Year 12 PhysicsModule 8⌛ ~20 min5 MC · 2 Short AnswerLesson 7 of 17
Nucleosynthesis and the Origin of Elements
In 1957 Margaret Burbidge, Geoffrey Burbidge, William Fowler and Fred Hoyle published a single paper, known ever since as B2FH, that traced almost every element heavier than helium to nuclear reactions inside stars. Hoyle had already predicted a specific energy level in carbon-12 purely because carbon exists at all, and experiment found it exactly where he said. Their work explains why hydrogen still makes up about three quarters of ordinary matter, why iron sits at a turning point, and why the atoms in your body were assembled in stars that died before the Sun formed.
Today's hook: The first few minutes after the Big Bang made hydrogen and helium and almost nothing else. Every carbon atom in your cells, every oxygen atom you breathe and every iron atom in your blood was built later, inside stars, by fusion that releases energy only up to iron. Past iron the arithmetic reverses and fusion costs energy, yet gold, uranium and lead all exist. Where did the elements heavier than iron come from?
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You're here
Orient and predict
Set up the vocabulary for nucleosynthetic sites and binding energy, then predict why the elements are so unevenly abundant.
Warm up first
Three quick questions from earlier lessons. Pulling old material back to mind before you learn something new makes the new material stick better, so this is not busywork.
Worksheets
Practise this lesson
Four printable worksheets that build from the foundations up to exam-style questions, start at whatever level suits you.
Mass defect ($\Delta m$)The difference in mass between reactants and products in a nuclear reaction; related to energy by $E = \Delta m c^2$.
Cross-lesson links: L06 showed how stars generate energy through fusion and how a star’s mass sets its fate. L07 asks where the atoms themselves came from, tracing each element to Big Bang nucleosynthesis, fusion in stellar cores, or neutron capture. The binding energy curve introduced here underpins nuclear stability in L14, and the supernovae that scatter these elements into space are the subject of L10.
Core Content
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Map the first elements
Trace what the first three minutes actually produced, and why Big Bang nucleosynthesis stopped at lithium.
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Big Bang Nucleosynthesis
+5 XP
The first elements forged in the hot early universe
The universe today is approximately 73% hydrogen and 25% helium by mass, far more helium than stars alone could ever produce in 13.8 billion years. This ratio is a fossil record of the first three minutes after the Big Bang, when the universe was hot and dense enough for nuclear fusion to occur. This process, Big Bang nucleosynthesis (BBN), produced:
Hydrogen (~75% by mass): Protons that never fused.
Helium-4 (~25% by mass): From fusion of protons and neutrons.
Trace deuterium, helium-3, and lithium-7: Small amounts produced before the universe cooled below fusion temperatures.
By the time the universe cooled to ~$10^9$ K (about 3 minutes), the density had dropped too low for further fusion. No elements heavier than lithium-7 were produced. The observed primordial helium abundance (~24–25%) and deuterium abundance are powerful confirmations of the Big Bang model, no alternative theory predicts these exact values.
Stop and check
Why did Big Bang nucleosynthesis stop after only three minutes? What prevented the formation of carbon and heavier elements?
Big Bang nucleosynthesis (first ~3 minutes) produced ~75% H and ~25% He-4 by mass, plus trace D, He-3, and Li-7; no heavier elements formed because the universe cooled below $10^9$ K and became too dilute for further fusion. The observed primordial He abundance (~24–25%) precisely confirms the Big Bang model.
Pause, copy the highlighted definition into your book before moving on.
Big Bang nucleosynthesis produced approximately what proportion of helium-4 by mass?
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Read the binding-energy curve
Use the broad maximum near iron-56 to explain why fusion of lighter nuclei releases energy and fusion well beyond the iron group absorbs energy.
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The Binding Energy Curve
+5 XP
Why fusion and fission release energy
We just saw that Big Bang nucleosynthesis produced H and He but stopped before forming anything heavier. That raises a question: why does any nuclear reaction release energy at all, and why is iron special? This card answers it → via the binding energy per nucleon curve, whose broad maximum lies in the iron-nickel region (~8.8 MeV/nucleon); Fe-56 is close to this maximum, and both fusion of lighter nuclei and fission of heavier nuclei move products toward it, via $E = \Delta m c^2$.
The binding energy per nucleon curve shows how much energy is required to remove a nucleon from a nucleus. It has a broad maximum in the iron-nickel region (mass numbers roughly 56 to 62, about 8.8 MeV/nucleon). Iron-56 lies close to this maximum and is a useful representative of the iron group; energy-releasing fusion in massive stars ends near this region.
Fusion of light nuclei (left side of peak): Moving toward iron increases binding energy per nucleon, so energy is released.
Fission of heavy nuclei (right side of peak): Moving toward iron also increases binding energy per nucleon, so energy is released.
Fusion beyond iron: Moving away from iron decreases binding energy per nucleon, so energy must be absorbed: this is why stars cannot fuse iron into heavier elements.
The mass defect $\Delta m$ in any nuclear reaction relates to energy via $E = \Delta m c^2$:
$$\Delta m = \text{(mass of reactants)} - \text{(mass of products)}$$
If $\Delta m > 0$, energy is released. For fusion up to iron and fission of very heavy elements, $\Delta m > 0$.
Figure 1, Binding energy per nucleon has a broad maximum in the iron-nickel region; iron-56 is near it (~8.8 MeV). Fusion releases energy for light nuclei (left of peak); fission releases energy for heavy nuclei (right of peak).Text description
A graph of binding energy per nucleon (MeV) against mass number A, from hydrogen to uranium.
It rises steeply through the light nuclei (helium-4 stands out at about 7.1 MeV), has a broad maximum near iron-56 at about 8.8 MeV, then falls slowly to about 7.6 MeV for uranium.
Fusion of light nuclei (left of the peak) and fission of heavy nuclei (right of the peak) both move towards the peak, so both release energy.
Mass Defect and Binding Energy
$\Delta m = m_\text{reactants} - m_\text{products}$, mass defect
$E = \Delta m c^2$, energy released (J) when $\Delta m$ in kg
$E = \Delta m \times 931.5\ \text{MeV}$, when $\Delta m$ in atomic mass units (u)
The net proton-proton chain is $4p \rightarrow \alpha + 2e^+ + 2\nu_e$. Calculate its nuclear Q-value before positron annihilation using $m_p = 1.00727647$ u, $m_\alpha = 4.00150618$ u, and $m_e = 0.00054858$ u. Then calculate the gross release if both positrons annihilate with ambient electrons. Use 1 u = 931.5 MeV/$c^2$ and $2m_ec^2 = 1.022$ MeV.
Binding energy per nucleon peaks in the iron-nickel region, mass number roughly 56 to 62 (~8.8 MeV/nucleon); Fe-56 is the endpoint of stellar fusion. Fusion of light nuclei up to iron releases energy ($\Delta m > 0$); fusion beyond iron absorbs energy. $E = \Delta m \times 931.5$ MeV (with $\Delta m$ in u). For the complete pp-chain, $4p \rightarrow \alpha + 2e^+ + 2\nu_e$. The nuclear Q-value is about 24.69 MeV before positron annihilation; annihilation of the two positrons with two ambient electrons adds $4m_ec^2 \approx 2.04$ MeV, for about 26.73 MeV gross before subtracting the energy carried away by neutrinos. Alpha-particle binding energy is a separate comparison: $2m_p + 2m_n - m_\alpha \approx 0.03038$ u, or 28.3 MeV.
Add the highlighted formula and worked example to your notes before the check below.
Fusion of nuclei lighter than iron releases energy because the products have higher binding energy per nucleon.
Iron-56 has the greatest binding energy per nucleon of all nuclei, so it is the most stable.
Fission of uranium releases energy because the fragments are closer to the peak of the binding energy curve.
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Compare the s-process and the r-process
Follow neutron capture past the iron peak, then work a mass defect from the fusion figures.
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Heavy Element Production: r-process and s-process
+5 XP
Neutron capture builds elements beyond iron
We just saw that fusion beyond iron-56 is endothermic, stars cannot make heavier elements by fusion. That raises a question: where do gold, platinum, and uranium come from? This card answers it → via neutron capture (s-process in AGB stars; r-process in supernovae and neutron star mergers), with the r-process confirmed by the 2017 kilonova GW170817.
Since fusion cannot produce elements heavier than iron, nature uses neutron capture instead. A nucleus absorbs a neutron to form a heavier isotope; if that isotope is unstable it undergoes beta decay, increasing atomic number by one. There are two main capture processes:
The s-process (slow neutron capture):
Occurs in late-stage low- to intermediate-mass stars (asymptotic giant branch, AGB, stars).
Neutrons are captured slowly, one at a time, with time for beta decay between captures.
Produces roughly half the heavy elements, including strontium, barium, and lead.
Occurs in supernova explosions and neutron star mergers.
Extremely high neutron flux: nuclei capture many neutrons before they can beta-decay.
Builds very neutron-rich nuclei far from stability, which then decay to stable heavy elements.
Produces the other half of heavy elements, including gold, platinum, and uranium.
The 2017 gravitational wave event GW170817, produced by merging neutron stars, was followed by an optical counterpart (a "kilonova") rich in heavy elements. This confirmed that neutron star mergers are major sites of r-process nucleosynthesis.
Figure 2, Summary of nucleosynthetic sites and the elements they produce.Text description
Big Bang (< 3 min): H (~75%), He (~25%), traces of Li.
r-process means rapid neutron capture; s-process means slow neutron capture; AGB means asymptotic giant branch.
Stop and check
Distinguish between the s-process and the r-process. Why does the r-process produce different isotopes than the s-process?
s-process (slow neutron capture in AGB stars): time for beta decay between captures → produces Sr, Ba, Pb. r-process (rapid neutron capture in supernovae and neutron star mergers): many captures before decay → produces more neutron-rich, heavier isotopes including Au, Pt, U. GW170817 kilonova (2017) confirmed neutron star mergers as a major r-process site.
Pause, write the highlighted distinctions into your book before the check below.
The alpha-particle binding-energy mass difference, $2m_p + 2m_n - m_\alpha$, using $m_p=1.007276$ u, $m_n=1.008665$ u and $m_\alpha=4.001506$ u, is _____ u (give 4 sig. figs).
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Apply the mass-defect calculations
Check the unit traps for atomic mass units and MeV, then run the energy calculations yourself.
HSC Tip, Nucleosynthesis and Binding Energy
Exam questions often ask you to identify where specific elements were produced. Remember: H and He from the Big Bang; C, O from low-mass stellar cores (triple-alpha); elements up to Fe from massive star cores; elements beyond Fe from supernovae (r-process) and neutron star mergers. The binding energy per nucleon curve is central, and the curve has a broad maximum in the iron-nickel region; iron-56 is near this maximum and often represents the iron group in HSC explanations. Strictly, nickel-62 has the highest binding energy per nucleon, with iron-58 and iron-56 close behind. Iron-56 has the lowest mass per nucleon of any nuclide and is where fusion in massive stars stops. A common trap: saying fusion produces elements heavier than iron. It does not, fusion beyond iron is endothermic. Heavy elements require neutron capture (r-process or s-process). When calculating mass defect, use atomic mass units and convert with 1 u = 931.5 MeV/$c^2$.
Activity 1, Mass Defect and Energy Release
ApplyBand 5
Practice $E = \Delta m c^2$ calculations with fusion reactions
Calculate the alpha-particle binding energy from $2m_p + 2m_n - m_\alpha$, using $m_p = 1.007276$ u, $m_n = 1.008665$ u, $m_\alpha = 4.001506$ u, and 1 u = 931.5 MeV/$c^2$.
A fusion reaction has a mass defect of $5.00 \times 10^{-29}$ kg. Calculate the energy released in joules and in MeV. ($c = 3.00 \times 10^8$ m/s, $1\ \text{eV} = 1.60 \times 10^{-19}$ J)
Explain why the binding energy per nucleon curve has a broad maximum in the iron-nickel region, with iron-56 near the maximum. What does this mean for fusion and fission reactions?
A student claims that "all elements can be produced by stellar fusion." Identify the error and correct it.
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Weigh the evidence for where elements form
Argue from cosmic abundances and from GW170817, then sort out what fusion can and cannot make.
Activity 2, Element Origins and Evidence
UnderstandBand 5
Connect element production to observational evidence
Explain why hydrogen is far more abundant in the universe than carbon, even though stars produce carbon through stellar nucleosynthesis.
The gravitational wave event GW170817 produced a "kilonova" rich in heavy elements. Explain how this observation supports the r-process model of heavy element nucleosynthesis.
Distinguish between the r-process and s-process, including: (a) where each occurs, (b) the timescale of neutron capture, (c) one example element produced by each.
Misconceptions, Final Check
Wrong: "Stars produce all elements, including gold and uranium, through fusion."
Right: Fusion only produces elements up to iron (the peak of the binding energy curve). Beyond iron, fusion is endothermic. Gold, platinum, and uranium are produced by neutron capture (r-process) in supernovae and neutron star mergers.
Wrong: "The Big Bang produced all the hydrogen and helium we see today."
Right: The Big Bang produced primordial H and He. Stars have since converted some H into He (and heavier elements) through stellar nucleosynthesis. The current cosmic ratio is similar to but not identical to the primordial ratio.
Three of these statements about nucleosynthesis are correct. Pick the odd one out.
Analyse7 marks
Analyse how the curve of binding energy per nucleon against mass number accounts for energy release in both nuclear fusion and nuclear fission, and explain the significance of its peak. (7 marks)
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Define the quantity the axis actually shows
This curve is misread constantly because the vertical axis is a ratio, not a total.
Binding energy per nucleon is the energy that would be needed to remove one nucleon from the nucleus, averaged over all of them, and it measures how tightly bound, and so how stable, a nucleus is.
Defining it per nucleon rather than as total binding energy is the foundation. The whole argument depends on comparing ratios between nuclei of different sizes.
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State the shape and locate the peak
Describe the curve in two movements so the peak has meaning.
The curve rises steeply for light nuclei, reaches a broad maximum in the iron-nickel region, then falls away slowly towards the heaviest nuclei. Iron-56 lies near the maximum, while nickel-62 has the greatest binding energy per nucleon.
Rises, peaks, falls. Identify the broad iron-nickel maximum and place iron-56 near it; distinguish this approximation from the exact maximum at nickel-62.
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Derive the condition for energy release
One rule governs both processes. State it once, generally.
Any reaction that moves nucleons to a position higher on the curve releases energy, because the products are more tightly bound than the reactants and the excess appears as energy according to $E = \Delta m c^2$.
Deriving the general condition before applying it is the analytical move, and it is what lets one sentence cover fusion and fission together.
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Apply the rule on the rising side
Now the first application.
On the rising side, combining light nuclei moves them upward, so fusion of light nuclei such as hydrogen into helium releases energy.
The direction of movement along the curve is the reason, not merely the result. Note the mark is for "moves upward", not for "fusion releases energy".
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Apply the same rule on the falling side
The second application reverses the operation but not the rule.
On the falling side beyond iron, splitting a heavy nucleus moves its nucleons upward towards the peak, so fission of heavy nuclei such as uranium also releases energy.
Showing that opposite operations release energy for the same reason is the point of the whole card.
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Draw out what the peak forbids
The strongest conclusion is about what cannot happen.
Iron-56 is near the broad maximum of the binding-energy curve. Once a massive star builds an iron-group core, further ordinary fusion no longer supplies energy to support it against gravity; making nuclei well beyond the iron group by fusion requires energy.
This links the curve to stellar collapse and to the origin of heavy elements in one step, which is why the peak is significant rather than incidental.
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The full-mark answer
Define the ratio, describe the shape, derive one rule, apply it twice, then draw the consequence of the peak.
Binding energy per nucleon is the energy needed to remove one nucleon from a nucleus, averaged over all of them, and it measures how tightly bound and therefore how stable a nucleus is. The curve rises steeply for light nuclei, reaches a broad maximum in the iron-nickel region, then falls away slowly towards the heaviest nuclei. Nickel-62 has the exact highest binding energy per nucleon; iron-56 lies close to this maximum. Any reaction that moves nucleons higher on the curve releases energy, because the products are more tightly bound than the reactants and the mass difference appears as energy according to $E = \Delta m c^2$. On the rising side, combining light nuclei moves them upward, so fusion of hydrogen into helium releases energy; on the falling side beyond iron, splitting a heavy nucleus moves its nucleons upward towards the peak, so fission of uranium also releases energy. Because the iron group lies near the curve’s broad maximum, further ordinary fusion in a massive star no longer provides a sustained energy source, and fusion well beyond this region requires energy rather than releasing it.
Seven marks from a single graph, because the answer derives one rule and applies it rather than describing two processes separately.
Account6 marks
Account for the presence of elements heavier than iron in the Solar System. (6 marks)
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Start from the constraint that makes the question hard
An account for answer should begin with the obstacle, because the rest of the chain exists to get around it.
Fusion of light nuclei releases energy as products move toward the broad maximum in the iron-nickel region; iron-56 lies near that maximum. Beyond iron, fusion absorbs energy rather than releasing it, so a star's ordinary fusion cannot build these elements.
Without this step the answer has nothing to explain. The constraint is the reason heavy elements need a special account at all.
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Identify what such a process would require
Turn the obstacle into a specification.
Forming heavier nuclei therefore requires an external supply of energy and an environment rich in free neutrons, since adding a neutron avoids the Coulomb repulsion that makes charged-nucleus fusion so difficult.
Naming both requirements, energy and neutrons, sets up the mechanism. The Coulomb point explains why neutron capture rather than proton capture is the route.
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Give the mechanism
Now the process itself, in the order it happens.
In neutron capture a nucleus absorbs one or more neutrons and then undergoes beta decay, in which a neutron converts to a proton, raising the atomic number and so producing a heavier element.
Capture followed by beta decay is the mechanism. Capture alone changes only the mass number, so omitting the decay leaves the element unchanged.
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Name the environments where the conditions exist
Specify where, but keep it at the level the syllabus requires.
These conditions occur in the extreme neutron fluxes of supernova explosions and in neutron-star mergers, and more slowly in the late stages of evolved stars.
Two or three named sites is enough. Detailed s- and r-process pathways and specific merger sites are beyond the syllabus in this lesson.
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Close the chain at the Solar System
The question asks about here. The last link has to be transport.
The explosions that produce these elements also disperse them into the interstellar medium, which later collapsed to form the Solar System, so the heavy elements in it were inherited from earlier generations of stars rather than made by the Sun.
The final clause answers the question as asked. An answer that stops at "supernovae make them" has not explained how they came to be here.
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The full-mark answer
Constraint, specification, mechanism, sites, transport. Five links, one chain.
Fusion of light nuclei releases energy as products move toward the broad iron-nickel maximum, while fusion well beyond the iron group absorbs energy, so a star's ordinary fusion cannot build heavier elements. Forming them requires an external energy supply and an environment rich in free neutrons, because adding a neutron avoids the Coulomb repulsion that makes the fusion of charged nuclei so difficult. In neutron capture a nucleus absorbs one or more neutrons and then undergoes beta decay, converting a neutron into a proton, which raises the atomic number and produces a heavier element. These conditions occur in the extreme neutron fluxes of supernova explosions and neutron-star mergers, and more slowly in the late stages of evolved stars. The same explosions disperse the new elements into the interstellar medium, which later collapsed to form the Solar System, so its heavy elements were inherited from earlier generations of stars rather than produced by the Sun.
Six marks, six causal links. The chain answers "why here" as well as "how made", which is what the wording of the question requires.
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Independent practice
Show what you can do without prompts
Complete a shuffled question-bank set, then write full nucleosynthesis responses in HSC style.
Quick recall, Nucleosynthesis and binding energy
+5 XP
A fresh five-question set drawn from this lesson's bank, feedback shown immediately. +5 XP per correct · +25 XP all correct
Pick your answer, then rate your confidence, that tells the system what to drill next.
Short Answer, 8 marks
+5 XP
ApplyBand 4(3 marks) 1. (a) Define mass defect and state the equation used to calculate the energy released in a nuclear reaction. (b) For the net pp-chain reaction $4p \rightarrow \alpha + 2e^+ + 2\nu_e$, calculate the nuclear Q-value before positron annihilation using $m_p = 1.00727647$ u, $m_\alpha = 4.00150618$ u, $m_e = 0.00054858$ u and 1 u = 931.5 MeV/$c^2$. Then state the gross release after both positrons annihilate with ambient electrons.
AnalyseBand 6(5 marks) 2. (a) Outline Big Bang nucleosynthesis and explain why it produced only hydrogen, helium, and trace lithium. (b) Explain why stellar nucleosynthesis cannot produce elements heavier than iron. (c) Distinguish between the s-process and r-process, including where each occurs. (d) Explain how the observed primordial helium abundance (~25%) provides evidence for the Big Bang model.
MC answers and full explanations are shown inline as you complete each question. Use the retry button to attempt a fresh set drawn from the lesson bank.
Short Answer, Model Answers
Q1 (3 marks): (a) Mass defect is the difference between the total mass of reactants and products; $E=\Delta mc^2$ (1 mark). (b) Charge is conserved in $4p \rightarrow \alpha+2e^++2\nu_e$: initial charge is +4e and final charge is +2e+2e=+4e. The nuclear mass difference is $4m_p-m_\alpha-2m_e = 4(1.00727647)-4.00150618-2(0.00054858)=0.026503$ u, giving $Q=0.026503(931.5)=24.69$ MeV before positron annihilation (1 mark). Two positrons annihilating with two ambient electrons add $4m_ec^2=2.044$ MeV, so the gross release is about 26.73 MeV before subtracting the energy carried away by neutrinos (1 mark).
Q2 (5 marks): (a) Big Bang nucleosynthesis occurred in the first ~3 minutes after the Big Bang. The universe was hot and dense enough for fusion; protons and neutrons combined to form deuterium, then helium-4. As the universe expanded and cooled below ~$10^9$ K, the density became too low for further fusion, so only H (~75%), He (~25%), and trace Li-7 were produced (1 mark). (b) The binding energy per nucleon has a broad maximum in the iron-nickel region, with iron-56 near it. Fusing light nuclei moves products toward this maximum and releases energy; fusion well beyond the iron group moves away from it and requires energy, so ordinary stellar fusion does not produce heavier elements this way (1 mark). (c) The s-process (slow neutron capture) occurs in AGB stars; nuclei capture one neutron at a time with beta decay between captures, producing elements like Sr, Ba, Pb (1 mark). The r-process (rapid neutron capture) occurs in supernovae and neutron star mergers; extreme neutron flux means many neutrons are captured before beta decay, producing very neutron-rich nuclei that decay to stable heavy elements like Au, Pt, U (1 mark). (d) The observed primordial helium abundance of ~24–25% matches exactly what Big Bang nucleosynthesis theory predicts. No other model (e.g. steady-state) can account for this specific ratio, it is a strong quantitative confirmation of the Big Bang (1 mark).
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Final step
Retrieve, reflect and finish
Check what stuck, revisit your opening abundance predictions and record the reasoning you will reuse.
Check what actually stuck
How did your thinking change?
At the start you were asked why hydrogen is by far the most abundant element, why elements heavier than iron are so rare, and what could build them once fusion stops releasing energy. All three answers come from the same binding energy curve: fusion runs uphill towards iron and stops there, so everything past iron has to be assembled by neutron capture in rare, violent environments.
Did you predict hydrogen is most abundant because BBN produced mostly hydrogen and most protons never fused? Correct, the primordial ratio of 73% H and 25% He by mass has barely changed since the Big Bang.
Did you predict heavy elements beyond iron are rare because their production requires rare events such as the supernovae and neutron star mergers that result when stars exceed Chandrasekhar's limit? Correct, these events are far less common than ordinary stellar fusion.
Did you predict neutron capture (r-process/s-process) for elements beyond iron? Correct, neutron capture is the pathway that builds elements beyond the iron group once ordinary energy-releasing fusion ends.
Extend: The mass of the Sun is $2.0 \times 10^{30}$ kg, and in 5 billion years the Sun will have converted roughly 0.07% of its total mass into energy through hydrogen fusion. (a) Calculate the total energy released over this time. (b) If each completed proton-proton chain reaction releases a gross 26.73 MeV (including annihilation of both positrons with ambient electrons, before neutrino losses), calculate the number of fusion reactions that have occurred. (c) Explain why only elements up to carbon and oxygen will be produced in the Sun's core.
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