Checkpoint 1
Maths Standard Year 11 - Module 1 Algebra - Lessons 1 to 4
Variables and substitution
One-step and two-step equations
Equations from worded problems
Rearranging formulas
10 MC
3 short answer
25 min
0/10
Multiple Choice Score
Answer questions to see your score.
Part A - Multiple Choice
The number of kilometres
The fixed starting cost
The rate per kilometre
The final cost for every trip
B. The 8 is added before the variable part, so it is the fixed starting cost.
$x = 7$
$x = 12$
$x = 19$
$x = 26$
B. Subtract 7 from both sides: $x=12$.
$x = 5$
$x = 7$
$x = 9$
$x = 10.3$
B. Subtract 5 to get $3x=21$, then divide by 3.
$18 + 6t = 78$
$6 + 18t = 78$
$78 + 18t = 6$
$6t + 78 = 18$
B. The fixed booking fee is 6 and each ticket costs 18.
C. $18+0.10n=32$, so $0.10n=14$ and $n=140$.
$s = dt$
$s = \frac{d}{t}$
$s = \frac{t}{d}$
$s = d - t$
B. Divide both sides by $t$: $s=\frac{d}{t}$.
54 km/h
60 km/h
183 km/h
540 km/h
B. $s=180/3=60$ km/h.
$r = C - 2\pi$
$r = \frac{C}{2\pi}$
$r = \frac{2\pi}{C}$
$r = 2C\pi$
B. Divide by the whole multiplier $2\pi$.
The student forgot to divide by $\pi$
The student divided by $\pi$ twice
The student made $C$ the subject
The student should have added 2
A. Since the multiplier is $2\pi$, both 2 and $\pi$ must be divided out.
Part B - Short Answer
a. Find the cost for 15 km. 2 marks
b. Explain what 12 and 2.40 represent. 2 marks
$C = 12 + 2.40(15) = 12 + 36 = 48$. The cost is $48. The 12 is the fixed starting cost; 2.40 is the cost per kilometre.
a. Define the variable and write an equation. 2 marks
b. Solve the equation and interpret the answer. 2 marks
Let $h$ be the number of hours. $45 + 20h = 145$, so $20h = 100$ and $h = 5$. The van was hired for 5 hours.
a. Make $t$ the subject. 2 marks
b. Find $t$ when $d = 240$ km and $s = 80$ km/h. 2 marks
From $d = st$, divide by $s$: $t = \frac{d}{s}$. Then $t = \frac{240}{80} = 3$. The time is 3 hours.
Use this checkpoint to decide whether Lessons 1-4 are secure before moving further into the module.
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