Logarithmic Scales
A logarithmic scale replaces a range that spans billions with one that fits on a ruler. The cost is that equal steps no longer mean equal amounts, and if you forget that, the numbers mislead you badly.
The quietest sound a person can hear and the sound of a jet engine differ in intensity by a factor of about $10^{12}$, a million million. If you drew that on ordinary graph paper with the quietest sound $1$ mm from the origin, how far away would the jet engine be? Give your answer in kilometres, and then say what you would do about it.
On an ordinary scale equal steps mean equal differences: $10, 20, 30$. On a logarithmic scale equal steps mean equal RATIOS: $10, 100, 1000$. Because a logarithm converts multiplication into addition, a quantity that multiplies by a fixed factor moves a fixed distance along the axis.
$$\text{scale reading} = \log_{10}\left(\frac{\text{quantity}}{\text{reference}}\right)$$
So a difference of $1$ on almost any base-ten logarithmic scale means a factor of $10$ in the thing being measured, a difference of $2$ means a factor of $100$, and a difference of $n$ means a factor of $10^{n}$. Reading the difference and then raising ten to it is the whole technique.
Know
- That a logarithmic scale is defined by $\log_{10}$ of a ratio to a reference value
- That pH, the Richter magnitude and the decibel scale are all logarithmic
- That a difference of $d$ on a base-ten scale means a factor of $10^{d}$
Understand
- Why a logarithmic scale compresses an enormous range into a readable one
- Why equal steps on such a scale are equal ratios, not equal amounts
Can Do
- Convert between a scale reading and the quantity it represents
- Compare two readings by finding the ratio of the quantities
- Explain, in context, why a logarithmic scale was chosen
Audible sound intensity runs from about $10^{-12}$ watts per square metre at the threshold of hearing to about $1$ at the threshold of pain. That is a range of $10^{12}$ to one.
On a linear axis at $1$ mm for the quietest sound, the loudest would sit $10^{12}$ mm away, which is a million kilometres. No graph, ruler or dial can carry that.
Taking logarithms turns the range $10^{-12}$ to $1$ into the range $-12$ to $0$. Multiply by $10$ and shift, and you get the familiar decibel scale from $0$ to $120$: a number you can print on a dial.
Because $\log_{10} A - \log_{10} B = \log_{10}\left(\dfrac{A}{B}\right)$, subtracting two readings gives the logarithm of the ratio. Undo that logarithm and you have the ratio itself.
$$\frac{A}{B} = 10^{\,d} \quad \text{where } d \text{ is the difference in readings}$$
Two earthquakes measuring $7.0$ and $5.0$ differ by $d = 2$, so the ground moves $10^{2} = 100$ times as far in the larger one. A lemon at pH $2$ and black coffee at pH $5$ differ by $3$, so the lemon has $10^{3} = 1000$ times the hydrogen ion concentration.
Notice this is just the quotient law from Lesson 3, doing exactly what it was derived to do.
pH. $\text{pH} = -\log_{10}[\text{H}^{+}]$. The minus sign is there because the concentrations are tiny, so their logarithms are negative and the sign makes the readings positive. Because of it, a LOWER pH means a HIGHER concentration.
Richter magnitude. $+1$ in magnitude means ten times the amplitude of ground movement. Released energy grows faster still, by a factor of about $31.6$, which is $10^{1.5}$, for each whole step.
Decibels. $L = 10\log_{10}\left(\dfrac{I}{I_0}\right)$, with $I_0 = 10^{-12}$ W/m². The factor of $10$ in front means that $+10$ dB, not $+1$ dB, corresponds to ten times the intensity.
From quantity to reading. A solution has $[\text{H}^{+}] = 10^{-4}$ mol/L. Then $\text{pH} = -\log_{10}(10^{-4}) = -(-4) = 4$.
From reading to quantity. A solution has pH $9$. Then $-\log_{10}[\text{H}^{+}] = 9$, so $\log_{10}[\text{H}^{+}] = -9$ and $[\text{H}^{+}] = 10^{-9}$ mol/L.
Comparing two. Milk at pH $6.5$ and lemon juice at pH $2.5$ differ by $4$, so the lemon juice has $10^{4} = 10\,000$ times the hydrogen ion concentration.
Every one of these is Lesson 5's method: to undo a logarithm, raise ten to both sides.
Watch Me Solve It · 3 examples
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1Find the difference in readings$d = 9.0 - 5.6 = 3.4$On a logarithmic scale the difference is what carries the information.
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2Turn the difference into a ratio$\frac{A_1}{A_2} = 10^{\,3.4}$Because $\log_{10} A_1 - \log_{10} A_2 = \log_{10}\left(\dfrac{A_1}{A_2}\right)$, by the quotient law.
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3Evaluate$10^{3.4} \approx 2512$
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4State it in context$\text{about } 2500 \text{ times the amplitude}$A difference of 3.4 on the scale is a factor of thousands, not a factor of two.
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1Write the definition$\text{pH} = -\log_{10}[\text{H}^{+}] = 8.4$
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2Remove the minus sign$\log_{10}[\text{H}^{+}] = -8.4$Multiply both sides by $-1$.
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3Undo the logarithm$[\text{H}^{+}] = 10^{-8.4}$Raise ten to both sides, exactly as in Lesson 5.
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4Evaluate and check the size$10^{-8.4} \approx 4.0 \times 10^{-9} \text{ mol/L}$It lies between $10^{-9}$ and $10^{-8}$, as a pH between 8 and 9 requires.
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1Write the formula$L = 10\log_{10}\left(\frac{I}{I_0}\right)$The leading 10 is the part most often dropped.
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2Subtract the two readings$70 - 60 = 10\log_{10}\left(\frac{I_1}{I_0}\right) - 10\log_{10}\left(\frac{I_2}{I_0}\right)$
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3Simplify with the quotient law$10 = 10\log_{10}\left(\frac{I_1}{I_2}\right)$$\log_{10}\left(\frac{I_1}{I_2}\right) = 1$The reference $I_0$ cancels, which is why only the difference matters.
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4Undo the logarithm$\frac{I_1}{I_2} = 10^{1} = 10$So $+10$ dB is ten times the intensity, not $+1$ dB.
Brain Trainer · 4 problems
Four quick problems. Work each one, then reveal the answer.
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1 Two earthquakes measure $6.0$ and $4.0$. How many times greater is the amplitude of the larger?
Difference $2$, so the ratio is $10^{2}$.$100$ times -
2 A solution has $[\text{H}^{+}] = 10^{-3}$ mol/L. Find its pH.
$\text{pH} = -\log_{10}(10^{-3}) = 3$.pH $3$ -
3 Sound A is $1000$ times as intense as sound B. What is the difference in decibels?
$10\log_{10}(1000) = 10 \times 3$.$30$ dB -
4 Solution X has pH $4$ and solution Y has pH $7$. Which is more acidic, and by what factor in $[\text{H}^{+}]$?
Lower pH means more acidic; the difference of $3$ gives $10^{3}$.X, by $1000$ times
Multiple Choice · 5 questions
On a base-ten logarithmic scale, an increase of $1$ in the reading corresponds to:
An earthquake of magnitude $7$ has ground amplitude how many times that of one of magnitude $4$?
A solution of pH $3$ compared with one of pH $6$ has a hydrogen ion concentration that is:
Sound intensity increases by a factor of $100$. The increase in the decibel reading is:
The main reason scientists use a logarithmic scale for quantities like sound intensity is that it:
Short Answer · 3 questions
(a) Vinegar has $[\text{H}^{+}] = 10^{-2.9}$ mol/L. Find its pH.
(b) Seawater has pH $8.1$. Find $[\text{H}^{+}]$ in scientific notation to two significant figures.
(c) How many times greater is the hydrogen ion concentration in vinegar than in seawater?
(a) State this range as a single ratio.
(b) Explain, with reference to a specific difficulty, why a linear scale is unusable here.
(c) Show how the decibel definition $L = 10\log_{10}\left(\dfrac{I}{I_0}\right)$ with $I_0 = 10^{-12}$ turns this range into $0$ to $120$.
(a) Explain what is wrong with this reasoning.
(b) State the actual ratio of ground amplitudes.
(c) Given that released energy scales as $10^{1.5}$ per whole step of magnitude, find the ratio of released energies and comment on whether the report is defensible.
(a) State this range as a ratio, and say how many orders of magnitude it spans.
(b) Design a logarithmic "bioscale" that reads $0$ for a bacterium and $100$ for a blue whale. Give its formula.
(c) Find the bioscale reading for a $70$ kg human, and state what a difference of $10$ on your scale means in kilograms.
Equal steps
Equal ratios, not equal amounts
Difference $d$
Quantity ratio $10^{d}$
pH
$-\log_{10}[\text{H}^{+}]$; lower pH is more acidic
Decibels
$10\log_{10}\left(\dfrac{I}{I_0}\right)$; $+10$ dB is ten times
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