ChemistryYear 11 · Module 1 · IQ3⏱ ~30 min

The Periodic Table: Organisation

Mendeleev had a problem: 63 known elements, no organising principle, and chemistry was a confused mess. His insight was to arrange them by atomic mass and look for repeating patterns in properties. He was so confident in the pattern that he left blank spaces for undiscovered elements — and predicted their properties before anyone had seen them. When those elements were discovered (gallium in 1875, germanium in 1886), they matched his predictions almost exactly. The periodic table isn't just a chart — it's one of the greatest predictive tools in science.

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📝 Choose how you work: type answers below, or work in your book.

📚 Know

  • How the periodic table is organised (periods and groups)
  • Names and properties of key groups (alkali metals, halogens, noble gases, transition metals)
  • How Mendeleev organised the original periodic table and why it worked

🔗 Understand

  • Why elements in the same group have similar properties
  • The difference between Mendeleev's and the modern periodic table
  • How the periodic table reflects electron configuration

✅ Can Do

  • Identify element location (period, group, block) from the table
  • Predict properties of unknown elements from group/period position
  • Compare organisation principles of Mendeleev's and modern table
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Key Definitions

periodA horizontal row in the periodic table. Elements in the same period have the same number of electron shells. Period number = number of electron shells. 7 periods in the modern table.
groupA vertical column in the periodic table. Elements in the same group have the same number of valence electrons and similar chemical properties. Groups 1–18 in the modern table (IUPAC).
valence electronsElectrons in the outermost (highest energy) shell of an atom. These are the electrons involved in bonding and chemical reactions. Group number (for main-group elements) = number of valence electrons.
periodicityThe repeating pattern of elemental properties at regular intervals when elements are arranged by atomic number. Properties such as ionisation energy, electronegativity, and atomic radius repeat in a predictable pattern across periods.
s-block, p-block, d-blockRegions of the periodic table defined by which subshell the highest-energy electron occupies. s-block: Groups 1–2. p-block: Groups 13–18. d-block: transition metals (Groups 3–12). f-block: lanthanides and actinides.

Core Content

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How the Modern Periodic Table is Organised

The modern periodic table arranges elements in order of increasing atomic number (Z), not atomic mass (as Mendeleev used). This resolves a few inconsistencies Mendeleev faced (e.g. Te/I and Co/Ni are out of order by mass but in the correct order by Z).

FeatureMendeleev (1869)Modern periodic table
Ordering principleRelative atomic mass (increasing)Atomic number Z (increasing)
Basis for similar propertiesEmpirical observation of repeating propertiesSame valence electron count (electron configuration)
GapsLeft deliberate gaps for undiscovered elements; predicted their propertiesAll known elements included (118 confirmed)
AnomaliesTe/I, Co/Ni out of order by mass — placed by chemical propertiesCorrectly ordered by Z; no anomalies
Predictive powerPredicted eka-aluminium (Ga), eka-boron (Sc), eka-silicon (Ge)Predicts periodic trends (ionisation energy, electronegativity, reactivity)
Why Z ordering works: Chemical properties are determined by electron configuration, which is determined by Z. Elements with the same number of valence electrons have similar chemistry. Mendeleev accidentally discovered this pattern before electron configuration was understood — his table worked because valence electrons are what determines chemical behaviour.
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Key Groups and Their Properties

GroupNameValence e⁻Key propertiesExamples
1Alkali metals1Soft, low MP, very reactive metals; react vigorously with water to form H₂ + metal hydroxide; reactivity increases down the groupLi, Na, K, Rb, Cs, Fr
2Alkaline earth metals2Harder/denser than Group 1; still reactive; form 2+ ions; less reactive than Group 1Be, Mg, Ca, Sr, Ba, Ra
17Halogens7Non-metals; exist as diatomic molecules (F₂, Cl₂, Br₂, I₂); very reactive (one electron from full shell); reactivity decreases down the group; form −1 ions (halides)F, Cl, Br, I, At
18Noble gases8 (He: 2)Full valence shell → extremely unreactive; monatomic gases; no tendency to form bonds; very low BP (weak dispersion only)He, Ne, Ar, Kr, Xe, Rn
3–12Transition metals1–2 (d-block)Hard, high MP, multiple oxidation states; form coloured compounds; good conductors; catalytic propertiesFe, Cu, Zn, Ti, Cr, Mn
Key pattern — reactivity in metals vs non-metals: For metals (Groups 1–2), reactivity increases going down the group (outer electrons further from nucleus → easier to lose). For non-metals/halogens (Group 17), reactivity decreases going down the group (atoms get larger → harder to attract the extra electron needed). This is the basis of the displacement reactions you'll study in later modules.
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Blocks: Where Electrons Are

The block structure of the periodic table directly maps to which subshell the highest-energy (outermost) electrons occupy — a concept you'll explore fully in L16. For now, the key locations:

BlockGroupsSubshell fillingElement type
s-block1, 2s subshellReactive metals (alkali/alkaline earth) + H and He
p-block13–18p subshellNon-metals, metalloids, and some metals
d-block3–12d subshellTransition metals
f-block(separate rows)f subshellLanthanides, actinides (rare earths)
Quick location rule: Period number = number of electron shells. Group number (for s- and p-block) = valence electrons. So Na (Group 1, Period 3) has 1 valence electron in 3 shells. Cl (Group 17, Period 3) has 7 valence electrons in 3 shells. Both are in Period 3 but opposite ends of the table and very different in reactivity.

Worked Examples

1

Worked Example 1 — Method A: Locate and describe from position

Element X is in Group 2, Period 4. (a) Identify element X. (b) State the number of valence electrons. (c) Predict whether X would be more or less reactive than calcium (Group 2, Period 4 — wait, calcium IS Group 2, Period 4). Let's use: Element Y is in Group 2, Period 5. Predict Y's reactivity compared to calcium (Group 2, Period 4).
Method A — Using position directly Step 1 — Identify element Y Group 2, Period 5 → alkaline earth metal in the 5th period Counting down Group 2: Be (Period 2), Mg (Period 3), Ca (Period 4), Sr (Period 5) Element Y = Strontium (Sr) Step 2 — Valence electrons from group number Group 2 → 2 valence electrons (all alkaline earth metals have 2 valence e⁻) Step 3 — Predict reactivity vs Ca Y (Sr) is below Ca in Group 2 (Period 5 vs Period 4). Going down a group: atomic radius increases → valence electrons are further from the nucleus and shielded by more inner electron shells → weaker nuclear attraction on valence electrons → easier to lose them in reactions. For metals: easier to lose valence electrons = more reactive. Conclusion: Sr is MORE reactive than Ca.
Answer
Y = Strontium (Sr). Valence electrons = 2 (Group 2). Sr is more reactive than Ca because it is in Period 5 (one period lower) — its valence electrons are further from the nucleus with more electron shielding, making them easier to remove in reactions.
2

Worked Example 2 — Method B: Predict properties of an undiscovered element (Mendeleev-style)

An element Q has Z = 119 (not yet discovered/confirmed). Using the periodic table, predict: (a) the group and period of Q, (b) the block, (c) likely physical properties (metal/non-metal), (d) number of valence electrons.
Method B — Extrapolate from periodic table structure Step 1 — Determine period Current table: Period 7 ends at oganesson (Og, Z = 118). Z = 119 would be in Period 8 (next row after Period 7 ends). Period 8, first element → Group 1 (same column as H, Li, Na, K, Rb, Cs, Fr) Step 2 — Determine group and block Group 1, Period 8 → element is in s-block (Group 1 = s-block) 1 valence electron (Group 1 always has 1 valence e⁻) Step 3 — Predict physical properties All Group 1 elements are: soft, low melting point, highly reactive metals with 1 valence e⁻. Reactivity trend: increases down the group (Fr > Cs > Rb > K > Na > Li). Q (Period 8) would be the most reactive alkali metal known — even more reactive than Fr. Likely very low density, very soft, reacts extremely violently with water. Step 4 — Compare Methods A and B Method A (known element): use Z and position directly. Method B (undiscovered): extrapolate from group/period trends. Both methods use the same principle: group = valence electrons = chemical character.
Answer
Q (Z=119) would be in Group 1, Period 8, s-block. 1 valence electron. Predicted: a very soft, low-density, highly reactive metal — the most reactive alkali metal. It would react explosively with water, producing Q(OH) and H₂. More reactive than francium (the current most reactive naturally occurring alkali metal).
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Common Mistakes

Confusing period and group directions. Periods are HORIZONTAL rows (left → right, increasing Z within a period). Groups are VERTICAL columns (top → bottom, same valence electrons). A common error: "Period 3, Group 1 is Na — going DOWN is going to Period 4" — correct. "Going RIGHT from Na is going to Mg in Group 2" — also correct.
Saying noble gases are "inert" because they have no electrons. Noble gases have full valence shells (8 electrons for most, 2 for helium), not zero. Their unreactivity comes from having a complete, stable electron configuration — no tendency to gain or lose electrons.
Applying metal reactivity trends to non-metals. For metals, reactivity INCREASES down a group (easier to lose electrons). For halogens (Group 17), reactivity DECREASES down a group (harder to attract an electron as atom grows larger). These are opposite trends — always specify which type of element you're discussing.

📓 Copy Into Your Books

🧩 Table Structure

  • Periods = horizontal rows (same shells)
  • Groups = vertical columns (same valence e⁻)
  • Period # = number of electron shells
  • Group # (1–2, 13–18) = valence electrons
  • 118 confirmed elements

🔑 Key Groups

  • Gp 1: Alkali metals — 1 valence e⁻, very reactive
  • Gp 2: Alkaline earth metals — 2 valence e⁻
  • Gp 17: Halogens — 7 valence e⁻, very reactive non-metals
  • Gp 18: Noble gases — full shells, unreactive
  • Gp 3–12: Transition metals — multiple oxidation states

📊 Reactivity Trends

  • Metals: reactivity ↑ down group (easier to lose e⁻)
  • Halogens: reactivity ↓ down group (harder to gain e⁻)
  • Noble gases: essentially no reactivity (full shells)

⚠️ Mendeleev vs Modern

  • Mendeleev: ordered by mass → worked mostly
  • Modern: ordered by Z → always works
  • Why: Z determines electron config → properties
  • Mendeleev: predicted undiscovered elements from gaps

Activities

🧩 Activity 1 — Location and Properties

1 For each element, state the group, period, block, and number of valence electrons: (a) Lithium (Z=3), (b) Oxygen (Z=8), (c) Calcium (Z=20), (d) Bromine (Z=35).

✏️ Answer in your book

2 An unknown element M is described as: "A soft, silvery metal that reacts violently with water, forming a strongly alkaline solution and releasing hydrogen gas. Its melting point is lower than sodium." Identify the most likely group for M. Which specific element is most likely M? Justify using periodic trends.

✏️ Answer in your book
🔍 Activity 2 — Compare and Apply

A Compare Mendeleev's periodic table and the modern periodic table by discussing: (i) the organising principle used, (ii) one advantage of the modern approach, (iii) one example where Mendeleev's approach was insufficient and how the modern approach resolved it.

✏️ Answer in your book

B Element Z is in Period 3, Group 16. (a) Name and identify this element. (b) Predict its charge when it forms a simple ion. (c) Predict whether it would be more or less electronegative than the Group 16 element in Period 2. Justify.

✏️ Answer in your book

Multiple Choice

Multiple Choice Questions

1. What determines the period number of an element in the modern periodic table?

A
Number of valence electrons
B
Relative atomic mass
C
Number of occupied electron shells
D
Number of neutrons in the nucleus

2. Tellurium (Te, Z=52) has a higher Ar than iodine (I, Z=53), yet Te is placed before I in the periodic table. The reason the modern table handles this correctly is:

A
Te is a metalloid and always placed before halogens regardless of mass
B
The modern table orders by atomic number (Z), not atomic mass — Te has Z=52 and I has Z=53, placing them in the correct order based on electron configuration and chemical behaviour
C
Mendeleev originally placed them in the wrong order, and this was never corrected
D
Te and I have the same number of valence electrons, so they can be placed in either order

3. Why do elements in the same group have similar chemical properties?

A
They have the same number of electron shells
B
They have the same atomic mass
C
They have the same number of neutrons
D
They have the same number of valence electrons, giving them the same bonding tendencies and reactivity patterns

4. The reactivity of Group 1 alkali metals increases going down the group. The correct explanation is:

A
Atomic radius increases → valence electron is further from the nucleus and more shielded by inner electrons → weaker nuclear attraction → easier to lose the valence electron → more reactive
B
The number of valence electrons increases going down the group, increasing reactivity
C
Atomic mass increases going down the group, making reactions faster
D
The melting point decreases going down the group, making elements more reactive as liquids

5. Fluorine (F) is a more reactive halogen than iodine (I). The correct explanation is:

A
Fluorine has fewer electrons, making it easier to gain one more
B
Fluorine has a higher atomic mass than iodine
C
Fluorine's valence shell is closer to the nucleus with less electron shielding → stronger attraction for an incoming electron → greater tendency to gain an electron (more reactive as an oxidising agent)
D
Fluorine is a gas and iodine is a solid, so fluorine reacts faster due to greater surface area

Short Answer

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Short Answer Questions

6. Evaluate Mendeleev's contribution to chemistry, including: (a) the organising principle he used, (b) an example of a successful prediction he made about an undiscovered element, and (c) one limitation of his approach that the modern periodic table resolved. 4 MARKS

✏️ Answer in your book

7. An unknown element W has Z = 20. (a) Determine its group, period, and block. (b) State the number of valence electrons and predict its ion charge. (c) Compare the reactivity of W to magnesium (Z=12) and explain using electron shell theory. 5 MARKS

✏️ Answer in your book

✅ Comprehensive Answers

🧩 Activity 1

1. (a) Li (Z=3): Group 1, Period 2, s-block, 1 valence electron. (b) O (Z=8): Group 16, Period 2, p-block, 6 valence electrons. (c) Ca (Z=20): Group 2, Period 4, s-block, 2 valence electrons. (d) Br (Z=35): Group 17, Period 4, p-block, 7 valence electrons.

2. Group 1 (alkali metal) — reacts with water to form alkaline solution and H₂ is characteristic of Group 1. Lower MP than Na suggests it is further down Group 1 than Na (Period 3). MP decreases: Li > Na > K > Rb > Cs. Element M is most likely potassium (K) — one period below Na, MP = 63°C vs Na's 98°C. (Could also be Rb or Cs if even lower MP.)

🔍 Activity 2

A: (i) Mendeleev used increasing relative atomic mass as the ordering principle; the modern table uses increasing atomic number (Z). (ii) The modern approach correctly places Te before I — by Ar, Te (127.6) > I (126.9) which would put I before Te by mass; by Z, Te (52) < I (53), placing Te first as its chemical properties require (Te is in Group 16, I in Group 17). (iii) The same Te/I anomaly: Mendeleev was forced to override mass ordering to preserve chemical group relationships, acknowledging his principle was imperfect. The modern table resolved this completely because Z directly determines electron configuration and chemical properties, explaining why some elements are "out of order" by mass.

B: (a) Period 3, Group 16 = Sulfur (S). (b) Group 16 elements have 6 valence electrons; they need 2 more to reach a full shell of 8 → S forms S²⁻ ion (charge = 2−). (c) Less electronegative than the Period 2 element (oxygen, O). Electronegativity decreases down a group because the valence shell is further from the nucleus and more shielded → weaker nuclear attraction on the bonding electrons → less tendency to attract electrons → lower electronegativity.

❓ Multiple Choice

1. C — Period number = number of occupied electron shells. Group = valence electrons. Ar is the ordering principle of Mendeleev's (not modern) table.

2. B — Z ordering correctly places Te (Z=52) before I (Z=53). Their chemical properties (Te is Group 16, I is Group 17) are consistent with Z ordering. Ar ordering fails here.

3. D — Same valence electrons = same bonding tendencies = similar chemistry. Same shells = same period, not group.

4. A — The valence electron distance and shielding explanation. B is wrong — Group 1 always has 1 valence electron. MP (D) is a result of reactivity, not a cause.

5. C — Halogens gain an electron to complete their valence shell. Fluorine (Period 2) has its valence shell closest to the nucleus → strongest nuclear pull → greatest tendency to gain → most reactive. Physical state (D) affects rate, not reactivity (tendency).

📝 Short Answer Model Answers

Q6 (4 marks): (a) Mendeleev organised elements in order of increasing relative atomic mass and identified that properties repeated at regular intervals — he arranged elements with similar properties into vertical groups (1 mark). (b) Example: Mendeleev predicted the existence of eka-aluminium (later discovered as gallium, 1875) and eka-silicon (germanium, 1886), leaving gaps in his table and predicting their properties (atomic mass, density, valence) from the surrounding elements — the actual properties of the discovered elements closely matched his predictions, validating the periodic pattern (1 mark). (c) Limitation: ordering by mass led to anomalies where elements would be misplaced — Te (Ar 127.6) would come after I (Ar 126.9) by mass, but their chemical properties required Te in Group 16 and I in Group 17 (opposite order). Mendeleev overrode mass ordering empirically. The modern table resolved this by using Z instead: Te (Z=52) correctly precedes I (Z=53) (1 mark). Overall evaluation: Mendeleev's table was a landmark achievement — it unified chemistry and had predictive power, though it was later refined when atomic structure was understood (1 mark).

Q7 (5 marks): (a) Z=20. Electron shells: 2,8,8,2 → 4 occupied shells → Period 4. Last 2 electrons in s subshell → s-block, Group 2. Element W = calcium (Ca) (1 mark). (b) Valence electrons = 2 (Group 2). Ca loses 2 electrons to achieve noble gas configuration → Ca²⁺ ion (charge = 2+) (1 mark). (c) W (Ca, Period 4) is more reactive than Mg (Period 3). Both are in Group 2 (s-block, 2 valence electrons). Going from Period 3 to Period 4: atomic radius increases (additional electron shell) → valence electrons are further from the nucleus (1 mark) → more inner electron shells provide greater shielding of nuclear charge (1 mark) → weaker effective nuclear attraction on the 2 valence electrons → they are more easily removed in reactions → Ca is more reactive than Mg (1 mark).

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Tick when you've finished all activities and checked your answers.

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