Maths Extension 1 Year 11 - Module 4 - Lesson 6
Combinations ($^nC_r$)
Name
Date
Class
1. Lesson focus
Combinations nCr. An unordered selection of r objects from n distinct objects has nCr=n!/[r!(n−r)!]; order does not matter.
Success criteria
- Apply the lesson method accurately in a routine example.
- Show each algebraic or domain step and check the result.
- Explain why the method and restrictions fit the question.
2. Worked practice
2. How many pairs can be selected from 12 students?
3. A team of 4 is chosen from 8 students. How many teams?
3. Challenge
A committee has at least 2 women chosen from 6 women and 4 men; it has 3 members. How many committees?
4. Multiple choice
How many ways can a 3-person committee be selected from 8 people?
A. 8C3=56
B. 8P3=336
C. 3!=6
D. 8×3=24
Worked answer key
Compare each step with your working. Keep stated intervals, domains and restrictions in your final answer.
1. Evaluate 10C3.
10C3=(10×9×8)/(3×2×1)=120.
2. How many pairs can be selected from 12 students?
12C2=12×11/2=66.
3. A team of 4 is chosen from 8 students. How many teams?
8C4=8×7×6×5/(4×3×2×1)=70.
Challenge. A committee has at least 2 women chosen from 6 women and 4 men; it has 3 members. How many committees?
Exactly 2 women: 6C2×4C1=15×4=60. Exactly 3 women: 6C3=20. Total 80.
Multiple choice. How many ways can a 3-person committee be selected from 8 people?
Correct answer: A. A committee is unordered, so use combinations: 8C3=8×7×6/(3×2×1)=56.
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