Maths Extension 1 Year 11 - Module 2 - Lesson 4
The Factor Theorem
1. Lesson focus
Factor theorem. (x−a) is a factor of P(x) exactly when P(a)=0; after finding one factor, divide to factor the quotient.
Success criteria
- Apply the lesson method accurately in a routine example.
- Show each algebraic or domain step and check the result.
- Explain why the method and restrictions fit the question.
2. Worked practice
2. Factor x³−3x²−4x+12 given that x=3 is a zero.
3. Factor x⁴−5x²+4 over the reals.
3. Challenge
If P(−2)=0, state a corresponding linear factor.
4. Multiple choice
If P(5)=0, which expression must divide P(x)?
A. x−5²
B. x+5
C. 5x−1
D. x−5
Worked answer key
Compare each step with your working. Keep stated intervals, domains and restrictions in your final answer.
1. Show that x−3 is a factor of x³−4x²+x+6, then factor completely.
P(3)=27−36+3+6=0. Division gives x²−x−2=(x−2)(x+1); full factorisation (x−3)(x−2)(x+1).
2. Factor x³−3x²−4x+12 given that x=3 is a zero.
Divide by x−3 to get x²−4=(x−2)(x+2); full factorisation (x−3)(x−2)(x+2).
3. Factor x⁴−5x²+4 over the reals.
Let u=x²: (u−1)(u−4)=(x−1)(x+1)(x−2)(x+2).
Challenge. If P(−2)=0, state a corresponding linear factor.
x−(−2)=x+2 is a factor.
Multiple choice. If P(5)=0, which expression must divide P(x)?
Correct answer: D. The factor theorem pairs the zero a with the factor x−a; for a=5 this is x−5.
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