Mathematics • Year 9 • Unit 4 • Lesson 5

Surface Area and Volume of Prisms and Cylinders

Build fluency with V = (cross-section area) × length for prisms, V = πr²h for cylinders, and SA = 2πr² + 2πrh. One step at a time, from a fully worked example through guided practice to independent problems.

Build · I Do / We Do / You Do

1. I do, fully worked example

Read every line. Each step has a short reason on the right so you can see why, not just what.

Problem. Find the volume and total surface area of a cylinder with radius 4 cm and height 10 cm. Leave answers in terms of π AND give a decimal to 1 dp.

r = 4 cm h = 10 cm
Volume = πr²h; total surface area = 2πr² + 2πrh (two circles + the curved side).

Step 1, Write the formulas you need.

V = π r² h
SA = 2π r² + 2π r h

Reason: write them down BEFORE you substitute, that way you can't accidentally use the wrong one.

Step 2, Identify r and h.

r = 4 cm, h = 10 cm.

Reason: r is RADIUS, not diameter. Always check, many problems give the diameter to catch you out.

Step 3, Compute the VOLUME.

V = π × 4² × 10 = π × 16 × 10 = 160π cm³ ≈ 502.7 cm³

Reason: square the radius FIRST, then multiply by height, then by π.

Step 4, Compute the SURFACE AREA in two parts.

2π r² (two circular ends) = 2π × 4² = 32π
2π r h (curved/lateral surface) = 2π × 4 × 10 = 80π

Reason: the cylinder net has TWO circles + ONE rectangle. Adding them gives the total SA.

Step 5, Add and write the final answer with correct units.

SA = 32π + 80π = 112π cm² ≈ 351.9 cm²

Reason: SA is measured in cm² (area), V in cm³ (volume). Different shapes of units!

Answer: V = 160π cm³ ≈ 502.7 cm³; SA = 112π cm² ≈ 351.9 cm².

Stuck? Revisit lesson § "Cylinders", the formulas V = πr²h and SA = 2πr² + 2πrh are the two you must know cold.

2. We do, fill in the missing steps

Same structure as Section 1, but with the working faded. Fill in each blank line. 4 marks

Problem. Find the volume and total surface area of a rectangular prism with length 8 cm, width 5 cm, height 3 cm.

Step 1, Write the formulas:

V = l × w × ____     SA = 2(lw + l____ + w____)

Step 2, Substitute l = 8, w = 5, h = 3:

Step 3, Compute V:

V = 8 × 5 × ____ = ____________ cm³

Step 4, Compute each face product (then add them inside the brackets):

l w = 8 × 5 = ____
l h = 8 × ____ = ____
w h = 5 × ____ = ____
Sum inside the brackets = ____ + ____ + ____ = ____

Step 5, Multiply by 2 and state units:

SA = 2 × ____ = ____________ cm²

Stuck? Each rectangular face is a rectangle. There are 6 faces in 3 pairs (top/bottom, front/back, left/right), which is why we multiply by 2.

3. You do, independent practice

Show your working in the space under each problem. The first four are foundation (one formula). The middle two are standard (both formulas, or with a twist). The last two are extension (work backwards / reasoning).

Foundation, single formula

3.1 Find the volume of a cube with side 5 cm.    1 mark

3.2 Find the surface area of a cube with side 5 cm.    1 mark

3.3 Find the volume of a cylinder with radius 3 cm and height 7 cm. Leave answer in terms of π.    1 mark

3.4 Find the LATERAL (curved) surface area only of a cylinder with radius 2 cm and height 8 cm. Leave answer in terms of π.    1 mark

Standard, both formulas

3.5 Find the volume AND the total surface area of a rectangular prism with dimensions 6 × 4 × 2 cm.    2 marks

3.6 A cylinder has DIAMETER 10 cm and height 12 cm. Find its volume and total surface area to 1 dp. (Careful: diameter, not radius!)    2 marks

Extension, push your thinking

3.7 A cylinder has volume 100π cm³ and radius 5 cm. Find its height.    2 marks

3.8 A triangular prism has a right-triangle cross-section with legs 3 cm and 4 cm, and the prism is 10 cm long. Find its volume. (Hint: area of the right triangle = ½ × base × height.)    2 marks

Stuck on 3.8? Use V = (cross-section area) × length. The cross-section area is the area of the 3-4-5 right triangle = ½ × 3 × 4 = 6 cm².

How did this worksheet feel?

What I'll revisit before next class:

Answers, Do not peek before attempting

Section 2, We do (rectangular prism 8 × 5 × 3)

Step 1: V = l × w × h; SA = 2(lw + l h + w h).
Step 3: V = 8 × 5 × 3 = 120 cm³.
Step 4: lw = 40, lh = 8 × 3 = 24, wh = 5 × 3 = 15. Sum = 40 + 24 + 15 = 79.
Step 5: SA = 2 × 79 = 158 cm².

3.1, Cube volume, side 5

V = 5 × 5 × 5 = 5³ = 125 cm³.

3.2, Cube surface area, side 5

A cube has 6 equal square faces. SA = 6 × 5² = 6 × 25 = 150 cm².

3.3, Cylinder volume, r = 3, h = 7

V = π × 3² × 7 = 9 × 7 × π = 63π cm³ (≈ 197.9 cm³).

3.4, Cylinder lateral SA, r = 2, h = 8

Lateral SA = 2π r h = 2π × 2 × 8 = 32π cm² (≈ 100.5 cm²). This is only the curved part, does NOT include the two circular ends.

3.5, Prism 6 × 4 × 2

V = 6 × 4 × 2 = 48 cm³.
SA = 2(6×4 + 6×2 + 4×2) = 2(24 + 12 + 8) = 2(44) = 88 cm².

3.6, Cylinder DIAMETER 10, height 12

Diameter = 10 → radius = 5 cm. (Halve the diameter first.)
V = π × 5² × 12 = π × 25 × 12 = 300π ≈ 942.5 cm³.
SA = 2π × 5² + 2π × 5 × 12 = 50π + 120π = 170π ≈ 534.1 cm².
If you forgot to halve and used r = 10, you'd get 4× the correct volume, a common error.

3.7, Cylinder V = 100π, r = 5

V = π r² h → 100π = π × 25 × h → 100 = 25h → h = 4 cm.

3.8, Triangular prism, legs 3 cm and 4 cm, length 10 cm

Cross-section area = ½ × 3 × 4 = 6 cm².
V = 6 × 10 = 60 cm³.
This works for ANY prism: V = (cross-section area) × length.