Mathematics • Year 8 • Unit 4 • Lesson 17

Venn Diagrams

Build fluency with filling in two-set Venn diagrams, calculating probabilities from each region, and using the addition rule P(A ∪ B) = P(A) + P(B) − P(A ∩ B).

Build · I Do / We Do / You Do

1. I do, fully worked example

Watch how we fill a Venn diagram starting from the intersection and working outward.

Problem. In a survey of 30 students, n(A) = 18 like art, n(B) = 15 like baking, and n(A ∩ B) = 8 like both. Find n(neither) and P(A only).

10 8 7 Art Baking neither: 5
Both = 8 first; Art-only = 18 − 8 = 10; neither = 30 − 25 = 5; P(Art only) = 10/30.

Step 1, Place the intersection first.

n(A ∩ B) = 8 → write 8 in the overlap

Reason: the intersection is part of both n(A) and n(B), so we must subtract it before we can fill the "only" regions.

Step 2, A only = n(A) − n(A ∩ B).

A only = 18 − 8 = 10

Reason: of the 18 people who like A, 8 also like B, so only 10 like A alone.

Step 3, B only = n(B) − n(A ∩ B).

B only = 15 − 8 = 7

Step 4, Neither = n(ξ) − (A only + A ∩ B + B only).

Neither = 30 − 10 − 8 − 7 = 5

Step 5, Check all regions add to the total.

10 + 8 + 7 + 5 = 30 ✓

Step 6, Calculate P(A only).

P(A only) = 10 / 30 = 1 / 3

Answer: n(neither) = 5 and P(A only) = 1/3.

Stuck? Revisit lesson § "Filling In a Venn Diagram", always start with the intersection, then work outward.

2. We do, fill in the missing steps

Same shape as Section 1, but with the working faded. Fill in each blank. 4 marks

Problem. A class of 25 students surveyed: n(F) = 14 play football, n(N) = 10 play netball, n(F ∩ N) = 6 play both. Find n(neither) and P(F only).

Step 1, Intersection in the overlap:

n(F ∩ N) = ______

Step 2, F only = n(F) − n(F ∩ N):

F only = ______ − ______ = ______

Step 3, N only = n(N) − n(F ∩ N):

N only = ______ − ______ = ______

Step 4, Neither:

Neither = 25 − ______ − ______ − ______ = ______

Step 5, Check:

______ + ______ + ______ + ______ = 25 ✓

Step 6, P(F only):

P(F only) = ______ / 25 = ______

Stuck? F only is "football but NOT netball", start by subtracting the 6 who play both from the 14 who play football.

3. You do, independent practice

Show your working under each problem. Foundation problems are single-skill, standard apply the full method, and extension uses the addition rule.

Foundation, recall and basic regions

3.1 Write the formula for the addition rule for P(A ∪ B).    1 mark

3.2 If n(A) = 20 and n(A ∩ B) = 6, find "A only".    1 mark

3.3 Two events A and B are mutually exclusive. State the value of P(A ∩ B).    1 mark

3.4 n(ξ) = 40, A only = 12, n(A ∩ B) = 5, B only = 18. Find n(neither).    1 mark

Standard, fill the diagram and find a probability

3.5 In a group of 35 students, 20 like maths (M), 18 like science (S), and 9 like both. (a) Find M only, S only, and neither. (b) Calculate P(M ∩ S).    2 marks

3.6 n(ξ) = 60, n(A) = 25, n(B) = 30, n(A ∩ B) = 10. Find P(A ∪ B).    2 marks

Extension, addition rule and verification

3.7 Use the addition rule with P(A) = 0.45, P(B) = 0.30, P(A ∩ B) = 0.15 to find P(A ∪ B). Then state the value of P(neither).    2 marks

3.8 A class of 28 students: 16 own a dog (D), 12 own a cat (C), and 7 own neither pet. (a) How many own both? (b) Find P(owns a cat only).    2 marks

Stuck on 3.8? Total in at least one set = 28 − 7 = 21. Use the addition rule: 21 = 16 + 12 − n(both).

How did this worksheet feel?

What I'll revisit before next class:

Answers, Do not peek before attempting

Section 2, We do (football and netball)

Step 1: 6. Step 2: F only = 14 − 6 = 8. Step 3: N only = 10 − 6 = 4. Step 4: Neither = 25 − 8 − 6 − 4 = 7. Step 5: 8 + 6 + 4 + 7 = 25 ✓. Step 6: P(F only) = 8 / 25.

3.1, Addition rule

P(A ∪ B) = P(A) + P(B) − P(A ∩ B).

3.2, A only

A only = n(A) − n(A ∩ B) = 20 − 6 = 14.

3.3, Mutually exclusive

P(A ∩ B) = 0 the events cannot both occur, so the circles do not overlap.

3.4, Neither

Neither = 40 − 12 − 5 − 18 = 5.

3.5, Maths and science

(a) M only = 20 − 9 = 11; S only = 18 − 9 = 9; Neither = 35 − 11 − 9 − 9 = 6. Check: 11 + 9 + 9 + 6 = 35 ✓.
(b) P(M ∩ S) = 9 / 35.

3.6, P(A ∪ B)

Addition rule: P(A ∪ B) = 25/60 + 30/60 − 10/60 = 45 / 60 = 3/4.

3.7, Addition rule with probabilities

P(A ∪ B) = 0.45 + 0.30 − 0.15 = 0.60. P(neither) = 1 − P(A ∪ B) = 1 − 0.60 = 0.40.

3.8, Dogs and cats

(a) In at least one set = 28 − 7 = 21. By the addition rule, 21 = 16 + 12 − n(both), so n(both) = 28 − 21 = 7.
(b) C only = 12 − 7 = 5. P(cat only) = 5 / 28.