Learning objective: Calculate escape speed and connect launch speed to total-energy sign in an ideal isolated two-body model.

Select Planet

Escape Velocity

v_esc = √(2GM/R)
11.19 km/s
Minimum speed to escape from surface
v_esc at altitude h
11.19 km/s
v_esc(h) = √(2GM/(R+h))
Energy condition for escape: Total energy ≥ 0
½mv² - GMm/r ≥ 0  →  v ≥ √(2GM/r) = v_esc

Three Energy Regimes

v < v_esc

7.91 km/s
E < 0 / Bound

v = v_esc

11.19 km/s
E = 0 / Threshold

v > v_esc

15.00 km/s
E > 0 / Unbound
Path-shape condition: ellipse, parabola and hyperbola describe ideal non-collision inverse-square two-body paths with suitable angular momentum. A radial path is a degenerate case.

Energy Diagram

Escape Velocity Facts

11.2 km/s
Earth
2.4 km/s
Moon
59.5 km/s
Jupiter