Covering Lessons 07–10: metal activity series, displacement reactions, redox reactions, oxidation states, half-equations, galvanic cells, standard reduction potentials, inert electrodes, and cathodic protection.
1. According to the NESA activity series, which metal is the most reactive?
2. An iron nail is placed in copper(II) sulfate solution. Which observation would be expected?
3. In the reaction 2Mg(s) + O₂(g) → 2MgO(s), which statement correctly identifies what happens to magnesium?
4. What is the oxidation number of nitrogen in the nitrate ion (NO₃⁻)?
5. In the half-equation Fe²⁻ → Fe³⁻ + e⁻, the iron is:
6. In a galvanic cell with a zinc anode and a copper cathode, in which direction do electrons flow through the external circuit?
7. Given E°(Zn²⁻/Zn) = −0.76 V and E°(Cu²⁻/Cu) = +0.34 V, what is E°cell for a galvanic cell with a zinc anode and copper cathode?
8. An inert electrode (such as platinum) is required in a galvanic cell when:
9. Which of the following correctly identifies the condition for a galvanic cell reaction to be spontaneous?
10. A silver wire is placed in a solution of copper(II) nitrate. Given E°(Ag⁺/Ag) = +0.80 V and E°(Cu²⁻/Cu) = +0.34 V, which prediction is correct?
SA1. A student separately adds strips of zinc and copper to silver nitrate solution. (a) Using the NESA activity series, predict whether each metal will react with AgNO₃(aq). (b) Write the balanced equation for each reaction that occurs, or state ‘no reaction’ if not. (3 marks)
1 mark for correct prediction for both metals (Zn above Ag → reacts; Cu above Ag → reacts); 1 mark each for balanced equations: Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag; Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
SA2. For the reaction between permanganate ions and iron(II) ions in acidic solution: MnO₄⁻(aq) + Fe²⁻(aq) → Mn²⁻(aq) + Fe³⁻(aq). (a) Determine the oxidation number of Mn in MnO₄⁻ and in Mn²⁻. (b) Identify which species is oxidised and which is reduced. (c) Write the half-equation for the oxidation of Fe²⁻. (3 marks)
1 mark: Mn in MnO₄⁻ = +7 (O₄=−8, overall −1, so Mn=+7); Mn in Mn²⁻ = +2; 1 mark: Mn reduced (+7→+2); Fe oxidised (+2→+3); 1 mark: Fe²⁻ → Fe³⁻ + e⁻
SA3. A galvanic cell is constructed using a zinc electrode in ZnSO₄(aq) and a silver electrode in AgNO₃(aq) connected by a salt bridge. E°(Zn²⁻/Zn) = −0.76 V; E°(Ag⁺/Ag) = +0.80 V. (a) Identify the anode and cathode. (b) Calculate E°cell and determine if the cell is spontaneous. (c) Write the balanced overall cell reaction. (3 marks)
1 mark: Zn = anode (lower E°, oxidised); Ag = cathode (higher E°, reduced); 1 mark: E°cell = +0.80 − (−0.76) = +1.56 V > 0 → spontaneous; 1 mark: Zn + 2Ag⁺ → Zn²⁻ + 2Ag (balance electrons: Zn → Zn²⁻ + 2e⁻; 2×(Ag⁺ + e⁻ → Ag))
SA4. A steel (iron) pipeline is buried underground in moist soil. An engineer attaches blocks of magnesium metal to the pipeline to prevent corrosion. E°(Fe²⁻/Fe) = −0.44 V; E°(Mg²⁻/Mg) = −2.37 V. (a) Name this type of cathodic protection. (b) Explain why magnesium is effective for this purpose using E° values. (c) Predict what will happen to the magnesium blocks over time. (3 marks)
1 mark: sacrificial anode protection; 1 mark: Mg has lower (more negative) E° than Fe → Mg is more readily oxidised → Mg acts as anode (is preferentially oxidised), Fe is protected as cathode; E°cell = −0.44 − (−2.37) = +1.93 V > 0 confirms spontaneous; 1 mark: Mg blocks gradually dissolve/corrode (Mg → Mg²⁻ + 2e⁻) and must be periodically replaced
SA1: (a) Zinc is above silver in the NESA activity series → Zn will react with AgNO₃. Copper is also above silver → Cu will also react with AgNO₃. (b) Zn(s) + 2AgNO₃(aq) → Zn(NO₃)₂(aq) + 2Ag(s); Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s). In both cases, a silver-grey solid deposits on the metal strip and the metal ions in solution change: Zn²⁻ replaces Ag⁺ (colourless solution remains); Cu²⁻ replaces Ag⁺ (solution turns blue as Cu²⁻ forms).
SA2: (a) In MnO₄⁻: O = −2 × 4 = −8; overall charge = −1; Mn = −1 − (−8) = +7. In Mn²⁻: Mn = +2. (b) Mn decreases from +7 to +2 → reduced. Fe increases from +2 to +3 → oxidised. (c) Fe²⁻(aq) → Fe³⁻(aq) + e⁻ [Note: the permanganate half-reaction requires H⁺ and H₂O to balance in acidic solution; that full balancing is beyond this checkpoint scope, but the Fe²⁻ half-equation is straightforward].
SA3: (a) Anode = Zn (lower reduction potential, E° = −0.76 V; Zn is oxidised). Cathode = Ag (higher reduction potential, E° = +0.80 V; Ag⁺ is reduced). (b) E°cell = E°cathode − E°anode = +0.80 − (−0.76) = +1.56 V. E°cell > 0 → spontaneous. (c) Half-equations: Zn → Zn²⁻ + 2e⁻; 2 × (Ag⁺ + e⁻ → Ag). Overall: Zn(s) + 2Ag⁺(aq) → Zn²⁻(aq) + 2Ag(s).
SA4: (a) Sacrificial anode protection (a form of cathodic protection). (b) Mg has a more negative standard reduction potential (E° = −2.37 V) than Fe (E° = −0.44 V). This means Mg is more readily oxidised than Fe. When both metals are in electrical contact in the moist soil (acting as an electrolyte), Mg acts as the anode (is preferentially oxidised: Mg → Mg²⁻ + 2e⁻) and Fe is protected as the cathode — electrons flow from Mg to Fe rather than Fe being oxidised. E°cell = −0.44 − (−2.37) = +1.93 V > 0 confirms the process is spontaneous. (c) The magnesium blocks gradually corrode and dissolve as Mg is continuously oxidised. Over time they shrink and must be periodically inspected and replaced to maintain protection.
Which topics do you need to revisit before moving on? Note the lesson numbers below.