Calculate pH, [H⁺], [OH⁻], and pOH at 25°C (Kw = 1.0 × 10⁻¹⁴)
pH = -log[H⁺]
[H⁺] = 10⁻ᵖᴴ
pOH = 14 - pH
Kw = [H⁺][OH⁻] = 10⁻¹⁴