Year 11 Chemistry Module 3 Checkpoint 1

Checkpoint 1

Covering Lessons 01–06: physical and chemical change, reaction types, balancing equations, precipitation, solubility, combustion, acid-base reactions, and Indigenous detoxification.

⏱ ~20 min 10 MC · 4 Short Answer Lessons 01–06

What’s Covered

L01
Physical & Chemical Change
  • Signs of chemical change
  • Physical vs chemical
  • Law of conservation
  • Properties before/after
L02
Synthesis & Decomposition
  • Synthesis reactions
  • Decomposition reactions
  • Balancing equations
  • 7 reaction types overview
L03
Precipitation & Solubility
  • Solubility rules
  • Molecular equations
  • Net ionic equations
  • Spectator ions
L04
Combustion Reactions
  • Complete combustion
  • Incomplete combustion
  • Balancing hydrocarbons
  • Flame colour/carbon soot
L05
Acid-Base Reactions
  • Acid + base → salt + water
  • Acid + carbonate
  • Identifying products
  • Balancing acid reactions
L06
Indigenous Detoxification
  • Cycad toxicity (BMAA)
  • Physical vs chemical methods
  • Water-solubility & leaching
  • Classifying all 7 types

Multiple Choice — 10 marks

L01 — Physical vs Chemical Change

1. Which of the following is an example of a chemical change?

A Dissolving salt in water
B Grinding chalk into a fine powder
C Iron rusting in moist air
D Ice melting in a warm room
L02 — Decomposition

2. Which of the following equations represents a decomposition reaction?

A CaO + H₂O → Ca(OH)₂
B 2H₂O₂ → 2H₂O + O₂
C C + O₂ → CO₂
D 2Na + Cl₂ → 2NaCl
L02 — Balancing Equations

3. When the equation C₃H₈ + O₂ → CO₂ + H₂O is fully balanced, what is the coefficient of O₂?

A 3
B 4
C 5
D 6
L03 — Precipitation

4. Which combination of solutions would produce a precipitate when mixed?

A NaCl(aq) + KNO₃(aq)
B BaCl₂(aq) + Na₂SO₄(aq)
C KBr(aq) + NaCl(aq)
D Ca(NO₃)₂(aq) + NaCl(aq)
L03 — Net Ionic Equations

5. Lead(II) nitrate solution is added to potassium iodide solution. The precipitate formed is:

A Lead(II) nitrate
B Potassium iodide
C Lead(II) iodide
D Potassium nitrate
L04 — Combustion Products

6. What are the products of complete combustion of ethanol (C₂H₅OH)?

A Carbon monoxide and water
B Carbon dioxide and water
C Carbon dioxide and hydrogen gas
D Carbon (soot) and water vapour
L05 — Acid-Carbonate Reactions

7. A student adds hydrochloric acid to sodium carbonate powder. Which of the following is NOT a product of this reaction?

A Carbon dioxide gas
B Water
C Sodium chloride
D Sodium hydroxide
L05 — Acid-Base Neutralisation

8. Which equation correctly represents an acid-base neutralisation?

A H₂SO₄ + CaCO₃ → CaSO₄ + H₂O + CO₂
B H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C H₂SO₄ + Zn → ZnSO₄ + H₂
D H₂SO₄ → 2H⁺ + SO₄²⁻
L06 — Classifying Reactions

9. Iron(III) oxide reacts with sulfuric acid: Fe₂O₃ + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂O. This reaction is best classified as:

A Combustion
B Precipitation
C Acid-carbonate
D Acid-base
L01–L06 — Synthesis

10. Traditional cycad seed processing involves prolonged soaking and washing in running water. Which statement best explains why this technique is effective at removing the water-soluble toxin BMAA?

A Running water decomposes BMAA through a series of hydrolysis reactions
B The process is a physical change that exploits BMAA’s water-solubility to remove it by leaching — no new substance is formed
C Water neutralises the toxin through an acid-base reaction
D The toxin undergoes combustion when seeds are dried in sunlight after washing

Short Answer — 12 marks

L03 — Precipitation

SA1. A student mixes solutions of barium chloride and sodium sulfate. (a) Write the balanced molecular equation for the reaction. (b) Write the net ionic equation. (c) Identify the precipitate and name the two spectator ions. (3 marks)

1 mark: BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl; 1 mark: Ba²⁻(aq) + SO₄²⁻(aq) → BaSO₄(s); 1 mark: precipitate = barium sulfate; spectators = Na⁺ and Cl⁻

Saved
L04–L05 — Combustion & Acid Reactions

SA2. (a) Write the balanced equation for the complete combustion of propane (C₃H₈). (b) State the conditions under which incomplete combustion occurs and name the additional product formed. (c) Write the balanced equation for the reaction between dilute hydrochloric acid and calcium carbonate (marble chips). (3 marks)

1 mark each: (a) C₃H₈ + 5O₂ → 3CO₂ + 4H₂O; (b) limited oxygen supply → CO (carbon monoxide); (c) CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

Saved
L02 — Balancing & Reaction Types

SA3. For each of the following, balance the equation (if needed) and identify the reaction type:
(i) Mg + O₂ → MgO
(ii) CaCO₃ → CaO + CO₂
(iii) C₂H₅OH + O₂ → CO₂ + H₂O (3 marks — 1 per sub-part)

(i) 2Mg + O₂ → 2MgO — synthesis; (ii) already balanced — decomposition; (iii) C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O — combustion

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L01 & L06 — Physical vs Chemical Change

SA4. Define what is meant by a ‘physical change’ and give one example from the traditional preparation of cycad seeds. Explain why prolonged leaching in running water (a physical process) is effective at removing the water-soluble neurotoxin BMAA, and why direct application of heat is not recommended as the primary detoxification method. (3 marks)

1 mark: physical change = no new substance formed, original substance recoverable (e.g. soaking/leaching); 1 mark: BMAA is water-soluble → dissolves into washing water and is removed by diffusion/leaching without chemically altering the seed; 1 mark: heat could cause unwanted chemical changes (decomposition, cooking) that alter the seed’s chemistry, or the BMAA may not be fully destroyed and the products could be unknown/toxic

Saved
  • Q1 — C: Rusting forms a new substance (iron(III) oxide, Fe₂O₃) with different properties from iron. Options A, B, and D are all physical changes — no new substance is formed and the change is reversible.
  • Q2 — B: Decomposition: one reactant breaks down into two or more products. 2H₂O₂ → 2H₂O + O₂ fits this pattern. Option A is synthesis; C is combustion/synthesis; D is synthesis.
  • Q3 — C: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Check: C 3=3 ✓; H 8=8 ✓; O 10=6+4=10 ✓.
  • Q4 — B: BaSO₄ is insoluble (barium sulfate precipitates). All other combinations produce only soluble salts (NaNO₃, KBr, NaBr, CaNO₃, NaCl are all soluble).
  • Q5 — C: Lead(II) iodide (PbI₂) is a bright yellow insoluble solid. The net ionic equation: Pb²⁻(aq) + 2I⁻(aq) → PbI₂(s). KNO₃ remains in solution as spectator ions.
  • Q6 — B: Complete combustion of any hydrocarbon or alcohol produces only CO₂ and H₂O. C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O.
  • Q7 — D: Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂. Products are the salt (NaCl), water, and CO₂. Sodium hydroxide is NOT produced — it is a base, not a product of an acid-carbonate reaction.
  • Q8 — B: Acid-base neutralisation: acid + base → salt + water, no gas produced. Option A is acid-carbonate (produces CO₂). Option C is metal-acid (produces H₂ gas). Option D is dissociation, not a reaction.
  • Q9 — D: Fe₂O₃ is a metal oxide, which acts as a base when reacting with an acid. Acid + base (metal oxide) → salt + water. No carbonate is present (not acid-carbonate); no precipitation; no combustion.
  • Q10 — B: Leaching is a physical process — BMAA dissolves in water (exploiting water-solubility) and diffuses out of the seed into the running water over time. No new substance is formed in the seed or in the water; BMAA is simply diluted and removed. This is a classic physical separation technique.

SA1: (a) BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq). (b) Ba²⁻(aq) + SO₄²⁻(aq) → BaSO₄(s). (c) Precipitate: barium sulfate (BaSO₄, white solid). Spectator ions: Na⁺(aq) and Cl⁻(aq) — they appear on both sides of the molecular equation and are not involved in the precipitation.

SA2: (a) C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. (b) Incomplete combustion occurs when the supply of oxygen is insufficient (limited O₂). The additional product is carbon monoxide (CO) — a toxic colourless gas: 2C₃H₈ + 7O₂ → 6CO + 8H₂O. (c) CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g).

SA3: (i) 2Mg(s) + O₂(g) → 2MgO(s) — synthesis (two reactants combine to form one product). (ii) CaCO₃(s) → CaO(s) + CO₂(g) — decomposition (already balanced; one reactant breaks down into two products). (iii) C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g) — combustion (check: C 2=2; H 6=6; O 3+1=4 on left; 4+3=7 on right… recheck: left O = 3×2+1=7, right = 4+3=7 ✓).

SA4: A physical change is a change in which no new substance is formed — the identity and composition of the substance remain the same, and the change is often reversible. In cycad preparation, soaking and washing in running water is a physical change: BMAA (a water-soluble amino acid-like toxin) dissolves into the water and is carried away, but no new chemical substance is formed in the seed or the water. Leaching works because BMAA is water-soluble — it dissolves readily and diffuses out of the seed tissue down a concentration gradient into the surrounding water. Replacing the water with running or fresh water maintains a steep concentration gradient, speeding removal. Heat is not ideal as the primary method because: (1) direct heat may not chemically destroy the toxin at low cooking temperatures — BMAA could survive and the products of thermal decomposition are unknown; (2) high heat causes unwanted chemical changes to the seed (gelatinisation, denaturation) altering nutritional quality; (3) the effectiveness of heat in removing a polar, water-soluble toxin is unreliable without extensive testing of the resulting decomposition products for toxicity.

Track Your Score

Multiple Choice (Q1–10) / 10
Short Answer (SA1–4) / 12
Total — / 22

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