Short Answer, Model Answers
Q1 (a): (1) A hot dense source produces a continuous spectrum. (2) A hot thin gas produces an emission spectrum (bright lines at characteristic wavelengths). (3) A cool thin gas in front of a continuous source produces an absorption spectrum (dark lines at the same wavelengths as the emission lines of that gas) (1 mark).
Q1 (b): Atoms have discrete energy levels. An emission line is produced when an electron drops from a higher to a lower level, emitting a photon of energy $E = hf = \Delta E$. An absorption line is produced when an electron absorbs a photon of exactly the same energy and jumps to a higher level. Since the energy difference $\Delta E$ is identical for both transitions, both produce photons of the same frequency and wavelength (1 mark).
Q1 (c): The presence of Fraunhofer lines indicates that the continuous spectrum emitted by the Sun's hot, dense photosphere passes outward through cooler, less dense gas containing hydrogen, calcium and sodium. That gas absorbs photons at its characteristic wavelengths, creating the dark lines. These lines form in the cooler outer layers above the region that produces the continuous spectrum, across photospheric and overlying atmospheric layers rather than in one separate named shell (1 mark).
Q2 (a): $\Delta\lambda = 664.0 - 656.3 = 7.7$ nm. $v = c \times \Delta\lambda/\lambda_0 = 3.00\times10^8 \times 7.7/656.3 = 3.52\times10^6$ m/s $\approx$ 3520 km/s (receding) (1 mark).
Q2 (b): The orbiting planet causes its host star to wobble around the common centre of mass. This wobble produces tiny periodic Doppler shifts in the star's spectral lines, blueshift as the star moves toward us, redshift as it moves away. The period of the shift equals the planet's orbital period, and the amplitude gives the star's orbital velocity, from which the planet's minimum mass can be derived. It is only a minimum mass because the orbital inclination is unknown, if the orbit is tilted, only the radial (line-of-sight) component of velocity is measured, which is less than the true orbital speed (1 mark + 1 mark).
Q2 (c): After allowing for local peculiar velocities, the systematic increase of cosmological redshift with distance is evidence that the large-scale universe is expanding (1 mark). In the Big Bang model, extrapolating that expansion backward indicates an earlier universe that was much hotter and denser; the model does not describe ordinary matter exploding from one point into pre-existing space (1 mark).
Q3 (a)(i): $\Delta\lambda = 392.7 - 393.3 = -0.6$ nm. $v = 3.00\times10^8 \times (-0.6)/393.3 = -4.58\times10^5$ m/s $\approx$ -458 km/s (approaching).
Q3 (a)(ii): $\Delta\lambda = 393.9 - 393.3 = +0.6$ nm. $v = +4.58\times10^5$ m/s $\approx$ +458 km/s (receding). The equal speeds suggest the two stars have equal masses (since both orbit their common centre of mass at the same speed if their masses are equal).
Q3 (b): The orbital period $T$ and semi-major axis $a$ (from the Doppler velocity and period) give the total mass via Kepler's third law: $M_1 + M_2 = 4\pi^2 a^3/(GT^2)$. The ratio of the orbital speeds gives the mass ratio: $M_1/M_2 = v_2/v_1$. Together these give individual stellar masses, the only direct way to measure stellar masses accurately.
Q4 (a): Continuous spectrum: an incandescent tungsten filament (light bulb), a hot dense solid. Emission spectrum: a discharge tube (hydrogen or neon gas excited by high voltage), a hot thin gas. Absorption spectrum: reflected sunlight viewed through a prism or spectroscope, showing dark Fraunhofer lines from the Sun's cooler outer atmosphere.
Q4 (b): The tungsten bulb shows a smooth, unbroken rainbow (continuous spectrum) because its atoms are packed closely together as a hot dense solid, so an enormous range of overlapping energy transitions smears into a continuous range of wavelengths. The hydrogen discharge tube shows only a few bright lines at fixed wavelengths (an emission spectrum) because hydrogen is a hot, thin gas whose isolated atoms have discrete energy levels, so photons are emitted only at the specific wavelengths matching the gaps between those levels.
Q5 (a): Star X's broader lines indicate a denser (higher-pressure) atmosphere. In a dense gas, atoms collide with each other far more often, and each collision briefly perturbs the colliding atoms' energy levels, so the exact transition wavelength varies slightly from atom to atom, smearing what would be a sharp line into a broad band, pressure (collisional) broadening.
Q5 (b): Star X (broad lines, dense atmosphere) is more likely a compact, high-gravity dwarf star. Star Y (narrow, sharp lines, diffuse atmosphere) is more likely an extended, low-gravity giant star.
Q5 (c): Line position (which wavelength the line sits at) reveals composition (which element), and shifts in position reveal velocity (Doppler shift) and, combined with the overall spectral pattern, temperature. Line width is a completely separate piece of information, it does not depend on where the line sits, only on how smeared it is, so it lets astronomers determine density (dwarf vs giant) even when two stars have identical composition, temperature and velocity.