Review of Algebraic Expressions
Three tools, one toolbox, collect like terms, substitute values, and apply BIDMAS. You'll lean on these in every lesson this unit.
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Before you read on, if $a = 3$ and $b = 5$, what is the value of $2a + 3b - a$? Try it in your head, then note which order you did the operations in.
Algebra is shorthand for "do this with a number whatever the number turns out to be." When you write $3x$ you're saying "three of whatever $x$ is." The rest of the lesson is just three small tools, see below.
Every problem in this unit is just three small moves: combine like terms, substitute letters with numbers, and follow BIDMAS for order.
Know
- What an expression is vs an equation
- Term, coefficient, variable, constant
- The BIDMAS order of operations
Understand
- Why only like terms can combine
- Why $(-3)^2 = 9$, not $-9$
- Why brackets matter in substitution
Can Do
- Simplify by collecting like terms
- Substitute values, including negatives
- Evaluate with correct BIDMAS order
Wrong: "$3x + 5y$ simplifies to $8xy$."
Right: $3x$ and $5y$ are NOT like terms. They stay separate: $3x + 5y$ is already in simplest form.
Wrong: "If $x = -3$, then $x^2 = -9$."
Right: $(-3)^2 = (-3) \times (-3) = +9$. A negative times a negative is positive.
Every algebraic expression is built from terms, joined by $+$ or $-$ signs. Each term has up to three parts you need to recognise on sight.
An expression is a math phrase with no equals sign. It describes a value rather than asserting one. Each term is a block. Each block has a coefficient, a variable, or is a plain constant.
EXPRESSION
Knowing the parts by name makes everything easier. When a question says "find the coefficient of $x$" or "substitute $x = 4$", you'll know exactly where to look.
Two terms are like terms when they share exactly the same letters raised to exactly the same powers. Coefficients don't have to match, only the letter-and-power signature does. Sort the like terms together, then sum.
Sort terms into letter groups. Inside each group, add (or subtract) the coefficients. Groups with different letters stay apart they're already in simplest form.
- $3x$ and $7x$, like ✓ (both $x^1$)
- $5a^2$ and $-2a^2$, like ✓ (both $a^2$)
- $3x$ and $3y$, not like ✗ (different letters)
- $4x$ and $4x^2$, not like ✗ (different powers)
When collecting, simply add or subtract the coefficients and keep the letter-part the same:
$$3x + 7x = 10x \qquad 5a - 2a = 3a \qquad 4x + 3y + 2x = 6x + 3y$$
Substitution means replacing each variable with a given number, then evaluating. Golden rule: always use brackets when substituting, especially around negatives.
Wherever you see a letter, write its number in brackets. Then evaluate the resulting number-only expression using BIDMAS. Brackets are your insurance policy against sign errors.
Worked example: if $x = 4$ and $y = -2$, find the value of $3x + 2y$.
When an expression has more than one operation, the answer depends on which one you do first. BIDMAS is the order, and when two operations share a priority, work left to right.
Climb the ladder from the top: B rackets, then I ndices, then D iv/M ult, then A dd/S ub. Same priority? Left to right. Most mistakes come from forgetting that.
The full ladder same as the mini above, with the example operations spelt out:
Example: evaluate $2 + 3 \times 4^2$.
$$2 + 3 \times 4^2 = 2 + 3 \times 16 \;\text{(indices)} = 2 + 48 \;\text{(mult)} = 50$$
Watch Me Solve It · 3 examples
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1Group like terms$(5a - 2a) + (3b + 7b)$Bring the $a$-terms together and the $b$-terms together, never mix letters when combining.
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2Combine coefficients$= 3a + 10b$$5 - 2 = 3$ and $3 + 7 = 10$. Keep the letter part the same.
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3Check it's simplest form$3a + 10b$ ✓Each letter appears once, nothing left to combine.
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1Substitute with brackets$2(5)^2 - 3(-3)$Brackets around $-3$ save you from sign errors.
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2Apply indices (BIDMAS)$2(25) - 3(-3)$Indices come before multiplication, so $5^2$ first.
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3Multiply then add$= 50 - (-9) = 50 + 9 = 59$Subtracting a negative becomes adding.
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1Set up perimeter formula$P = 2(3x + 2) + 2(2x - 1)$Perimeter = 2 × length + 2 × width.
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2Expand brackets$P = 6x + 4 + 4x - 2$Multiply each term inside by the 2 outside.
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3Collect like terms$P = 10x + 2$$x$-terms together: $6x + 4x = 10x$. Constants: $4 - 2 = 2$.
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4Substitute $x = 4$$P = 10(4) + 2 = 42$ cmNow we have a number-only expression, evaluate it.
Definitions
- Expression, math phrase, no equals sign
- Term, block separated by + or −
- Coefficient, number multiplying the variable
- Constant, plain number, no variable
Like Terms Rule
- Same letter AND same power → combine
- $3x + 7x = 10x$
- $5a^2 - 2a^2 = 3a^2$
- $3x + 5y$ stays as $3x + 5y$
Substitution
- Use brackets around negatives
- $(-3)^2 = 9$, not $-9$
- Replace every instance of each letter
BIDMAS Order
- Brackets → Indices → ×÷ → +−
- Same priority = left to right
- $10 - 5 + 2 = 7$, not $3$
How are you completing this lesson?
Brain Trainer · 4 problems
Four problems mixing all three tools. Work each one, then reveal the answer to check.
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1 Simplify $7a + 4b - 3a + 6b - 2a$.
Group $a$-terms and $b$-terms: $(7a - 3a - 2a) + (4b + 6b)$$= 2a + 10b$ -
2 If $x = -2$ and $y = 5$, evaluate $x^2 - 2y$.
Substitute with brackets: $(-2)^2 - 2(5)$$= 4 - 10 = -6$ -
3 Evaluate $20 - 6 \div 2 + 3 \times 4$.
Division and multiplication first (left to right): $20 - 3 + 12$$= 17 + 12 = 29$ -
4 If $m = 3$ and $n = -4$, find $2m^2 + 3mn$.
$2(3)^2 + 3(3)(-4) = 2(9) + (-36)$$= 18 - 36 = -18$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Simplify $9p - 2q + 4p + 7q - 5p$.
Q7. If $m = 5$ and $n = -2$, evaluate: (a) $m^2 + n^2$ (b) $3mn - 2m$.
Q8. A rectangle has length $(3x + 2)$ cm and width $(2x - 1)$ cm. (a) Write a simplified expression for the perimeter. (b) Find the perimeter when $x = 4$.
Multiple Choice
1. C$7m$ and $-2m$ share variable $m$ to the same power.
2. A$(8x-5x)+(3y+2y) = 3x + 5y$.
3. B$3(4) - 2(-2) = 12 + 4 = 16$. Subtracting a negative adds.
4. A$(2x^2 - 3x^2) + (5x + 2x) = -x^2 + 7x$.
5. A$(-3)^2 - 2(-3)(2) = 9 + 12 = 21$.
Short Answer Model Answers
Q6 (2 marks): $(9p + 4p - 5p) + (-2q + 7q) = 8p + 5q$. [1 grouping, 1 answer]
Q7 (3 marks): (a) $5^2 + (-2)^2 = 25 + 4 = 29$ [1]. (b) $3(5)(-2) - 2(5)$ [1] $= -30 - 10 = -40$ [1].
Q8 (3 marks): (a) $P = 2(3x+2) + 2(2x-1) = 6x+4+4x-2$ [1] $= 10x + 2$ [1]. (b) $P = 10(4) + 2 = 42$ cm [1].
The Hidden Substitution
The identity $a^2 + 2ab + b^2 = (a + b)^2$ is worth memorising. Use it to evaluate $97^2$ without a calculator. Hint: let $a = 100$ and $b = -3$.
Reveal solution
$97^2 = (100 - 3)^2 = 100^2 + 2(100)(-3) + (-3)^2 = 10\,000 - 600 + 9 = 9409$.
Like Terms
Same letter, same power
Collecting
Add/subtract coefficients only
Substitute
Brackets around negatives
$(-x)^2$
Always positive
BIDMAS
B · I · DM · AS, left to right
Same priority
Work L → R
Interactive: Expression Simplifier
Practise collecting like terms and substituting values until it's automatic.
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