Maths Extension 1 Year 11 - Module 2 - Lesson 12

Graphing Polynomials

Use this worksheet after reading the lesson to practise the key ideas and prove you can meet the success criteria.

Name
Date
Class

1. Lesson focus

Graphing polynomial functions. Use real zeros and their multiplicities for x-intercepts, the leading term for end behaviour, and P(0) for the y-intercept.

Success criteria

  • Apply the lesson method accurately in a routine example.
  • Show each algebraic or domain step and check the result.
  • Explain why the method and restrictions fit the question.

2. Worked practice

1. For P(x)=(x+2)(x−1)², give its x-intercepts and multiplicities.

2. For the same cubic, state the y-intercept and end behaviour.

3. Describe how the graph meets the axis at each zero of P(x)=(x−3)³(x+1)².

3. Challenge

For Q(x)=−2(x−1)(x+2)², state the degree and end behaviour.

4. Multiple choice

The y-intercept of (x+2)(x−1)² is what?

A. 1

B. 0

C. −2

D. 2

Worked answer key

Compare each step with your working. Keep stated intervals, domains and restrictions in your final answer.

1. For P(x)=(x+2)(x−1)², give its x-intercepts and multiplicities.

x=−2 has multiplicity 1; x=1 has multiplicity 2.

2. For the same cubic, state the y-intercept and end behaviour.

P(0)=2. Positive leading cubic: P→−∞ as x→−∞ and P→∞ as x→∞.

3. Describe how the graph meets the axis at each zero of P(x)=(x−3)³(x+1)².

It crosses with flattening at x=3 (odd multiplicity 3) and touches at x=−1 (even multiplicity 2).

Challenge. For Q(x)=−2(x−1)(x+2)², state the degree and end behaviour.

Degree 3, negative leading coefficient: Q→∞ as x→−∞ and Q→−∞ as x→∞.

Multiple choice. The y-intercept of (x+2)(x−1)² is what?

Correct answer: D. Substitute x=0: (2)(1)=2.

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