Covering Lessons 11–12: defining reaction rate, collision theory, activation energy, the Maxwell-Boltzmann distribution, the effect of temperature and catalysts, and catalytic converters.
1. Marble chips react with hydrochloric acid and produce 48 mL of CO₂ in the first 4 minutes. What is the average rate of CO₂ production?
2. For a collision between two reactant molecules to result in a chemical reaction, which conditions must BOTH be satisfied?
3. On a Maxwell-Boltzmann energy distribution diagram, the activation energy (Eₐ) is represented by:
4. Which of the following correctly describes the effect of increasing temperature on the Maxwell-Boltzmann energy distribution?
5. A catalyst increases the rate of a reaction by:
6. Platinum (solid) catalyses the oxidation of carbon monoxide (gas) in a catalytic converter. This is an example of:
7. The rate of a reaction at 40°C is approximately four times the rate at 20°C. Which explanation is most consistent with collision theory?
8. Which of the following correctly explains why adding a catalyst does not change ΔH?
9. A catalytic converter becomes less effective when the car uses leaded petrol. Which explanation is correct?
10. Equal masses of marble chips (CaCO₃) react with excess HCl at 20°C and at 40°C. Which statement correctly describes the outcome?
SA1. Define reaction rate and explain, using collision theory, why the rate of the reaction CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g) decreases over time even if temperature is held constant. (3 marks)
1 mark: reaction rate = change in concentration/mass/volume per unit time; 1 mark: as reaction proceeds, [HCl] decreases → fewer H⁺ ions per unit volume; 1 mark: collision frequency between H⁺ and CaCO₃ surface decreases → fewer effective collisions per second → rate decreases
SA2. Explain, with reference to a Maxwell-Boltzmann energy distribution diagram, how a catalyst increases the rate of a reaction at constant temperature. In your answer: (a) describe what changes on the diagram when the catalyst is added; (b) explain why this leads to more effective collisions per second; (c) explain why ΔH is unchanged. (3 marks)
1 mark: catalyst lowers Eₐ → a new (lower) Eₐ line is drawn to the left on the same unchanged distribution curve; 1 mark: larger area to the right of the new (catalysed) Eₐ → greater proportion of particles now exceed the lower threshold → more effective collisions per second; 1 mark: ΔH unchanged because reactants and products are identical in both pathways — catalyst only lowers the barrier height, not the starting or finishing energy levels
SA3. A car’s catalytic converter converts toxic nitrogen oxide (NO) to harmless nitrogen and oxygen. (a) Write the balanced equation for this reaction. (b) Explain why this reaction is an example of heterogeneous catalysis. (c) Explain why the converter does not reduce NO emissions in the first 30–60 seconds after the car is started. (3 marks)
1 mark: 2NO(g) → N₂(g) + O₂(g) [check: N 2=2; O 2=2 ✓]; 1 mark: heterogeneous because catalyst (solid Pt/Pd) is in a different phase from the reactants (gaseous NO); reaction proceeds by surface adsorption; 1 mark: at startup the Pt surface is below operating temperature (~300–400°C) and cannot effectively adsorb and activate NO molecules — the catalytic cycle cannot begin until the converter warms up
SA1: Reaction rate is the change in concentration, mass, or volume of a reactant or product per unit time (e.g. mol/L/s, g/s, mL/s). As the reaction proceeds, HCl is consumed — its concentration decreases over time. With fewer H⁺ ions per unit volume in solution, the average distance between H⁺ ions and the CaCO₃ surface increases, so collisions between H⁺ and the solid surface occur less frequently. The proportion of those collisions that are effective (energy ≥ Eₐ and correct orientation) is unchanged at constant temperature. Therefore the number of effective collisions per second decreases → rate decreases. This continues until CaCO₃ or HCl is fully consumed and the rate reaches zero.
SA2: (a) When a catalyst is added at constant temperature, the Maxwell-Boltzmann distribution curve is unchanged — the same spread of particle energies exists at the same temperature. A second vertical line is drawn to the left of the original Eₐ line, at a lower energy value (Eₐ(cat)). This represents the lower activation energy of the catalysed pathway. (b) The area under the distribution curve to the right of Eₐ(cat) is larger than the area to the right of Eₐ(uncat). This means a greater proportion of particles now have sufficient kinetic energy to undergo effective collisions. At the same temperature and collision frequency, more effective collisions occur per second → rate increases. (c) ΔH is unchanged because the catalyst provides an alternative reaction mechanism that still starts from the same reactants and ends with the same products. ΔH = energy of products − energy of reactants; since both are fixed (same chemical species), the energy difference is the same in both the catalysed and uncatalysed pathways. The catalyst only changes the height of the energy barrier (Eₐ), not the energy levels of reactants or products.
SA3: (a) 2NO(g) → N₂(g) + O₂(g). [Check: left = 2N, 2O; right = 2N, 2O ✓]. (b) This is heterogeneous catalysis because the catalyst (solid platinum or palladium) is in a different physical phase from the reactants (gaseous NO). The mechanism involves: (1) gaseous NO molecules adsorbing onto the solid platinum surface at active sites; (2) reaction on the surface, breaking N–O bonds and forming N–N and O–O bonds; (3) desorption of N₂ and O₂ products into the gas phase. The platinum surface is regenerated and not consumed. (c) Heterogeneous catalysis requires reactant gas molecules to adsorb onto the catalyst surface and be activated. Below the operating temperature (~300–400°C), the platinum surface does not have sufficient thermal energy to facilitate effective adsorption of NO molecules — the molecules cannot bind to the active sites and the catalytic cycle cannot begin. Therefore NO passes through the cold converter unreacted, and emissions remain high until the converter warms up (typically within 30–90 seconds of starting the engine).
Which topics do you need to revisit before sitting the module quiz? Note them below.