Checkpoint 1

Maths Standard Year 11 - Module 1 Algebra - Lessons 1 to 4

Variables and substitution One-step and two-step equations Equations from worded problems Rearranging formulas
10 MC 3 short answer 25 min
0/10
Multiple Choice Score
Answer questions to see your score.
Part A - Multiple Choice
1In the formula $C = 8 + 1.50k$, what does the 8 represent?
The number of kilometres
The fixed starting cost
The rate per kilometre
The final cost for every trip
B. The 8 is added before the variable part, so it is the fixed starting cost.
2Evaluate $2n + 5$ when $n = 7$.
14
17
19
75
C. $2(7)+5=14+5=19$.
3Solve $x + 7 = 19$.
$x = 7$
$x = 12$
$x = 19$
$x = 26$
B. Subtract 7 from both sides: $x=12$.
4Solve $3x + 5 = 26$.
$x = 5$
$x = 7$
$x = 9$
$x = 10.3$
B. Subtract 5 to get $3x=21$, then divide by 3.
5Adult tickets cost $18 each plus a $6 booking fee. The total is $78. Which equation is correct if $t$ is the number of tickets?
$18 + 6t = 78$
$6 + 18t = 78$
$78 + 18t = 6$
$6t + 78 = 18$
B. The fixed booking fee is 6 and each ticket costs 18.
6A phone plan costs $18 plus $0.10 per text. The bill is $32. How many texts were sent?
14
32
140
180
C. $18+0.10n=32$, so $0.10n=14$ and $n=140$.
7Rearrange $d = st$ to make $s$ the subject.
$s = dt$
$s = \frac{d}{t}$
$s = \frac{t}{d}$
$s = d - t$
B. Divide both sides by $t$: $s=\frac{d}{t}$.
8Using $s = \frac{d}{t}$, find speed when $d = 180$ km and $t = 3$ h.
54 km/h
60 km/h
183 km/h
540 km/h
B. $s=180/3=60$ km/h.
9Rearrange $C = 2\pi r$ to make $r$ the subject.
$r = C - 2\pi$
$r = \frac{C}{2\pi}$
$r = \frac{2\pi}{C}$
$r = 2C\pi$
B. Divide by the whole multiplier $2\pi$.
10What is the error in rearranging $C = 2\pi r$ as $r = C/2$?
The student forgot to divide by $\pi$
The student divided by $\pi$ twice
The student made $C$ the subject
The student should have added 2
A. Since the multiplier is $2\pi$, both 2 and $\pi$ must be divided out.
Part B - Short Answer
1The formula $C = 12 + 2.40m$ gives courier cost in dollars for $m$ kilometres.
a. Find the cost for 15 km. 2 marks
b. Explain what 12 and 2.40 represent. 2 marks
$C = 12 + 2.40(15) = 12 + 36 = 48$. The cost is $48. The 12 is the fixed starting cost; 2.40 is the cost per kilometre.
2A van hire costs $45 plus $20 per hour. The total cost is $145.
a. Define the variable and write an equation. 2 marks
b. Solve the equation and interpret the answer. 2 marks
Let $h$ be the number of hours. $45 + 20h = 145$, so $20h = 100$ and $h = 5$. The van was hired for 5 hours.
3Rearrange and use $d = st$.
a. Make $t$ the subject. 2 marks
b. Find $t$ when $d = 240$ km and $s = 80$ km/h. 2 marks
From $d = st$, divide by $s$: $t = \frac{d}{s}$. Then $t = \frac{240}{80} = 3$. The time is 3 hours.

Use this checkpoint to decide whether Lessons 1-4 are secure before moving further into the module.

Back to Module Overview