What Is a Polynomial
Nothing here is a new kind of expression. Every quadratic you have expanded and every cubic you have substituted into was already a polynomial. What is new is one precise rule for membership, and the vocabulary that lets you say something about all of them at once.
Write down the expression $4x^3 - x + 9$. Now write $4x^3 - x^{-1} + 9$. The two differ by a single minus sign in an exponent. One of them can be evaluated at every real number and the other cannot. Which is which, and what goes wrong at $x = 0$?
A polynomial in $x$ is a sum of terms of the form a real number times a whole-number power of $x$. That is the whole definition. Everything else in this focus area is vocabulary for describing one, or a technique for taking one apart.
$$P(x) = a_n x^n + a_{n-1}x^{n-1} + \cdots + a_1 x + a_0$$
Read the definition backwards to test an expression. Every power of $x$ must be a whole number, zero included. No $x$ in a denominator, none under a root sign, none in an exponent, none inside absolute value bars. If any term breaks that, the whole expression is not a polynomial.
Know
- The definition of a polynomial in $x$, and which expressions it excludes
- The meaning of degree, leading term, coefficient, leading coefficient and constant term
- That a monic polynomial is one whose leading coefficient is $1$
Understand
- Why the restriction to whole-number powers is what makes the whole topic work
- Why degree is the single most useful number attached to a polynomial
Can Do
- Decide whether a given expression is a polynomial, with a reason
- State the degree, leading term, leading coefficient and constant term of any polynomial
- Classify a polynomial as monic or non-monic
A polynomial in $x$ is any expression that can be written as
$$P(x) = a_n x^n + a_{n-1}x^{n-1} + \cdots + a_1 x + a_0$$
where $n$ is a whole number and $a_0, a_1, \ldots, a_n$ are real numbers. Two conditions are doing all the work: the powers of $x$ are whole numbers, and the coefficients are ordinary real numbers.
So these are polynomials:
$$x^2 + 3x, \qquad 7 - 2x^5, \qquad 5, \qquad 0, \qquad \tfrac{2}{3}x^3 - \sqrt{2}\,x$$
The last two are worth a look. A plain number like $5$ is a polynomial, because $5 = 5x^0$ and $0$ is a whole number. And $\sqrt{2}$ is fine as a coefficient: the rule restricts the powers of $x$, not the numbers in front.
These are not polynomials:
$$\frac{1}{x} = x^{-1}, \qquad \sqrt{x} = x^{1/2}, \qquad 2^x, \qquad |x|, \qquad \frac{x+1}{x-3}$$
Each fails the same test once rewritten. A negative power, a fractional power, the variable in the exponent, a shape that no single power produces, and a variable in a denominator.
The degree of a polynomial is the highest power of $x$ appearing with a non-zero coefficient. Write the polynomial in descending powers and it is the first exponent you see.
$$P(x) = 3x^4 - 5x^2 + 7x - 2 \quad \text{has degree } 4$$
Degree is not just a label. It controls almost everything you will meet later: how many zeroes the polynomial can have, how many times its graph can turn, what happens far out to the left and right, and how long a division will take. Low degrees have names you already use:
degree $0$ is a non-zero constant, degree $1$ is linear, degree $2$ is quadratic, degree $3$ is cubic, degree $4$ is quartic.
Two edge cases are worth settling now. A non-zero constant such as $5$ has degree $0$, since $5 = 5x^0$. The zero polynomial $P(x) = 0$ is given no degree at all, because there is no non-zero coefficient to point at. That sounds like pedantry until Lesson 3, where the degree of a product is the sum of the degrees, and the zero polynomial would break the rule.
Take $P(x) = 3x^4 - 5x^2 + 7x - 2$ and name every part.
The leading term is $3x^4$, the term of highest degree. Its coefficient, $3$, is the leading coefficient. The constant term is $-2$, the term with no $x$.
The coefficient of $x^2$ is $-5$, not $5$. A coefficient carries the sign of its term, and losing that sign is the single most common slip in this topic.
Two more traps. The coefficient of $x^3$ here is $0$, because no $x^3$ term is written; a missing term is a zero coefficient, not an absent one, which will matter enormously when you set up a division in Lesson 5. And the coefficient of $x$ is $7$, since $7x$ means $7x^1$.
Writing out every power, including the ones with coefficient zero, gives
$$P(x) = 3x^4 + 0x^3 - 5x^2 + 7x - 2$$
which is the same polynomial, written in the form that makes every coefficient visible.
A polynomial is monic when its leading coefficient is exactly $1$.
$$x^3 - 4x + 1 \quad \text{is monic} \qquad 2x^3 - 4x + 1 \quad \text{is not}$$
Three things people get wrong about this word:
It is about the leading coefficient only. $x^3 + 6x^2 - 11$ is monic even though $6$ and $-11$ are nowhere near $1$.
A leading coefficient of $-1$ makes it non-monic. $-x^2 + 3$ has leading coefficient $-1$, and $-1 \neq 1$.
Monic is not a property of the polynomial's value. $2x + 2$ is non-monic, even though it factors as $2(x+1)$ where $x + 1$ is monic. Dividing out the leading coefficient always produces a monic polynomial, and that is a genuinely useful move, but it changes the polynomial rather than revealing that it was monic all along.
Watch Me Solve It · 3 examples
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1(a) Check the powers, not the numbers$4x^3 - \sqrt{5}x^0$The powers are $3$ and $0$, both whole numbers. An irrational coefficient is allowed. It is a polynomial.
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2(b) Rewrite the awkward term as a power$\frac{2}{x} = 2x^{-1}$The power $-1$ is not a whole number, so it is not a polynomial.
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3(c) Split the fraction$\frac{x^3 - 1}{4} = \tfrac{1}{4}x^3 - \tfrac{1}{4}$Dividing by a number is multiplying by a number. The powers are $3$ and $0$, so it is a polynomial.
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4(d) Read the fractional index$x^{1/3} = \sqrt[3]{x}$$\tfrac{1}{3}$ is not a whole number, so it is not a polynomial.
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1Reorder into descending powers$P(x) = x^5 - 2x^3 - 4x + 6$Nothing can be named safely until the terms are in order.
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2Fill in the missing powers explicitly$P(x) = x^5 + 0x^4 - 2x^3 + 0x^2 - 4x + 6$Now every coefficient is visible, including the zeros.
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3Read off the namesDegree $5$; leading term $x^5$; leading coefficient $1$; constant term $6$; coefficient of $x^2$ is $0$.
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4Decide monic or notThe leading coefficient is $1$, so $P$ is monic. The $6$ and the $-4$ are irrelevant to that.
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1Start from the degree$P(x) = ax^3 + bx^2 + cx + d$Degree $3$ means the $x^3$ coefficient is non-zero, so $a \neq 0$.
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2Apply each condition to a coefficient$d = -7, \quad c = 0, \quad a \neq 1$Constant term fixes $d$; the coefficient of $x$ fixes $c$; non-monic rules out $a = 1$ only.
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3Choose the free values$P(x) = 2x^3 + 5x^2 - 7$Taking $a = 2$ and $b = 5$ satisfies every condition. Any $a \neq 0, 1$ and any $b$ would do.
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4Count the answersInfinitely many, since $a$ can be any real number except $0$ and $1$, and $b$ can be anything at all. Four conditions cannot pin down four coefficients when two of them are inequalities rather than equations.
Brain Trainer · 5 problems
Five quick items on the definition and the vocabulary. Work each one, then reveal the answer.
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1 Is $5x^2 - \dfrac{3}{x^2}$ a polynomial?
The second term is $-3x^{-2}$, and $-2$ is not a whole number.No -
2 State the degree and leading coefficient of $8 - 3x^4 + x$.
Reorder: $-3x^4 + x + 8$.Degree $4$, leading coefficient $-3$ -
3 What is the coefficient of $x^3$ in $x^5 - 2x^2 + 6$?
No $x^3$ term is written, so its coefficient is zero.$0$ -
4 Is $-x^7 + x$ monic?
Its leading coefficient is $-1$, and monic requires exactly $+1$.No -
5 What is the degree of the constant polynomial $P(x) = 12$?
$12 = 12x^0$, so the highest power present is zero.$0$
Multiple Choice · 5 questions
An expression is a polynomial in $x$ exactly when:
The degree of $P(x) = 9 - x^2 + 4x^6 - x^3$ is:
In $P(x) = 2x^4 - 7x^3 + x - 5$, the coefficient of $x^3$ is:
Which of these is monic?
Which statement is TRUE?
Short Answer · 3 questions
(a) $\dfrac{2x^4 - x}{5}$
(b) $3x^2 - 4x^{-1} + 1$
(c) $(x+2)(x-3)$
(d) $\sqrt{7}x^3 + \pi$
(e) $\dfrac{5}{x^2 + 1}$
(a) Write $P(x)$ in descending powers of $x$.
(b) State the degree, the leading term, the leading coefficient and the constant term.
(c) State the coefficient of $x^3$ and explain why the answer is not "there isn't one".
(d) Is $P$ monic? Justify your answer, and state what would have to change for it to become monic.
(b) Write a polynomial of degree $2$ that is not monic and has no constant term.
(c) Explain why there is no polynomial of degree $2$ whose leading coefficient is $0$.
(d) A student claims that $x^2 + 3$ and $2x^2 + 6$ must both be monic "because one is twice the other". Explain what has gone wrong.
(a) Give a value of $x$ at which $x^2 + 3x + 1$ can be evaluated but $x^{-1} + 3x + 1$ cannot, and explain why no polynomial ever has this problem.
(b) A student suggests allowing infinitely many terms, so that $1 + x + x^2 + x^3 + \cdots$ counts as a polynomial. Give one property from this lesson that would stop making sense, and say why.
(c) The sum of two polynomials of degree $4$ can have degree less than $4$. Give an example, state the smallest degree the sum can have, and explain why the product of two degree-$4$ polynomials can never behave the same way.
The rule
Every power of $x$ is a whole number
Degree
The highest power present, read after reordering
Coefficients
Carry their sign; a missing term means zero
Monic
Leading coefficient exactly $1$
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