Checkpoint 2

Maths Standard Year 11 - Module 1 Algebra - Lessons 5 to 8

Formulas from tables Spreadsheet-style formulas Applied quadratic formulas Mixed formula strategies

10 MC 3 short answer 25 min

0/10

Multiple Choice Score

Answer questions to see your score.

Part A - Multiple Choice

1A delivery company charges $\$10$ plus $\$3$ per kilometre. Which formula gives cost $C$ for $k$ kilometres?

B. The starting value is 10 and the repeated change is 3 per kilometre.

2Outputs are 12, 17, 22, 27 for inputs 0, 1, 2, 3. Which formula matches?

A. The output at input 0 is 12, and the repeated increase is 5.

3In the spreadsheet formula =B2*C2+D2, B2 is quantity, C2 is price per item, and D2 is delivery. What does it calculate?

C. The formula multiplies quantity by unit price, then adds delivery.

4Use =B2*C2+D2 when B2 = 18, C2 = 3 and D2 = 12.

C. $18 \times 3 + 12 = 54 + 12 = 66$.

5What does $v^2$ mean?

C. Squaring means multiplying the value by itself.

6Use $D = 0.01v^2 + 0.3v$ to estimate $D$ when $v = 60$.

B. $0.01(60^2)+0.3(60)=36+18=54$ m.

7A square has side length 9.5 m. Use $A = s^2$ to find its area.

C. $9.5^2 = 90.25$ m2.

8A printer charges $\$25$ setup plus $\$2$ per page. A job costs $81. How many pages were printed?

C. $25 + 2p = 81$, so $2p = 56$ and $p = 28$.

9A cyclist travels 135 km in 3 hours. Which strategy is best for finding speed from $d = st$?

B. Speed is not the subject, so rearrange first: $s = d/t$.

10A stopping-distance calculation should give 54 m, but a student writes 540 m. What is the most likely issue?

A. A result ten times too large often signals a decimal-place or multiplier error.

Part B - Short Answer

1A hire company charges $\$30$ plus $\$8$ per hour.

a. Write a formula for total cost $C$ after $h$ hours. 2 marks

b. Find the cost for 6 hours. 2 marks

$C = 30 + 8h$. For 6 hours, $C = 30 + 8(6) = 78$. The cost is $78.

2A spreadsheet formula is =B2*C2+D2. B2 is quantity, C2 is price per item and D2 is delivery.

a. Explain the formula in words. 2 marks

b. Calculate the output when B2 = 15, C2 = 4 and D2 = 9. 2 marks

The formula calculates quantity times price per item, plus delivery. Output $= 15 \times 4 + 9 = 69$.

3Use $D = 0.01v^2 + 0.3v$ for a stopping-distance model.

a. Estimate $D$ when $v = 70$ km/h. 3 marks

b. Explain why this formula does not behave like a constant-rate formula. 2 marks

$D = 0.01(70)^2 + 0.3(70) = 49 + 21 = 70$ m. The squared term means the output grows faster as speed increases, so it is not constant-rate.

Use this checkpoint to consolidate formula building, spreadsheets, applied quadratics and mixed strategy selection.