ChemistryYear 11 · Module 1 · IQ2⏱ ~30 min

Metallic Bonding and Properties

In 1897, J.J. Thomson discovered the electron. Within a decade, the "electron sea" model of metallic bonding emerged: a lattice of positive metal ions surrounded by freely flowing valence electrons. This model — over 125 years old — still explains every strange property of metals, from why copper wire bends without breaking to why mercury is liquid at room temperature.

⚙️

📝 Choose how you work: type answers below, or work in your book.

📚 Know

  • The electron sea (delocalised electron) model of metallic bonding
  • The physical properties of metals: conductivity, malleability, ductility, lustre, high MP
  • How alloy formation changes metallic properties

🔗 Understand

  • Why the electron sea model explains every key metallic property
  • Why metal strength and MP vary across the periodic table
  • Why alloying disrupts the regular lattice and changes mechanical properties

✅ Can Do

  • Explain any metallic property using the electron sea model
  • Compare metals and alloys in terms of structure and properties
  • Predict how alloying would change the properties of a metal
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Key Definitions

metallic bondingElectrostatic attraction between a lattice of positive metal cations and a sea of mobile, delocalised valence electrons.
delocalised electronsElectrons that are not associated with any specific atom but are free to move throughout the entire metallic structure — the "electron sea".
malleabilityAbility to be hammered or pressed into sheets without fracturing. Metals are malleable because ion layers slide while the electron sea maintains bonding.
ductilityAbility to be drawn into wire. Same principle as malleability — non-directional bonding allows deformation without fracture.
alloyA mixture of a metal with one or more other elements (metals or non-metals), designed to improve properties like hardness, corrosion resistance, or strength.
thermal conductivityAbility to conduct heat. In metals, delocalised electrons transfer kinetic energy through the lattice rapidly, making metals good thermal conductors.

Core Content

The Electron Sea Model

What is metallic bonding?

When metal atoms come together, their valence electrons are released from individual atoms and become shared across the entire structure — they are delocalised. The result is a regular lattice of positive metal cations (now missing their valence electrons) immersed in a mobile "sea" of delocalised electrons. The metallic bond is the electrostatic attraction between this cation lattice and the electron sea.

Key insight: Unlike ionic bonds (between specific pairs of ions) or covalent bonds (between specific pairs of atoms), metallic bonding is non-directional — there is no preferred direction for the bond. This non-directionality is the root cause of malleability and ductility.

Property-by-Property Explanation

PropertyExplanation using the electron sea model
Electrical conductivityDelocalised electrons are always mobile — applying a voltage causes them to flow as current. No lattice disruption needed. Conductivity in solid AND liquid state.
Thermal conductivityMobile electrons absorb kinetic energy at the heated end and rapidly transfer it throughout the lattice — much faster than vibration alone in ionic/covalent lattices.
Malleability / ductilityWhen force is applied, cation layers slide past each other. The electron sea redistributes around the new arrangement, maintaining bonding. No localised bonds break → no fracture.
Metallic lustreDelocalised electrons on the surface absorb and re-emit light across all visible wavelengths → shiny appearance (characteristic metallic shine).
Variable melting pointDepends on number of delocalised electrons per atom and ion charge. More delocalised electrons + higher charge = stronger electron-cation attraction = higher MP. (e.g. W 3422°C vs Cs 29°C)
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Diagram: Electron Sea Model

Insert diagram: rows of close-packed metal cations (labelled M⁺, shown as circles) with a background of tiny dots representing delocalised electrons throughout. Label: metal cation (M⁺), delocalised electron sea, metallic bond (electrostatic attraction between cations and electron sea). Show layered arrangement to illustrate malleability — one layer slightly shifted with arrows showing direction of force.

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Metallic Properties — Trends and Variations

Why do different metals have different properties?

Not all metals behave identically. The strength of metallic bonding — and therefore properties like MP and hardness — varies depending on:

MetalGroupApprox. MP (°C)Delocalised e⁻ per atomTrend explanation
Caesium (Cs)1291Very low MP — weak metallic bonding (1 delocalised e⁻, large ion)
Sodium (Na)1981Low MP — 1 delocalised e⁻, smaller than Cs
Magnesium (Mg)26502Moderate MP — 2 delocalised e⁻
Iron (Fe)Transition15382–3+High MP — multiple d electrons contribute to bonding
Tungsten (W)Transition34226+Highest MP of all metals — very strong metallic bonding
🔩

Alloys — Designed Metallic Materials

What is an alloy and why make one?

A pure metal has a regular lattice of identical-sized cations. This regularity means layers slide easily — pure metals are often too soft or too corrosion-prone for engineering applications. An alloy introduces atoms of different sizes into the lattice, disrupting the regular arrangement and making it harder for layers to slide.

Why alloys are harder than pure metals: Foreign atoms (different size) create distortions in the lattice. When a force is applied, the distortions prevent smooth sliding of layers — more force is required to deform the alloy. Result: harder, stronger, less ductile than the pure metal.
AlloyBase metalAdded elementsKey property improvementApplication
SteelIron (Fe)Carbon (C, 0.2–2%)Harder, stronger than pure FeConstruction, tools
Stainless steelIronChromium (Cr, ~18%), NiCorrosion resistant, harderCutlery, surgical tools
BronzeCopper (Cu)Tin (Sn, ~10–12%)Harder, stronger than pure CuBearings, medals, instruments
BrassCopperZinc (Zn, 20–45%)Stronger, corrosion resistant, golden colourPipes, musical instruments
DuraluminAluminium (Al)Cu (~4%), Mg, MnMuch stronger than pure Al, low densityAircraft bodies
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Diagram: Alloy Structure vs Pure Metal

Insert side-by-side diagrams: (left) pure metal — rows of identical-sized circles, neat layers, arrow showing easy layer sliding; (right) alloy — rows disrupted by a few larger/smaller foreign atoms, arrow showing layer sliding blocked at disruption points. Label: pure metal lattice, foreign atom (different size), lattice distortion, blocked sliding plane.

Worked Examples

1

Worked Example 1 — Compare two substances: why magnesium has a higher MP than sodium

Compare the melting points of sodium (Na, MP 98°C, Group 1) and magnesium (Mg, MP 650°C, Group 2). Explain the difference using the electron sea model.

Sodium (Na) — MP 98°C

  • Group 1 — releases 1 valence electron per atom
  • Cation: Na⁺ (charge = +1)
  • Electron sea: 1 delocalised electron per Na atom
  • Electrostatic attraction between Na⁺ and electron sea is relatively weak (low charge, fewer electrons)
  • Result: metallic bonding is relatively weak → low MP for a metal

Magnesium (Mg) — MP 650°C

  • Group 2 — releases 2 valence electrons per atom
  • Cation: Mg²⁺ (charge = +2)
  • Electron sea: 2 delocalised electrons per Mg atom
  • Electrostatic attraction between Mg²⁺ and the denser electron sea is much stronger (higher charge, more electrons)
  • Result: metallic bonding is stronger → significantly higher MP
Conclusion
Mg has a higher MP than Na because Mg²⁺ has double the ionic charge of Na⁺ and releases twice as many electrons into the electron sea. The stronger attraction between Mg²⁺ cations and the denser electron sea produces stronger metallic bonding, requiring more energy (higher temperature) to disrupt the lattice and allow atoms to move freely.
2

Worked Example 2 — Compare two substances: pure copper vs bronze alloy

Pure copper (Cu) is malleable and relatively soft. Bronze (Cu + ~10% Sn) is significantly harder. Explain this difference using the electron sea model and the structure of alloys.

Pure Copper

  • Regular lattice of identical Cu²⁺ cations, all the same size
  • Electron sea flows uniformly throughout
  • Under force: layers of Cu ions slide smoothly past each other — no size irregularities to impede motion
  • Electron sea adjusts and maintains bonding through the deformation
  • Result: highly malleable, relatively soft — layers slide too easily

Bronze (Cu + 10% Sn)

  • Lattice mostly Cu²⁺, but ~10% of sites occupied by larger Sn⁴⁺/Sn²⁺ ions
  • Lattice is distorted where Sn ions sit — different size disrupts regular packing
  • Under force: layer sliding is impeded at Sn sites — layers cannot slide past the larger Sn atoms
  • More energy (greater force) is required to move layers past the distortions
  • Result: harder, stronger, less malleable than pure Cu
Conclusion
Bronze is harder than pure copper because the addition of tin (different-sized atoms) disrupts the regular Cu lattice, creating local distortions that prevent smooth layer sliding. This is the general mechanism behind alloy hardening: foreign atoms of different size act as obstacles to dislocation movement, requiring greater force to deform the material.
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Common Mistakes

Saying metals have "free electrons" without specifying they are delocalised valence electrons. The correct term is "delocalised electrons" — they come from the valence shells of metal atoms and are shared across the entire structure. "Free electrons" is acceptable informal language, but in an exam response, say "delocalised valence electrons" for full marks.
Saying alloys are harder because they have "more atoms". The correct reason is the disruption of the regular lattice by different-sized foreign atoms, which prevents smooth layer sliding. The number of atoms per se is not the issue — it's the size irregularity creating obstacles to deformation.
Confusing thermal and electrical conductivity mechanisms. Both rely on delocalised electrons, but the mechanisms differ: electrical conductivity = electrons move directionally under voltage; thermal conductivity = electrons carry kinetic energy rapidly through the lattice. You can mention both in an answer, but keep the mechanisms distinct.

📓 Copy Into Your Books

📖 Electron Sea Model

  • Metal cation lattice + sea of delocalised valence electrons
  • Electrostatic attraction: cations ↔ electron sea
  • Non-directional bonding → layers can slide → malleability
  • Mobile electrons → electrical and thermal conductivity

🔑 MP Trend (Metallic)

  • More delocalised e⁻ per atom → stronger bonding → higher MP
  • Higher cation charge → stronger attraction → higher MP
  • Smaller cation → stronger attraction → higher MP
  • Group 1 < Group 2 < Transition metals (general trend)

🎯 Alloy Mechanism

  • Foreign atoms (different size) disrupt regular lattice
  • Distortions impede layer sliding → harder, stronger
  • Trade-off: harder but less malleable/ductile
  • Examples: steel (Fe+C), brass (Cu+Zn), duralumin (Al+Cu)

⚠️ Exam Traps

  • Say "delocalised valence electrons" not just "free electrons"
  • Alloy hardness: reason = lattice distortion by different-sized atoms
  • Thermal + electrical conductivity: both from mobile electrons
  • Malleability: non-directional bonding, NOT "no ionic bonds"

Activities

⚖️ Activity 1 — Compare Metallic Properties

Compare Two Metals

Use the electron sea model to compare each pair. Identify which will have the higher MP or greater malleability, and justify.

Comparison A: Potassium (K, Group 1) vs Calcium (Ca, Group 2)

Predict which metal has the higher melting point. Explain using ionic charge and number of delocalised electrons.

✏️ Answer in your book
Comparison B: Pure iron (Fe) vs Steel (Fe + 0.5% C)

Compare the hardness and malleability of pure iron versus steel. Explain using the alloy structure model.

✏️ Answer in your book
🌍 Activity 2 — Apply to Novel Contexts

Novel Application Questions

Novel Context 1

An engineer needs a metal for high-temperature jet engine turbine blades. She is considering tungsten (W, MP 3422°C) or aluminium (Al, MP 660°C). Using the electron sea model, explain which is more suitable for this application and why W has such a dramatically higher MP than Al.

✏️ Answer in your book
Novel Context 2

A jeweller argues that 24-carat gold (pure gold) makes the best jewellery because it is "the purest and strongest." A chemist disagrees. Evaluate the chemist's position using your knowledge of alloy structure. Would 18-carat gold (75% Au, 25% other metals) be stronger or weaker than pure gold? Explain.

✏️ Answer in your book

Multiple Choice

Multiple Choice Questions

Click to check. One attempt only.

1. The primary reason metals are malleable is that:

A
Metal atoms are larger than non-metal atoms, allowing more room to deform
B
Metallic bonding is non-directional — cation layers can slide while the delocalised electron sea maintains bonding throughout
C
Metals have no bonds between atoms — they are held together only by gravity
D
The ionic bonds in metals are weaker than in ionic compounds, allowing deformation

2. Which trend in metallic bonding strength is correctly described?

A
Group 1 metals have stronger bonding than Group 2 because they have fewer valence electrons
B
Larger metal cations always form stronger metallic bonds than smaller ones
C
Metals with more delocalised electrons per atom and higher cation charge generally have stronger metallic bonding and higher MPs
D
All metals have the same strength of metallic bonding because the electron sea is uniform

3. Why is bronze (Cu + Sn) harder than pure copper?

A
Tin increases the number of delocalised electrons in the alloy
B
Tin atoms form ionic bonds with copper atoms, creating a stronger lattice
C
The mixture of two metals always produces a compound with covalent bonds
D
Tin atoms of different size disrupt the regular Cu lattice, creating distortions that impede layer sliding and require greater force to deform

4. A metal has the following properties: excellent electrical conductivity, high melting point, hard but not brittle, malleable. Which structural model best explains ALL of these properties simultaneously?

A
Electron sea model — positive cation lattice surrounded by mobile delocalised electrons
B
Ionic lattice model — alternating positive and negative ions in a 3D lattice
C
Covalent network model — atoms connected by strong directional bonds throughout
D
Molecular model — discrete molecules held by weak intermolecular forces

5. An engineer wants to maximise both strength and corrosion resistance in a metal used for outdoor structures. Which material would be most appropriate?

A
Pure iron — highest strength, naturally corrosion resistant
B
Stainless steel (Fe + ~18% Cr + Ni) — alloying increases strength and Cr provides a protective oxide layer for corrosion resistance
C
Pure aluminium — lightest metal, immune to all corrosion
D
Bronze — best overall corrosion resistance and strength of all alloys

Short Answer

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Short Answer Questions

6. Using the electron sea model, explain why metals are good conductors of both electricity and heat. Clearly distinguish the mechanisms for each type of conductivity. 3 MARKS

✏️ Answer in your book

7. Explain why adding carbon atoms to iron produces steel that is harder and less malleable than pure iron. Refer specifically to the effect on the metallic lattice structure. 3 MARKS

✏️ Answer in your book

8. Tungsten (W, Group 6 transition metal, MP 3422°C) has one of the highest melting points of all metals, while caesium (Cs, Group 1, MP 29°C) has one of the lowest. Using the electron sea model, explain this large difference in melting points in terms of the metallic bonding in each metal. 4 MARKS

✏️ Answer in your book

✅ Comprehensive Answers

⚖️ Activity 1

A: Calcium has the higher MP. K (Group 1) contributes 1 valence electron and forms K⁺ (charge +1). Ca (Group 2) contributes 2 valence electrons and forms Ca²⁺ (charge +2). Ca²⁺ has a higher ionic charge and contributes more electrons to the electron sea — both factors increase the electrostatic attraction between cations and the electron sea → stronger metallic bonding → higher MP (Ca: 842°C vs K: 63°C).

B: Pure Fe has a regular lattice of identical Fe cations — layers slide relatively smoothly, making it malleable (though less so than Group 1 metals due to stronger bonding). When 0.5% carbon is added, the smaller C atoms occupy interstitial spaces in the Fe lattice, distorting the regular arrangement. These distortions act as obstacles to layer sliding — more force is required to deform the steel. Result: steel is harder and less malleable than pure iron, which is why raw iron is rarely used in structural applications.

🌍 Activity 2

Novel Context 1: Tungsten (W) is far more suitable for turbine blades — its MP of 3422°C means it remains solid at operating temperatures of jet engines (~1500°C). Aluminium (MP 660°C) would melt immediately. W has such a dramatically higher MP because it is a transition metal that contributes ~6 valence electrons per atom into the electron sea (compared to Al's 3). Additionally, W⁶⁺ carries a much higher charge than Al³⁺. The combination of many delocalised electrons and high cation charge produces extremely strong metallic bonding requiring enormous energy (very high temperature) to overcome.

Novel Context 2: The chemist is correct — pure 24-carat gold is actually the weakest and softest form of gold jewellery, not the strongest. 18-carat gold (an alloy with 25% other metals such as Ag, Cu, or Pd) is significantly harder and stronger than pure gold. The added atoms have different sizes from Au and disrupt the regular gold lattice, creating distortions that prevent smooth layer sliding — more force is required to scratch or deform the alloy. Pure gold is so soft that rings made from it will deform under normal wear. The trade-off is reduced purity, but the alloy is far more practical for everyday jewellery.

❓ Multiple Choice

1. B — Non-directional bonding allows layer sliding while the electron sea maintains cohesion. A, C, D are all incorrect descriptions of metallic structure.

2. C — More delocalised electrons + higher charge → stronger bonding → higher MP. This is the correct general principle.

3. D — Different-sized Sn atoms distort the regular Cu lattice → impede layer sliding → harder. Not about electron numbers, ionic bonds, or covalent bonds.

4. A — Only the electron sea model simultaneously explains conductivity (mobile electrons), malleability (non-directional bonding, layer sliding), and high MP (strong cation–electron attraction).

5. B — Stainless steel combines alloying strength with Cr's passive oxide layer for corrosion resistance. Pure iron corrodes easily; pure Al is weak structurally; bronze is for bearings, not structural applications.

📝 Short Answer Model Answers

Q6 (3 marks): Metals conduct electricity because their delocalised valence electrons are free to move throughout the lattice at all times. When a voltage (potential difference) is applied, electrons flow from the negative terminal toward the positive terminal — this directed electron movement constitutes an electric current (1 mark). Metals conduct heat because mobile delocalised electrons can absorb kinetic energy at the hot end of the metal and rapidly transfer this energy through collisions with other electrons and cations throughout the lattice — much faster than vibration-mediated heat transfer in non-metallic solids (1 mark). The mechanisms differ: electrical conductivity is directed electron movement driven by a voltage gradient; thermal conductivity is kinetic energy transfer by electrons moving randomly but carrying energy from hot to cool regions — one is electrical, the other is thermal (1 mark).

Q7 (3 marks): Pure iron has a regular lattice of Fe cations of uniform size, allowing layers to slide past each other relatively easily under applied force — the electron sea redistributes and maintains bonding as layers shift (1 mark). Carbon atoms are much smaller than Fe atoms. When added, they occupy interstitial spaces in the Fe lattice, distorting the regular cubic arrangement at those sites (1 mark). These distortions act as obstacles — when a shear force is applied, layers cannot slide smoothly past the sites where C atoms sit, because the C atom's size difference blocks dislocation movement. Greater force is required to deform the steel → harder; reduced ability to slide → less malleable (1 mark).

Q8 (4 marks): Caesium is a Group 1 metal — each Cs atom contributes only 1 valence electron to the electron sea, and forms a Cs⁺ cation with charge +1 (1 mark). The attraction between Cs⁺ (low charge, very large ion) and the sparse electron sea (1 electron per atom) is very weak → very low lattice energy → low MP of 29°C (1 mark). Tungsten is a Group 6 transition metal — each W atom can contribute up to ~6 valence electrons to the electron sea, and the cation carries a much higher effective charge (1 mark). The electrostatic attraction between the highly charged W cation and the very dense electron sea (~6× more electrons per atom than Cs) is enormously strong → very high lattice energy → highest MP of any metal at 3422°C. The 3393°C difference in melting point reflects this ~6× difference in the number of delocalised electrons and the dramatic difference in cation charge (1 mark).

Mark lesson as complete

Tick when you've finished all activities and checked your answers.

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