Successive Percentage Changes
Why a $20\%$ rise followed by a $20\%$ drop doesn't bring you back to where you started.
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A price goes up $20\%$ then comes down $20\%$. Are you back to the original? Most people get this wrong. Jot down your first reaction, then we'll see who's right.
Two percentage changes applied in sequence DO NOT add. They multiply. A $20\%$ rise then $20\%$ fall ends with $96\%$ of the original, a $4\%$ overall LOSS.
Start with $\$100$. Rise $20\%$: $100 \times 1.20 = \$120$. Now fall $20\%$: $120 \times 0.80 = \$96$. NOT back to $\$100$. The percent rise was on $\$100$, but the percent fall was on the BIGGER $\$120$. Combined multiplier: $1.20 \times 0.80 = 0.96$, a $4\%$ overall decrease.
Know
- Successive changes multiply, never add
- Combined multiplier = product of individual multipliers
- Overall % change = $(m_1 m_2 - 1) \times 100$
- Order of multiplication doesn't affect the final value
Understand
- Why the second percentage is on a different base than the first
- How equal-and-opposite percentage moves don't cancel
- Why this matters for sales, investments, and depreciation
Can Do
- Compute final value after multiple successive percentage changes
- Find the equivalent single percentage change
- Recognise common traps in everyday percentage thinking
Wrong: "$20\%$ up then $20\%$ down = $0\%$ change", NO. It's a $4\%$ DECREASE.
Right: Multipliers: $1.20 \times 0.80 = 0.96$. That's $4\%$ down.
Wrong: "$10\%$ off then $5\%$ off = $15\%$ off", NO. It's about $14.5\%$ off (multipliers $0.90 \times 0.95 = 0.855$).
Right: $0.90 \times 0.95 = 0.855$, you pay $85.5\%$, save $14.5\%$, not $15\%$.
Each percentage change uses the CURRENT value as the base. So $20\%$ of $\$120$ is bigger than $20\%$ of $\$100$, that's where the asymmetry comes from.
Start at $\$100$, rise $20\%$ to $\$120$. The next $20\%$ DECREASE is on the new $\$120$, not the original $\$100$. So the drop is $\$24$, not $\$20$. The price falls to $\$96$, $\$4$ below where we started.
Multiply all the individual multipliers together to get one combined multiplier. This represents the entire chain of changes as a single multiplication.
Three changes: $+10\%, -20\%, +5\%$. Multipliers: $1.10, 0.80, 1.05$. Combined: $1.10 \times 0.80 \times 1.05 = 0.924$. So the overall change is $0.924 - 1 = -0.076 = -7.6\%$. The starting value ends up at $92.4\%$ of its original sizea $7.6\%$ overall decrease.
Watch Me Solve It · 3 examples
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1After $+20\%$$100 \times 1.20 = \$120$Multiplier 1.20.
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2After $-20\%$$120 \times 0.80 = \$96$New multiplier on the $\$120$.
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3Combined$1.20 \times 0.80 = 0.96 \Rightarrow$ $\$100 \times 0.96 = \$96$Same answer via one multiplier.
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1Multipliers$0.75 \times 0.90 = 0.675$Combined.
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2Final price$200 \times 0.675 = \$135$Sale price.
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3Equivalent single discount$1 - 0.675 = 0.325 = 32.5\%$Not $35\%$!
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1Set up multipliers$1.15, 0.90, 1.08$Convert each.
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2Combine$1.15 \times 0.90 \times 1.08 = 1.1178$Multiply all three.
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3Equivalent change$1.1178 - 1 = 0.1178 = 11.78\%$ increaseNet up, not $13\%$.
Common Pitfalls
Combined Multiplier
- Multiply all multipliers together
- $1.20 \times 0.80 = 0.96$
- $96\%$ = $4\%$ loss
Asymmetry Rule
- $+P\%$ then $-P\%$ $\neq 0$
- Always slight LOSS
- Different bases cause it
Equivalent Single %
- Combined $-$ 1, then $\times 100$
- $0.96 \to -4\%$
- $1.10 \to +10\%$
Order Doesn't Matter
- $0.80 \times 1.20 = 1.20 \times 0.80$
- Multiplication is commutative
- Apply in any order
How are you completing this lesson?
Brain Trainer · 4 problems
Four drill problems to sharpen your skills. Work each, then reveal the answer.
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1 $\$100 \to +10\% \to -10\%$. Final?
$100 \times 1.10 \times 0.90 = \$99$.$\$99$ -
2 $\$200, -25\%$ then $-20\%$. Final?
$200 \times 0.75 \times 0.80 = \$120$.$\$120$ -
3 Combined multiplier for $+30\%$ and $+20\%$:
$1.30 \times 1.20 = 1.56 \Rightarrow 56\%$ rise.$56\%$ -
4 $\$400 \to +50\%, -50\%$. Final?
$400 \times 1.50 \times 0.50 = \$300$.$\$300$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. A jacket has its price modified twice: $+20\%$, then $-15\%$, on an original of $\$80$. (a) Find the price after each change. (b) Compute the combined multiplier. (c) What is the equivalent single percentage change?
Q7. A shop offers $30\%$ off, then a $10\%$ student discount on top. What does a $\$200$ item cost the student?
Q8. Asha thinks a $40\%$ pay rise followed by a $40\%$ pay cut puts her back at her original salary. (a) Starting from $\$50\,000$, show with calculations whether she is right or wrong. (b) Calculate the actual percentage change. (c) Explain in plain words WHY two equal-and-opposite percentages don't cancel.
Quick Check
1. B$\$99$.
2. B$36\%$ off.
3. C$\$585$.
4. A$5.5\%$ decrease.
5. C$-25\%$.
Show Your Working Model Answers
Q6 (3 marks): (a) After $+20\%$: $80 \times 1.20 = \$96$. After $-15\%$: $96 \times 0.85 = \$81.60$ [1]. (b) Combined: $1.20 \times 0.85 = 1.02$ [1]. (c) $2\%$ overall increase [1].
Q7 (2 marks): $200 \times 0.70 \times 0.90 = \$126$ [2].
Q8 (4 marks): (a) After $+40\%$: $50000 \times 1.40 = \$70\,000$. After $-40\%$: $70000 \times 0.60 = \$42\,000$ [2]. (b) She finishes at $\$42\,000$, an overall $16\%$ decrease ($1.40 \times 0.60 = 0.84$) [1]. (c) The $40\%$ rise was on her original $\$50k$ (a $\$20k$ gain), but the $40\%$ cut was on the larger $\$70k$ (a $\$28k$ loss). The second percentage acts on a DIFFERENT base, so the changes don't cancel [1].
The Compound Equivalent
A house price changes in 3 consecutive years: $+15\%$, $-8\%$, $+5\%$. (a) Find the combined multiplier. (b) Find the equivalent single percentage change. (c) If we replaced the three changes with three equal $+P\%$ changes (compounded), what single yearly $P\%$ would give the same total? (Hint: cube root.)
Reveal solution
(a) Combined $= 1.15 \times 0.92 \times 1.05 = 1.1109$. (b) Overall change $\approx +11.09\%$. (c) $1.1109^{1/3} \approx 1.0357$, so $P \approx 3.57\%$ per year, compounded.
Multiply
Multipliers multiply, percentages don't add
Different bases
Second % is on new value
Combined $= m_1 \times m_2$
One number captures the chain
$+P\%, -P\%$
Always slight loss
Order doesn't matter
Commutative multiplication
Equivalent single %
Combined $- 1$, then $\times 100$
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