Checkpoint 1

Maths Standard Year 11 - Module 1 Algebra - Lessons 1 to 4

Variables and substitution One-step and two-step equations Equations from worded problems Rearranging formulas

10 MC 3 short answer 25 min

0/10

Multiple Choice Score

Answer questions to see your score.

Part A - Multiple Choice

1In the formula $C = 8 + 1.50k$, what does the 8 represent?

B. The 8 is added before the variable part, so it is the fixed starting cost.

2Evaluate $2n + 5$ when $n = 7$.

C. $2(7)+5=14+5=19$.

3Solve $x + 7 = 19$.

B. Subtract 7 from both sides: $x=12$.

4Solve $3x + 5 = 26$.

B. Subtract 5 to get $3x=21$, then divide by 3.

5Adult tickets cost $\$18$ each plus a $\$6$ booking fee. The total is $\$78$. Which equation is correct if $t$ is the number of tickets?

B. The fixed booking fee is 6 and each ticket costs 18.

6A phone plan costs $\$18$ plus $\$0.10$ per text. The bill is $32. How many texts were sent?

C. $18+0.10n=32$, so $0.10n=14$ and $n=140$.

7Rearrange $d = st$ to make $s$ the subject.

B. Divide both sides by $t$: $s=\frac{d}{t}$.

8Using $s = \frac{d}{t}$, find speed when $d = 180$ km and $t = 3$ h.

B. $s=180/3=60$ km/h.

9Rearrange $C = 2\pi r$ to make $r$ the subject.

B. Divide by the whole multiplier $2\pi$.

10What is the error in rearranging $C = 2\pi r$ as $r = C/2$?

A. Since the multiplier is $2\pi$, both 2 and $\pi$ must be divided out.

Part B - Short Answer

1The formula $C = 12 + 2.40m$ gives courier cost in dollars for $m$ kilometres.

a. Find the cost for 15 km. 2 marks

b. Explain what 12 and 2.40 represent. 2 marks

$C = 12 + 2.40(15) = 12 + 36 = 48$. The cost is $48. The 12 is the fixed starting cost; 2.40 is the cost per kilometre.

2A van hire costs $\$45$ plus $\$20$ per hour. The total cost is $145.

a. Define the variable and write an equation. 2 marks

b. Solve the equation and interpret the answer. 2 marks

Let $h$ be the number of hours. $45 + 20h = 145$, so $20h = 100$ and $h = 5$. The van was hired for 5 hours.

3Rearrange and use $d = st$.

a. Make $t$ the subject. 2 marks

b. Find $t$ when $d = 240$ km and $s = 80$ km/h. 2 marks

From $d = st$, divide by $s$: $t = \frac{d}{s}$. Then $t = \frac{240}{80} = 3$. The time is 3 hours.

Use this checkpoint to decide whether Lessons 1-4 are secure before moving further into the module.