Perimeter and Arc Length

Trace the boundary. Every edge counts — straight or curved. The arc is just a fraction of the full circumference, and the fraction is determined by the angle.

45–50 min MS-M1 3 MC 3 SA Lesson 5 of 22 Free

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Think First

A pizza slice (sector) has a curved crust and two straight edges going in to the centre. If you wanted to know the total length of pastry needed to frame the slice, which edges would you measure? Is the crust the only part that matters?

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Key Formulas — This Lesson

$C = 2\pi r$
Circumference of a full circle  |  Equivalently: $C = \pi d$ Starting point for all arc length calculations
$\ell = \dfrac{\theta}{360} \times 2\pi r$
Arc length — $\theta$ = central angle (degrees), $r$ = radius Think: arc is a fraction $\theta/360$ of the full circumference
$P = 2r + \ell$
Perimeter of a sector — two radii plus the arc The most common error: calculating only the arc and forgetting the two straight edges
CIRCUMFERENCE ARC LENGTH SECTOR PERIMETER r C = 2πr or πd (d = 2r) θ r r ℓ = (θ/360) × 2πr fraction of full circumference r r P = 2r + ℓ two radii + arc — don't forget the straight sides

Know

  • The circumference formula $C = 2\pi r$ and its equivalents
  • The arc length formula $\ell = (\theta/360) \times 2\pi r$
  • What a composite perimeter problem requires

Understand

  • Why an arc is a fraction of the full circumference — and why that fraction is $\theta/360$
  • Why the perimeter of a sector includes two radii, not just the arc
  • Why you must account for every boundary edge, including straight edges

Can Do

  • Calculate arc length for any sector
  • Find the perimeter of a sector (arc + two radii)
  • Find the perimeter of composite shapes involving straight sides and arcs
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Key Vocabulary

PerimeterThe total length of the boundary of a shape — the distance around the outside
CircumferenceThe perimeter of a circle — $C = 2\pi r$ or $C = \pi d$
ArcA portion of the circumference — a curved section of the boundary
SectorA "pizza slice" region of a circle — bounded by two radii and an arc
Subtended angleThe central angle $\theta$ formed by two radii — determines what fraction of the circle you have

Misconceptions to Fix

Wrong: Rounding 4.5 down gives 4.

Right: Standard rounding rounds 4.5 up to 5; rounding to the nearest even number (banker's rounding) is different.

01

Perimeter of Polygons and Composite Shapes

Perimeter is the total length of the boundary. For any polygon — add every side. For composite shapes — trace the outer boundary and add every edge you cross.

ShapeFormula
Rectangle$P = 2\ell + 2w$
Square$P = 4s$
Triangle$P = a + b + c$
Circle$C = 2\pi r = \pi d$

Composite Perimeter Strategy

  1. Trace the outer boundary of the shape with your finger
  2. Every edge your finger crosses is part of the perimeter
  3. Any internal construction lines are not part of the perimeter
  4. Add every boundary edge — straight and curved sections separately, then combine
The trap: In a rectangle-plus-semicircle, the diameter of the semicircle is an internal edge — it is not on the outer boundary. Only three sides of the rectangle plus the curved arc form the perimeter.
02

Arc Length

An arc is a curved portion of a circle's circumference. A sector with central angle $\theta$ contains an arc that is exactly $\theta/360$ of the full circumference.

$$\ell = \frac{\theta}{360} \times 2\pi r$$
$\theta$Fraction of circleArc length
360°Full circle$2\pi r$ — the full circumference ✓
180°Semicircle$\pi r$
90°Quarter circle$\tfrac{1}{2}\pi r$
60°Sixth of circle$\tfrac{1}{3}\pi r$
Sense check: When $\theta = 360°$, the arc formula gives $\frac{360}{360} \times 2\pi r = 2\pi r$ — the full circumference. The formula always works, even for the complete circle.
03

Perimeter of a Sector

A sector has three edges — two straight radii and one curved arc. The perimeter includes all three.

$$P = 2r + \ell = 2r + \frac{\theta}{360} \times 2\pi r$$
Most common error: Students calculate the arc length and write it as the "perimeter of the sector." The arc is only one of three edges. Write $P = 2r + \ell$ at the top of your working to commit to accounting for all three boundaries.
04

Composite Perimeters Involving Arcs

Many HSC problems combine straight sides and arcs. Trace the boundary, identify each edge, calculate each separately, then add.

Running Track Example

A rectangle with a semicircle on each short end. The outer perimeter consists of:

  • Two long straight sides of the rectangle
  • Two semicircular arcs — which together make one full circle
  • The short sides of the rectangle are NOT included — they are replaced by the semicircles (internal)
Efficiency trick: Two semicircles of the same radius = one full circle. Instead of calculating two separate semicircle arcs, find the circumference of one full circle: $2\pi r$. This saves a step and reduces rounding error.
Distinguish arc length from sector area:
Arc length → uses $2\pi r$ (circumference) → answer in linear units (cm, m)
Sector area → uses $\pi r^2$ (full circle area) → answer in square units (cm², m²)
If your "arc length" answer has square units, you used the wrong formula.
05

Common Mistakes

Mistake 1 — Only calculating the arc for a sector perimeter
A sector has three edges: arc + two radii. Write $P = 2r + \ell$ before calculating anything.
Mistake 2 — Including internal edges in a composite perimeter
Trace the boundary physically before writing numbers. Any edge shared between two joined shapes is interior — do not count it.
Mistake 3 — Confusing arc length formula with sector area formula
Both start with $\theta/360$. Arc length: multiply by $2\pi r$ (circumference) → linear units. Sector area: multiply by $\pi r^2$ (area) → square units. Check your answer's units to catch this error.
06
Worked Example 1
Arc Length of a Sector

Problem

Find the arc length of a sector with radius 9 cm and central angle 80°. Give your answer correct to 2 decimal places.

Step-by-Step Solution

1
Identify and write formula
$\ell = \dfrac{\theta}{360} \times 2\pi r$
Arc length question. $\theta = 80°$, $r = 9$ cm.
07
Worked Example 2
Perimeter of a Sector

Problem

Find the perimeter of a sector with radius 12 m and central angle 135°. Give your answer correct to 2 decimal places.

Step-by-Step Solution

1
Plan the calculation
$P = 2r + \ell$   (two radii + arc)
Write the plan first — commits you to all three boundary edges.
08
Worked Example 3
Composite Perimeter — Running Track

Problem

A running track consists of a rectangle 60 m long and 20 m wide, with a semicircle attached to each short end. Find the perimeter of the outside edge of the track correct to 2 decimal places.

Step-by-Step Solution

1
Trace the boundary — identify edges
2 long sides + 2 semicircular arcs
(short sides are interior — not included)
The semicircles replace the short ends. The two short sides of the rectangle are internal edges — they are not on the outer boundary.
09
Worked Example 4
Composite Perimeter — Square + Sector

Problem

A shape is formed by taking a square of side 10 cm and attaching a sector of radius 10 cm and angle 60° to one side. Find the perimeter of the composite shape correct to 2 decimal places.

Step-by-Step Solution

1
Trace and identify boundary edges:
Arc (sector) + two radii of sector + three sides of square
(fourth side of square = interior edge)
The sector attaches to one side of the square. That side is now interior. The two sector radii become new outer boundary edges.
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Perimeter and Arc Length Practice

For composite shapes, describe which edges form the boundary before calculating.

Section A — Arc Length

1 Find the arc length of a sector with $r = 6$ cm and $\theta = 90°$.

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2 Find the arc length of a sector with $r = 15$ m and $\theta = 120°$.

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3 Find the arc length of a sector with $r = 8$ cm and $\theta = 45°$. Answer to 2 decimal places.

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Section B — Perimeter of a Sector

4 Find the perimeter of a sector with $r = 10$ cm and $\theta = 90°$.

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5 Find the perimeter of a sector with $r = 7$ m and $\theta = 150°$. Answer to 2 decimal places.

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Section C — Composite Perimeter

6 A shape is made from a rectangle 8 cm × 5 cm with a semicircle of diameter 5 cm attached to one short end. Find the perimeter of the outside edge to 2 decimal places.

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7 A sector has radius 6 m and angle 240°. Find its perimeter to 2 decimal places.

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8 A quarter-circle of radius 4 cm is removed from the corner of a square of side 4 cm. Find the perimeter of the resulting shape to 2 decimal places.

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Show Answers

Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

1 A sector has radius 5 cm and central angle 72°. Its arc length is:

A   $2\pi$ cm
B   $4\pi$ cm
C   $5\pi$ cm
D   $10\pi$ cm

? Regarding this topic, 1 A sector has radius 5 cm and central angle 72°. Its arc length is:

A     $2\pi$ cm
B     $4\pi$ cm
C     $5\pi$ cm
D     $10\pi$ cm
A - Correct!
A — $\ell = \frac{72}{360} \times 2\pi \times 5 = \frac{1}{5} \times 10\pi = 2\pi$ cm.

2 A sector has radius 8 m and arc length 12 m. Its perimeter is:

A   12 m
B   20 m
C   28 m
D   192 m

? Regarding this topic, 2 A sector has radius 8 m and arc length 12 m. Its perimeter is:

A     12 m
B     20 m
C     28 m
D     192 m
C - Correct!
C — $P = 2r + \ell = 2 \times 8 + 12 = 16 + 12 = 28$ m. Option A gives only the arc — forgetting the two radii.

3 A rectangle (14 cm × 6 cm) has a semicircle of diameter 6 cm removed from one short end. The perimeter of the remaining shape is closest to:

A   34.42 cm
B   37.42 cm
C   43.42 cm
D   49.42 cm

? Regarding this topic, 3 A rectangle (14 cm × 6 cm) has a semicircle of diameter 6 cm removed from one short end. The perimeter of the remaining shape is closest to:

A     34.42 cm
B     37.42 cm
C     43.42 cm
D     49.42 cm
C - Correct!
C — Boundary: $2 \times 14 + 6 + \frac{1}{2} \times 2\pi \times 3 = 28 + 6 + 3\pi = 34 + 9.42 = 43.42$ cm. The short end where the semicircle was removed is replaced by the arc.
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SA 4 2 marks Find the arc length of a sector with radius 18 cm and central angle 40°. Give your answer correct to 2 decimal places.

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11

SA 5 3 marks Find the perimeter of a sector with radius 14 cm and central angle 225°. Give your answer correct to 2 decimal places.

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12

SA 6 4 marks A garden path is bounded by three straight sides (8 m, 5 m, and 8 m) and a curved arc on the fourth side. The arc is part of a circle with radius 5 m, centred at the midpoint of the 5 m side.

(a) Find the central angle of the arc.  (1 mark)

(b) Find the arc length correct to 2 decimal places.  (1 mark)

(c) Find the total perimeter correct to 2 decimal places.  (2 marks)

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Show Model Answers

Interactive

Sector Explorer — Arc Length & Sector Area

120°
8 cm
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Boss Battle

Boss Battle — Perimeter & Arc Length!

Face the boss using your knowledge of perimeter and arc length calculations. Pool: lessons 1–5.

Mark lesson complete

Tick when you have finished the lesson and checked your answers.