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Lesson 10 ~25 min Unit 2 · Linear Relationships +90 XP

The y-Intercept

Discover where lines cross the y-axis. Learn to read, calculate and interpret the y-intercept from graphs, equations and real-world contexts.

Think about it: A line crosses the y-axis at $(0, 4)$. What do we know about this point? What is the x-coordinate of any point on the y-axis?
0/5QUESTS
Think First
warm-up

A line crosses the y-axis at $(0, 4)$. What do we know about this point? What is the x-coordinate of any point on the y-axis?

Record your answer in your workbook.
1
What is the y-Intercept?
+5 XP

The y-intercept of a straight line is the point where the line crosses (or "intercepts") the y-axis. Because the y-axis is the line $x = 0$, every point on it has an x-coordinate of zero. Therefore, the y-intercept is always written as:

$$\text{y-intercept} = (0,\ c)$$

where $c$ is a number, positive, negative, or zero, telling us how far up or down the line crosses the vertical axis.

Four lines cross the y-axis at (0, 3), (0, 2), (0, 0) and (0, −1): every y-intercept has x = 0.xyO(0, 3)(0, 2)(0, 0)(0, −1)
Four lines showing positive, negative and zero y-intercepts. Each one crosses the y-axis at a point (0, c).
Text description
  • A grid with x from −3.5 to 3.5 and y from −2 to 4.5, equal scales, with the origin O marked.
  • A plum line sloping gently down to the right crosses the y-axis at the plum point labelled (0, 3).
  • A teal line sloping up to the right crosses the y-axis at the teal point labelled (0, 2).
  • A gold line at 45 degrees passes through the origin, marked with the point labelled (0, 0).
  • A coral line sloping gently down to the right crosses the y-axis below the origin at the coral point labelled (0, −1).
  • Every crossing point lies on the y-axis, so its x-coordinate is 0.
Always $(0, c)$
The y-intercept always has $x = 0$. Never $(c, 0)$.
Point or number
Write it as the point $(0, c)$ or just the number $c$, both are correct.
2
Finding y-Intercept from a Graph
+5 XP

To find the y-intercept from a graph:

  1. Locate where the line crosses the y-axis (the vertical axis).
  2. Read the y-value at that crossing point.
  3. Write the y-intercept as $(0, c)$.
Worked Example 1, Reading the y-Intercept
Find the y-intercept of the line shown on the graph below.
A line crossing the y-axis 2 units below the origin, at (0, −2).xy−4−24246O−2crosses here
The line meets the y-axis 2 units below the origin, so its y-intercept is (0, −2).
Text description
  • A grid with x from −5 to 7 and y from −3.5 to 7, equal scales; x-axis numbered −4, −2, 4 and y-axis numbered −2, 2, 4, 6.
  • A teal straight line slopes up to the right.
  • A coral point marks where the line crosses the y-axis, at y = −2, with the callout "crosses here".
  1. Locate where the line crosses the y-axis (the vertical axis through the origin).
  2. The line crosses the y-axis 2 units below the origin, so $y = -2$.
  3. Since $x = 0$ at the y-axis, the y-intercept is $(0, -2)$ or simply $c = -2$.
3
The y-Intercept and $y = mx + c$
+5 XP

The equation of a straight line in gradient-intercept form is:

$$y = mx + c$$
In y = mx + c, m is the gradient of the line and c is where it crosses the y-axis, shown on the line y = 0.5x + 2.y = mx + cxyrunrisem = gradient(0, 2)c = y-intercept
In y = mx + c, m is the gradient (rise over run) and c is the y-intercept. Here the line crosses the y-axis at (0, 2).
Text description
  • At the top, the equation y = mx + c, with m in teal and c in coral.
  • Below, a grid with a teal line sloping up to the right, labelled m = gradient.
  • A coral point on the y-axis at (0, 2), where the line crosses, labelled c = y-intercept.
  • A dashed plum gradient triangle from (0, 2): a horizontal run of 2 units labelled run, then a vertical rise of 1 unit labelled rise, back up to the line.

By reading the equation you instantly know both the gradient ($m$) and the y-intercept ($c$).

$y = 3x + 5$
$m = 3$, $c = 5$, y-intercept is $(0, 5)$.
$y = -2x - 1$
$m = -2$, $c = -1$, y-intercept is $(0, -1)$.
4
Finding y-Intercept from an Equation
+5 XP

Two methods, choose whichever fits the equation:

Method A, Read $c$ directly
If the equation is already in $y = mx + c$ form, the y-intercept is simply the constant $c$.
Method B, Set $x = 0$
Substitute $x = 0$ into any equation and solve for $y$. Works every time.
Worked Example 2, Using Method A
Find the y-intercept of $y = 4x - 3$.
  1. Identify the form: $y = 4x - 3$ matches $y = mx + c$ with $m = 4$ and $c = -3$.
  2. The y-intercept is $c = -3$, i.e. the point $(0, -3)$.
Worked Example 3, Using Method B (rearranging needed)
Find the y-intercept of $2y = 4x + 6$.
  1. Substitute $x = 0$: $2y = 4(0) + 6$.
  2. Simplify: $2y = 6$.
  3. Divide both sides by 2: $y = 3$. The y-intercept is $(0, 3)$.
5
y-Intercept as Starting Value
+5 XP

In real-world problems the y-intercept often represents a starting value, initial amount, or fixed cost the value of $y$ when $x = 0$ (before anything has happened).

$\text{Cost} = 30h + 50$
Plumber: $\$50$ call-out fee + $\$30$/hr. y-intercept = $50$ (fee before any work).
$\text{Height} = 2t + 10$
Balloon starts at 10 m. y-intercept = $10$ (starting height).
$\text{Value} = -500n + 8000$
Car worth $\$8000$ new. y-intercept = $8000$ (initial value).
Hours (h) Cost ($) $50 Call-out fee (fixed charge) $30/hour

The y-intercept $(0, 50)$ represents the $\$50$ call-out fee, the cost before any hours are worked.

6
Sketching from the y-Intercept
+5 XP

When sketching a line, the y-intercept is your starting point. It gives you the first point to plot. From there, use the gradient to find additional points.

Worked Example 4, Sketching Using y-Intercept and Gradient
Sketch the line $y = 2x + 3$.
  1. Identify the y-intercept: $c = 3$, so plot $(0, 3)$ on the y-axis.
  2. Identify the gradient: $m = 2 = \frac{2}{1}$, so rise $= 2$, run $= 1$.
  3. From $(0, 3)$, go up 2 and right 1 to reach $(1, 5)$. Plot this point.
  4. Join the points with a straight line and extend both ways. Label $y = 2x + 3$.
Sketch of y = 2x + 3: start at the y-intercept (0, 3), then run 1 and rise 2 to reach (1, 5).xy1Orun = 1rise = 2(0, 3)(1, 5)y = 2x + 3
Start at (0, 3), then use m = 2 (rise 2, run 1) to find the next point, (1, 5). Join the points with a straight line.
Text description
  • A grid with equal scales and the origin O marked; the x-axis is numbered 1.
  • A coral point at (0, 3) on the y-axis, labelled (0, 3).
  • A dashed plum gradient triangle from (0, 3): run = 1 to the right, then rise = 2 up, reaching the coral point labelled (1, 5).
  • A teal straight line labelled y = 2x + 3 passes through (0, 3) and (1, 5).
Anchor first
Always plot the y-intercept first. It anchors your sketch before you use the gradient.
Brain Trainer, Find the y-Intercept
+10 XP

Set a 2-minute timer and race through all 10. Click ? to reveal each answer.

$y = 4x + 5$
?$c = 5$
$y = 2x - 3$
?$c = -3$
$y = -x + 6$
?$c = 6$
$y = 5x$
?$c = 0$
$y = -2x - 4$
?$c = -4$
$y = \frac{1}{2}x + 1$
?$c = 1$
$y = 3x + 0.5$
?$c = 0.5$
$2y = 6x + 8$
?$c = 4$
$y + 3 = 2x$
?$c = -3$
$3y = 9x - 12$
?$c = -4$

Q1. Look at the graph below. What is the y-intercept of the line?

A straight line sloping downhill, with a marked point where it crosses the y-axis.xy−4−22−2246O
Find where the line meets the y-axis (the vertical axis).
Text description
  • A grid with equal scales and the origin O marked; x-axis numbered −4, −2, 2 and y-axis numbered −2, 2, 4, 6.
  • A teal straight line slopes down from upper left to lower right.
  • A coral point marks where the line crosses the y-axis, at the height 3 (between the 2 and 4 marks).

Q2. What is the y-intercept of $y = 3x + 2$?

Q3. A line crosses the y-axis at $(0, -2)$. What is the value of $c$?

Q4. Which line has a y-intercept of $4$?

Q5. Find the y-intercept of $2y = 4x + 6$. (Hint: substitute $x = 0$.)

SAQ 1. Write down the y-intercept of the line shown below. Give your answer as a coordinate.

A straight line sloping uphill, with a marked point where it crosses the y-axis.xy−4−24−4−224O
Read where the line meets the y-axis, then write it as a coordinate.
Text description
  • A grid with equal scales and the origin O marked; x-axis numbered −4, −2, 4 and y-axis numbered −4, −2, 2, 4.
  • A teal straight line slopes up from lower left to upper right.
  • A coral point marks where the line crosses the y-axis, 1 unit below the origin.
Show answer

The line crosses the y-axis 1 unit below the origin. y-intercept = $(0, -1)$, i.e. $c = -1$.

SAQ 2. The equation of a line is $y = -2x + 5$. Find the y-intercept and explain what it means in terms of the graph.

Show answer

$y = -2x + 5$ is in $y = mx + c$ form with $c = 5$. The y-intercept is $(0, 5)$. This means the line crosses the y-axis 5 units above the origin. At the y-intercept, $x = 0$ and $y = 5$.

SAQ 3. A plumber charges a $\$50$ call-out fee plus $\$30$ per hour. The cost equation is $C = 30h + 50$. What is the y-intercept and what does it represent?

Show answer

The y-intercept is $50$ (the constant in $C = 30h + 50$). It represents the $\$50$ call-out fee, the cost before any hours of work are completed ($h = 0$). Even if the plumber does zero hours of work, you still pay $\$50$.

Challenge 1, Two methods, same answer

A line has equation $3y = 6x - 9$.

(a) Find the y-intercept by rearranging into $y = mx + c$ form.

(b) Find the y-intercept by substituting $x = 0$ directly.

(c) Show both methods give the same answer.

Solution

(a) $3y = 6x - 9 \Rightarrow y = 2x - 3$. So $c = -3$.

(b) $x = 0$: $3y = -9 \Rightarrow y = -3$.

(c) Both give y-intercept $= (0, -3)$. ✓

Challenge 2, Same intercept, different gradients

Two lines both have y-intercept $(0, 2)$. One has gradient $3$, the other has gradient $-1$.

(a) Write the equation of each line.

(b) Explain why lines with the same y-intercept all pass through the same point.

Solution

(a) Line 1: $y = 3x + 2$.   Line 2: $y = -x + 2$.

(b) All lines with y-intercept $2$ must pass through $(0, 2)$ because the y-intercept is by definition the point where $x = 0$ and $y = 2$.

Challenge 3, Find $m$ and $c$ from two points

The line $y = mx + c$ passes through $(0, 5)$ and $(2, 9)$. Find $m$ and $c$.

Solution

From $(0, 5)$: $x = 0$, $y = 5$, so $c = 5$.

Using $(2, 9)$: $9 = m(2) + 5 \Rightarrow 2m = 4 \Rightarrow m = 2$.

So $y = 2x + 5$.

Key Takeaways, The y-Intercept
  1. The y-intercept is where a line crosses the y-axis. At that point, $x = 0$.
  2. It is written as the point $(0, c)$ or just the number $c$.
  3. In $y = mx + c$, the letter $c$ is the y-intercept.
  4. To find from an equation: substitute $x = 0$ and solve for $y$ (or read $c$ directly if already in $y = mx + c$ form).
  5. To find from a graph: read where the line crosses the y-axis.
  6. The y-intercept can be positive, negative, or zero.
  7. In context it often means starting value, initial cost, or beginning amount.
Common pitfall
Don't confuse the y-intercept ($x = 0$) with the x-intercept ($y = 0$). They are different points on different axes!

Lesson Complete!

You've mastered the y-intercept. Next up: putting $m$ and $c$ together to write the equation of a line.

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