Maths Extension 1 Year 11 - Module 1 - Lesson 14

Module Synthesis & Connections

Use this worksheet after reading the lesson to practise the key ideas and prove you can meet the success criteria.

Name
Date
Class

1. Lesson focus

Functions synthesis and connections. Combine inverse, composition and graph transformations while checking domains at every step.

Success criteria

  • Apply the lesson method accurately in a routine example.
  • Show each algebraic or domain step and check the result.
  • Explain why the method and restrictions fit the question.

2. Worked practice

1. Let f(x)=2x+1. Find f⁻¹(x).

2. Let f(x)=x² with x≥0 and g(x)=x−1. Find (f∘g)(x) and its domain.

3. For h(x)=|x−2|, solve h(x)=3.

3. Challenge

If f is one-to-one, explain why f⁻¹(f(4))=4 and evaluate it.

4. Multiple choice

For f(x)=2x+1, what is f⁻¹(x)?

A. (x−1)/2

B. (x+1)/2

C. 2x−1

D. 1−2x

Worked answer key

Compare each step with your working. Keep stated intervals, domains and restrictions in your final answer.

1. Let f(x)=2x+1. Find f⁻¹(x).

y=2x+1 ⇒ x=(y−1)/2, so f⁻¹(x)=(x−1)/2.

2. Let f(x)=x² with x≥0 and g(x)=x−1. Find (f∘g)(x) and its domain.

(f∘g)(x)=(x−1)²; require g(x)≥0 for f's restricted domain, so x≥1.

3. For h(x)=|x−2|, solve h(x)=3.

x−2=±3, so x=−1 or x=5.

Challenge. If f is one-to-one, explain why f⁻¹(f(4))=4 and evaluate it.

By the inverse identity f⁻¹(f(x))=x on f's domain; at x=4 the value is 4.

Multiple choice. For f(x)=2x+1, what is f⁻¹(x)?

Correct answer: A. Swap y=2x+1 and solve: x=(y−1)/2.

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