Module 3 · L13 of 14~50 minMST-11-04⚡ +90 XP available
The Cost of a Vehicle
The number on the windscreen is not what you pay, and what you pay to buy it is not what it costs to keep. Work out the real on-road price, add up a year of running costs, turn that into a figure per kilometre, then build the whole thing as a spreadsheet you can ask questions of.
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You are here
Learning Intentions
Build your own printable worksheet from any question in this module.
Worksheets
Practise this lesson
Build your own printable worksheet from any question in this module.
Two cars are for sale. One is $\$18{,}000$ and uses 9 litres of fuel per 100 km. The other is $\$22{,}000$ and uses 6. A friend says the cheaper one is obviously the better buy, because $\$4{,}000$ is a lot of money. Before you calculate anything, write down what you would need to know to answer that properly.
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Learning Intentions
Calculate stamp duty on a vehicle from a given rate table, including above the threshold
Add stamp duty, registration, CTP and transfer fees to a purchase price to get the on-road cost
Tell compulsory from non-compulsory insurance and say what each one covers
Total the ongoing costs of running a vehicle for a year and express them as a cost per kilometre
Model purchasing and running a vehicle in a spreadsheet, and use it to answer a "what if" question
KT
Key Terms
On-road costEverything you must pay before you can legally drive the car away, not just the advertised price. Like this: a $\$24{,}000$ car with $\$720$ stamp duty, $\$380$ registration, $\$620$ CTP and a $\$40$ transfer fee has an on-road cost of $\$25{,}760$.
Stamp dutyA government tax on the transfer, charged as a rate per $\$100$ of the vehicle's value. Like this: at $\$3$ per $\$100$, a $\$24{,}000$ car has $24000 \div 100 = 240$ lots of $\$100$, so the duty is $240 \times 3 = \$720$.
RegistrationThe annual fee that puts the car on the road and keeps the plates valid. Like this: $\$380$ paid when you buy it, and again every year you keep it, which is why it appears in both lists.
CTP insurance (green slip)Compulsory Third Party insurance, which covers injury to people and must be bought before the car can be registered. Like this: a $\$620$ green slip is not optional, so it belongs in the on-road cost of every vehicle.
Comprehensive insuranceOptional cover for damage to your own car as well as other people's property. Like this: a $\$620$ annual premium with a $\$700$ excess means you pay the first $\$700$ of any claim yourself.
Running costsWhat the car costs you every year after you own it: fuel, servicing, tyres, registration renewal and insurance. Like this: $\$2{,}400$ of fuel plus $\$2{,}100$ of everything else is $\$4{,}500$ a year.
Cost per kilometreAnnual running cost divided by kilometres driven, so two different cars can be compared fairly. Like this: $\$4{,}500$ over $15{,}000$ km is $4500 \div 15000 = \$0.30$, or 30 cents per kilometre.
Fuel consumptionLitres used per 100 km travelled, the figure quoted on every new car. Like this: at 8 L/100 km, driving $15{,}000$ km uses $15000 \times \dfrac{8}{100} = 1{,}200$ litres.
Stamp duty is charged at $\$3$ per $\$100$ of a vehicle's value. How much duty is payable on a $\$24{,}000$ car?
First count the lots of $\$100$: $24000 \div 100 = 240$. Then charge $\$3$ for each: $240 \times 3 = \mathbf{\$720}$. Stopping at $\$240$ counts the lots but forgets the rate, $\$2{,}400$ is 10% of the price, and $\$7{,}200$ charges $\$3$ per $\$10$.
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What It Really Costs To Drive It Away
The advertised price is only the first line of the bill.
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What It Really Costs To Drive It Away
The advertised price is only the first line of the bill. Before the car is legally yours and on the road you also pay stamp duty, registration, a CTP green slip and a small transfer fee. Added together those give the on-road cost.
Stamp duty is the only one you calculate rather than read off a receipt, and exam questions always supply the rate table. A typical one:
Up to $\$45{,}000$: $\$3$ for every $\$100$ (or part) of the value.
Over $\$45{,}000$: $\$1{,}350$ plus $\$5$ for every $\$100$ (or part) above $\$45{,}000$.
Take a car advertised at $\$24{,}000$. It sits under the threshold, so count the lots of $\$100$ first: $24000 \div 100 = 240$, then charge $\$3$ each: $240 \times 3 = \$720$.
Now add the rest. With registration $\$380$, a CTP green slip $\$620$ and a transfer fee $\$40$:
That is $\$1{,}760$ more than the windscreen said, or $\dfrac{1760}{24000} \times 100 = 7.3\%$ (to one decimal place) on top of the advertised price. Worth knowing before you agree to a budget.
Must do: Check which side of the threshold the value falls on before choosing a rate. Above $\$45{,}000$ only the excess is charged at the higher rate, not the whole price.
Common error: Reading "$\$3$ per $\$100$" as 3%. Here they happen to agree, because $\$3$ in every $\$100$ is 3%, but the two-rate table above is not a single percentage and treating it as one gets the over-threshold case wrong.
On-road cost = purchase price + stamp duty + registration + CTP + transfer fee. Stamp duty at 3 per 100: divide the value by 100, then multiply by 3. A 24,000 car: 240 x 3 = 720 duty, on-road 25,760 (dollars).
Pause, copy the on-road cost formula into your book with the $\$24{,}000$ car worked beside it (duty 720, rego 380, CTP 620, transfer 40, total 25,760), and copy the two-line stamp duty table underneath.
A $\$24{,}000$ car carries $\$720$ stamp duty, $\$380$ registration, a $\$620$ green slip and a $\$40$ transfer fee. The on-road cost is $\$$, which is $\$$ more than the advertised price.
Add the four extras first: $720 + 380 + 620 + 40 = \$1{,}760$. Then the on-road cost is $24000 + 1760 = \mathbf{\$25{,}760}$, and the amount above the advertised price is that same $\mathbf{\$1{,}760}$.
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Which Insurance You Must Buy, And Which You Choose
Three kinds of cover turn up in these questions, and the syllabus asks you to tell the compulsory one from the rest.
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Which Insurance You Must Buy, And Which You Choose
Three kinds of cover turn up in these questions, and the syllabus asks you to tell the compulsory one from the rest.
CTP, the green slip (compulsory). Covers injury to people in a crash. You cannot register a vehicle without it, so it always belongs in the on-road cost.
Third party property (not compulsory). Covers damage you do to someone else's car or property, and nothing of your own.
Comprehensive (not compulsory). Covers damage to your own vehicle as well as other people's property. The dearest of the three.
Any of the optional policies can carry an excess: the part of a claim you pay yourself. A $\$620$ premium with a $\$700$ excess means you pay $\$620$ a year, and if you claim for $\$3{,}000$ of damage the insurer pays $3000 - 700 = \$2{,}300$ and you pay the $\$700$.
A lower premium with a higher excess is not automatically cheaper. It is cheaper only if you do not claim, which is a judgement about risk rather than a calculation, and saying so is often the mark.
Must do: Put CTP in the purchase costs, because you cannot register without it, and comprehensive in the running costs, because it is a yearly choice.
Common error: Assuming CTP covers your car. It covers people, not panels. A driver with only a green slip who writes off their own car receives nothing for it.
CTP green slip is compulsory and covers injury to people. Third party property and comprehensive are optional; comprehensive is the only one covering your own vehicle. Excess = the part of a claim you pay yourself, so a 3,000 claim with a 700 excess pays out 2,300 (dollars).
Pause, copy the three insurance types into your book as a short list, writing next to each one whether it is compulsory and exactly whose property it covers.
True or False: CTP green slip insurance is optional, so a careful driver can leave it out of the on-road cost.
False. CTP is Compulsory Third Party insurance. A vehicle cannot be registered without a current green slip, so its cost belongs in the on-road total for every vehicle no matter who is driving. Comprehensive and third party property are the optional ones.
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A Year Of Running Costs, And What That Is Per Kilometre
Buying the car is one payment.
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A Year Of Running Costs, And What That Is Per Kilometre
Buying the car is one payment. Keeping it is a payment every year, and the ongoing list is short enough to memorise: fuel, servicing, tyres, registration renewal, insurance.
Fuel is the only one you calculate. Consumption is quoted in litres per 100 km, so:
litres used = distance $\times \dfrac{\text{consumption}}{100}$, then multiply by the price per litre.
Take someone driving $15{,}000$ km a year in a car using 8 L/100 km, with petrol at $\$2.00$ a litre. Litres used $= 15000 \times \dfrac{8}{100} = 1{,}200$ L, so fuel costs $1200 \times 2.00 = \$2{,}400$.
Divide by the distance to get the figure that lets you compare any two cars: $\dfrac{4500}{15000} = \$0.30$ per km, or 30 cents per kilometre.
Notice that only fuel changes when you drive further. Servicing, tyres, registration and insurance are much the same whether you drive $10{,}000$ km or $25{,}000$, so the more you drive, the lower the cost per kilometre becomes. That is why cost per km is only meaningful next to the distance it assumes.
Must do: Divide the consumption by 100 before multiplying. "8 L/100 km" is 0.08 litres per km, not 8.
Common error: Dividing distance by cost instead of cost by distance. $15000 \div 4500 = 3.33$, which is kilometres per dollar, not dollars per kilometre.
Litres used = distance x consumption / 100, then x price per litre. Annual running cost = fuel + servicing + tyres + registration + insurance. Cost per km = annual running cost / distance. 15,000 km at 8 L/100 km and 2.00/L: 1,200 L = 2,400 fuel, 4,500 total, 30 c/km (dollars).
Pause, copy the fuel formula and the cost-per-kilometre formula into your book, with the worked figures beside them: 1,200 L, $\$2{,}400$ fuel, $\$4{,}500$ total, 30 c/km.
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Modelling The Whole Thing In A Spreadsheet
Everything above is arithmetic you could do once on paper.
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Modelling The Whole Thing In A Spreadsheet
Everything above is arithmetic you could do once on paper. The reason to build it as a spreadsheet is that a model answers questions a single calculation cannot: change one number and every total updates.
Lay the running costs out with the inputs in their own cells, so nothing is buried inside a formula:
A
B
1
Distance per year (km)
15000
2
Consumption (L/100 km)
8
3
Fuel price ($\$$/L)
2.00
4
Fuel cost
=B1*B2/100*B3
5
Servicing
700
6
Tyres
400
7
Registration
380
8
Insurance
620
9
Annual running cost
=SUM(B4:B8)
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Cost per km
=B9/B1
B9 returns $\$4{,}500$ and B10 returns $\$0.30$, the same answers as Card 3. The gain is what happens next: type $25{,}000$ into B1 and the model immediately reports a higher fuel bill but a lower cost per kilometre, because only B4 depends on the distance.
Two rules make the model worth having:
Every input gets its own cell. Writing =15000*8/100*2 gives the right number and answers no question, because changing the fuel price means rewriting the formula.
Every total is a formula, never a typed number. A typed $4500$ in B9 stops updating the moment anything above it changes, and nothing on screen shows that it has gone stale.
Must do: Use a range in the sum, =SUM(B4:B8), so inserting a row for a new cost is picked up automatically.
Common error: Including B9 in its own sum, or summing B4:B9, which counts the total twice and gives $\$9{,}000$.
Spreadsheet model: every input in its own cell, every total a formula. Fuel =B1*B2/100*B3, annual running cost =SUM(B4:B8), cost per km =B9/B1. Change one input and every total updates, which is what a model gives you that a single calculation does not.
Pause, copy the ten-row layout into your book with the three formulas exactly as written, and note beside B10 why the cost per kilometre falls when B1 rises.
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Worked examples · reveal each step
Worked examples · reveal each step
Worked examples · reveal each step
WE1 · Stamp duty above the threshold. Using the table (up to $\$45{,}000$: $\$3$ per $\$100$; over $\$45{,}000$: $\$1{,}350$ plus $\$5$ per $\$100$ above $\$45{,}000$), find the duty on a $\$52{,}000$ vehicle.
The value is above the threshold, so the first $\$45{,}000$ contributes the flat $\$1{,}350$.
Amount above the threshold $= 52000 - 45000 = \$7{,}000$.
Lots of $\$100$ in that excess $= 7000 \div 100 = 70$, charged at $\$5$ each: $70 \times 5 = \$350$.
Stamp duty $= 1350 + 350 = \mathbf{\$1{,}700}$.
Sense check: charging the whole $\$52{,}000$ at $\$3$ per $\$100$ would give $\$1{,}560$, and the answer must be more than that because the excess is taxed harder ✓.
WE2 · Full on-road cost. A car is advertised at $\$31{,}000$. Stamp duty is $\$3$ per $\$100$, registration is $\$380$, the green slip is $\$645$ and the transfer fee is $\$40$. Find the on-road cost and the extra as a percentage of the advertised price.
As a percentage of the advertised price: $\dfrac{1995}{31000} \times 100 = \mathbf{6.4\%}$ (1 d.p.).
WE3 · A year of running costs. A car uses 8 L/100 km and is driven $15{,}000$ km a year. Fuel is $\$2.00$ per litre. Servicing is $\$700$, tyres $\$400$, registration $\$380$ and insurance $\$620$. Find the annual running cost and the cost per kilometre.
Litres used $= 15000 \times \dfrac{8}{100} = 1{,}200$ L.
Cost per kilometre $= \dfrac{4500}{15000} = \$0.30$, that is $\mathbf{30}$ cents per kilometre.
Check the units: dollars divided by kilometres gives dollars per kilometre ✓. The upside-down answer, $15000 \div 4500 = 3.33$, would be kilometres per dollar.
WE4 · Is the cheaper car cheaper? Car A costs $\$18{,}000$ and uses 9 L/100 km. Car B costs $\$22{,}000$ and uses 6 L/100 km. Both are driven $15{,}000$ km a year with fuel at $\$2.00$ per litre. Compare the total cost of buying and fuelling each over 5 years.
Car A fuel per year $= 15000 \times \dfrac{9}{100} = 1{,}350$ L, costing $1350 \times 2.00 = \$2{,}700$.
Car B fuel per year $= 15000 \times \dfrac{6}{100} = 900$ L, costing $900 \times 2.00 = \$1{,}800$.
Over 5 years: Car A fuel $= 5 \times 2700 = \$13{,}500$; Car B fuel $= 5 \times 1800 = \$9{,}000$.
Car A total $= 18000 + 13500 = \$31{,}500$. Car B total $= 22000 + 9000 = \mathbf{\$31{,}000}$.
Car B is $\$500$ cheaper over 5 years, despite costing $\$4{,}000$ more to buy, because it saves $\$900$ of fuel every year and $5 \times 900 = \$4{,}500$ is more than $\$4{,}000$.
The answer depends entirely on the distance and the fuel price. Drive less, or keep the car for fewer years, and Car A wins. Neither car is "obviously" better without the numbers.
A car costs $\$4{,}500$ a year to run and is driven $15{,}000$ km. What is the running cost per kilometre?
Cost per kilometre is cost divided by distance: $4500 \div 15000 = \$0.30$, which is 30 cents. The $\$3.33$ answer divides the other way round ($15000 \div 4500$) and is kilometres per dollar. The other two are the right digits with the decimal point in the wrong place, and both fail a sense check: no ordinary car costs $\$30$ to drive one kilometre.
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Show what you have learned
Multiple choice, then short answer under exam conditions.
MC
Multiple Choice
5 random questions from a replayable lesson bank, feedback shown immediately
SAQ
Short Answer Questions
SAQ 1. A vehicle is advertised at $\$48{,}000$. Stamp duty is charged at $\$3$ per $\$100$ up to $\$45{,}000$, then $\$1{,}350$ plus $\$5$ per $\$100$ above $\$45{,}000$. Registration is $\$380$, the CTP green slip is $\$710$ and the transfer fee is $\$40$.
(a) Calculate the stamp duty.
(b) Calculate the on-road cost.
(c) Express the total extra cost as a percentage of the advertised price, correct to one decimal place.
Show sample solution
(a) The value is above the threshold, so the first $\$45{,}000$ gives the flat $\$1{,}350$.
Excess $= 48000 - 45000 = \$3{,}000$, which is $3000 \div 100 = 30$ lots of $\$100$ at $\$5$ each $= \$150$
SAQ 2. Mia drives $20{,}000$ km a year. Her car uses 7.5 L/100 km and fuel costs $\$1.90$ a litre. Her other yearly costs are servicing $\$820$, tyres $\$500$, registration $\$380$ and insurance $\$950$.
(a) Calculate her annual fuel cost.
(b) Calculate her total annual running cost and her cost per kilometre, in cents.
(c) Mia takes a job that lifts her driving to $25{,}000$ km a year, with everything else unchanged. Calculate her new cost per kilometre, correct to one decimal place, and explain why it has moved the way it has.
Show sample solution
(a) Litres $= 20000 \times \dfrac{7.5}{100} = 1{,}500$ L
New cost per km $= \dfrac{6212.50}{25000} = \$0.2485 = \mathbf{24.9}$ cents per km (1 d.p.)
It has fallen, even though she is spending $\$712.50$ more in total. Only the fuel changes with distance; the $\$2{,}650$ of servicing, tyres, registration and insurance is the same whether she drives $20{,}000$ km or $25{,}000$. Spreading that fixed amount over more kilometres lowers the average cost of each one.
SAQ 3. Sam is building a spreadsheet to model his running costs. Column A holds labels and column B holds values: B1 distance per year, B2 consumption in L/100 km, B3 fuel price per litre, B4 fuel cost, B5 servicing, B6 tyres, B7 registration, B8 insurance.
(a) Write the formula for B4.
(b) Write formulas for B9, the annual running cost, and B10, the cost per kilometre.
(c) Sam types $4500$ straight into B9 instead of a formula. Explain what goes wrong, and why it is worse than getting the arithmetic wrong.
Show sample solution
(a)=B1*B2/100*B3
The consumption is per 100 km, so it is divided by 100 before being multiplied by the distance and then by the price.
(b) B9: =SUM(B4:B8) B10: =B9/B1
A range rather than =B4+B5+B6+B7+B8, so that inserting a row for a new cost is picked up automatically.
(c) A typed $4500$ is correct once and then never again. The moment Sam changes the fuel price in B3 or the distance in B1, B4 updates and B9 does not, so the model reports a total that no longer matches its own inputs, and B10 divides that stale total by the new distance.
It is worse than an arithmetic mistake because nothing on screen looks wrong. A wrong sum can be spotted by checking it; a hardcoded total agrees with itself forever and only disagrees with reality. The point of a model is that changing an input updates every figure that depends on it, and a typed number silently opts out of that.
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Consolidate and move on
Sit the module quiz, then close the lesson off.
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Revisit Your Initial Thinking
Back to the two cars. To answer properly you needed three things nobody mentioned: how far it is driven each year, what fuel costs, and how long it is kept. At $15{,}000$ km a year with fuel at $\$2.00$, the $\$18{,}000$ car burns $\$2{,}700$ of petrol a year and the $\$22{,}000$ car burns $\$1{,}800$. Over 5 years that is $\$13{,}500$ against $\$9{,}000$, so the totals are $\$31{,}500$ and $\$31{,}000$: the dearer car is $\$500$ cheaper. Change the distance or the years and the answer flips. Your friend was not wrong about the $\$4{,}000$, they just stopped counting too early, which is the same mistake as reading the windscreen price and ignoring the stamp duty.
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