L16-L17
- Write electron configurations using Aufbau, Pauli and Hund.
- Explain atomic radius using shell number, shielding and effective nuclear charge.
- Compare neutral atoms with cations and anions by radius.
This checkpoint closes Module 1 with electron configuration, periodic trends and full-module synthesis. Attempt the multiple choice first, then self-assess the short answers against the model responses.
Multiple Choice
1. Which is the correct electron configuration for sulfur, Z = 16?
2. Which arrangement violates Hund's rule?
3. Why does atomic radius generally decrease across a period?
4. Which species is larger?
5. Why is caesium more reactive than lithium as a metal?
6. The bond between potassium and fluorine is best classified as:
7. Lithium and sodium show similar chemistry mainly because they:
8. An unknown solid has an extremely high melting point, does not conduct in any state, is insoluble and very hard. It is most likely:
9. HF has a much higher boiling point than HCl mainly because:
10. Graphene is exceptionally strong and electrically conductive because it has:
Short Answer
11. Explain why chlorine is smaller than phosphorus even though both are in Period 3. 3 marks
12. Copper can form both Cu⁺ and Cu²⁺, while sodium usually forms only Na⁺. Explain why. 4 marks
13. A chemist concludes that an unknown substance is a covalent network solid rather than an ionic, metallic or molecular substance. Write a short justification using at least three properties. 4 marks
1. C. 2. D. 3. B. 4. C. 5. D. 6. B. 7. A. 8. C. 9. A. 10. D.
Chlorine is smaller than phosphorus because both atoms have their valence electrons in the same main shell, so shielding is similar. Chlorine has more protons, giving it a higher effective nuclear charge. The stronger nuclear attraction pulls the outer electrons closer to the nucleus, reducing atomic radius.
Sodium has the configuration [Ne]3s¹, so losing one electron gives the very stable [Ne] arrangement. Removing a second electron would mean taking one from a full inner shell, which requires far more energy. Copper has accessible 4s and 3d electrons of similar energy, so it can lose the 4s electron to form Cu⁺ and, in many contexts, one additional 3d electron to form Cu²⁺. Transition metals therefore show more variable oxidation states than Group 1 metals.
A covalent network solid is justified by the combination of extremely high melting point, extreme hardness and insolubility. Those properties indicate a giant three-dimensional lattice of strong covalent bonds rather than discrete molecules. The lack of electrical conductivity rules out a metallic solid, and non-conductivity even when heated helps distinguish it from a typical ionic substance. The structure therefore best matches a covalent network solid such as diamond or silicon carbide.
Tick this once you have attempted the multiple choice and checked the model answers.