Year 11 Physics Module 3: Waves 35 min Lesson 6 of 18

Diffraction of Waves

Waves do not always travel in straight lines past obstacles. They can spread into gaps and bend around edges. That spreading is diffraction, and it becomes most noticeable when the gap or obstacle size is similar to the wavelength.

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Think First

You can hear music around a doorway even when you cannot see the speaker directly. Why can sound spread around the opening so effectively, while visible light usually seems to travel straight through?

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📐

Key Relationship — This Lesson

Diffraction is greatest when gap size $\approx \lambda$
Longer wavelength = more noticeable diffraction Shorter wavelength = less noticeable diffraction
All waves diffract   |   Most visible when: obstacle or opening size is comparable to wavelength

≈λ
Diffraction Reference

gap $\approx \lambda$
Maximum Diffraction Condition
Most spreading happens when the opening or obstacle size is similar to the wavelength.
Use when: explaining why some waves bend strongly and others barely spread.
Common trap: diffraction does not only happen at one exact size. It becomes stronger as the size gets closer to the wavelength.
longer wavelength $\rightarrow$ more diffraction
Qualitative Comparison
Radio waves diffract more noticeably than visible light in everyday openings because their wavelengths are much larger.
Use when: comparing sound, radio, and light around obstacles.
Common trap: "light does not diffract" is false. It does diffract; it is usually just less noticeable in everyday-scale openings because its wavelength is tiny.

Know

  • What diffraction is
  • That all wave types can diffract
  • That diffraction is strongest when gap size is comparable to wavelength
  • Why long wavelengths diffract more noticeably

Understand

  • Why waves spread after passing through a narrow gap
  • Why sound bends around obstacles more noticeably than light in daily life
  • Why radio reception can persist without direct line of sight in some cases
  • Why ripple tanks are useful diffraction models

Can Do

  • Predict whether diffraction will be strong or weak
  • Explain the role of wavelength and gap size
  • Interpret simple ripple tank diffraction observations
  • Apply diffraction ideas to real contexts

Misconceptions to Fix

Wrong: Zero acceleration means an object is stationary.

Right: Zero acceleration means constant velocity — the object could be moving at constant speed in a straight line.

📚 Core Content

Key Terms
WorkThe product of force and displacement in the direction of the force; W = Fd.
EnergyThe capacity to do work, measured in joules (J).
Kinetic EnergyThe energy of motion; KE = ½mv².
Potential EnergyStored energy due to position or configuration.
PowerThe rate at which work is done or energy is transferred; P = W/t.
Conservation of EnergyThe principle that energy cannot be created or destroyed, only transformed.
01What Is Diffraction?

What Is Diffraction?

Diffraction is the spreading of waves around obstacles and through openings.

If waves pass through a very wide opening compared with their wavelength, they keep travelling in almost the same direction. If the opening becomes narrow enough relative to the wavelength, the outgoing wave spreads much more strongly. The same idea applies when waves encounter an obstacle edge — the wave bends into the shadow region behind the obstacle. This is not because the obstacle "pushes" the wave; it is a natural consequence of the wave nature of the disturbance.

Diffraction is most dramatic when the wavelength and the gap size are of the same order of magnitude. A water wave with wavelength 2 cm passing through a 2 cm gap will spread into a wide arc. The same wave passing through a 2 m gap will show almost no spreading at all. This dependence on relative size is one of the most important ideas in wave physics. It explains why some waves seem to travel in straight lines while others wrap around corners.

Key idea diffraction is a property of all waves — mechanical, electromagnetic, and matter waves.
02Why Gap Size Matters

Why Gap Size Matters

The most important comparison is not the absolute size of the gap, but the gap size relative to the wavelength.

When a wavefront reaches an opening, the edges of the opening act like new sources of circular or spherical wavelets — this is Huygens' principle in action. If the opening is very large, the edge effects are insignificant compared with the central part of the wave, so the beam continues almost straight. If the opening is small, the edge effects dominate, and the wavelets from the edges spread out across a wide angle. The transition from "straight through" to "strong spreading" happens gradually as the gap shrinks toward the wavelength.

Gap compared to wavelengthWhat happens?Example
Gap much larger than $\lambda$Little spreading, wave mostly continues straightLight through a window
Gap about equal to $\lambda$Strong diffractionSound through a doorway
Gap smaller than or comparable to $\lambda$Very strong spreadingWater waves through a narrow slit
Quick rule if the gap "matches the wavelength," expect strong diffraction.
03Why Longer Wavelengths Diffract More Noticeably

Why Longer Wavelengths Diffract More Noticeably

Long wavelengths are more likely to be comparable to everyday obstacles and openings.

Sound waves and radio waves often have wavelengths large enough that doors, buildings, or hill edges are not enormous compared with them. Visible light has a tiny wavelength (around 500 nm), so doors and walls are huge compared with the wavelength, which is why its diffraction is less obvious in everyday situations. However, scientists can create extremely narrow slits — much smaller than a human hair — to observe light diffraction clearly. This was one of the key pieces of evidence that established light as a wave.

The relationship is not that long wavelengths "like" to diffract more; it is simply that our everyday environment is built on a scale of metres and centimetres, which happens to match the wavelengths of sound and radio waves. If humans were the size of bacteria, we would notice light diffracting around specks of dust just as readily as we notice sound diffracting around doorways.

Sound

Can spread through a doorway and around corners more easily than visible light.

Radio

Long wavelengths can diffract around structures more noticeably than high-frequency light.

Visible Light

Does diffract, but the effect is usually subtle because the wavelength is so short.

Real-World Anchor AM radio waves have wavelengths of hundreds of metres. They can diffract around hills and buildings, which is why you can still pick up AM stations while driving through valleys where FM signals (shorter wavelength) drop out.
04Ripple Tank Observations

Ripple Tank Observations

Ripple tanks show diffraction clearly because we can vary the gap and watch the wavefront shape change.

A broad opening lets nearly straight wavefronts continue through. A narrow opening produces almost circular wavefronts beyond the gap. This visual evidence helps us connect the abstract rule "gap comparable to wavelength" with a clear physical observation. In the laboratory, students can place barriers with different gap widths in a ripple tank and directly observe how the spreading changes. When the gap is wide, the shadow behind the barrier is well-defined. When the gap is narrow, there is almost no shadow — the waves fill the space behind the barrier.

Ripple tanks are also excellent for demonstrating that diffraction occurs for obstacles as well as openings. A single post in a ripple tank casts a V-shaped diffraction pattern behind it. The wavelength, the obstacle size, and the angle of spreading can all be measured directly from the projected image. This hands-on evidence makes diffraction one of the most accessible wave phenomena to study experimentally.

Vector Protocol — Diffraction Predictions
Step 1 — Identify the wavelength of the wave
Step 2 — Compare the gap or obstacle size to the wavelength
Step 3 — Predict strong diffraction if gap $\approx \lambda$, weak diffraction if gap $\gg \lambda$
05Diffraction Around Obstacles

Diffraction Around Obstacles

Diffraction is not limited to openings — waves also bend around the edges of obstacles.

When a wave encounters a solid obstacle, the edge of the obstacle behaves like a new point source of wavelets. These wavelets spread into the region that would otherwise be in shadow. The amount of spreading depends on the same ratio: obstacle size compared to wavelength. A large island will cast a sharp acoustic shadow for sound waves, but a small post will not. This is why you can hear someone talking on the other side of a thin tree trunk but not on the other side of a warehouse.

Obstacle diffraction has important engineering consequences. Architects designing concert halls must account for how sound diffracts around balcony edges and columns. If the features are too large compared with sound wavelengths, they create unwanted acoustic shadows where the music sounds muffled. If the features are small, diffraction smooths the sound distribution across the audience.

Real-World Anchor Surf lifesavers at Bondi Beach can sometimes hear swimmers calling for help from behind rock outcrops because sound waves diffract around the rocks. The gaps and edges are comparable to the wavelengths of human voices, allowing the sound to wrap around into the shadow zone.
06Clearing Up Diffraction Myths

Clearing Up Diffraction Myths

A few common ideas about diffraction are wrong — and examiners know them well.

Common Misconceptions

Only small waves or weak waves diffract.
All waves diffract. The effect becomes more noticeable when the gap or obstacle size is comparable to the wavelength, but diffraction occurs regardless of amplitude or intensity.
Diffraction only happens through gaps, not around obstacles.
Waves diffract around obstacles just as they do through openings. The edge of any obstacle acts as a source of spreading wavelets.
Longer wavelengths always travel faster, which is why they diffract more.
Diffraction has nothing to do with wave speed. It depends on the ratio of wavelength to gap size. Sound diffracts more than light because its wavelength is larger, not because it travels faster or slower.

✏️ Worked Examples

Worked Example 1 Type 6 — Gap Comparison

Problem Setup

Scenario: Water waves of wavelength 2 cm pass through two gaps. Gap A is 20 cm wide. Gap B is 2.5 cm wide. Which gap shows stronger diffraction?

Solution

1
Compare each gap to wavelength
Diffraction depends on relative size, not just the gap on its own.
2
Gap A is much larger than $\lambda$; Gap B is close to $\lambda$
2.5 cm is much closer to 2 cm than 20 cm is.
3
Therefore Gap B shows much stronger diffraction
The smaller opening produces more spreading because it is comparable to the wavelength.

What would change if...

If the wavelength were made much shorter while the gap stayed 2.5 cm, the diffraction would become less noticeable.

Worked Example 2 Type 6 — Everyday Context

Problem Setup

Scenario: Explain why you can hear someone speaking around a doorway more easily than you can see them if they are fully out of sight.

Solution

1
Sound has a much longer wavelength than visible light
The doorway width is much more comparable to sound wavelengths than to light wavelengths.
2
Sound therefore diffracts more noticeably through the doorway
The wave spreads after passing through the opening.
3
Visible light diffracts too little to bend strongly around the doorway in daily life
Its wavelength is far too small compared with the doorway size, so the beam mostly travels straight.

What would change if...

If the opening were extremely tiny, even visible light could show noticeable diffraction patterns.

Worked Example 3 Type 6 — Obstacle Diffraction

Problem Setup

Scenario: A radio wave of wavelength 150 m encounters a hill that is 50 m wide. A second radio wave of wavelength 2 m encounters the same hill. Compare the diffraction of the two waves around the hill.

Solution

1
Compare hill width to each wavelength
Diffraction around an obstacle depends on the ratio of obstacle size to wavelength.
2
Wave A: hill width (50 m) is much smaller than $\lambda$ (150 m)
The obstacle is small compared with the wavelength, so diffraction will be very strong. The wave will wrap around the hill easily.
3
Wave B: hill width (50 m) is much larger than $\lambda$ (2 m)
The obstacle is enormous compared with the wavelength, so diffraction will be very weak. The wave will cast a sharp shadow behind the hill.

What would change if...

If the hill were 200 m wide, even the 150 m wave would show weaker diffraction, though still more noticeable than the 2 m wave.

Visual Break

Decision Flowchart — Predicting Diffraction

Wave approaches gap or obstacle Compare size to wavelength Gap size $\gg \lambda$ or $\approx \lambda$ ? Much larger Weak diffraction Comparable Strong diffraction What is the wavelength? Longer or shorter waves? Shorter Less obvious Longer More obvious

Copy into your books

Diffraction Definition

  • Diffraction = spreading of waves around obstacles and through openings
  • All wave types diffract
  • Not limited to gaps — obstacle edges also cause spreading
  • Explained by Huygens' principle: each point on a wavefront acts as a new source

Gap Size Rule

  • Strongest diffraction when gap size $\approx \lambda$
  • Weak diffraction when gap size $\gg \lambda$
  • Compare relative size, not absolute size
  • A narrow gap for radio waves might be wide for visible light

Wavelength and Everyday Life

  • Longer wavelengths show more noticeable diffraction
  • Sound (m–cm) diffracts around doorways
  • Radio (m–km) diffracts around hills
  • Visible light (nm) diffracts only through very tiny openings

Ripple Tank Evidence

  • Wide gap $\rightarrow$ straight wavefronts continue through
  • Narrow gap $\rightarrow$ circular wavefronts spread out
  • Obstacles cast V-shaped diffraction patterns
  • Direct visual proof of wave spreading

🏃 Activities

Activity 1

Predict the Spreading

For each case, state whether diffraction would be weak, moderate, or strong:

Activity 2

Explain the Doorway

Write two or three sentences explaining why sound diffracts around a doorway more noticeably than visible light.

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Activity 3

Obstacle Reasoning

A student says, "Only water waves diffract." Correct this statement with one clear sentence.

Activity 4

Radio vs FM Comparison

An AM radio station broadcasts at 1000 kHz (wavelength $\approx$ 300 m). An FM station broadcasts at 100 MHz (wavelength $\approx$ 3 m).

  1. Explain why AM radio is often easier to receive in hilly terrain than FM radio.
  2. Suggest why FM radio usually provides clearer, higher-fidelity sound despite this limitation.
  3. A building is 20 m wide. Will the AM signal or the FM signal diffract more around this building? Justify your answer.
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Activity 5

Design a Diffraction Experiment

You have a ripple tank, a set of barriers with different gap widths (1 cm, 5 cm, 10 cm, 20 cm), and a wave source that produces waves with wavelength 2 cm.

  1. State which gap you would use to produce the strongest diffraction. Explain your choice.
  2. Describe what you would observe with the 20 cm gap.
  3. Explain why using a gap much smaller than the wavelength would be difficult in practice.
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Interactive: Diffraction Pattern Simulator
Interactive: Diffraction Classifier
Revisit Your Thinking

Earlier you were asked why you can hear music around a doorway more easily than you can see the speaker directly.

The full answer: sound has a much longer wavelength than visible light, so a doorway is more comparable in size to the wavelength of sound. That makes diffraction more noticeable for sound. Visible light also diffracts, but far less obviously in an everyday doorway because its wavelength is tiny.

Now revisit your prediction. What role does wavelength play in your explanation?

Annotate your prediction in your book with what you now understand differently.

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Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

✅ Check Your Understanding

Multiple Choice

6 MARKS

1. Diffraction is best described as:

A
The reflection of waves from a barrier
B
The spreading of waves around obstacles and through openings
C
The change in frequency at a boundary
D
The conversion of a transverse wave into a longitudinal wave

2. Diffraction is greatest when:

A
The gap is much larger than the wavelength
B
The gap is irrelevant
C
The gap size is comparable to the wavelength
D
The frequency is zero

3. Which wave usually shows more noticeable diffraction around everyday openings?

A
Visible light
B
Blue light only
C
Any wave with the highest speed
D
Sound waves

4. A gap is 4 cm wide and the wavelength is 4 cm. The diffraction will be:

A
Strong
B
Very weak
C
Impossible
D
Zero because the values are equal

5. Which statement about diffraction is correct?

A
Only mechanical waves diffract
B
Mechanical and electromagnetic waves both diffract
C
Only light diffracts
D
Only longitudinal waves diffract

6. A wave with a longer wavelength will usually diffract more noticeably because:

A
It always travels faster
B
Its frequency is always lower than all other waves
C
Everyday gaps and obstacles are more likely to be comparable to its wavelength
D
It reflects more strongly

Short Answer

10 MARKS

7. Explain why diffraction becomes strong when the gap size is similar to the wavelength. 3 MARKS

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8. A water wave has wavelength 3 cm. Compare the expected diffraction for gaps of 30 cm and 4 cm. 3 MARKS

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9. Explain why radio waves are often more noticeable than visible light in diffraction around buildings or obstacles. 4 MARKS

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Comprehensive Answers

Multiple Choice

1. B — diffraction is the spreading of waves around obstacles and through openings.

2. C — diffraction is strongest when gap size is comparable to wavelength.

3. D — sound usually shows more noticeable diffraction around everyday openings.

4. A — a gap matching the wavelength gives strong diffraction.

5. B — all wave types can diffract.

6. C — long wavelengths are more likely to match everyday obstacle sizes.

Short Answer — Model Answers

Q7 (3 marks): Diffraction becomes strong when the gap size is similar to the wavelength because the opening is no longer extremely large compared with the wavefront spacing. In that case, the edges of the gap act as significant sources of spreading wavelets according to Huygens' principle. The wave emerging from the gap spreads out strongly instead of continuing almost straight ahead. The closer the gap is to the wavelength, the more noticeable the spreading becomes.

Q8 (3 marks): With wavelength 3 cm, a 30 cm gap is ten times larger than the wavelength, so diffraction will be weak and the wave will continue mostly straight with only slight spreading at the edges. A 4 cm gap is only slightly larger than the wavelength, so diffraction will be much stronger and the wave will spread out clearly into a wide arc after passing through the opening.

Q9 (4 marks): Radio waves often have much longer wavelengths than visible light. Because of that, buildings, doorways, and obstacle edges are more likely to be comparable to radio wavelengths than to light wavelengths. This makes diffraction more noticeable for radio waves. Visible light also diffracts, but its wavelength is so small that ordinary obstacles are enormous by comparison, so the spreading is usually much less obvious and requires specialised equipment to detect.

Activity Model Answers

Activity 2: Sound diffracts around a doorway more noticeably than visible light because the wavelength of sound is comparable to the width of a doorway, whereas the wavelength of visible light is many orders of magnitude smaller. Since diffraction is strongest when the gap size is similar to the wavelength, sound bends significantly while light travels almost straight through.

Activity 4: (1) AM radio has a much longer wavelength (≈ 300 m) than FM radio (≈ 3 m). Hills and valleys are comparable to AM wavelengths, so AM signals diffract around terrain features more effectively. FM signals have wavelengths much smaller than typical hills, so they tend to be blocked. (2) FM radio uses higher frequencies, which can carry more information and are less susceptible to certain types of electrical interference, providing clearer, higher-fidelity sound. (3) The AM signal will diffract more around the 20 m building because its wavelength (300 m) is much larger than the building, whereas the FM wavelength (3 m) is much smaller than the building.

Activity 5: (1) The 1 cm gap would produce the strongest diffraction because it is closest to the wavelength of 2 cm. (2) With the 20 cm gap, the wave would show very weak diffraction and continue almost straight through with nearly straight wavefronts. (3) A gap much smaller than the wavelength would be difficult because viscous forces and surface tension would dominate, distorting the wave and making it hard to produce clean wavefronts.

Science Jump

Jump Through Diffraction!

Scale the platforms using your knowledge of wave diffraction and interference patterns. Pool: lessons 1–6.

Mark lesson as complete

Tick when you have finished the activities and checked the answers.