Mathematics • Year 7 • Unit 3 • Lesson 19

Constructions: Bisecting Angles and Lines

Build fluency with the three classical constructions: perpendicular bisector of a segment, angle bisector, and perpendicular from a point to a line. Two tools only: a straight-edge and a pair of compasses. Do the constructions on paper, describe them clearly in writing on this worksheet.

Build · I Do / We Do / You Do

1. I do, fully worked example

Read every line. Each step shows why the construction works.

Problem. Describe the four steps for constructing the perpendicular bisector of a segment AB, and explain why the construction works.

A B perp. bisector
Equal arcs from A and B meet at points equidistant from both ends, so the line through them is the perpendicular bisector.

Step 1, Set the compass radius.

Open the compass to MORE than half the length of AB. (About 3/4 of AB is safe.)

Reason: if the radius is less than half AB, the arcs from A and B won't reach each other and won't intersect.

Step 2, Arcs from A.

Place compass point on A. Draw an arc above AB and a second arc below AB.

Reason: every point on these arcs is the same distance (the radius) from A.

Step 3, Arcs from B (same radius, don't change the compass!).

Move compass point to B. Draw arcs above and below that CROSS the first two arcs.

Reason: every point on these arcs is the same distance from B. The two crossing points are therefore equidistant from BOTH A and B.

Step 4, Join the two crossings.

Use the straight-edge to draw a line through both intersection points.

Reason: every point on this line is equidistant from A and B. That's the definition of a perpendicular bisector, and the line crosses AB at right angles through the midpoint.

Answer: Set radius wider than half AB → arc from A above and below → arc from B above and below (same radius) → join the two crossings.

Stuck? Revisit lesson § Card 4 "Construct the Perpendicular Bisector", keep the compass radius CONSTANT between the A-arcs and the B-arcs.

2. We do, fill in the missing steps

Same structure as Section 1, with the working faded. Fill in each blank. 4 marks

Problem. Describe the five steps to construct the bisector of an angle ∠ABC (vertex at B).

Step 1, Centre on the vertex. Place the compass point at _______ . Choose any radius.

Step 2, Arc across both arms. Draw an arc that crosses BOTH sides of the angle. Label the crossing on BA as _______ and the crossing on BC as _______ .

Step 3, Arc from P. WITHOUT changing the radius, place the compass point on _______ and draw an arc INSIDE the angle.

Step 4, Arc from Q. Same radius from _______ . Draw an arc that crosses the previous one. Label the crossing _______ .

Step 5, Draw the bisector. Use the straight-edge to draw a ray from _______ through _______ . This ray is the angle bisector, it cuts ∠ABC into two equal halves: ∠ABR = ∠RBC.

Stuck? Revisit lesson § Card 5 "Construct the Angle Bisector", vertex first, then arc across both arms, then equal arcs from each crossing.

3. You do, independent practice

Answer each question. Some are written description; some are calculation. The first four are foundation, the middle two are standard, and the last two are extension.

Foundation, recall

3.1 Name the TWO tools used in a classical construction. 1 mark

3.2 A perpendicular bisector cuts a segment into two parts of length ____ and crosses it at ___° . 1 mark

3.3 Bisecting an angle of 80° creates two angles, each of ___° . 1 mark

3.4 What does it mean for a line to be "perpendicular" to another? 1 mark

Standard, apply the constructions

3.5 Bisecting a right angle gives an angle of ___° . Explain why. 2 marks

3.6 If the perpendicular bisector of AB is constructed and AB = 10 cm, what is the distance from the midpoint of AB to each endpoint? 2 marks

Extension, push your thinking

3.7 Explain in your own words why the angle bisector construction works. Use the fact that triangles △BPR and △BQR are congruent by SSS. 2 marks

3.8 Bisecting an angle TWICE (i.e. bisect, then bisect one of the halves) divides the original angle into how many equal parts? If the original angle is 120°, what is the smallest angle produced? 3 marks

Stuck on 3.8? First bisect: 120 → two pieces of 60° each. Bisect one of the 60° pieces: 60 → two pieces of 30°. So total = 30°, 30°, 60°.

How did this worksheet feel?

What I'll revisit before next class:

Answers, Do not peek before attempting

Section 2, We do (angle bisector)

Step 1: compass at B.
Step 2: crossings labelled P (on BA) and Q (on BC).
Step 3: compass on P.
Step 4: compass on Q; crossing labelled R.
Step 5: draw ray from B through R.

3.1, Two tools

Straight-edge (ruler used only for its edge) and a pair of compasses. NO protractor.

3.2, Perpendicular bisector facts

Cuts into two equal halves; crosses the segment at 90° (right angle).

3.3, Bisecting 80°

Each new angle = 80 ÷ 2 = 40°.

3.4, Perpendicular

"Perpendicular" means at a right angle (90°) to another line.

3.5, Bisecting a right angle

Right angle = 90°. Bisected: each new angle = 90 ÷ 2 = 45°. Because the bisector cuts the angle exactly in half, the two new angles are equal, both 45°.

3.6, Midpoint distance

The perpendicular bisector passes through the midpoint. AB = 10 cm, so each half = 5 cm from the midpoint to each endpoint.

3.7, Why the angle bisector works

The compass guarantees that BP = BQ (same arc from B) and PR = QR (same arc from each of P and Q). Also BR = BR (same side, shared by both triangles). So in triangles △BPR and △BQR, all three sides are equal, the triangles are congruent by SSS. Corresponding angles in congruent triangles are equal, so ∠PBR = ∠QBR. That means BR cuts the original angle into two equal halves, it's the angle bisector.

3.8, Bisecting twice

First bisection: original angle ÷ 2 → 2 equal pieces. Bisect ONE of those pieces → 2 more pieces. Total pieces: 1 unbisected half + 2 quarter pieces = 3 pieces in total (not equal! one is half, two are quarters).
If the original is 120°: first bisection gives two 60° halves. Bisecting one half gives two 30° quarters. So the smallest angle produced = 30°.
If both halves were bisected, the result would be 4 equal quarters of 30° each, but the question only asks about ONE further bisection.