Carbon dating tells archaeologists whether a bone is 500 years old or 50,000 years old. It works because carbon has isotopes — atoms of carbon with different numbers of neutrons. ¹⁴C is slightly unstable and decays at a known rate; ¹²C is stable. The ratio of ¹⁴C to ¹²C in organic material decreases predictably over time. Without isotopes, there would be no carbon dating, no nuclear medicine, no PET scans. Understanding isotopes is also the key to understanding why chlorine's atomic mass is 35.5 — not a whole number.

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Chlorine has two naturally occurring isotopes: chlorine-35 and chlorine-37. Both are chlorine atoms, but one is slightly heavier than the other. If you look up chlorine on the periodic table, its relative atomic mass is listed as 35.45 — not a whole number. Why isn't it simply 35 or 37?
Before reading on, write your best answer. What would need to be true for the relative atomic mass to be exactly 36 (halfway between 35 and 37)?
Core Content
Wrong: Isotopes have different chemical properties because they have different masses.
Right: Isotopes have identical chemical properties because chemistry is determined by electron configuration, which is the same for all isotopes of an element. Isotopes differ in physical properties (density, boiling point) and nuclear stability due to different neutron numbers.
Isotopes of the same element share the same number of protons (Z) but differ in neutron number. Since chemical behaviour is determined by the number and arrangement of electrons (which equals protons in neutral atoms), isotopes have identical chemical properties. They do differ in:
| Isotope | Protons (Z) | Neutrons (A−Z) | Mass number (A) | Stability | Natural abundance |
|---|---|---|---|---|---|
| ¹H (protium) | 1 | 0 | 1 | Stable | 99.985% |
| ²H (deuterium) | 1 | 1 | 2 | Stable | 0.015% |
| ³H (tritium) | 1 | 2 | 3 | Radioactive | Trace (artificial) |
| ¹²C | 6 | 6 | 12 | Stable | 98.89% |
| ¹³C | 6 | 7 | 13 | Stable | 1.11% |
| ¹⁴C | 6 | 8 | 14 | Radioactive (t½ = 5730 yr) | Trace |
| ³⁵Cl | 17 | 18 | 35 | Stable | 75.77% |
| ³⁷Cl | 17 | 20 | 37 | Stable | 24.23% |
The relative atomic mass (Ar) is the weighted average of all isotopic masses, weighted by their fractional abundance. The standard reference is ¹²C = exactly 12.
A mass spectrometer ionises atoms and accelerates them through a magnetic field. Heavier ions deflect less, lighter ions more — they separate by mass. A detector measures the relative number of ions at each mass value, producing a mass spectrum showing peaks at each isotope's mass, with peak height proportional to abundance.
Worked Examples
Activities
1 Magnesium has three isotopes: ²⁴Mg (78.99%), ²⁵Mg (10.00%), ²⁶Mg (11.01%). Calculate the relative atomic mass of magnesium. Show full working.
2 Copper has two stable isotopes: ⁶³Cu and ⁶⁵Cu. If Ar(Cu) = 63.55, calculate the percentage abundance of each isotope. Show working.
A mass spectrum of an unknown element X shows three peaks:
A Calculate the relative atomic mass of element X. Show full working.
B Use the calculated Ar to identify the element (refer to the periodic table). State how many isotopes this element has.
Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?
Multiple Choice
5 random questions from a replayable lesson bank — feedback shown immediately
Short Answer
6. Carbon-12 (¹²C) and carbon-14 (¹⁴C) are isotopes of carbon. (a) State one similarity and two differences between these isotopes. (b) Explain why both isotopes react identically with oxygen to form CO₂. 4 MARKS
7. The Ar of neon is 20.18. Neon has three isotopes: ²⁰Ne (90.48%), ²¹Ne (0.27%), and ²²Ne (9.25%). Using the Ar formula, verify that these abundances are consistent with Ar = 20.18. Show full working. 3 MARKS
1. Fractions: ²⁴Mg = 78.99÷100 = 0.7899, ²⁵Mg = 0.1000, ²⁶Mg = 0.1101. Sum = 1.0000 ✓. Ar = (24 × 0.7899) + (25 × 0.1000) + (26 × 0.1101) = 18.958 + 2.500 + 2.863 = 24.321 ≈ 24.32. (Compare to periodic table: Ar(Mg) = 24.31 ✓).
2. Let x = fractional abundance of ⁶³Cu. Then (1−x) = fractional abundance of ⁶⁵Cu. Ar = (63×x) + (65×(1−x)) = 63.55. 63x + 65 − 65x = 63.55. −2x = 63.55 − 65 = −1.45. x = 0.725. ⁶³Cu = 72.5%; ⁶⁵Cu = 27.5%. Verify: (63×0.725) + (65×0.275) = 45.675 + 17.875 = 63.55 ✓.
A: Check: 1.4 + 24.1 + 22.1 + 52.4 = 100.0% ✓. Fractions: 204→0.014, 206→0.241, 207→0.221, 208→0.524. Ar = (204×0.014) + (206×0.241) + (207×0.221) + (208×0.524) = 2.856 + 49.646 + 45.747 + 108.992 = 207.24 ≈ 207.2.
B: Element X is Lead (Pb), Ar ≈ 207.2 (matches periodic table value of 207.2). Lead has 4 naturally occurring isotopes: ²⁰⁴Pb, ²⁰⁶Pb, ²⁰⁷Pb, ²⁰⁸Pb.
1. C — Isotopes: same Z (protons), different A (neutrons count differs). Same element means same Z always.
2. B — Ar = (79 × 0.5069) + (81 × 0.4931) = 40.045 + 39.941 = 79.986 ≈ 79.99. Almost exactly 80 because the abundances are nearly equal.
3. D — Ar = 6.94, very close to 6. The lighter isotope dominates. If x = fraction of mass 6: 6x + 7(1−x) = 6.94 → −x = −0.06 → x = 0.94 = 94% mass-6 (this is lithium: ⁶Li 7.5%, ⁷Li 92.5% — the question uses hypothetical values).
4. A — Same protons → same electrons → same electron configuration → identical chemical behaviour. Neutrons don't participate in bonding.
5. C — Ar = (107 × 0.52) + (109 × 0.48) = 55.64 + 52.32 = 107.96. (This is silver, Ag.)
Q6 (4 marks): (a) Similarity: both have 6 protons (atomic number Z = 6) and 6 electrons (1 mark). Differences: (1) ¹²C has 6 neutrons, ¹⁴C has 8 neutrons (1 mark). (2) ¹²C is stable; ¹⁴C is radioactive (unstable nucleus) (1 mark). (b) Both react identically with oxygen because chemical behaviour is determined by electron configuration. ¹²C and ¹⁴C both have 6 protons → 6 electrons in a neutral atom → identical electron arrangement → same bonding behaviour → both form 2 C=O bonds with 2 oxygen atoms to give CO₂ (1 mark).
Q7 (3 marks): Fractions: ²⁰Ne = 90.48÷100 = 0.9048, ²¹Ne = 0.0027, ²²Ne = 0.0925. Sum = 0.9048 + 0.0027 + 0.0925 = 1.0000 ✓ (1 mark). Ar = (20 × 0.9048) + (21 × 0.0027) + (22 × 0.0925) (1 mark) = 18.096 + 0.0567 + 2.035 = 20.188 ≈ 20.18 ✓ (1 mark). The calculated value matches the stated Ar, confirming the abundances are consistent.
Return to your Think First response. You should now be able to explain the 35.45 value precisely:
Isotopes and Relative Atomic Mass
Tick when you've finished all activities and checked your answers.