Mathematics • Year 9 • Unit 1 • Lesson 17

Operations in Scientific Notation

Build fluency with $\times$, $\div$, $+$ and $-$ on numbers in $a \times 10^n$ form. Multiply coefficients and add indices, divide coefficients and subtract indices, match powers before adding or subtracting, and re-standardise the coefficient back into $[1, 10)$ when it drifts.

Build · I Do / We Do / You Do

1. I do, fully worked example

Read every line. Each step has a short reason on the right so you can see why, not just what.

Problem. Calculate $(5 \times 10^3) \times (4 \times 10^2)$. Give your answer in scientific notation.

Step 1, Spot the operation.

Two numbers in $a \times 10^n$ form being multiplied. So: $\times$ on the coefficients, $+$ on the indices.

Reason: $(a \times 10^m)(b \times 10^n) = (a \cdot b) \times 10^{m+n}$, the product rule on $10^m \cdot 10^n$ adds indices.

Step 2, Multiply the coefficients.

$5 \times 4 = 20$

Reason: the coefficients are just ordinary numbers, handle them with ordinary arithmetic.

Step 3, Add the indices.

$10^3 \times 10^2 = 10^{3+2} = 10^5$

Reason: product rule on powers of the same base, add the indices.

Step 4, Combine.

$20 \times 10^5$

Reason: $20$ is outside $[1, 10)$, this is right value, wrong form. Re-standardise.

Step 5, Re-standardise.

$20 \times 10^5 = 2.0 \times 10^6$   (decimal shifts one left $\to$ index goes up by 1)

Reason: shift the decimal one place left, bump the power of 10 up by 1, so the value is unchanged.

Answer: $\mathbf{2 \times 10^6}$.

Stuck? Revisit lesson § "Spot the Trap", multiplying the indices instead of adding them is the most common slip.

2. We do, fill in the missing steps

Same structure as Section 1, with the working faded. Fill in each blank. 4 marks

Problem. Calculate $3 \times 10^4 + 2 \times 10^3$. Give your answer in scientific notation.

Step 1, Spot the operation: addition, so the powers of $10$ must __________________ first.

Step 2, Rewrite the smaller-power term to share the larger power $10^4$:

$2 \times 10^3 = \_\_\_\_ \times 10^4$

Step 3, Now both terms share $10^4$. Add the coefficients:

$3 + \_\_\_\_ = \_\_\_\_$

Step 4, Write the result:

$3 \times 10^4 + 2 \times 10^3 = \_\_\_\_\_\_\_ \times 10^4$

Step 5, Check the form: Is the coefficient in $[1, 10)$?   __________ (yes / no)

Stuck? Revisit lesson § "Watch Me Solve It · Add", that worked the exact same calculation step-by-step.

3. You do, independent practice

Show your working under each problem. The first four are foundation (single operation, clean numbers). The middle two are standard (need a re-standardise or negative index). The last two are extension (real context or extra step).

Foundation, single operation

3.1 Calculate $(4 \times 10^3) \times (2 \times 10^5)$.    1 mark

3.2 Calculate $\dfrac{9 \times 10^8}{3 \times 10^3}$.    1 mark

3.3 Calculate $\dfrac{6 \times 10^9}{3 \times 10^4}$.    1 mark

3.4 Calculate $4 \times 10^5 + 3 \times 10^4$.    1 mark

Standard, re-standardise or negatives

3.5 Calculate $(6 \times 10^5) \times (5 \times 10^{-2})$. Give your answer in scientific notation.    2 marks

3.6 Calculate $5 \times 10^{-3} - 2 \times 10^{-4}$. Give your answer in scientific notation.    2 marks

Extension, push your thinking

3.7 Calculate $(8 \times 10^4) \times (5 \times 10^3)$, giving the answer in scientific notation. (Hint: the coefficient won't stay in $[1, 10)$ at first.)    2 marks

3.8 A student writes "$3 \times 10^4 + 2 \times 10^3 = 5 \times 10^7$." Explain in one sentence what they did wrong, then give the correct answer in scientific notation.    2 marks

Stuck on 3.7? Multiply coefficients first ($8 \times 5 = 40$), then add indices, then re-standardise the $40$.

How did this worksheet feel?

What I'll revisit before next class:

Answers, Do not peek before attempting

Section 2, We do (faded $3 \times 10^4 + 2 \times 10^3$)

Step 1: powers of 10 must match first.
Step 2: $2 \times 10^3 = \mathbf{0.2} \times 10^4$.
Step 3: $3 + \mathbf{0.2} = \mathbf{3.2}$.
Step 4: $3 \times 10^4 + 2 \times 10^3 = \mathbf{3.2} \times 10^4$.
Step 5: $3.2$ is in $[1, 10)$, yes, already in standard form.

3.1, $(4 \times 10^3) \times (2 \times 10^5)$

Coefficients: $4 \times 2 = 8$. Indices: $10^{3+5} = 10^8$. Answer: $\mathbf{8 \times 10^8}$.

3.2, $\dfrac{9 \times 10^8}{3 \times 10^3}$

Coefficients: $9 / 3 = 3$. Indices: $10^{8 - 3} = 10^5$. Answer: $\mathbf{3 \times 10^5}$.

3.3, $\dfrac{6 \times 10^9}{3 \times 10^4}$

Coefficients: $6 / 3 = 2$. Indices: $10^{9 - 4} = 10^5$. Answer: $\mathbf{2 \times 10^5}$.

3.4, $4 \times 10^5 + 3 \times 10^4$

Match powers: $3 \times 10^4 = 0.3 \times 10^5$. Add coefficients: $4 + 0.3 = 4.3$. Answer: $\mathbf{4.3 \times 10^5}$.

3.5, $(6 \times 10^5) \times (5 \times 10^{-2})$

Coefficients: $6 \times 5 = 30$. Indices: $10^{5 + (-2)} = 10^3$. Current: $30 \times 10^3$, coefficient out of $[1, 10)$. Re-standardise: $\mathbf{3 \times 10^4}$.

3.6, $5 \times 10^{-3} - 2 \times 10^{-4}$

Match powers to the larger index ($-3$): $2 \times 10^{-4} = 0.2 \times 10^{-3}$. Subtract: $5 - 0.2 = 4.8$. Answer: $\mathbf{4.8 \times 10^{-3}}$.

3.7, $(8 \times 10^4) \times (5 \times 10^3)$

Coefficients: $8 \times 5 = 40$. Indices: $10^{4+3} = 10^7$. Current: $40 \times 10^7$, $40$ is outside $[1, 10)$. Re-standardise: $40 = 4.0 \times 10^1$, so $40 \times 10^7 = 4 \times 10^8$. Answer: $\mathbf{4 \times 10^8}$.

3.8, Find the mistake in $3 \times 10^4 + 2 \times 10^3$

The student added the coefficients and the indices together ($3 + 2 = 5$ and $4 + 3 = 7$), but addition of scientific-notation terms requires the powers of $10$ to match first you never add indices when adding terms.
Correct working: rewrite $2 \times 10^3 = 0.2 \times 10^4$, then $(3 + 0.2) \times 10^4 = \mathbf{3.2 \times 10^4}$.