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hscscience Maths Adv · Y11
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Module 6 · L7 of 11 ~45 min ⚡ +90 XP available

Surds

A surd is a root that cannot be written exactly as a fraction. Working with them exactly, rather than rounding, is what keeps later answers precise.

Today's hook, Your calculator shows $\sqrt{2} = 1.414213562...$ and then stops. It has to, because the decimal never terminates or repeats. Surd form is how you write the exact value instead of a rounded one.
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Recall, your gut answer first

Meet the destination, bring back what you already know, and gather the terms and formulas this lesson leans on.

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Recall, your gut answer first
+5 XP warm-up

Is $\sqrt{9}$ a surd? Is $\sqrt{10}$? Decide what makes a root a surd, then estimate $\sqrt{50}$ to the nearest whole number without a calculator.

Before you work it out, what is your instinct? Write it down, then check it against the lesson.

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Simplifying a surd means extracting perfect squares

Work through the core explanation before applying it.

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Simplifying a surd means extracting perfect squares
+5 XP to read

A surd is simplified when the number under the root sign has no perfect square factor left. Finding the largest perfect square factor is the whole technique.

$\sqrt{72}$ is not simplified, because $72 = 36 \times 2$ and 36 is a perfect square. So $\sqrt{72} = \sqrt{36}\sqrt{2} = 6\sqrt{2}$. Using a smaller square such as 4 also works, it just takes more steps.

$\sqrt{ab} = \sqrt{a}\,\sqrt{b}$    $\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}$    $\left(\sqrt{a}\right)^2 = a$    $m\sqrt{a} + n\sqrt{a} = (m+n)\sqrt{a}$
Roots split over multiplication only
$\sqrt{ab} = \sqrt{a}\sqrt{b}$ is true. $\sqrt{a+b} = \sqrt{a} + \sqrt{b}$ is false; test it with 9 and 16.
Only like surds add
$3\sqrt{5} + 2\sqrt{5} = 5\sqrt{5}$, but $3\sqrt{5} + 2\sqrt{7}$ cannot be combined. Treat $\sqrt{5}$ like a variable.
Simplify before adding
$\sqrt{8} + \sqrt{18}$ looks unlike until you simplify: $2\sqrt{2} + 3\sqrt{2} = 5\sqrt{2}$.
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What you'll master

Meet the destination, bring back what you already know, and gather the terms and formulas this lesson leans on.

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What you'll master
Know

Key facts

  • A surd is a root whose exact value is irrational, such as $\sqrt{2}$ or $\sqrt[3]{5}$.
  • $\sqrt{ab} = \sqrt{a}\sqrt{b}$ and $\sqrt{a/b} = \sqrt{a}/\sqrt{b}$, but roots do not split over addition.
  • Like surds have the same number under the root sign and can be added or subtracted.
  • Brackets containing surds expand exactly as algebraic brackets do.
Understand

Concepts

  • Why $\sqrt{9}$ is not a surd while $\sqrt{10}$ is.
  • Why extracting the largest perfect square factor is the efficient route.
  • Why $\sqrt{a+b} \neq \sqrt{a} + \sqrt{b}$.
Can do

Skills

  • Simplify a surd by extracting perfect square factors.
  • Multiply, divide, add and subtract surds.
  • Expand brackets containing surds, including squaring a binomial surd.
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Key terms
SurdA root that cannot be written exactly as a fraction, so its decimal never ends or repeats. Like this: $\sqrt{2}$ is a surd, but $\sqrt{9} = 3$ is not.
Rational numberA number that can be written as one whole number over another. Like this: 3, $\frac{7}{4}$ and $0.25$ are rational; $\sqrt{2}$ is not.
Perfect squareA whole number that is another whole number squared, used to simplify surds. Like this: 36 is a perfect square because $6^2 = 36$, so $\sqrt{72} = 6\sqrt{2}$.
Simplified surd formA surd where the number under the root has no perfect square factor left. Like this: $6\sqrt{2}$ is simplified, $\sqrt{72}$ and $2\sqrt{18}$ are not.
Like surdsSurds with the same number under the root sign, which can be added or subtracted. Like this: $3\sqrt{5}$ and $2\sqrt{5}$ are like surds, so they add to $5\sqrt{5}$.
Coefficient of a surdThe number multiplying the root. Like this: in $7\sqrt{3}$ the coefficient is 7 and the surd part is $\sqrt{3}$.
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What a surd is, and how to simplify one

Work through the core explanation before applying it.

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What a surd is, and how to simplify one
core concept

A root is a surd when its value is irrational. $\sqrt{9} = 3$ is rational, so it is not a surd. $\sqrt{10} = 3.1622...$ never terminates or repeats, so it is.

To simplify, split the number under the root into a perfect square times whatever is left, using the rule $\sqrt{ab} = \sqrt{a}\sqrt{b}$. For $\sqrt{72}$, the largest perfect square factor is 36, giving $\sqrt{36}\sqrt{2} = 6\sqrt{2}$.

If you use a smaller square you still get there, just more slowly: $\sqrt{72} = \sqrt{4}\sqrt{18} = 2\sqrt{18} = 2 \times 3\sqrt{2} = 6\sqrt{2}$.

Roots do not split over addition. $\sqrt{9 + 16} = \sqrt{25} = 5$, but $\sqrt{9} + \sqrt{16} = 3 + 4 = 7$. The rule works for multiplication and division only.
Quick check: simplify $\sqrt{50}$.

A surd is an irrational root. Simplify by writing the number under the root as a perfect square times a remainder, then taking the square root of the perfect square outside. Roots split over multiplication and division, never over addition.

Pause, copy the definition of a surd, the simplifying method with $\sqrt{72} = 6\sqrt{2}$, and the counter-example proving $\sqrt{a+b} \neq \sqrt{a}+\sqrt{b}$, into your book.

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Multiplying and dividing surds
core concept

We just saw how to simplify a single surd by extracting perfect squares. That raises a question: what happens when two surds are multiplied or divided? This card answers it → multiply the coefficients and the surd parts separately, then simplify the result.

Multiply the numbers outside the roots together, and the numbers inside the roots together: $(2\sqrt{3})(5\sqrt{6}) = 10\sqrt{18}$.

Then simplify what you get: $10\sqrt{18} = 10 \times 3\sqrt{2} = 30\sqrt{2}$. Almost every product needs this final simplification step.

Division works the same way: $\dfrac{12\sqrt{20}}{3\sqrt{5}} = 4\sqrt{4} = 8$. A surd divided by a surd can come out rational.

Squaring a surd. $\left(\sqrt{a}\right)^2 = a$, so $\left(3\sqrt{5}\right)^2 = 9 \times 5 = 45$. Square the coefficient and the surd separately.
Which expression does NOT equal $6\sqrt{2}$?

Multiply coefficients together and the numbers under the roots together, then simplify. Divide the same way. $\left(\sqrt{a}\right)^2 = a$, so squaring removes the root.

Pause, copy the multiply rule with the worked $(2\sqrt{3})(5\sqrt{6}) = 30\sqrt{2}$, the divide example $\frac{12\sqrt{20}}{3\sqrt{5}} = 8$, and the squaring rule, into your book.

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Adding, subtracting and expanding brackets
core concept

We just saw that surds multiply and divide freely. That raises a question: can you add them just as freely? This card answers it → no, only like surds combine, so you must simplify everything first to see which are alike.

Only like surds add or subtract. Treat $\sqrt{5}$ as if it were a variable: $3\sqrt{5} + 2\sqrt{5} = 5\sqrt{5}$, but $3\sqrt{5} + 2\sqrt{7}$ stays as it is.

Simplify before deciding. $\sqrt{8} + \sqrt{18}$ looks unlike, but simplifies to $2\sqrt{2} + 3\sqrt{2} = 5\sqrt{2}$.

Brackets expand exactly as in algebra: $(\sqrt{5} + 2)(\sqrt{5} - 3) = 5 - 3\sqrt{5} + 2\sqrt{5} - 6 = -1 - \sqrt{5}$.

Squaring a binomial surd. $(\sqrt{3} + 1)^2 = 3 + 2\sqrt{3} + 1 = 4 + 2\sqrt{3}$. The middle term is the one students lose, exactly as with $(a+b)^2$.
Fill the blank: $\sqrt{12} + \sqrt{27}$ simplifies to $5\sqrt{\;}$ where the number under the root is .

Only like surds add or subtract, so always simplify first to reveal which are alike. Brackets containing surds expand exactly as algebraic brackets, including the middle term when squaring a binomial.

Pause, copy the like-surds rule, the worked $\sqrt{8} + \sqrt{18} = 5\sqrt{2}$, and one bracket expansion such as $(\sqrt{3}+1)^2 = 4 + 2\sqrt{3}$, into your book.

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Work examples end to end

Follow the reasoning through complete worked solutions.

PROBLEM 1 · SIMPLIFYING

Simplify $\sqrt{72} + \sqrt{50} - \sqrt{18}$.

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$\sqrt{72} = \sqrt{36}\sqrt{2} = 6\sqrt{2}$
Largest perfect square factor of 72 is 36.
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$\sqrt{50} = 5\sqrt{2}$ and $\sqrt{18} = 3\sqrt{2}$
Perfect square factors 25 and 9.
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$6\sqrt{2} + 5\sqrt{2} - 3\sqrt{2} = 8\sqrt{2}$
All three are like surds now, so combine the coefficients.
PROBLEM 2 · MULTIPLYING

Simplify $(2\sqrt{3})(5\sqrt{6})$.

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Coefficients: $2 \times 5 = 10$
Multiply the numbers outside the roots.
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Surds: $\sqrt{3} \times \sqrt{6} = \sqrt{18}$
Multiply the numbers under the roots.
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$10\sqrt{18} = 10 \times 3\sqrt{2} = 30\sqrt{2}$
Simplify $\sqrt{18}$, then multiply out.
PROBLEM 3 · EXPANDING BRACKETS

Expand and simplify $(\sqrt{5} + 2)(\sqrt{5} - 3)$.

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$= \sqrt{5}\sqrt{5} - 3\sqrt{5} + 2\sqrt{5} - 6$
Multiply every term by every term, as with any binomial product.
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$\sqrt{5}\sqrt{5} = 5$
A surd times itself gives the number under the root.
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$= 5 - \sqrt{5} - 6 = -1 - \sqrt{5}$
Collect the like surds and the rational terms separately.
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Quick-fire practice

Work through the core explanation before applying it.

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Quick-fire practice
+10 XP
  1. Simplify $\sqrt{48}$.
  2. Simplify $3\sqrt{7} - \sqrt{7}$.
  3. Simplify $(4\sqrt{2})(3\sqrt{5})$.
  4. Expand $(\sqrt{2} + 3)^2$.
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Revisit your estimate of $\sqrt{50}$

Run the quick drill and copy the summary into your book.

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Revisit your estimate of $\sqrt{50}$

At the start you estimated $\sqrt{50}$. Now write it in simplified surd form and explain how the simplified form makes the estimate easy to check mentally.

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Multiple choice

Answer the drill bank and rate your confidence.

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Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence, that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

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Short answer

Write full responses, then check them against the model answers.

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Short answer
ApplyBand 43 marks

Q1. Simplify $\sqrt{75} + \sqrt{12} - \sqrt{27}$, showing each simplification. (3 marks)

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ApplyBand 43 marks

Q2. Expand and simplify $(2\sqrt{3} - 1)^2$. (3 marks)

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UnderstandBand 32 marks

Q3. Explain why $\sqrt{16}$ is not a surd but $\sqrt{17}$ is, and state what "simplified surd form" means. (2 marks)

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📖 Comprehensive answers (click to reveal)

Practice 1: $4\sqrt{3}$. Practice 2: $2\sqrt{7}$. Practice 3: $12\sqrt{10}$. Practice 4: $11 + 6\sqrt{2}$.

Q1 (3 marks): $\sqrt{75} = 5\sqrt{3}$, $\sqrt{12} = 2\sqrt{3}$, $\sqrt{27} = 3\sqrt{3}$ [2]. $5\sqrt{3} + 2\sqrt{3} - 3\sqrt{3} = 4\sqrt{3}$ [1].

Q2 (3 marks): $(2\sqrt{3})^2 = 4 \times 3 = 12$ [1]. Middle term $= 2 \times 2\sqrt{3} \times (-1) = -4\sqrt{3}$ [1]. Total $= 12 - 4\sqrt{3} + 1 = 13 - 4\sqrt{3}$ [1].

Q3 (2 marks): $\sqrt{16} = 4$, a whole number, so it is rational and not a surd; $\sqrt{17}$ is irrational, so it is a surd [1]. A surd is in simplified form when the number under the root has no perfect square factor other than 1 [1].

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Review and finish

Take the module quiz if you are ready, then mark the lesson complete.

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Boss battle · Surd Simplifier
earn bronze · silver · gold

Simplify, combine and expand surd expressions at speed without reaching for a decimal. Beat the boss to bank a tier, gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

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Mark lesson as complete

Tick when you've finished the practice and review.