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Year 8 Mathematics · Unit 3 · Lesson 15 of 20

Angles in Triangles

A bridge truss has two angles of 42° and 76°. What is the third angle? And why must the three always add to exactly 180°?

9cards
5MC
3SAQs
~30min
1

The Big Idea

The three interior angles of any triangle always add to exactly 180°. An exterior angle of a triangle equals the sum of the two remote interior angles.

α β γ α + β + γ = 180° e e = α + γ
Angle Sum Theorem
α + β + γ = 180°
True for every triangle
Exterior Angle Theorem
e = α + γ
Sum of two non-adjacent interior angles
2

Learning Objectives

  • State and apply the angle sum theorem: the three interior angles of any triangle add to 180°
  • Find a missing angle in a triangle given two angles
  • Apply the exterior angle theorem to find missing angles
  • Set up and solve algebraic equations using triangle angle properties
  • Classify triangles by their angles (acute, right, obtuse) and sides (equilateral, isosceles, scalene)
3

Key Vocabulary

Term Meaning
Interior angle An angle inside the triangle, at a vertex
Exterior angle Angle formed by extending a side of the triangle; supplementary to the adjacent interior angle
Remote interior angles The two interior angles that are not adjacent to a given exterior angle
Equilateral triangle All three sides equal; all three angles equal 60°
Isosceles triangle Two equal sides; two equal base angles
Scalene triangle All sides and angles different
Right-angled triangle Contains exactly one 90° angle; the other two angles add to 90°
4

The Angle Sum Theorem

Theorem

The sum of the interior angles of a triangle is 180°.

$$\alpha + \beta + \gamma = 180°$$

This is true for every triangle, no matter how flat, how tall, or how skewed.

To find a missing angle:

  1. Add the two known angles
  2. Subtract from 180°
  3. State: "angle sum of a triangle is 180°"
Bridge hook answer: $42° + 76° = 118°$, so third angle $= 180° - 118° = 62°$
Copy into your book
  • Angle sum of a triangle = 180°
  • Missing angle = 180° − (sum of other two)
5

The Exterior Angle Theorem

Theorem

An exterior angle of a triangle equals the sum of the two non-adjacent interior angles.

$$e = \alpha + \gamma \quad \text{(remote interior angles)}$$

An exterior angle is formed when you extend a side of the triangle. It is always larger than either remote interior angle.

Why does this work?

The exterior angle and the adjacent interior angle form a straight line (180°). The adjacent interior angle = 180° − (sum of other two). So the exterior angle = sum of the other two.

Copy into your book
  • Exterior angle = sum of two remote interior angles
  • Reason: "exterior angle of a triangle"
6

Classifying Triangles

By Angles

Acute All angles < 90°
Right One angle = 90°
Obtuse One angle > 90°

By Sides

Equilateral 3 equal sides; 3 × 60°
Isosceles 2 equal sides; 2 equal angles
Scalene All sides & angles different
Key fact: An equilateral triangle has angles 60°, 60°, 60°. An isosceles triangle's base angles are equal. Use these to set up equations when algebraic sides are given.
Copy into your book
  • Acute: all < 90°; Right: one = 90°; Obtuse: one > 90°
  • Equilateral: 3 equal sides, 60° each
  • Isosceles: 2 equal sides, 2 equal base angles
  • Scalene: all different
7

Worked Examples

Example 1, Find the missing angle

A triangle has angles 55°, 72°, and $x$°. Find $x$.

Step 1, Write the angle sum equation

$$55 + 72 + x = 180$$

Example 2, Algebra with angle sum

A triangle has angles $x$, $2x$, and $3x$. Find all three angles and classify the triangle.

Step 1, Set up equation

$$x + 2x + 3x = 180$$

Example 3, Exterior angle theorem

An exterior angle of a triangle is 110°. One of the remote interior angles is 45°. Find the other remote interior angle and the adjacent interior angle.

Step 1, Use exterior angle theorem

Exterior angle = sum of two remote interior angles:

$$110° = 45° + \text{other remote angle}$$

8

Brain Trainer

Find each missing angle. Click to reveal.

Triangle angles: 60°, 80°, and $x$°. Find $x$.
Two angles of a triangle are both 45°. Find the third angle.
Exterior angle = 130°. One remote interior angle = 70°. Find the other.
An isosceles triangle has a vertex angle of 40°. Find the base angles.
Triangle angles: $x$, $x$, $x$. Find $x$ and classify.
One angle of a right triangle is 37°. Find the third angle.
Triangle angles: $4x$, $3x$, and $2x$. Find each angle.
Exterior angle = 95°. Remote interior angles are $(x+10)°$ and $(2x-5)°$. Find $x$.
Can a triangle have angles 100°, 50°, and 40°?
Is a triangle with angles 30°, 60°, 90° acute, right or obtuse? And what type by sides?
9

Common Mistakes

Adding all four angles (exterior + interior)

Only the three interior angles add to 180°. The exterior angle is not one of the three, it replaces the adjacent interior angle on a straight line.

Using the wrong pair for exterior angle theorem

The exterior angle equals the sum of the two remote (non-adjacent) interior angles, not all three. The adjacent interior angle is supplementary to the exterior angle (together they make 180°).

Forgetting isosceles base angles are equal

When a triangle is labelled isosceles (or has two equal sides marked), the two base angles are equal. Use this to set up equations, don't guess which angle is the vertex angle.

Not checking by substituting back

Always verify your answer: do the three angles add to 180°? A quick check prevents losing marks for arithmetic errors.

Q1

Missing Angle

A triangle has angles 55° and 72°. The third angle is:

Q2

Exterior Angle

An exterior angle of a triangle is 120°. One remote interior angle is 50°. The other remote interior angle is:

Q3

Algebraic Angles

A triangle has angles $x$, $2x$ and $3x$. What is $x$?

Q4

Isosceles Triangle

An isosceles triangle has a vertex angle of 100°. Each base angle measures:

Q5

Triangle Classification

A triangle has angles $(2x + 10)°$, $(x + 20)°$, and $x°$. What is the largest angle?

Q6

Angle Sum, 3 marks

A triangle has angles $(3x + 5)°$, $(2x - 10)°$, and $(x + 45)°$.

  1. Write an equation using the angle sum theorem and solve for $x$. (1 mark)
  2. Find the size of each angle. (1 mark)
  3. Classify the triangle by its angles. Give a reason. (1 mark)
Q7

Exterior Angle, 2 marks

In triangle $ABC$, the exterior angle at $C$ is $(5x + 8)°$. The two remote interior angles are $(3x - 4)°$ at $A$ and $(x + 22)°$ at $B$.

  1. Write an equation using the exterior angle theorem and solve for $x$. (1 mark)
  2. Find the exterior angle and verify using the angle sum of the triangle. (1 mark)
Q8

Isosceles Triangle, 4 marks

An isosceles triangle has two equal sides. The vertex angle (between the equal sides) is $(4x - 20)°$. Each base angle is $(x + 35)°$.

  1. Write an equation using the angle sum theorem and solve for $x$. (1 mark)
  2. Find the vertex angle and each base angle. (1 mark)
  3. Verify by checking the angle sum. (1 mark)
  4. Classify the triangle by its angles. (1 mark)
Angle sum
α + β + γ = 180°
Exterior angle
= sum of remote interior
Equilateral
3 × 60°
Isosceles
2 equal base angles
S

Stretch Challenge

Clock angles: The hour and minute hands of a clock form a triangle with the centre of the clock face.

  1. At exactly 3:00, the hour hand points to 3, the minute hand points to 12. What angle do they form at the centre?
  2. At 3:20, the minute hand points to 4. The hour hand has moved $\tfrac{20}{60}$ of the way from 3 to 4. What angle has the hour hand moved from its 3:00 position? What is the angle between the hands?
  3. At what time after 3:00 will the two hands next form a 90° angle? Show your working.
Reveal Solution

Part 1: At 3:00 the hands are 90° apart (3 out of 12 equal segments, each 30°: $3 \times 30° = 90°$).

Part 2: Hour hand moves $0.5°$ per minute. In 20 min: $20 \times 0.5° = 10°$. Minute hand is at 4 (120° from 12). Hour hand is at $90° + 10° = 100°$ from 12. Angle between hands: $120° - 100° = 20°$.

Part 3: The minute hand gains $5.5°$ per minute over the hour hand. Starting at 90° separation. For 90° again (closing gap to 0° then opening): the hands coincide at $90 \div 5.5 \approx 16.36$ min after 3:00. After coinciding, they reach 90° again in a further $90 \div 5.5 \approx 16.36$ min, i.e., about $32.7$ min after 3:00, so at approximately 3:33.

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