ChemistryYear 11 · Module 1 · IQ2⏱ ~20 min

📋 Checkpoint Quiz 2

This quiz covers Lessons 6–10: Physical Properties and Classification, Ionic Compounds, Metallic Bonding, Covalent Molecular and Network Solids, and Intermolecular Forces. 20 multiple choice + 3 short answer questions.

Lesson Summaries — Quick Review

🔬 L06 — Physical Properties and Classification IQ2

Four structural types: ionic (high MP, conducts molten/dissolved, hard+brittle), covalent molecular (low MP, no conductivity, soft), covalent network (very high MP, no conductivity except graphite, extremely hard except graphite), metallic (variable MP, always conducts, malleable). Classification requires at least three properties — no single property is uniquely diagnostic.

ioniccovalent molecularcovalent networkmetallicgraphite exception

🧂 L07 — Ionic Compounds: Structure and Properties IQ2

Ionic compounds form regular 3D lattices of cations and anions. Lattice energy depends on ionic charge (higher charge → stronger attraction) and ion size (smaller → stronger). Key conductivity rule: ions fixed in solid (no conductivity) → mobile when molten or dissolved (conducts). Hard but brittle due to layer-shift causing like-charge repulsion.

ionic latticelattice energycation/anioncharge effect on MP

⚙️ L08 — Metallic Bonding and Properties IQ2

Metallic bonding: cation lattice + sea of delocalised valence electrons. Non-directional → malleable/ductile. Mobile electrons → electrical and thermal conductivity. Metallic bond strength increases with more delocalised electrons per atom and higher cation charge → higher MP. Alloys: foreign atoms (different size) disrupt regular lattice → harder, less malleable.

electron sea modeldelocalised electronsmalleabilityalloy hardening

💎 L09 — Covalent Compounds: Molecular and Network IQ2

Covalent molecular: discrete molecules, IMFs between them → low MP (break IMFs, not covalent bonds). Covalent network: continuous covalent bonds throughout crystal → very high MP (break covalent bonds). Classic comparison: CO₂ (molecular, gas) vs SiO₂ (network, MP 1713°C). Graphite: network but conducts and is soft (layer structure, delocalised electrons within layers).

covalent molecularcovalent networkCO₂ vs SiO₂IMFs vs covalent bonds

🧲 L10 — Intermolecular Forces and Physical Properties IQ2

Three IMFs: dispersion forces (all molecules, increases with size), dipole-dipole (polar molecules), hydrogen bonding (N–H, O–H, F–H only — strongest IMF). BP prediction: check for H-bonding first, then polarity, then size. Larger non-polar molecules can exceed small H-bonding molecules in BP. BP anomalies (e.g. H₂O vs H₂S) explained by H-bonding.

dispersion forcesdipole-dipolehydrogen bondingBP prediction

📝 Best completed without notes first, then check your answers.

Instructions: 20 multiple choice (click to check instantly, 1 mark each). Then 3 short answer questions (self-assessed). Score tracker below updates in real time.
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L06 — Physical Properties and Classification

1. Which combination of properties is uniquely consistent with a covalent network solid? L06

A
High MP, excellent solid conductivity, malleable
B
High MP, no solid conductivity, conducts when dissolved
C
Low MP, no conductivity in any state, soft
D
Very high MP, no conductivity in solid or molten state, extremely hard

2. A substance melts at 801°C, does not conduct as a solid, but conducts well when melted. It is hard and brittle. Its structural type is: L06

A
Metallic element
B
Ionic compound
C
Covalent network solid
D
Covalent molecular compound

3. Graphite is a covalent network solid, yet it is used as a lubricant and as electrode material. Which properties make this possible? L06

A
High MP and extreme hardness
B
Non-conductivity and softness due to ionic bonds between layers
C
Delocalised electrons within carbon layers (→ conducts) and weak forces between layers (→ soft, layers slide)
D
Metallic bonding that forms between carbon atoms at high temperatures

4. Why are ionic solids described as "hard but brittle"? L06/L07

A
The rigid lattice resists deformation (hard), but a shear force shifts ion layers so like charges align, causing strong repulsion that shatters the crystal (brittle)
B
They are hard because of covalent network bonds but brittle because of ionic repulsion within layers
C
They are hard when wet but brittle when dry due to loss of hydration
D
The brittle nature comes from weak ionic bonds; hardness comes from the mass of the lattice
L07 — Ionic Compounds

5. Magnesium oxide (MgO) has a much higher melting point than sodium chloride (NaCl). The best explanation is: L07

A
Mg and O are heavier atoms, increasing lattice mass
B
MgO is a covalent network solid while NaCl is ionic
C
Mg²⁺ and O²⁻ carry charges of ±2, producing much stronger electrostatic attraction and higher lattice energy than the ±1 charges in NaCl
D
MgO has more ions per formula unit, requiring more energy to melt

6. A student dissolves potassium iodide (KI) in water and measures excellent electrical conductivity. Which correctly explains this? L07

A
KI forms covalent bonds when dissolved, and covalent bonds conduct electricity in water
B
Water molecules separate K⁺ and I⁻ ions from the lattice; the mobile hydrated ions carry charge through the solution
C
Water donates electrons to KI, creating free electrons that carry charge
D
KI releases free electrons when it dissolves, like a metal would

7. Which pair of ionic compounds would have the most similar melting points? L07

A
NaCl and MgO
B
LiF and CsI
C
NaCl and MgCl₂
D
NaCl and KBr (both ±1 charges, similar ion sizes)
L08 — Metallic Bonding

8. In the electron sea model of metallic bonding, what are the charge carriers that conduct electricity? L08

A
Mobile cations moving through the lattice
B
Delocalised electrons moving through the lattice
C
Both cations and electrons moving simultaneously
D
Anions released when the metal is connected to a circuit

9. Tungsten (W, Group 6, transition metal) has a much higher melting point than potassium (K, Group 1). Using the electron sea model, the best explanation is: L08

A
Tungsten forms ionic bonds while potassium forms covalent bonds
B
Potassium is larger than tungsten, so its lattice is less dense
C
Tungsten contributes many more valence electrons per atom to the electron sea and its cation carries a much higher charge, producing far stronger metallic bonding
D
Tungsten has covalent network bonding while potassium has only weak metallic bonds

10. Which correctly explains why adding tin to copper (to make bronze) increases hardness? L08

A
Tin atoms are a different size to copper atoms, disrupting the regular lattice and impeding the sliding of layers, requiring greater force to deform
B
Tin atoms form ionic bonds with copper atoms, locking the lattice more rigidly
C
Tin reduces the number of electrons in the electron sea, making the lattice less mobile
D
Bronze is a compound of Cu and Sn with covalent network bonding
L09 — Covalent Molecular and Network

11. When liquid iodine (I₂) vaporises, what type of interaction is broken? L09

A
Covalent I–I bonds within I₂ molecules
B
Ionic bonds between I⁺ and I⁻
C
Dispersion forces between I₂ molecules (the covalent I–I bond remains intact)
D
Both covalent bonds and dispersion forces

12. CO₂ is a gas at room temperature (BP −78°C), while SiO₂ is a solid with MP 1713°C. The best explanation for this dramatic difference is: L09

A
C=O bonds are weaker than Si–O bonds, so CO₂ requires less energy to melt
B
CO₂ is ionic while SiO₂ is covalent, giving SiO₂ a much higher lattice energy
C
CO₂ molecules are smaller than SiO₂ molecules, so weaker dispersion forces hold them together
D
CO₂ forms discrete molecular units (molecular compound) with only weak IMFs between them; SiO₂ is a covalent network solid requiring covalent bonds to be broken throughout the entire lattice to melt

13. Which substance is correctly classified as a covalent network solid? L09

A
Silicon carbide (SiC), MP 2730°C, extremely hard, non-conducting
B
Sulfur dioxide (SO₂), BP −10°C, non-polar, gaseous at room temperature
C
Glucose (C₆H₁₂O₆), MP 146°C, dissolves in water, no conductivity
D
Mercury (Hg), liquid at room temperature, excellent conductor
L10 — Intermolecular Forces

14. Which of the following molecules has ONLY dispersion forces as its IMF? L10

A
HF
B
CCl₄ (non-polar, symmetric)
C
HCl
D
NH₃

15. Which correctly ranks these substances from lowest to highest boiling point? L10

A
H₂O < HCl < CH₄
B
HCl < H₂O < CH₄
C
CH₄ < HCl < H₂O
D
H₂O < CH₄ < HCl

16. The boiling points of the hydrogen halides are: HF 19°C, HCl −85°C, HBr −67°C, HI −35°C. Which statement correctly explains why HF has a higher BP than HCl, while HI has a higher BP than HBr? L10 HOT

A
Both trends are explained by increasing dispersion forces down the group
B
Both trends are explained by hydrogen bonding — all hydrogen halides form H-bonds
C
HF is anomalously low; HI is the highest due to most electrons
D
HF is anomalously high due to hydrogen bonding (F is electronegative enough); HCl→HBr→HI follows the expected dispersion force trend (more electrons → higher BP)

17. A student claims that ethanol (C₂H₅OH, MW 46, BP 78°C) has a higher boiling point than propane (C₃H₈, MW 44, BP −42°C) because "ethanol is a larger molecule with more electrons." Evaluate this claim. L10 HOT

A
The conclusion is correct but the reasoning is incomplete — ethanol's much higher BP is primarily due to hydrogen bonding (O–H) rather than slightly larger molecular size; the size difference is minimal
B
The claim is entirely correct — molecular size and electron count are the only factors determining BP
C
The claim is incorrect — propane should have a higher BP because it has more carbon atoms
D
The claim is incorrect — both molecules are non-polar, so they should have the same BP
Cross-topic HOT Questions

18. A substance has a sharp MP of 1085°C, excellent electrical conductivity in solid and liquid states, and is malleable. When melted, the conductivity remains excellent. What is the charge carrier in the molten state? L06/L08

A
Mobile ions that are freed when the solid melts
B
Electrons that move between atoms via covalent bonds
C
Delocalised electrons — the metallic electron sea is maintained in the liquid state
D
Protons released from the metal when it melts

19. Two substances both have the formula XY₂: one is a gas at room temperature (BP −78°C), the other is a hard solid that melts at 1713°C. The most likely explanation is: L09 HOT

A
One is polar and one is non-polar, giving different IMF strengths
B
One (CO₂) forms discrete molecular units while the other (SiO₂) forms a continuous covalent network — the structural type, not just the bonds, determines the properties
C
One is ionic and one is covalent, accounting for the different properties
D
The gas has metallic bonding while the solid has ionic bonding

20. A student is given an unknown substance and tests: sharp MP 660°C, excellent conductivity as solid and liquid, malleable, not soluble in water. A second unknown has: BP 100°C, no conductivity in any state, dissolves in water, forms hydrogen bonds. Which pair of structural types correctly identifies both substances? L06–L10 HOT

A
First: ionic compound; Second: covalent network solid
B
First: covalent network solid; Second: ionic compound
C
First: ionic compound; Second: covalent molecular compound
D
First: metallic element (aluminium, Al); Second: covalent molecular compound (water, H₂O)
Short Answer — Self-Assessed
📝

Short Answer Questions

Attempt all three before checking model answers.

21. A data table lists the following properties of three substances: X (MP 2852°C, no solid conductivity, no liquid conductivity, extremely hard, insoluble); Y (MP 650°C, excellent solid conductivity, malleable, insoluble in water); Z (MP −117°C, no conductivity in any state, soft, slightly soluble in water). Identify the structural type of each substance, classify each as a named structural category, and justify your classification for each with reference to at least two properties. 6 MARKS

✏️ Answer in your book

22. Explain why the boiling point of ammonia (NH₃, BP −33°C) is much higher than the boiling point of phosphine (PH₃, BP −88°C), even though phosphine is a larger, heavier molecule. In your answer, identify all IMFs present in each substance and explain which type is responsible for the difference. 4 MARKS

✏️ Answer in your book

23. Compare the electrical conductivity of solid copper (Cu), solid sodium chloride (NaCl), and molten sodium chloride. For each, state whether it conducts, identify the charge carrier (if any), and explain why. 5 MARKS

✏️ Answer in your book

24. (L06/L07 — 3 marks) Magnesium oxide (MgO) has a melting point of 2852°C, while magnesium chloride (MgCl₂) melts at 714°C. Both are ionic compounds. Explain this difference in melting point using Coulomb's law and ionic charge. 3 MARKS

✏️ Answer in your book

25. (L07 — 3 marks) Sodium chloride (NaCl) does not conduct electricity as a solid but does conduct when melted or dissolved in water. Explain this behaviour at the particle level for each state. 3 MARKS

✏️ Answer in your book

26. (L08 — 3 marks) Explain why metals are: (a) good electrical conductors, (b) malleable (can be shaped by hammering), and (c) have relatively high melting points. Refer to the metallic bonding model (electron sea) in each answer. 3 MARKS

✏️ Answer in your book

27. (L08/L09 — 3 marks) Graphite conducts electricity while diamond does not, even though both are made entirely of carbon atoms. Explain this difference using electron configuration and bonding. 3 MARKS

✏️ Answer in your book

28. (L09 — 4 marks) Compare the structure and properties of silicon dioxide (SiO₂) and carbon dioxide (CO₂). Both contain a Group 14 element bonded to oxygen, yet their properties are dramatically different. In your answer, address: bonding type, structure, melting point, and electrical conductivity. 4 MARKS

✏️ Answer in your book

29. (L10 — 4 marks) The boiling points of the noble gases are: He (−269°C), Ne (−246°C), Ar (−186°C), Kr (−153°C), Xe (−108°C). (a) Describe and explain the trend. (b) Noble gases are monatomic and non-polar — what type of IMF exists between them? (c) Explain why Xe has a higher boiling point than He despite both being monatomic and non-polar. 4 MARKS

✏️ Answer in your book

30. (L10/Synthesis — 4 marks) Hydrogen fluoride (HF, BP 19.5°C), water (H₂O, BP 100°C), and ammonia (NH₃, BP −33°C) all form hydrogen bonds. Explain why their boiling points differ despite all three forming H-bonds. In your answer, compare the number of H-bonds each molecule can form and relate this to boiling point. 4 MARKS

✏️ Answer in your book

✅ All Answers

❓ Multiple Choice — All 20

1. D — Very high MP + no molten conductivity + extremely hard = covalent network. A = metal. B = ionic. C = covalent molecular.

2. B — 801°C + no solid conduct + conducts molten + hard/brittle = ionic compound (NaCl).

3. C — Graphite's unique layered structure: delocalised electrons within layers (conducts); weak interlayer van der Waals (soft/lubricant).

4. A — Hard: rigid lattice. Brittle: layer shift → like-charge alignment → repulsion → fracture. Metals avoid this with non-directional bonding and electron sea.

5. C — Higher ionic charge (±2 vs ±1) → stronger electrostatic attraction → higher lattice energy → higher MP. The charge effect dominates.

6. B — Water hydrates and separates K⁺ and I⁻; mobile hydrated ions carry charge. No free electrons involved.

7. D — NaCl and KBr: both ±1 charges, similar ion sizes → similar lattice energies → similar MPs (~800–730°C). All other pairs have large charge or size differences.

8. B — Delocalised electrons are always the charge carriers in metallic conductors. Cations don't move significantly in normal conductivity.

9. C — W contributes ~6 valence electrons per atom (Group 6); K contributes only 1. Higher cation charge + denser electron sea = much stronger metallic bonding = much higher MP.

10. A — Different-sized Sn atoms disrupt regular Cu lattice → impede layer sliding → harder. Not ionic bonds, not electron reduction, not covalent network.

11. C — Boiling iodine breaks dispersion forces between I₂ molecules. The covalent I–I bond within each molecule stays intact. Gas-phase iodine is still I₂.

12. D — Structural type is the key: CO₂ = discrete molecules (weak IMFs between them); SiO₂ = continuous covalent network (must break covalent bonds to melt). Not about bond strength or polarity per se.

13. A — SiC: MP 2730°C + extremely hard + non-conducting = covalent network solid. B = covalent molecular (gas). C = covalent molecular (sugar). D = metal.

14. B — CCl₄ is non-polar (symmetric tetrahedral) → only dispersion. HF: H-bonding. HCl: dipole-dipole + dispersion. NH₃: H-bonding.

15. C — CH₄: dispersion only, very small → lowest (−161°C). HCl: dispersion + dipole-dipole → moderate (−85°C). H₂O: H-bonding → highest (100°C).

16. D — HF is anomalously HIGH (H-bonding). HCl→HBr→HI follows normal dispersion trend (increasing electrons → increasing BP: −85, −67, −35°C).

17. A — Ethanol is higher, but the reason is H-bonding (O–H), not molecular size. The MW difference is tiny (46 vs 44) — dispersion forces are almost identical. The ~120°C BP difference is almost entirely due to H-bonding in ethanol.

18. C — MP 1085°C + conducts solid + malleable = metal (copper, Cu). In molten metal, the electron sea is maintained → delocalised electrons remain the charge carriers (not ions, unlike molten ionic compounds).

19. B — CO₂ (molecular, XY₂ gas) vs SiO₂ (network, XY₂ solid) — the classic same-formula, different-structural-type pair.

20. D — First: MP 660°C (Al's exact MP) + excellent conductivity + malleable → metallic (aluminium). Second: BP 100°C + no conductivity + dissolves in water + H-bonding → covalent molecular (water). No other combination fits all data points.

📝 New Short Answer Model Answers (Q24–30)

Q24 (3 marks): MgO contains Mg²⁺ and O²⁻ (both charge magnitude 2). MgCl₂ contains Mg²⁺ and Cl⁻ (charges 2 and 1). By Coulomb's law, electrostatic force ∝ q₁×q₂/r². For MgO: charge product = 2×2 = 4. For MgCl₂: charge product = 2×1 = 2. MgO has twice the charge product → electrostatic attraction between ions is roughly twice as strong per ion pair → lattice energy is much higher → far more thermal energy needed to overcome the lattice and melt → much higher MP (2852°C vs 714°C). Additionally, O²⁻ has a smaller ionic radius than Cl⁻ (O²⁻ ≈ 140 pm; Cl⁻ ≈ 181 pm) → smaller r → even stronger force (force ∝ 1/r²) → further elevating MgO's lattice energy above MgCl₂.

Q25 (3 marks): Solid: Na⁺ and Cl⁻ ions are held in fixed positions in the face-centred cubic lattice by strong electrostatic forces. Ions cannot move — they can only vibrate about their lattice positions. No mobile charge carriers → no current → insulator. Molten: heating supplies enough thermal energy to overcome the lattice energy. Ions break free from their fixed positions and move freely as a liquid. Under an applied electric field, Na⁺ migrates toward the negative electrode and Cl⁻ toward the positive electrode → charge flows → conducts. Dissolved in water: the δ− oxygen of water molecules is attracted to Na⁺ (ion-dipole); the δ+ hydrogen is attracted to Cl⁻. These ion-dipole forces overcome lattice energy — ions are hydrated and dispersed throughout the solution. Hydrated Na⁺(aq) and Cl⁻(aq) ions are free to migrate under an applied field → conducts.

Q26 (3 marks): (a) Conductivity: valence electrons leave their parent atoms and become delocalised throughout the metallic lattice — the "electron sea." These electrons are not fixed to any atom and move freely. Under a potential difference, electrons flow from negative to positive terminal — electrical current. No new bonds need to be broken; the electron sea simply flows. (b) Malleability: metal cations sit in the electron sea. When a mechanical force causes one layer of cations to slide relative to another, the electron sea instantly surrounds the cations in their new positions and continues to hold them together electrostatically. No bonds are permanently broken or formed — the structure is maintained in any shape. Compare to ionic crystals where slip aligns same-charge ions → repulsion → fracture. (c) High melting points: all metal cations are simultaneously attracted to the entire surrounding electron sea (non-directional, 3D electrostatic bonding). Melting requires enough thermal energy so that all cation-electron sea interactions are overcome simultaneously across the lattice — significant energy, giving moderate-to-high melting points. More delocalised electrons (e.g. transition metals with d-electrons) → stronger binding → higher melting points.

Q27 (3 marks): Carbon has 4 valence electrons. Diamond: each C uses all 4 in localised sp³ C–C sigma bonds (tetrahedral). Every electron is paired in a covalent bond — no free or delocalised electrons exist anywhere in the crystal. No mobile charge carriers → electrical insulator. Graphite: each C uses 3 valence electrons in sp² C–C sigma bonds within hexagonal layers. The remaining 1 electron per C is not bonded — it occupies a p orbital perpendicular to the layer and overlaps with p orbitals on all neighbouring C atoms → completely delocalised π-electron system across the entire layer. These π-electrons are mobile (analogous to conduction electrons in a metal) and can carry charge parallel to the layers under an applied field → graphite conducts electricity along its layers.

Q28 (4 marks): CO₂ structure: C (Period 2, small atom) can form stable C=O double bonds. Each CO₂ molecule is discrete: O=C=O, linear, non-polar. Between molecules: only weak London dispersion forces. MP = −78°C (sublimes) — only very small energy to overcome weak dispersion forces. Non-conducting in all states: all electrons localised in C=O bonds; no ions; no free electrons. SiO₂ structure: Si (Period 3, larger atom with available d-orbitals) cannot form stable Si=O double bonds (pπ-pπ overlap is inefficient for larger atoms). Instead, Si forms 4 Si–O single bonds (sp³); each O bridges two Si atoms — infinite 3D covalent network. MP ≈ 1710°C — must break strong Si–O covalent bonds (≈460 kJ/mol) throughout the entire network. Non-conducting: all electrons in Si–O bonds; no free electrons or ions. Key difference: molecular vs network structure arises from the inability of Si to form double bonds, forcing it into an extended covalent network.

Q29 (4 marks): (a) BP increases from He to Xe as atomic number increases. Each successive noble gas has more electrons in a larger, more diffuse electron cloud — the electron cloud is more easily distorted (more polarisable). (b) London (instantaneous) dispersion forces — the only IMF possible for non-polar, monatomic species. An instantaneous fluctuation in electron distribution creates a temporary dipole, which induces a dipole in neighbouring atoms. (c) Xe (Z=54, 54 electrons, electron cloud extending to n=5 shell) vs He (Z=2, 2 electrons, only n=1 shell). Xe's much larger, more polarisable electron cloud creates larger instantaneous dipoles → stronger induced dipoles in neighbours → stronger dispersion forces → more energy needed to overcome them in the liquid → higher BP. He's tiny, barely-polarisable electron cloud creates only extremely weak, fleeting dipoles → almost no IMF → BP just above absolute zero.

Q30 (4 marks): All three molecules contain H bonded to a highly electronegative atom (F, O, N) — H-bond donor. All three have lone pairs — H-bond acceptors. The BP differences arise primarily from the number and strength of H-bonds each molecule can form. H₂O (BP 100°C): O has 2 lone pairs (accept 2 H-bonds) + 2 O–H bonds (donate 2 H-bonds) → up to 4 H-bonds per molecule. Forms an extensive, highly directional 3D H-bond network → strongest and most numerous H-bonds → highest BP. NH₃ (BP −33°C): N has 1 lone pair (accept 1 H-bond) + 3 N–H bonds (donate 3) — can form up to 4 H-bonds geometrically, but lone pair limitation means each molecule can only accept 1. Also N is less electronegative than O (χ: N=3.0 vs O=3.4) → weaker H-bonds (less δ+ on H). Network is less complete than water → intermediate BP. HF (BP 19.5°C): F has 3 lone pairs (accept up to 3 H-bonds) but only 1 H–F (donate 1) → maximum 2 H-bonds per molecule. Despite F being the most electronegative element (strongest H-bonds individually), the HF chain can only form linear H-bond chains (not a 3D network) due to the limited number of donors → fewer H-bonds per molecule than H₂O → lower BP than water but much higher than HCl (which has no H-bonding).

📝 Short Answer Model Answers

Q21 (6 marks): X is a covalent network solid (1 mark). MP 2852°C is extremely high — only covalent network solids with continuous strong covalent bonds throughout can require this much energy to melt (1 mark). No conductivity in solid or molten state confirms absence of free electrons or mobile ions (excludes metals and ionic compounds). Extremely hard and insoluble further confirms — this substance is MgO... wait, actually MgO is ionic (conducts when molten). Re-check: no liquid conductivity + MP 2852°C + extremely hard + insoluble = covalent network solid. Could be SiC or similar. Correct answer: X = covalent network solid — justified by very high MP AND no conductivity in both states (2 criteria required). Y is a metallic element (1 mark). MP 650°C is consistent with a metal (Mg); excellent solid conductivity indicates delocalised electrons; malleability is exclusive to metals with non-directional bonding. Identified as magnesium (Mg) (1 mark). Z is a covalent molecular compound (1 mark). MP −117°C is very low — only weak IMFs between discrete molecules can be overcome at this temperature; no conductivity and softness confirm molecular structure; slight water solubility suggests polarity. Justified by low MP AND soft/no conductivity (1 mark).

Q22 (4 marks): NH₃ IMFs: dispersion forces AND hydrogen bonding (N–H bonds present; N is electronegative enough to form N–H···N hydrogen bonds with adjacent molecules) (1 mark). PH₃ IMFs: dispersion forces and weak dipole-dipole forces only (P–H bonds present but P is not electronegative enough to form hydrogen bonds; χ(P) ≈ 2.2 vs χ(N) = 3.0) (1 mark). NH₃ has a higher BP because hydrogen bonding between NH₃ molecules is far stronger than the dipole-dipole forces in PH₃ — despite PH₃ being larger and heavier (and therefore having stronger dispersion forces), the hydrogen bonding energy in NH₃ dominates (1 mark). To boil NH₃, the strong N–H···N hydrogen bonds must be overcome — this requires more energy than overcoming the weaker dispersion + dipole-dipole forces in PH₃ → BP of −33°C for NH₃ vs −88°C for PH₃, a difference of 55°C (1 mark).

Q23 (5 marks): Solid copper (Cu): conducts electricity (1 mark). Charge carrier: delocalised electrons (1 mark). Reason: Cu metal has a sea of delocalised valence electrons that are always mobile — they can flow under a voltage without any structural disruption. Solid NaCl: does not conduct electricity. Charge carrier: none mobile in solid state. Reason: Na⁺ and Cl⁻ ions are fixed in the rigid ionic lattice at defined positions — they cannot move to carry charge (1 mark). Molten NaCl: conducts electricity excellently. Charge carrier: mobile Na⁺ and Cl⁻ ions (1 mark). Reason: at 801°C the ionic lattice breaks down — Na⁺ and Cl⁻ ions become free to move independently in the liquid. Under a voltage, Na⁺ migrates to the negative electrode and Cl⁻ to the positive electrode — this ion movement constitutes a current (1 mark).

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