Year 12 Physics Module 7 ⏱ ~45 min 5 MC · 5 Short Answer Lesson 6 of 14

Spectroscopy and Astronomical Applications

In 1925 Cecilia Payne at Harvard College Observatory analysed the spectra of more than 300 stars and concluded that stars are 73% hydrogen and 25% helium by mass, far more hydrogen-rich than anyone had believed. Her supervisor Henry Russell dismissed the finding; four years later he confirmed it independently and acknowledged her priority. Payne's result, enabled entirely by spectroscopy, is the most important finding in the history of stellar physics.

Today's hook: In 1925 Cecilia Payne at Harvard College Observatory studied the spectra of more than 300 stars. The absorption lines told her that stars are 73% hydrogen and 25% helium, but when she submitted her thesis, her supervisor declared the result "impossible." Where do these dark lines come from, and what can they really tell us about the composition of objects billions of kilometres away?
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You’re here

Orient and predict

Predict where the dark lines in sunlight go, then set your goals and vocabulary for spectroscopy.

Warm up first

Three quick questions from earlier lessons. Pulling old material back to mind before you learn something new makes the new material stick better, so this is not busywork.

Worksheets

Practise this lesson

Four printable worksheets that build from the foundations up to exam-style questions, start at whatever level suits you.

Before you read, predict

When white light from the Sun passes through a prism, it produces a continuous rainbow spectrum. But when passed through cool gas before reaching the prism, dark lines appear at specific colours.

  1. Why are the dark lines dark? Where did that specific colour of light go?
  2. Why would a hot gas produce bright lines at those same colours?
  3. How might an astronomer use these lines to determine what a distant star is made of?

Write your predictions before reading on, you will revisit them at the end.

Warm-up, which type of spectrum is produced by a hot thin gas?

Learning Intentions
goals

Know, Spectra Types

  • Continuous, emission and absorption spectra
  • Kirchhoff's laws of spectroscopy
  • Spectral lines as atomic fingerprints

Understand, Doppler Effect for Light

  • Redshift: source moving away ($\lambda$ increases)
  • Blueshift: source moving toward ($\lambda$ decreases)
  • $\Delta\lambda/\lambda_0 = v/c$ for $v \ll c$

Can Do, Analyse Spectral Data

  • Identify elements from spectral lines
  • Calculate velocities from Doppler shifts
  • Interpret astronomical spectra
Scan these before reading
vocab
SpectroscopyThe study of the interaction between matter and electromagnetic radiation as a function of wavelength.
Emission spectrumA spectrum of bright lines at specific wavelengths produced by excited atoms transitioning to lower energy levels.
Absorption spectrumA continuous spectrum with dark lines at wavelengths where photons have been absorbed by atoms in a cool gas.
Fraunhofer linesDark absorption lines in the Sun's spectrum caused by elements in the cooler solar atmosphere absorbing photons from the hotter interior.
RedshiftThe increase in wavelength (shift toward red) of light from a source moving away from the observer.
BlueshiftThe decrease in wavelength (shift toward blue) of light from a source moving toward the observer.
Cross-lesson links: L01–L05 showed light behaves as a wave. L09 introduces atomic spectra, the discrete emission and absorption lines that the classical wave model cannot explain. Cecilia Payne's 1925 Harvard analysis of 300+ stellar spectra (73% hydrogen, 25% helium by mass) shows what spectroscopy can reveal. In L10 you will see how the photoelectric effect and the UV catastrophe further break the classical wave model, motivating the quantum revolution.
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Classify spectra with Kirchhoff's laws

Match continuous, emission and absorption spectra to their sources, then explain each with energy levels.

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Types of Spectra, Kirchhoff's Laws
+5 XP

Kirchhoff's laws and the quantum explanation

In the 1850s, Gustav Kirchhoff and Robert Bunsen systematically studied the spectra of different elements heated in flames. They established three laws that form the foundation of spectroscopy:

  1. A hot solid, liquid or dense gas produces a continuous spectrum a complete rainbow without gaps.
  2. A hot thin gas produces an emission spectrum bright lines at specific wavelengths, unique to each element.
  3. A cool thin gas in front of a continuous source produces an absorption spectrum a rainbow with dark lines at the same wavelengths as the emission lines of that gas.
Continuous Hot solid/dense gas Emission Hot thin gas Absorption Cool gas + hot source Quantum Explanation Atoms absorb/emit photons with E = hf = ΔE_levels Each element has unique energy levels → unique spectral lines Emission: electron drops to lower level, emits photon Absorption: electron absorbs photon, jumps to higher level

Figure 1, Kirchhoff's three spectra: continuous (hot dense source), emission (bright lines from hot thin gas), and absorption (dark lines on continuous background from cool gas in front of hot source)

The quantum mechanical explanation is elegant: atoms exist in discrete energy levels. When an electron drops from a higher level to a lower one, it emits a photon with energy equal to the difference: $E = hf = E_{upper} - E_{lower}$. Since each element has a unique set of energy levels, each produces a unique pattern of spectral lines, an atomic fingerprint.

In absorption, a photon of exactly the right energy excites an electron from a lower level to a higher one, removing that wavelength from the transmitted beam. The dark absorption lines in the Sun's spectrum (called Fraunhofer lines) reveal the presence of elements like hydrogen, sodium, iron and calcium in the cooler outer layers of the Sun.

Stop & Check

Astronomers observe a star and find dark lines in its spectrum at the exact wavelengths where hydrogen emits light. Explain what this tells us about the star's atmosphere. Why don't we see hydrogen emission lines from the star itself?

Kirchhoff's three spectral laws: (1) hot dense source → continuous spectrum; (2) hot thin gas → emission spectrum (bright lines); (3) cool thin gas in front of hot source → absorption spectrum (dark lines at the same wavelengths as that element's emission lines). Each element's unique energy levels produce a unique spectral fingerprint.

Pause, copy the highlighted three laws into your book before moving on.

A cool cloud of sodium gas sits between an observer and a hot star. The observer sees a continuous spectrum with dark lines. Those dark lines appear at exactly the same wavelengths as the bright lines in sodium's emission spectrum because:

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Identify real spectral sources

Link filaments, discharge tubes and reflected sunlight to the spectrum each one actually produces.

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Real Spectral Sources, Filaments, Discharge Tubes and Sunlight
+5 XP

NESA syllabus (IQ1, dot point 4): spectra produced by discharge tubes, incandescent filaments and reflected sunlight

We just saw Kirchhoff's three abstract categories, continuous, emission and absorption spectra. That raises a question: what real, physical equipment in a lab or in nature actually produces each type? This card answers it → the tungsten filament, the discharge tube and reflected sunlight, three concrete real-world sources you could point to and photograph.

Kirchhoff's laws describe categories of spectra, but the NESA syllabus asks you to identify the actual apparatus that produces each one. Three real sources map directly onto the three spectrum types.

Incandescent filaments (continuous spectrum): A tungsten light bulb filament is heated by an electric current to roughly 2,700-3,000 K, hot enough to glow white. Because tungsten is a hot, dense solid, its atoms are packed closely together and constantly colliding, so instead of isolated sharp transitions, an enormous range of energy transitions overlap and smear together, producing a smooth, continuous (approximately black-body) spectrum across all visible wavelengths. This is the classic real-world source of Kirchhoff's first law.

Discharge tubes (emission spectrum): A discharge tube is a sealed glass tube containing a low-pressure gas, hydrogen or neon are common examples, with electrodes at each end. A high voltage strips electrons from the gas atoms and accelerates them, and as excited electrons fall back to lower energy levels they emit photons only at the specific wavelengths corresponding to that gas's discrete energy-level gaps. A hydrogen discharge tube shows four visible lines (656 nm red, 486 nm blue-green, 434 nm blue-violet, 410 nm violet), the same Balmer lines used to identify hydrogen in stars. A neon discharge tube glows orange-red because neon's strongest visible transitions cluster in that part of the spectrum, the physical basis of "neon" signage. This is the classic real-world source of Kirchhoff's second law.

Reflected sunlight (absorption spectrum): The Sun's photosphere is a hot, dense layer that behaves like an incandescent filament, producing a continuous spectrum. But that light must pass through the Sun's own cooler outer atmosphere (and reflect off the Moon, a planet, or a mirror, and pass through Earth's atmosphere) before it reaches your spectroscope. Cooler gas atoms along the path absorb photons at their characteristic wavelengths, removing those exact colours from the transmitted beam. Passing reflected sunlight through a prism or spectroscope reveals a continuous rainbow interrupted by thousands of dark Fraunhofer absorption lines, the classic real-world source of Kirchhoff's third law, and the same physical principle whether the sunlight reaches you directly or reflected from the Moon.

Incandescent Filament Tungsten bulb, ~2900 K Continuous spectrum Discharge Tube H₂ or Ne gas, high voltage Emission spectrum Reflected Sunlight Sun (photosphere) Prism Absorption (Fraunhofer) spectrum

Figure 1b, Three real apparatus sources matched to Kirchhoff's three spectrum types: a tungsten filament (continuous), a hydrogen or neon discharge tube (emission), and reflected sunlight through a prism, showing dark Fraunhofer lines (absorption)

Stop & Check

A neon sign glows a distinctive orange-red, and a spectroscope aimed at it shows only a few bright lines, no continuous rainbow. Identify the real-world source type and explain, using Kirchhoff's laws, why only discrete lines appear rather than a continuous spectrum.

Three real-world sources, one per Kirchhoff law: incandescent filaments (tungsten light bulb, ~2900 K) produce continuous spectra; discharge tubes (hydrogen or neon gas excited by high voltage) produce emission (bright-line) spectra; reflected sunlight through a prism or spectroscope shows a continuous spectrum with dark Fraunhofer absorption lines from the Sun's cooler outer atmosphere.

Copy the three apparatus-to-spectrum matches into your book before the check below.

Which real-world apparatus is the classic source of an emission (bright-line) spectrum?

4

Read motion from a Doppler shift

Get the sign convention right for redshift and blueshift, and use the low-speed approximation safely.

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The Doppler Effect for Light
+5 XP

Motion written in wavelengths, redshift and blueshift

We just saw that spectral lines act as element fingerprints. That raises a question: what happens to those lines when a source is moving relative to us? This card answers it → the Doppler effect shifts wavelengths, giving redshift (receding) or blueshift (approaching), quantified by $\Delta\lambda/\lambda_0 = v/c$.

When a light source moves relative to an observer, the observed wavelength shifts. This is the Doppler effect for light. Unlike the Doppler effect for sound, the shift in light depends only on the relative velocity between source and observer.

  • Moving away (receding): Wavelength increases → redshift ($\lambda_{obs} > \lambda_0$)
  • Moving toward (approaching): Wavelength decreases → blueshift ($\lambda_{obs} < \lambda_0$)

For speeds much less than $c$ ($v \ll c$), the fractional shift is:

Non-relativistic Doppler Shift

$$\dfrac{\Delta\lambda}{\lambda_0} = \dfrac{v}{c}$$

where $\Delta\lambda = \lambda_{obs} - \lambda_0$; positive $v$ = receding (redshift); negative $v$ = approaching (blueshift)

Redshift Parameter

$$z = \dfrac{\Delta\lambda}{\lambda_0} = \dfrac{v}{c} \qquad \Rightarrow \qquad \lambda_{obs} = \lambda_0(1 + z)$$

Rest (λ₀) Redshift (away) Blueshift (toward) λ_obs > λ₀ λ_obs < λ₀ 380 nm 750 nm Wavelength →

Figure 2, The H-alpha line (656 nm at rest) shifts to longer wavelengths (red) when the source recedes, and to shorter wavelengths (blue) when it approaches

Astronomical applications of the Doppler effect:

  • Stellar radial velocities: Measuring how fast stars move toward or away from us along the line of sight.
  • Binary stars: Periodic Doppler shifts reveal stars orbiting each other, the line shifts back and forth with the orbital period.
  • Exoplanet detection: A star's small wobble induced by an orbiting planet produces tiny but measurable Doppler shifts (the radial velocity method).
  • Galaxy recession (Hubble's Law): Measurements showed that more distant galaxies generally have larger redshifts, approximately described at low redshift by $v = H_0 d$. This distance-redshift relation became major evidence for cosmic expansion; it was not the only evidence.
  • Galactic rotation: One side of a rotating galaxy is blueshifted, the other redshifted, revealing rotation speeds and evidence for dark matter.
Stop & Check

The H$\alpha$ line of hydrogen has a rest wavelength of 656.3 nm. In the spectrum of a distant galaxy, this line is observed at 675.0 nm. Calculate the galaxy's recession velocity as a fraction of $c$. Is this galaxy moving toward or away from us?

Doppler shift (non-relativistic): $\Delta\lambda/\lambda_0 = v/c$, so $v = c\Delta\lambda/\lambda_0$. Positive $\Delta\lambda$ → redshift (receding); negative → blueshift (approaching). Redshift parameter $z = \Delta\lambda/\lambda_0$; observed wavelength $\lambda_{obs} = \lambda_0(1+z)$.

Add the highlighted Doppler formula and sign convention to your notes before the check below.

A spectral line with rest wavelength 500 nm is observed at 505 nm. The source's recession velocity is:

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Solve a Doppler worked example

Work the H-alpha shift line by line, checking that the low-speed approximation is justified.

Beyond the syllabus. Spectra sources, element identification, temperature, motion and density evidence are core. Hubble-distance calculations, Big Bang discussion, exoplanet minimum-mass analysis, binary-star mass derivations and dark-matter rotation detail are extension here — some of it returns as core in Module 8. The exam assesses what a spectrum tells you about a star.
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Worked Example, Doppler Shifts and Stellar Motion
+5 XP

Reading velocity from spectral lines

We just saw the Doppler formula $v = c\Delta\lambda/\lambda_0$. That raises a question: how do you apply this to find stellar velocities, distinguish approaching from receding stars, and interpret binary systems? This card answers it → multi-part worked example with sign convention and binary interpretation.

Problem

A distant star has a spectral line of ionised calcium (Ca II) with a rest wavelength of 393.3 nm. In the star's observed spectrum, this line appears at 394.2 nm.

  1. Calculate the Doppler shift $\Delta\lambda$.
  2. Calculate the star's radial velocity. Is it approaching or receding?
  3. Another star shows the same Ca II line at 392.5 nm. Calculate its radial velocity.
  4. A binary star system shows periodic variation in the Ca II line from 393.0 nm to 393.6 nm with a period of 14 days. Explain what this reveals about the system.
Step 1, Doppler shift

$\Delta\lambda = \lambda_{obs} - \lambda_0 = 394.2 - 393.3 = $ 0.9 nm

Step 2, Radial velocity (Star 1)

$v = c \times \dfrac{\Delta\lambda}{\lambda_0} = 3.00\times10^8 \times \dfrac{0.9}{393.3} = 6.87\times10^5\ \text{m/s} \approx \textbf{687 km/s}$

Positive $\Delta\lambda$ → receding (redshift).

Step 3, Radial velocity (Star 2)

$\Delta\lambda = 392.5 - 393.3 = -0.8\ \text{nm}$

$v = 3.00\times10^8 \times \dfrac{-0.8}{393.3} = -6.10\times10^5\ \text{m/s} \approx \textbf{-610 km/s}$

Negative velocity → approaching (blueshift).

Step 4, Binary system interpretation

The periodic variation reveals the star is in orbit around an unseen companion. When moving toward us the line is blueshifted (393.0 nm); when moving away it is redshifted (393.6 nm). The 14-day period is the orbital period. From the velocity amplitude and period, astronomers can determine the companion's minimum mass, a key method for detecting exoplanets.

HSC Tip, Doppler Sign Convention

The most common error: using $\lambda_{obs}/\lambda_0 = v/c$ instead of $\Delta\lambda/\lambda_0 = v/c$. The correct form uses the shift, not the observed wavelength. Sign rule: positive $\Delta\lambda$ = receding (redshift); negative $\Delta\lambda$ = approaching (blueshift). Also note: this non-relativistic formula is only valid for $v \ll c$. For distant galaxies with large $z$, the relativistic formula is required.

Stop & Check

The sodium D-lines have rest wavelengths of 589.0 nm and 589.6 nm. In a galaxy's spectrum, they appear at 601.0 nm and 601.6 nm. Calculate the galaxy's redshift $z$ and recession velocity.

Applying the Doppler formula: $v = c \cdot \Delta\lambda/\lambda_0$ where $\Delta\lambda = \lambda_{obs} - \lambda_0$. Positive $\Delta\lambda$ → receding; negative → approaching. Periodic Doppler shifts in binary systems reveal orbital period and unseen companion mass; tiny periodic shifts indicate exoplanet "wobble."

Pause, write the highlighted calculation method into your book before the check below.

A star's spectrum shows periodic Doppler shifts with a period of 3 years, with maximum blueshift and redshift of 20 km/s each. This is best explained by:

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Infer stellar and galactic properties from starlight

Turn line position and shift into composition, temperature, velocity, rotation and recession distance.

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Astronomical Spectroscopy, What Starlight Tells Us
+5 XP

Stellar composition, temperature, and the expanding universe

We just saw how Doppler shifts reveal stellar radial velocities. That raises a question: what else can spectroscopy tell us about stars and the universe? This card answers it → composition from Fraunhofer lines, temperature from spectral class, and Hubble's Law as evidence for expansion.

Spectroscopy is the dominant observational tool in astrophysics. Without ever visiting a star, astronomers can determine its composition, temperature, luminosity, magnetic field strength, rotation, and radial velocity.

Stellar composition from Fraunhofer lines: The Sun's spectrum contains thousands of dark absorption lines. By matching their wavelengths to laboratory spectra of known elements, astronomers identified hydrogen (most abundant), helium, calcium, sodium, magnesium, iron and many other elements. The same technique works for all stars.

Stellar temperature from spectral class: Hotter stars excite higher energy transitions, producing spectral lines from more highly ionised elements. Cooler stars show molecular bands. This is the basis of the stellar classification system (O, B, A, F, G, K, M), from hottest (O, ~50,000 K) to coolest (M, ~3,000 K).

Hubble's Law and the expanding universe: Edwin Hubble (1929) discovered that almost all galaxies show redshift, and that more distant galaxies recede faster:

Hubble's Law

$$v = H_0 \, d$$

$v$ = recession velocity (km/s), $H_0 \approx 70$ km/s/Mpc = Hubble constant, $d$ = distance (Mpc)

This was the first direct evidence that the universe is expanding. Running the expansion backward suggests all matter originated in a single event, the Big Bang.

Distance (Mpc) Recession velocity(km/s) v = H₀d Hubble's Law, Velocity vs Distance Each red dot = a galaxy; slope = H₀ ≈ 70 km/s/Mpc

Figure 3, Hubble diagram: recession velocity of galaxies is proportional to their distance. The slope of the best-fit line is the Hubble constant $H_0$

Stop & Check

A galaxy is observed to have a redshift of $z = 0.05$. (a) Calculate its recession velocity. (b) Using $H_0 = 70$ km/s/Mpc, estimate its distance. (c) Explain why spectroscopy is described as the most important observational tool in astronomy.

Fraunhofer (absorption) lines reveal stellar composition; spectral class (O→M) reflects surface temperature. Hubble's Law: $v = H_0 d$ ($H_0 \approx 70$ km/s/Mpc), more distant galaxies recede faster, providing evidence for an expanding universe and the Big Bang model.

Add the highlighted laws and their significance to your notes before the check below.

A galaxy has a redshift $z = 0.05$. Its recession velocity is approximately:

7

Use line width as density evidence

Read pressure broadening from a line profile and separate what width tells you from what position tells you.

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Pressure Broadening, What Line Width Reveals About Density
+5 XP

NESA syllabus (IQ1, dot point 6): the spectra of stars reveal density, not just composition, temperature and velocity

We just saw that Doppler shifts reveal a star's velocity, Fraunhofer lines reveal composition, and spectral class reveals temperature. That raises a question: the syllabus also says stellar spectra reveal density, so what spectral feature could possibly encode that? This card answers it → pressure broadening, the width of a spectral line, not just its position, carries information about the density of the gas that produced it.

So far every property (composition, temperature, velocity) has come from the position of spectral lines, which wavelength they sit at. Density is different: it is read from the width of the lines, how sharp or smeared out they are.

In a low-density gas, atoms are far apart and rarely collide during the brief moment they emit or absorb a photon. Each atom's energy levels are essentially undisturbed, so every atom of a given element produces a photon at almost exactly the same wavelength, giving a narrow, sharp spectral line. In a high-density (high-pressure) gas, atoms are packed closely together and collide with each other far more frequently. Each collision briefly perturbs a nearby atom's electric field and energy levels, so the exact transition energy varies slightly from atom to atom and from instant to instant. Averaged over billions of atoms, this collisional perturbation, called pressure broadening (or collisional broadening), smears a would-be sharp line into a noticeably wider band of wavelengths.

This gives astronomers a direct observational handle on stellar atmospheric density: a compact, high-gravity star (a dwarf star, including white dwarfs) has a dense, high-pressure atmosphere with frequent particle collisions, producing broad, smeared spectral lines. A large, extended, low-gravity star (a giant star) has a diffuse, low-pressure atmosphere with far less frequent collisions, producing narrow, sharp spectral lines, even if the giant and the dwarf have the same surface temperature (the same spectral class, so the same set of lines at the same wavelengths). Line width is therefore how astronomers distinguish luminosity classes, dwarfs from giants of the same spectral type, an axis of information completely independent of the line's wavelength.

Wavelength (around the same rest line, both stars same temperature) Giant star, low density narrow, sharp line Dwarf star, high density broad, smeared line (pressure broadening)

Figure 3b, Two stars of identical surface temperature and composition can show the same spectral line at the same central wavelength, but a dense dwarf star's frequent particle collisions smear the line into a broad profile, while a diffuse giant star's rare collisions leave it narrow and sharp

Stop & Check

Two stars have identical surface temperature and identical spectral lines (same composition). Star A's hydrogen absorption lines are narrow and sharp; Star B's are broad and smeared. Which star is more likely a giant and which a dwarf? Explain using pressure broadening.

Pressure (collisional) broadening: in a dense, high-pressure stellar atmosphere, frequent particle collisions perturb atomic energy levels, smearing spectral lines into broad profiles. In a diffuse, low-pressure atmosphere, rare collisions leave lines narrow and sharp. Line width (not position) is how spectroscopy reveals stellar density, letting astronomers distinguish a dense dwarf star from a diffuse giant of the same temperature.

Add the highlighted pressure-broadening principle to your notes before the check below.

Two stars have the same surface temperature and the same spectral lines, but Star X's lines are much broader than Star Y's. This is best explained by:

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Simulate spectra and apply the method

Drive the spectral line simulator, then analyse real astronomical spectra end to end.

Activity 1, Spectral Line Simulator
ApplyBand 4

Observe Kirchhoff's laws and Doppler shifts interactively

z = 0.000
Hα observed: 656 nm
v = 0 km/s
  1. Select Emission spectrum. Identify the four hydrogen lines shown. Increase the redshift and observe how the lines move to longer wavelengths.
  2. Select Absorption spectrum. At z = 0, explain why the dark lines appear at the same wavelengths as the emission lines of hydrogen.
  3. Set z = 0.03. Calculate the recession velocity in km/s. At what observed wavelength does H$\alpha$ ($\lambda_0 = 656$ nm) now appear?
  4. A star shows a blueshift of 0.5% in its spectral lines (z = −0.005). Calculate its approach velocity. Would this be detectable with a modern spectrograph?
Activity 2, Astronomical Spectroscopy Analysis
AnalyseBand 5

Apply Kirchhoff's laws and Doppler shift to real scenarios

  1. A spectrum of a distant star shows dark lines at 397 nm, 410 nm, 434 nm, 486 nm and 656 nm. Identify the element present and state which of Kirchhoff's laws applies. Explain what the star's atmospheric structure must be.
  2. The H$\alpha$ line ($\lambda_0 = 656.3$ nm) in a galaxy's spectrum is observed at 664.0 nm. (a) Calculate $\Delta\lambda$, (b) calculate $z$, (c) calculate the recession velocity, and (d) estimate the distance using $H_0 = 70$ km/s/Mpc.
  3. A planet is detected around a star using the radial velocity method. The star's Ca II line (393.3 nm) shifts between 393.29 nm and 393.31 nm with a period of 365 days. (a) Calculate the maximum Doppler velocity of the star. (b) Explain what this tells us about the planet. (c) Why does the method give only a minimum mass for the planet?