Tools extend and limit observation — Apply worksheet
Original practice. Write explanations that distinguish observations, evidence and claims.
Name: __________________________ Date: ______________
Measure a cell using an image scale
Text description
- An elongated cell outline spans 120 image pixels horizontally. A separate scale bar spans 40 image pixels and represents 20 micrometres. Only the outer boundary is depicted; no internal structure or species is identified.
An elongated cell outline spans 120 image pixels horizontally. A separate scale bar spans 40 image pixels and represents 20 micrometres. Only the outer boundary is depicted; no internal structure or species is identified.
| Image feature | Length in image pixels | Known actual length (µm) |
|---|---|---|
| Scale bar | 40 | 20 |
| Horizontal cell span | 120 | To calculate |
Question 1
Use the synthetic cell image above: a 40-pixel bar represents 20 µm and the cell spans 120 pixels. Calculate its horizontal size, showing the scale conversion.
Question 2
Would a one-second logger confidently resolve a 0.05 s peak? Explain.
Question 3
Both the cell image and its scale bar are enlarged by a factor of two. Recalculate the cell size and explain why its blurred boundary does not become better resolved.
Teacher answer key — 3 questions
Model responses identify the essential ideas. Accept scientifically correct alternatives that address the question; wording need not match exactly.
- 20/40 = 0.5 µm per pixel; 120 × 0.5 = 60 µm. The estimate uses a shared image scale and defined horizontal endpoints, not the physical size of your screen.
- No. The peak can occur between samples or be smeared by sensor response; use a suitably faster tool and check response.
- 240/80 × 20 = 60 µm: the ratio is unchanged. Enlarging existing pixels does not add resolved detail. Boundary ambiguity can dominate measurement uncertainty, so do not claim the synthetic size is an exact empirical measurement.