Optimisation Problem Solver
Maximise the area of a rectangle with a fixed perimeter
w = 10
h = 5
Perimeter =
30
Area =
50
Max Area =
56.25
Width
For fixed perimeter, maximum area occurs when the rectangle is a square. A = w(15-w), dA/dw = 15-2w = 0 → w = 7.5.