Metal Activity Series & Reactions of Metals
Steel ships, pipelines and offshore structures are protected from rusting by bolting on blocks of a more reactive metal, such as zinc or magnesium. These "sacrificial anodes" corrode in place of the steel because they sit higher in the activity series, so they lose electrons more readily. The activity series predicts which metal corrodes first, and engineers use it deliberately to choose which metal to sacrifice.
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Four printable worksheets that build from the foundations up to exam-style questions, start at whatever level suits you.
Galvanised steel (zinc-coated steel) contains both steel (iron alloy) and zinc. When both metals are exposed to oxygen and moisture, the zinc corrodes preferentially, greatly reducing corrosion of the iron while the zinc is gradually consumed (the protection lasts while zinc and electrical contact remain).
Key facts
- The standard HSC activity series from K (most reactive) to Au (least reactive)
- Metals above hydrogen in the series react with dilute acids; metals below do not
- Displacement reactions are also redox reactions: the more reactive metal is oxidised
Concepts
- Reactivity reflects ease of electron loss (ionisation energy); more reactive metals have lower ionisation energy and are found as ores rather than native
- The activity series was derived from experimental observations of water, acid, and displacement reactions
- Aluminium appears anomalously unreactive due to a protective Al₂O₃ passivation layer, its true reactivity is higher than its behaviour suggests
Skills
- Use the activity series to predict whether a displacement reaction will occur and write the balanced equation
- Explain why metals above H dissolve in dilute acid while metals below H do not
- Identify the oxidised and reduced species in a displacement reaction
Drop sodium into water: violent fizzing, hydrogen gas, the metal dissolves in seconds. Drop copper into the same water: nothing. Leave iron in water overnight: slight orange staining, then nothing dramatic. All three are metals, all three react differently with the same substance. The difference is measurable, predictable, and can be listed in order: the metal activity series.
Three atomic properties determine how easily electrons are lost:
Down Group 1 of the periodic table, atomic radius increases, ionisation energy decreases, and electronegativity decreases, reactivity increases. This is why caesium is more reactive than lithium, and why potassium reacts more violently with water than sodium. These periodic trends explain reactivity within a group, but the full activity series (which compares metals from different groups) is established from experimental reactions and E° data, not from atomic trends alone.
Metal reactivity reflects how readily a metal loses electrons (M → Mⁿ⁺ + ne⁻). Periodic trends (larger atomic radius and lower ionisation energy down a group) partly explain this, but the activity series is ranked from observed reactions and standard electrode potentials (E°), not derived from atomic trends alone, because aqueous reactivity also depends on atomisation, hydration and conditions.
Pause, copy the highlighted definition into your book before moving on.
Odd one out: Which of these properties increases as metal reactivity increases?
We just saw that metal reactivity varies due to several factors, including ionisation energy and atomic radius. That raises a question: how do chemists experimentally measure and rank this reactivity to build the activity series? This card answers it → by comparing reactions with oxygen, cold water, and dilute acids, then combining displacement observations to rank metals in order.
The activity series is constructed experimentally by comparing how vigorously different metals react with the same reagents under the same conditions. Three standard investigations are used:
| Metal | Reaction with O₂ | Reaction with Cold Water | Reaction with Dilute HCl |
|---|---|---|---|
| Potassium (K) | Burns vigorously | Explosive | Explosive (not used) |
| Sodium (Na) | Burns vigorously | Very vigorous | Explosive (not used) |
| Calcium (Ca) | Burns | Vigorous, bubbles | Vigorous |
| Magnesium (Mg) | Burns brightly | Very slow (reacts with steam) | Vigorous |
| Aluminium (Al) | Burns | Slow or none at first (passivation; oxide can be removed) | Moderate (slowed by oxide layer) |
| Zinc (Zn) | Burns | No reaction | Moderate |
| Iron (Fe) | Burns slowly (as powder) | No reaction | Slow |
| Lead (Pb) | Tarnishes | No reaction | Very slow |
| Copper (Cu) | Surface oxide only | No reaction | No reaction |
| Silver (Ag) | No reaction | No reaction | No reaction |
| Gold (Au) | No reaction | No reaction | No reaction |
The activity series is built from three experimental tests: vigour of reaction with O₂, cold water, and dilute acid. Aluminium appears less reactive than expected due to passivation (protective Al₂O₃ layer). Hydrogen sits between Pb and Cu as a reference point for acid reactions.
Add the highlighted point to your notes before the check below.
Fill the gap: Aluminium appears less reactive than expected because it rapidly forms a protective [___] layer on its surface that prevents further reaction with water or dilute acids.
We just saw how experimental observations with water, oxygen, and acids are used to rank metal reactivity. That raises a question: what is the specific NESA-approved order that you need to memorise for HSC exams? This card answers it → K, Na, Ca, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au, with hydrogen as the reference point between Pb and Cu.
The standard activity series used in HSC Chemistry (confirm against the current NESA data sheet), from most reactive to least reactive:
Mnemonic: Please Stop Calling Me A Zombie, I Like Having Copper Silverware Guaranteed. (K, Na, Ca, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au)
Standard HSC activity series (most → least reactive; check the current NESA data sheet): K, Na, Ca, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au. Mnemonic: "Please Stop Calling Me A Zombie, I Like Having Copper Silverware Guaranteed." Metals above H react with dilute acids to produce H₂; metals below H (Cu, Ag, Au) do not.
Pause, write the highlighted series and mnemonic into your book.
Quick check: According to the NESA activity series, which metal would NOT react when added to dilute hydrochloric acid?
We just saw the NESA activity series in order. That raises a question: how do we use the series to predict which displacement reactions will occur, and write the correct balanced equations? This card answers it → if the metal added is ABOVE the ion in solution, displacement occurs; if BELOW, no reaction.
A more reactive metal will always displace a less reactive metal from its salt solution, the more reactive metal has a greater tendency to form ions, so it “takes” the electron-release role away from the less reactive metal’s ions.
Prediction rule: Is the metal being added higher (more reactive) than the metal ion in solution? If yes → reaction occurs. If no → no reaction.
| Metal Added | Solution | Reaction? | Reason |
|---|---|---|---|
| Zn(s) | CuSO₄(aq) | Yes ✓ | Zn more reactive than Cu |
| Fe(s) | CuSO₄(aq) | Yes ✓ | Fe more reactive than Cu |
| Cu(s) | ZnSO₄(aq) | No ✗ | Cu less reactive than Zn |
| Mg(s) | FeSO₄(aq) | Yes ✓ | Mg more reactive than Fe |
| Ag(s) | HCl(aq) | No ✗ | Ag below H in series |
| Zn(s) | HCl(aq) | Yes ✓ | Zn above H in series |
For Zn(s) + CuSO₄(aq): The blue colour of CuSO₄ solution fades (Cu²⁺ ions removed); reddish-brown solid copper deposits on the zinc surface; the zinc gradually dissolves.
Equation: Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s). Atom check: 1Zn, 1Cu, 1S, 4O each side. ✓
Displacement rule: if the added metal is ABOVE the ion in solution in the activity series, displacement occurs. E.g. Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s) ✓; Cu(s) + ZnSO₄(aq) → no reaction ✗. The sulfate anion is a spectator.
Add the highlighted rule to your notes before the check below.
Odd one out: Which of these combinations would result in a displacement reaction occurring?
We just saw that more reactive metals preferentially displace less reactive metals. That raises a question: how does this principle apply to real corrosion protection, such as galvanised steel and sacrificial anodes? This card answers it → zinc (higher in the activity series than iron) preferentially corrodes, sacrificially protecting the steel underneath.
Steel (iron alloy) and zinc are both susceptible to oxidation in the presence of oxygen and moisture. When they are in electrical contact, as they are when zinc bolts fasten steel panels, zinc preferentially loses electrons because it is higher in the activity series than iron. The zinc corrodes while the iron is protected. This is called sacrificial protection or cathodic protection.
The same principle is used in galvanised steel (zinc-coated steel), where the zinc coating sacrificially corrodes even if scratched, continuing to protect the underlying iron.
If copper bolts were used instead, the situation reverses, copper is below iron in the activity series, so iron would corrode preferentially. This is a galvanic corrosion problem.
Sacrificial protection: because Zn is more reactive than Fe, zinc preferentially oxidises (Zn → Zn²⁺ + 2e⁻), protecting steel from corrosion even when scratched. If copper bolts were used, iron would corrode instead (Fe is more reactive than Cu).
Pause, write the highlighted point into your book.
Fill the gap: Zinc protects iron in galvanised steel because zinc is [___] in the activity series than iron, so it preferentially loses electrons and corrodes first.
Worked examples · reveal as you go
Predict whether a reaction will occur in each case. Where a reaction occurs, write the balanced equation with state symbols and describe one observable change. (a) Iron nail placed in copper(II) sulfate solution. (b) Copper wire placed in silver nitrate solution. (c) Silver wire placed in copper(II) nitrate solution.
Explain why potassium reacts more vigorously with cold water than magnesium does, using the concepts of atomic radius, ionisation energy, and electronegativity.
Key Patterns, This Lesson
Common errors · the 3 traps that cost marks
Common misconception
A metal will displace any other metal from a compound if it is higher in the activity series.
Fix: Ordinary metal-ion displacement occurs only if the metal is higher in the activity series AND the reaction occurs in aqueous solution, where ions are free to move. (High-temperature reactions between solids, such as the thermite reaction Al + Fe₂O₃, are a separate case driven by strong heating, not this aqueous rule.)
Aluminium is less reactive than iron because it doesn't react with cold water
Students observe that aluminium doesn't react with dilute acid or cold water and rank it below iron or copper in the activity series.
Fix: Aluminium is more reactive than iron, it sits between Mg and Zn in the NESA activity series. However, Al rapidly forms a dense Al₂O₃ passivation layer that prevents further reaction. This protective oxide layer masks aluminium's true reactivity; if the oxide is removed (for example by acid over time, or by amalgamation), the aluminium underneath does react. In HSC answers about Al reactivity, mention the passivation layer as the reason for its apparent low reactivity.
A more reactive metal always displaces a less reactive one, even from solid compounds
Students apply the displacement rule to solid compounds, predicting for example that sodium metal dropped into solid CuSO₄ would displace copper.
Fix: Ordinary metal-ion displacement needs aqueous conditions so that ions are mobile and can migrate to the metal surface to be reduced. Sodium dropped onto solid CuSO₄ would react with any moisture present rather than performing a clean displacement. The activity series predicts displacement from aqueous solutions; high-temperature solid-state reactions such as thermite follow a different pathway.
Quick-fire practice · 5 reps +2 XP per reveal
Q1 (4 marks): Explain, using the concepts of atomic radius, ionisation energy, and electronegativity, why sodium reacts more vigorously with water than lithium, even though both are in Group 1.
Q2 (4 marks): A student places a piece of iron metal into a solution of copper(II) sulfate. (a) Predict whether a reaction will occur, with reference to the activity series. (b) Write the balanced equation with state symbols. (c) Describe two observable changes the student would see. (1 + 2 + 1 marks)
Q3 (5 marks): A coastal steel structure is protected with sacrificial zinc anodes bolted to the steel. (a) Explain, using the activity series, why the zinc corrodes preferentially while the iron is protected. (b) Calculate the mass loss if 0.050 mol of Zn corrodes (Zn = 65.4 g/mol). (c) A maintenance engineer proposes replacing the zinc anodes with stainless steel (iron-based) to reduce replacement frequency. Evaluate this proposal with reference to the activity series and the consequences for the structure. (2 + 1 + 2 marks)
Arrange the following metals in order of increasing reactivity: Ag, Fe, Na, Cu, Zn. For the Zn/Cu pair, write the balanced equation for the displacement reaction and identify which metal is oxidised.
A student places a copper strip in silver nitrate solution. (a) Predict whether a reaction will occur using the activity series. (b) Write the balanced ionic equation. (c) Describe two observable changes that would confirm the reaction is occurring.
Sacrificial protection is used wherever steel must survive a corrosive environment: ships' hulls, underground pipelines and offshore structures carry blocks of a more reactive metal (zinc or magnesium). Because that metal is higher in the activity series, it loses electrons more readily (e.g. Zn → Zn²⁺ + 2e⁻ occurs more readily than Fe → Fe²⁺ + 2e⁻), so it corrodes as the anode while the steel is protected as the cathode. Engineers choose the sacrificial metal, and pair metals carefully, using the activity series; if two metals far apart in reactivity are joined in a wet, salty environment, the more reactive one can corrode quickly.
Now revisit your initial response. What did you get right? What has changed in your thinking?
Look back at your initial response in your book. Annotate it with what you now understand differently.
Pick your answer, then rate your confidencethat tells the system what to drill next.
Q1. (4 marks) Explain, using the concepts of atomic radius, ionisation energy, and electronegativity, why sodium reacts more vigorously with water than lithium, even though both are in Group 1. (4 marks)
Q2. (4 marks) A student places a piece of iron metal into a solution of copper(II) sulfate. (a) Predict whether a reaction will occur, with reference to the activity series. (b) Write the balanced equation with state symbols. (c) Describe two observable changes the student would see. (1 + 2 + 1 marks)
Q3. (5 marks) A coastal steel structure is protected with sacrificial zinc anodes bolted to the steel. (a) Explain, using the activity series, why the zinc corrodes preferentially while the iron is protected. (b) Calculate the mass loss if 0.050 mol of Zn corrodes (Zn = 65.4 g/mol). (c) A maintenance engineer proposes replacing the zinc anodes with stainless steel (iron-based) to reduce replacement frequency. Evaluate this proposal with reference to the activity series and the consequences for the structure. (2 + 1 + 2 marks)
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