Volume of Prisms and Cylinders

Volume = cross-sectional area × length. Identify the uniform cross-section first — everything else follows. Unit conversions between cm³, m³, and litres are critical for practical problems.

55–60 min MS-M1 — MEDIUM 3 MC 3 SA Lesson 9 of 22 Free
📦

Choose how you work: type answers on screen, or work in your book.

Printable worksheet

Download this lesson's worksheet

Use the PDF for classwork, homework or revision. It includes key ideas, activities, questions, an extend task and success-criteria proof.

Think First

A swimming pool is 25 m long, 10 m wide, and has a depth that slopes from 1.2 m at the shallow end to 2.4 m at the deep end. How would you estimate how many litres of water it holds? What shape would you use, and why?

Type your initial response below — you will revisit this at the end of the lesson.

Write your initial response in your book. You will revisit it at the end of the lesson.

Write your initial thinking in your book
Saved

Come back to this at the end of the lesson.

📋

Volume Formulas — This Lesson

$V = Ah$
Any prism or cylinder — $A$ = area of uniform cross-section, $h$ = perpendicular length/height The cross-section is the shape you see when you "slice" perpendicular to the length
$V = \ell w h$
Rectangular prism (special case) — $\ell$ = length, $w$ = width, $h$ = height
$V = \pi r^2 h$
Cylinder (special case) — $r$ = radius, $h$ = height
$1 \text{ m}^3 = 1000 \text{ L}$
Unit conversion — also: $1 \text{ L} = 1000 \text{ cm}^3$, $1 \text{ kL} = 1 \text{ m}^3$ $1 \text{ cm}^3 = 1 \text{ mL}$
V = Ah — THE CROSS-SECTION RULE A h A V = A × h same cross-section throughout length VOLUME ↔ CAPACITY 1 m³ = 1000 L = 1 kL cubic metres → kilolitres 1 L = 1000 cm³ litres → cubic centimetres 1 cm³ = 1 mL cubic centimetre = millilitre

🧠 Know

  • $V = Ah$ applies to any prism or cylinder
  • The cross-section is the shape perpendicular to the length
  • Unit conversions: 1 m³ = 1000 L, 1 L = 1000 cm³
  • Composite volumes are found by addition or subtraction

💡 Understand

  • Why identifying the cross-section first simplifies every volume problem
  • How a trapezoidal prism models real-world sloped containers
  • Why unit consistency matters before substituting values

✅ Can Do

  • Calculate volume of rectangular prisms, triangular prisms, cylinders
  • Find volume of composite prisms by addition/subtraction
  • Convert between cm³, m³, and litres
  • Solve capacity/tank/pipe problems
📖

Key Terms

Volume The amount of three-dimensional space a solid occupies; measured in cubic units (mm³, cm³, m³)
Prism A solid with two identical parallel faces (the cross-sections) joined by rectangular faces
Cross-section The shape obtained by cutting a solid with a plane perpendicular to its length — must be uniform (constant) along a prism
Capacity The volume of liquid a container can hold; typically measured in litres (L) or kilolitres (kL)

Misconceptions to Fix

Wrong: A percentage over 100% is impossible.

Right: Percentages over 100% are valid and common in contexts like percentage increase, profit margins, and scale factors.

Key Point

Always check your units before substituting into formulas. Converting to consistent units is a common source of errors in assessment tasks.

Key Terms
and litrescritical for practical problems
swimming pool25 m long, 10 m wide, and has a depth that slopes from 1
sectionthe shape you see when you "slice" perpendicular to the length
Composite volumesfound by addition or subtraction
Converting to consistent unitsa common source of errors in assessment tasks
The keycorrectly identifying the cross-section

The Universal Rule: Volume = Area × Height

Every prism — regardless of its cross-sectional shape — has volume equal to the cross-sectional area multiplied by the perpendicular length.

The key is correctly identifying the cross-section. Ask: "If I sliced this solid perpendicular to its longest dimension, what shape would I see?" That area is $A$.

  • Rectangular prism: cross-section is a rectangle → $A = \ell w$, so $V = \ell w h$
  • Triangular prism: cross-section is a triangle → $A = \frac{1}{2}bh_{\triangle}$, then multiply by length $\ell$
  • Trapezoidal prism: cross-section is a trapezium → $A = \frac{1}{2}(a+b)h$, then multiply by length
  • Cylinder: cross-section is a circle → $A = \pi r^2$, then multiply by height
A = ½bh b h L V = A × L = ½bh × L
The orange face is the cross-section — find its area first, then multiply by L
Key insight: Label your cross-section dimensions separately from the prism length. A "height" can refer to two different things in the same problem.
Worked Example 1 Rectangular Prism

Problem

A fish tank is 80 cm long, 40 cm wide, and 35 cm deep. Find its volume in cm³ and capacity in litres.

Solution

1 $V = \ell w h = 80 \times 40 \times 35$ Rectangular prism formula; identify all three dimensions
Worked Example 2 Triangular Prism

Problem

A triangular prism has a right-triangular cross-section with base 6 cm and perpendicular height 4 cm. The prism is 15 cm long. Find its volume.

Solution

1 $A = \dfrac{1}{2} \times 6 \times 4 = 12 \text{ cm}^2$ Find the cross-sectional area first — a triangle with base 6, height 4

Volume of a Cylinder

A cylinder is just a circular prism. Its cross-section is always a circle, so $A = \pi r^2$ and the volume formula becomes $V = \pi r^2 h$.

  • If given the diameter $d$, find radius first: $r = d \div 2$
  • The "height" $h$ is the length along the axis of the cylinder
  • Hollow cylinders (pipes): subtract the inner cylinder's volume from the outer
Worked Example 3 Cylinder

Problem

A cylindrical water tank has diameter 1.4 m and height 2.2 m. Find its volume in m³ and capacity in kilolitres (kL).

Solution

1 $r = 1.4 \div 2 = 0.7 \text{ m}$ Always find radius from diameter first

Composite Volumes

A composite solid is built from two or more recognisable shapes. Identify each component, calculate its volume separately, then add (or subtract if one is removed/hollow).

Volume Unit Conversions
1 cm³1 mL
1 L1000 cm³
1 m³1000 L = 1 kL
1 m³1 000 000 cm³
Worked Example 4 Trapezoidal Prism

Problem

A swimming pool is 20 m long and 8 m wide. The depth slopes uniformly from 1.0 m at the shallow end to 2.5 m at the deep end. Find the volume in m³ and capacity in kL.

Solution

1 $A_{\text{cross}} = \dfrac{1}{2}(1.0 + 2.5) \times 20 = \dfrac{1}{2}(3.5)(20) = 35 \text{ m}^2$ The cross-section (viewed from the side) is a trapezium with parallel sides 1.0 m and 2.5 m, width 20 m
Practice

Practice Questions

Work through all questions. Use the collapsible answer panel to check your work.

Section A — Rectangular Prisms

  1. A brick is 22 cm × 11 cm × 7.5 cm. Find its volume in cm³.
  2. A rectangular storage container is 2.4 m long, 1.2 m wide, and 1.5 m high. Find its volume in m³.
  3. A rectangular tank holds 6000 L. Its base is 2.5 m × 1.2 m. Find its height in metres.

Section B — Triangular and Trapezoidal Prisms

  1. A triangular prism has a right-triangular cross-section with legs 5 cm and 8 cm. The prism is 20 cm long. Find its volume.
  2. A concrete ramp (trapezoidal cross-section) has parallel depths of 0.3 m and 0.8 m, width 4 m, and length 6 m. Find the volume of concrete needed.
  3. A swimming pool has trapezoidal cross-section with parallel sides 1.2 m and 2.0 m, horizontal length 25 m, and width 10 m. Find the capacity in kL.

Section C — Cylinders and Conversions

  1. A can has radius 4 cm and height 12 cm. Find its volume, giving your answer in terms of $\pi$ and as a decimal (cm³).
  2. A cylindrical fuel drum has diameter 0.6 m and height 1.0 m. Find its capacity in litres (correct to nearest litre).
  3. A pipe has outer radius 8 cm, inner radius 6 cm, and length 50 cm. Find the volume of metal in the pipe in cm³ (leave in terms of $\pi$).
  4. Convert 0.0025 m³ to litres.
  5. Convert 85 000 cm³ to litres.
  6. A tank holds 4.5 kL. Express this in cm³.

Q1

$22 \times 11 \times 7.5 = \mathbf{1815 \text{ cm}^3}$

Q2

$2.4 \times 1.2 \times 1.5 = \mathbf{4.32 \text{ m}^3}$

Q3

$6000 \text{ L} = 6 \text{ m}^3$; $h = 6 \div (2.5 \times 1.2) = 6 \div 3 = \mathbf{2 \text{ m}}$

Q4

$A = \frac{1}{2}(5)(8) = 20$; $V = 20 \times 20 = \mathbf{400 \text{ cm}^3}$

Q5

$A = \frac{1}{2}(0.3+0.8)(4) = \frac{1}{2}(1.1)(4) = 2.2$; $V = 2.2 \times 6 = \mathbf{13.2 \text{ m}^3}$

Q6

$A = \frac{1}{2}(1.2+2.0)(25) = \frac{1}{2}(3.2)(25) = 40$; $V = 40 \times 10 = 400 \text{ m}^3 = \mathbf{400 \text{ kL}}$

Q7

$V = \pi(4)^2(12) = 192\pi \approx \mathbf{603.19 \text{ cm}^3}$

Q8

$r = 0.3$; $V = \pi(0.09)(1.0) = 0.09\pi \approx 0.2827 \text{ m}^3 = \mathbf{283 \text{ L}}$

Q9

$V = \pi(8^2 - 6^2)(50) = \pi(64-36)(50) = \pi(28)(50) = \mathbf{1400\pi \text{ cm}^3}$

Q10

$0.0025 \times 1000 = \mathbf{2.5 \text{ L}}$

Q11

$85\,000 \div 1000 = \mathbf{85 \text{ L}}$

Q12

$4.5 \text{ kL} = 4.5 \text{ m}^3 = 4.5 \times 10^6 \text{ cm}^3 = \mathbf{4\,500\,000 \text{ cm}^3}$

Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

1 A triangular prism has a cross-section that is a right-angled triangle with legs 3 m and 4 m. The prism is 10 m long. Its volume is:

A   48 m³
B   60 m³
C   120 m³
D   240 m³

? Regarding this topic, 1 A triangular prism has a cross-section that is a right-angled triangle with legs 3 m and 4 m. The prism is 10 m long. Its volume is:

A     48 m³
B     60 m³
C     120 m³
D     240 m³
B - Correct!
B — $A = \frac{1}{2}(3)(4) = 6 \text{ m}^2$; $V = 6 \times 10 = 60 \text{ m}^3$.

2 A cylinder has diameter 1.2 m and height 0.8 m. Its volume in litres (to the nearest litre) is:

A   905 L
B   3619 L
C   452 L
D   724 L

? Regarding this topic, 2 A cylinder has diameter 1.2 m and height 0.8 m. Its volume in litres (to the nearest litre) is:

A     905 L
B     3619 L
C     452 L
D     724 L
A - Correct!
A — $r = 0.6$; $V = \pi(0.36)(0.8) = 0.288\pi \approx 0.9047 \text{ m}^3 = 905 \text{ L}$.

3 A trough has a trapezoidal cross-section with parallel sides 0.4 m and 0.6 m, and a perpendicular height of 0.3 m. The trough is 2 m long. Its capacity in litres is:

A   120 L
B   240 L
C   300 L
D   600 L

? Regarding this topic, 3 A trough has a trapezoidal cross-section with parallel sides 0.4 m and 0.6 m, and a perpendicular height of 0.3 m. The trough is 2 m long. Its capacity in litres is:

A     120 L
B     240 L
C     300 L
D     600 L
C - Correct!
C — $A = \frac{1}{2}(0.4+0.6)(0.3) = 0.15 \text{ m}^2$; $V = 0.15 \times 2 = 0.3 \text{ m}^3 = 300 \text{ L}$.
01

SA 4 3 marks A concrete retaining wall has a trapezoidal cross-section with parallel sides of 0.5 m and 0.8 m, a perpendicular height of 1.2 m, and a length of 15 m.

(a) Find the area of the trapezoidal cross-section.  (1 mark)

(b) Find the volume of concrete required in m³.  (1 mark)

(c) Concrete costs $\$220$ per m³. Find the cost of the concrete.  (1 mark)

Work in your book
Saved

(a)

$A = \frac{1}{2}(0.5+0.8)(1.2) = \frac{1}{2}(1.3)(1.2) = \mathbf{0.78 \text{ m}^2}$

(b)

$V = 0.78 \times 15 = \mathbf{11.7 \text{ m}^3}$

(c)

$\text{Cost} = 11.7 \times 220 = \mathbf{\$2574}$

02

SA 5 3 marks A cylindrical rainwater tank has an internal diameter of 2.4 m and a height of 3.0 m.

(a) Find the volume of the tank in m³ (correct to 2 decimal places).  (2 marks)

(b) Find the capacity in kilolitres.  (1 mark)

Work in your book
Saved

(a)

$r = 1.2$; $V = \pi(1.2)^2(3.0) = \pi(1.44)(3) = 4.32\pi \approx \mathbf{13.57 \text{ m}^3}$

(b)

$\mathbf{13.57 \text{ kL}}$ (since $1 \text{ m}^3 = 1 \text{ kL}$)

03

SA 6 4 marks A garden bed has a composite cross-section consisting of a rectangle (1.2 m wide, 0.4 m deep) sitting on top of a trapezium (parallel sides 1.2 m and 2.0 m, height 0.3 m). The garden bed is 8 m long.

(a) Find the area of the trapezoidal portion.  (1 mark)

(b) Find the total cross-sectional area.  (1 mark)

(c) Find the total volume of soil required in m³.  (1 mark)

(d) Soil is sold in bags of 0.1 m³. How many bags are needed?  (1 mark)

Work in your book
Saved

(a)

$A_{\text{trap}} = \frac{1}{2}(1.2+2.0)(0.3) = \frac{1}{2}(3.2)(0.3) = \mathbf{0.48 \text{ m}^2}$

(b)

$A_{\text{rect}} = 1.2 \times 0.4 = 0.48$; Total $= 0.48 + 0.48 = \mathbf{0.96 \text{ m}^2}$

(c)

$V = 0.96 \times 8 = \mathbf{7.68 \text{ m}^3}$

(d)

$7.68 \div 0.1 = 76.8$ → round up → $\mathbf{77 \text{ bags}}$

Consolidation Game

Volume of Prisms and Cylinders