Example 1, Find all 8 angles
Parallel lines cut by a transversal. Angle $a = 65°$. Find all other angles.
Step 1, Identify angle a
$a = 65°$ (given)
Step 2, Find all angles at line 1
$b = 180° - 65° = 115°$ (angles on a straight line)
$c = 65°$ (vertically opposite $a$); $d = 115°$ (vertically opposite $b$)
Step 3, Transfer to line 2 using corresponding angles
$e = a = 65°$; $f = b = 115°$; $g = c = 65°$; $h = d = 115°$
(corresponding angles are equal, parallel lines)
Step 4, Summary
Four angles of 65° and four angles of 115°.
When a transversal cuts parallel lines, there are always only 2 distinct angle values!
Example 2, Algebra with alternate angles
Alternate angles are $(3x - 10)°$ and $(x + 30)°$. Find $x$ and both angles.
Step 1, Set up equation
Alternate angles are equal (parallel lines):
$$3x - 10 = x + 30$$
Step 2, Solve for x
$3x - x = 30 + 10 \Rightarrow 2x = 40 \Rightarrow x = 20$
Step 3, Find the angles
$(3 \times 20 - 10)° = 50°$ and $(20 + 30)° = 50°$ ✓
Both equal 50°, confirms they are alternate angles.
Example 3, Algebra with co-interior angles
Co-interior angles are $(2x + 30)°$ and $(x + 60)°$. Find $x$ and both angles.
Step 1, Set up equation
Co-interior angles add to 180°:
$$(2x + 30) + (x + 60) = 180$$
Step 2, Solve
$3x + 90 = 180 \Rightarrow 3x = 90 \Rightarrow x = 30$
Step 3, Find the angles
$(2 \times 30 + 30)° = 90°$ and $(30 + 60)° = 90°$
$90° + 90° = 180°$ ✓, the transversal is perpendicular to both parallel lines!