ratios from the balanced equation), you can calculate the mass of the original substance.

Why precipitation? A precipitate is insoluble — it can be separated by filtration with high efficiency. Drying removes all solvent mass, so the dried precipitate mass reflects only the target substance. This makes mass measurement highly accurate.

General Procedure

1. Dissolve sample in water (or prepare aqueous solution of unknown) 2. Add excess precipitating reagent → target ion forms insoluble precipitate 3. Filter precipitate (use ashless filter paper to avoid adding mass) 4. Wash precipitate with distilled water to remove soluble impurities 5. Dry precipitate to constant mass (oven or desiccator) 6. Weigh dried precipitate 7. Use stoichiometry to calculate mass/amount of original substance

Example: Determining Chloride Content

To determine the mass of Cl⁻ ions in a solution: add excess silver nitrate (AgNO₃) solution. Cl⁻ reacts with Ag⁺ to form silver chloride (AgCl), a white precipitate that is insoluble in water.

Reaction:  Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

From the molar mass of AgCl (143.3 g mol⁻¹) and Cl⁻ (35.5 g mol⁻¹), the ratio is known. So if you weigh the dry AgCl precipitate, you can calculate the original mass of Cl⁻.

Sources of Error in Gravimetric Analysis

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Diagram: Gravimetric Analysis Workflow

Insert a flow diagram: Add sample solution → Add precipitating reagent → Precipitate forms → Filter (funnel + ashless paper) → Wash precipitate → Dry to constant mass → Weigh → Calculate. Use boxes with arrows, label each step briefly.

🗺️

Choosing the Right Separation Technique

You now have five techniques. Choosing correctly is a core HSC skill. The decision always starts with the physical and chemical properties of the components you are trying to separate.

Mixture typeKey property differenceTechnique
Insoluble solid in liquidParticle sizeFiltration
Dissolved solid in solutionSolubility changes with temperatureCrystallisation
Liquid + non-volatile solute (large BP diff)Boiling pointSimple distillation
Two miscible liquids with close BPsBoiling point (small difference)Fractional distillation
Multiple dissolved compounds (different polarities)Differential affinity for phasesChromatography
Dissolved ion — need to measure amount preciselyForms insoluble precipitateGravimetric analysis

Decision Framework

Is the target substance dissolved or undissolved? │ ├── Undissolved (insoluble solid) → FILTRATION │ └── Dissolved → What property differs? │ ├── Boiling point difference │ ├── Large difference / non-volatile solute → SIMPLE DISTILLATION │ └── Small difference / both volatile → FRACTIONAL DISTILLATION │ ├── Solubility changes with temperature → CRYSTALLISATION │ ├── Different polarity / affinity for solvents → CHROMATOGRAPHY │ └── Need quantitative measurement of a specific ion → GRAVIMETRIC ANALYSIS
Evaluating effectiveness: When asked to "evaluate", you must discuss both strengths and limitations. Ask: How complete is the separation? How pure is the product? How much does it cost in time and resources? Can it be scaled up?

Worked Examples

1

Worked Example 1 — Annotated: gravimetric analysis calculation

A 250 mL sample of drinking water is analysed for sulfate content. Excess barium chloride (BaCl₂) solution is added. The white precipitate of barium sulfate (BaSO₄) is filtered, dried, and weighed: mass = 0.466 g. Calculate the mass of sulfate (SO₄²⁻) in the 250 mL sample. [Molar masses: Ba = 137.3, S = 32.1, O = 16.0 g mol⁻¹]
Step 1 — Write the reactionBa²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
Molar mass of BaSO₄ = 137.3 + 32.1 + (4 × 16.0) = 233.4 g mol⁻¹
Molar mass of SO₄²⁻ = 32.1 + (4 × 16.0) = 96.1 g mol⁻¹
Always write the balanced ionic equation first. The 1:1 molar ratio means 1 mol BaSO₄ came from 1 mol SO₄²⁻. This ratio is what connects the precipitate mass to the original ion.
Step 2 — Find moles of BaSO₄n(BaSO₄) = mass ÷ molar mass
n(BaSO₄) = 0.466 ÷ 233.4 = 0.001997 mol
Work to 4 significant figures throughout to avoid rounding errors before the final answer.
Step 3 — Apply molar ratioFrom the equation: n(SO₄²⁻) = n(BaSO₄) = 0.001997 mol
(1:1 ratio from balanced equation)
This 1:1 ratio is the stoichiometric bridge between what you measured (BaSO₄) and what you want to know (SO₄²⁻). In other reactions the ratio may not be 1:1 — always check the balanced equation.
Step 4 — Calculate mass of SO₄²⁻m(SO₄²⁻) = n × M
m(SO₄²⁻) = 0.001997 × 96.1 = 0.192 g
Round to 3 significant figures at the end (limited by the precision of the mass measurement: 0.466 g is 3 sig figs).
Answer
The 250 mL water sample contains 0.192 g of sulfate (SO₄²⁻).
2

Worked Example 2 — Annotated: selecting and justifying a technique

A sample of ocean water contains: dissolved NaCl, dissolved MgCl₂, fine sand particles, and traces of oil (which floats on the surface and is immiscible with water). A researcher wants to obtain: (a) clean dry sand, (b) pure NaCl crystals, (c) separate the oil from the water. Recommend and justify a technique for each.
(a) Clean dry sandSand is insoluble in water. Separation basis: particle size. Technique: filtration. Pour the sample through filter paper to collect sand as residue; rinse with distilled water; dry. The key property is insolubility. Filtration works because sand particles are large enough to be retained by filter paper, while dissolved NaCl and MgCl₂ pass through in the filtrate.
(b) Pure NaCl crystalsNaCl is dissolved — filtration won't work. NaCl's solubility decreases on cooling. Technique: crystallisation. First filter to remove sand (filtrate = salt water). Heat filtrate to concentrate, cool slowly to crystallise NaCl, filter crystals, dry. Note: MgCl₂ will also be present — further purification (recrystallisation) would be needed for chemically pure NaCl. The step before crystallisation is important — you must remove the insoluble sand first, or it will be embedded in the crystals. This is an example of a sequential separation strategy.
(c) Separate oil from waterOil is immiscible with water (does not dissolve) and less dense (floats). The oil and water form two distinct liquid layers. Technique: separating funnel (this is an additional technique — two immiscible liquids are separated by draining the denser layer out the bottom tap while retaining the less dense layer). This is a technique not explicitly in the main syllabus list but tests your reasoning ability. The key property is immiscibility and density difference. Accept any reasonable technique that exploits these properties.
Summary
(a) Filtration — sand is insoluble. (b) Crystallisation of filtered solution — NaCl is dissolved. (c) Separating funnel — oil is immiscible with water. Each choice is justified by the key property difference between the target and the rest of the mixture.
⚠️

Common Mistakes

Not using excess precipitating reagent in gravimetric analysis. If insufficient BaCl₂ (or equivalent) is added, not all target ions precipitate → the collected mass is too low → the calculated result underestimates the true value. Always add excess.
Recommending filtration for a dissolved solid. A dissolved substance passes through filter paper — filtration cannot separate it. This is the most common technique selection error in exams. Always check: is the target dissolved or not?
Not drying the precipitate to constant mass. Any residual water adds to the measured mass and leads to an overestimate. Dry the precipitate in an oven, cool in a desiccator, weigh, dry again, reweigh — repeat until the mass stops changing.

📓 Copy Into Your Books

📖 Gravimetric Steps

  • Add excess precipitating reagent to dissolved sample
  • Filter precipitate (ashless paper)
  • Wash with distilled water
  • Dry to constant mass, then weigh
  • Use stoichiometry to find original mass

🔑 Technique Decision

  • Insoluble solid → filtration
  • Dissolved solid → crystallisation
  • Liquids, large BP diff → simple distillation
  • Liquids, close BPs → fractional distillation
  • Multiple dissolved compounds → chromatography
  • Quantitative ion measurement → gravimetric analysis

🎯 Gravimetric Calculation

  • Write balanced ionic equation
  • n(precipitate) = mass ÷ molar mass
  • Apply molar ratio from equation
  • m(target) = n × molar mass
  • Report to correct sig figs

⚠️ Exam Traps

  • Use excess reagent — incomplete precipitation underestimates
  • Dry to constant mass — moisture overestimates
  • Filtration ≠ works for dissolved substances
  • Evaluate = strengths AND limitations

Activities

⚖️ Activity 1 — Compare Techniques

Compare Gravimetric Analysis to Other Techniques

For each pair, explain the key difference in principle and state which is more appropriate for the given scenario.

Comparison A: Gravimetric Analysis vs Crystallisation

A chemist wants to know the exact mass of calcium ions (Ca²⁺) in a 100 mL sample of hard water. Would crystallisation or gravimetric analysis be more appropriate? Compare the two techniques and justify your choice.

✏️ Answer in your book
Comparison B: Filtration vs Gravimetric Analysis

A researcher needs to determine the mass of barium sulfate (BaSO₄) already present as an insoluble precipitate in a sample. Compare filtration and gravimetric analysis for this purpose.

✏️ Answer in your book
🌍 Activity 2 — Apply to Novel Context

Technique Selection — Novel Scenarios

For each scenario, (i) identify the most appropriate technique, (ii) state the key property the technique exploits, and (iii) briefly describe the procedure.

Scenario 1

A forensic chemist has a glass of water suspected to contain dissolved lead ions (Pb²⁺). She needs to confirm the presence of lead AND determine exactly how many milligrams of Pb²⁺ are in the sample. What technique should she use?

✏️ Answer in your book
Scenario 2

A student needs to separate a mixture of three amino acids from a solution. She does not need a quantitative result — she just needs to see how many components are present and whether each matches a known standard. What technique should she use?

✏️ Answer in your book
Scenario 3

A water treatment plant needs to remove fluoride ions (F⁻) from drinking water to below the WHO limit of 1.5 mg/L. They add calcium chloride (CaCl₂), which causes calcium fluoride (CaF₂) to precipitate. After precipitation, how do they remove the CaF₂? Describe the full procedure including how they would confirm the fluoride level after treatment.

✏️ Answer in your book

Multiple Choice

Multiple Choice Questions

Click to check. One attempt only.

1. What is the primary purpose of adding excess precipitating reagent in gravimetric analysis?

A
To improve the colour of the precipitate for easier identification
B
To ensure all of the target ions precipitate out of solution, so none remain dissolved and undetected
C
To dissolve any impurities that might contaminate the precipitate
D
To increase the molar mass of the precipitate, making it easier to weigh accurately

2. In a gravimetric analysis of chloride ions, 0.286 g of silver chloride (AgCl) precipitate is collected. What mass of Cl⁻ does this represent? [M(AgCl) = 143.3 g mol⁻¹; M(Cl) = 35.5 g mol⁻¹]

A
0.071 g
B
0.250 g
C
0.143 g
D
0.0709 g

3. A student performs a gravimetric analysis and obtains a result that is higher than the actual value. Which error most likely caused this?

A
Insufficient precipitating reagent was added
B
Some precipitate was lost during washing
C
The precipitate was not dried to constant mass — residual moisture added to the measured mass
D
The filter paper was not rinsed with distilled water before use

4. A mixture contains dissolved potassium iodide (KI) and insoluble barium sulfate (BaSO₄). A chemist wants to obtain dry, pure BaSO₄. Which technique is most appropriate as the first step?

A
Filtration — collect BaSO₄ as residue; KI passes through in the filtrate
B
Crystallisation — crystallise both substances together then separate
C
Distillation — boil off the KI solution and collect BaSO₄ in the flask
D
Chromatography — separate BaSO₄ from KI by differential movement through a stationary phase

5. Evaluate the following claim: "Gravimetric analysis is the best technique for separating and identifying all types of mixtures." Which statement best evaluates this claim?

A
The claim is correct — gravimetric analysis is the most accurate of all separation techniques
B
The claim is incorrect — gravimetric analysis is a quantitative measurement technique for specific ions, not a general-purpose separation method; it cannot separate volatile liquids, immiscible liquids, or components with similar solubilities
C
The claim is partially correct — gravimetric analysis works for all ionic compounds but not for covalent ones
D
The claim is incorrect only because gravimetric analysis is too slow to be useful in modern chemistry

Short Answer

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Short Answer Questions

6. Describe the steps involved in gravimetric analysis to determine the mass of barium ions (Ba²⁺) in a solution using sodium sulfate (Na₂SO₄) as the precipitating reagent. In your answer, explain why each step is important. 3 MARKS

✏️ Answer in your book

7. A sample of industrial waste water is suspected to contain sulfate ions (SO₄²⁻). A chemist adds excess barium chloride solution to a 500 mL sample and collects 0.932 g of dry barium sulfate precipitate. Calculate the mass of sulfate in the 500 mL sample. Show all working. [M(BaSO₄) = 233.4 g mol⁻¹; M(SO₄²⁻) = 96.1 g mol⁻¹] 4 MARKS

✏️ Answer in your book

8. A chemist is given a sample of sea water and asked to determine the concentration of chloride ions (Cl⁻) using gravimetric analysis. Evaluate the effectiveness of this technique for this purpose, discussing its strengths and at least two limitations. 5 MARKS

✏️ Answer in your book

✅ Comprehensive Answers

⚖️ Activity 1 — Compare

A: Crystallisation would recover NaCl crystals from the water but would not tell you the exact mass of Ca²⁺ — the dissolved calcium would remain in solution. Gravimetric analysis is more appropriate: add excess Na₂SO₄ (or Na₂CO₃) to precipitate all Ca²⁺ as CaSO₄ (or CaCO₃), filter, dry to constant mass, weigh, and use stoichiometry to calculate m(Ca²⁺). It is the only technique that provides a quantitative measurement of a specific dissolved ion.

B: Filtration could physically separate the BaSO₄ precipitate from the solution (it is already insoluble). Gravimetric analysis in this context would involve the same filtration step — but also includes washing, drying to constant mass, and weighing to obtain a quantitative result. The difference: filtration alone gives you the solid; gravimetric analysis gives you the solid AND its mass, which is required for any quantitative determination. If you only need the solid and not a precise mass, filtration alone is sufficient.

🌍 Activity 2 — Apply to Novel Context

Scenario 1: Gravimetric analysis. Key property: Pb²⁺ forms an insoluble precipitate with specific reagents (e.g. add Na₂SO₄ → PbSO₄(s) precipitates). Procedure: add excess Na₂SO₄ to the water sample → PbSO₄ precipitates → filter with ashless paper → wash → dry to constant mass → weigh → use stoichiometry to calculate m(Pb²⁺). This gives both confirmation (precipitate forms) and quantification (mass calculated).

Scenario 2: Chromatography (paper or TLC). Key property: differential attraction of each amino acid to stationary/mobile phases gives different Rf values. Procedure: spot all three amino acids on the baseline along with known standards → develop with appropriate solvent → measure Rf values for each spot → compare to standard Rf values for identification. No quantitative measurement needed — separation and identification only.

Scenario 3: Remove CaF₂ by filtration — it is an insoluble precipitate. Pour the treated water through filter paper (or a membrane filter for industrial scale); CaF₂ is retained as residue; the treated water (filtrate) has reduced F⁻. To confirm fluoride level: use gravimetric analysis on a sample of the treated water — add excess CaCl₂ to precipitate any remaining F⁻ as CaF₂, dry, weigh, and calculate m(F⁻) to verify it is below 1.5 mg/L.

❓ Multiple Choice

1. B — Excess reagent ensures complete precipitation of all target ions. Insufficient reagent leaves some ions in solution, giving an underestimate.

2. D — n(AgCl) = 0.286 ÷ 143.3 = 0.001996 mol. n(Cl⁻) = 0.001996 mol (1:1 ratio). m(Cl⁻) = 0.001996 × 35.5 = 0.0709 g.

3. C — Residual moisture adds to the measured mass, giving an overestimate. A (insufficient reagent) and B (precipitate loss) both cause underestimates.

4. A — BaSO₄ is insoluble → filtration separates it as residue. KI is dissolved → passes through in filtrate. Crystallisation, distillation, and chromatography are not suited to separating an insoluble solid from a solution in this way.

5. B — Gravimetric analysis is a quantitative measurement technique for specific ions that form insoluble precipitates. It cannot separate miscible liquids, volatile components, or immiscible liquids. D is wrong (it is still widely used); A and C are incorrect overstatements.

📝 Short Answer Model Answers

Q6 (3 marks): Step 1 — Add excess Na₂SO₄ to the solution: the excess ensures all Ba²⁺ ions react and precipitate as BaSO₄; without excess, some Ba²⁺ would remain dissolved and be unmeasured (1 mark). Step 2 — Filter the precipitate, wash with distilled water: filtration separates the insoluble BaSO₄ from the solution; washing removes soluble impurities that could add to the mass and cause overestimation (1 mark). Step 3 — Dry the precipitate to constant mass, then weigh: drying removes all residual water which would add falsely to the measured mass; drying to constant mass confirms no water remains; the final dry mass is used with stoichiometry to calculate m(Ba²⁺) (1 mark).

Q7 (4 marks): Reaction: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s) [1:1 molar ratio] (1 mark). n(BaSO₄) = 0.932 ÷ 233.4 = 0.003993 mol (1 mark). n(SO₄²⁻) = 0.003993 mol (1:1 ratio from balanced equation) (1 mark). m(SO₄²⁻) = 0.003993 × 96.1 = 0.384 g (1 mark).

Q8 (5 marks): Gravimetric analysis is effective for determining Cl⁻ concentration in sea water because it can precisely quantify very small amounts of an ion, and AgCl is a highly insoluble precipitate that forms reliably and quantitatively (1 mark). Strength: it is a direct mass measurement — does not depend on colour, electronic signals, or calibration curves, making it highly accurate and reproducible (1 mark). Limitation 1: sea water contains multiple anions (SO₄²⁻, Br⁻, I⁻) that may also precipitate with AgNO₃, leading to co-precipitation and overestimation of the Cl⁻ content; additional steps to remove interfering ions are needed (1 mark). Limitation 2: the procedure is time-consuming — drying to constant mass can take hours to days; modern methods like ion chromatography or potentiometric titration are faster for routine analysis (1 mark). Overall: gravimetric analysis is highly accurate for Cl⁻ in sea water if interfering ions are controlled, but is not ideal for high-throughput or field testing due to time requirements (1 mark).

Mark lesson as complete

Tick when you've finished all activities and checked your answers.

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