Mathematics • Year 8 • Unit 2 • Lesson 9
Finding Gradient from Two Points
Build fluency with the gradient formula m = (y₂ − y₁) / (x₂ − x₁). One worked example, one guided example with blanks, then eight independent problems including negatives and special cases.
1. I do, fully worked example
Given two coordinates, you can find the gradient without ever drawing the line.
Problem. Find the gradient of the line through (2, 3) and (6, 7).
Step 1, Label your points.
(x₁, y₁) = (2, 3) (x₂, y₂) = (6, 7)
Reason: pick either point as "1", just be consistent for both subtractions.
Step 2, Calculate the rise (y₂ − y₁).
Rise = y₂ − y₁ = 7 − 3 = 4
Reason: "y on top" of the gradient fraction.
Step 3, Calculate the run (x₂ − x₁).
Run = x₂ − x₁ = 6 − 2 = 4
Reason: "x on bottom".
Step 4, Compute m.
m = rise / run = 4 / 4 = 1
Answer: m = 1 (positive, line slopes uphill at 45°).
2. We do, fill in the missing steps
Same shape as Section 1, but with the working faded. Fill in each blank. 4 marks
Problem. Find the gradient through (1, 2) and (5, 14).
Step 1, Label points: (x₁, y₁) = (______, ______) and (x₂, y₂) = (______, ______).
Step 2, Rise = y₂ − y₁ = ______ − ______ = ______.
Step 3, Run = x₂ − x₁ = ______ − ______ = ______.
Step 4, m = rise / run = ______ / ______ = ______.
Sign check: y went up as x went up, so m should be ____________ (positive / negative).
3. You do, independent practice
Show your working under each problem. First four are foundation, next two are standard, last two are extension.
Foundation, apply the formula
3.1 Find m through (1, 3) and (4, 9). 1 mark
3.2 Find m through (0, 0) and (5, 10). 1 mark
3.3 Find m through (2, 7) and (5, 1). 1 mark
3.4 Find m through (3, 5) and (7, 5). State the gradient type. 1 mark
Standard, including negatives
3.5 Find m through (0, 0) and (−2, 6). 2 marks
3.6 Find m through (−3, −2) and (1, 4). 2 marks
Extension, simplify and decide
3.7 Find m through (−1, 2) and (3, −4). Give your answer as both a simplified fraction and a decimal. 2 marks
3.8 Show that the gradient through (1, 3) and (4, 9) is the same whether you label (1,3) as (x₁,y₁) or as (x₂,y₂). 2 marks
How did this worksheet feel?
What I'll revisit before next class:
Section 2, We do
(x₁, y₁) = (1, 2), (x₂, y₂) = (5, 14). Rise = 14 − 2 = 12. Run = 5 − 1 = 4. m = 12/4 = 3. Sign check: positive.
3.1, (1, 3) and (4, 9)
m = (9 − 3)/(4 − 1) = 6/3 = 2.
3.2, (0, 0) and (5, 10)
m = (10 − 0)/(5 − 0) = 10/5 = 2.
3.3, (2, 7) and (5, 1)
m = (1 − 7)/(5 − 2) = −6/3 = −2.
3.4, (3, 5) and (7, 5)
m = (5 − 5)/(7 − 3) = 0/4 = 0. Gradient type: zero (horizontal line).
3.5, (0, 0) and (−2, 6)
m = (6 − 0)/(−2 − 0) = 6/(−2) = −3.
3.6, (−3, −2) and (1, 4)
m = (4 − (−2))/(1 − (−3)) = 6/4 = 3/2 (= 1.5).
3.7, (−1, 2) and (3, −4)
m = (−4 − 2)/(3 − (−1)) = −6/4 = −3/2 = −1.5.
3.8, Order independence
If (x₁,y₁) = (1,3) and (x₂,y₂) = (4,9): m = (9−3)/(4−1) = 6/3 = 2.
If (x₁,y₁) = (4,9) and (x₂,y₂) = (1,3): m = (3−9)/(1−4) = −6/−3 = 2.
Both give m = 2. The order doesn't matter as long as you subtract consistently top and bottom.