Year 11 Chemistry Module 3 Checkpoint 3

Checkpoint 3

Covering Lessons 11–12: defining reaction rate, collision theory, activation energy, the Maxwell-Boltzmann distribution, the effect of temperature and catalysts, and catalytic converters.

⏱ ~20 min 10 MC · 3 Short Answer Lessons 11–12
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What’s Covered

L11
Collision Theory & Reaction Rate
  • Measuring reaction rate
  • Effective collision conditions
  • Activation energy concept
  • Energy diagrams
  • Rate decreases over time
L12
Factors Affecting Reaction Rate
  • Temperature & Maxwell-Boltzmann
  • Concentration & surface area
  • Homogeneous vs heterogeneous catalysts
  • Catalyst energy diagrams
  • Catalytic converters

Multiple Choice — 10 marks

L11 — Rate Calculation

1. Marble chips react with hydrochloric acid and produce 48 mL of CO₂ in the first 4 minutes. What is the average rate of CO₂ production?

A 4 mL/min
B 8 mL/min
C 12 mL/min
D 192 mL/min
L11 — Effective Collision Conditions

2. For a collision between two reactant molecules to result in a chemical reaction, which conditions must BOTH be satisfied?

A High temperature AND correct orientation
B Kinetic energy ≥ Eₐ AND correct orientation
C Kinetic energy ≥ Eₐ AND high reactant concentration
D Correct orientation AND a low activation energy
L11 — Activation Energy

3. On a Maxwell-Boltzmann energy distribution diagram, the activation energy (Eₐ) is represented by:

A The peak of the distribution curve
B A vertical line on the energy axis, to the right of which particles have sufficient energy to react
C The total area under the curve
D The average kinetic energy of all the particles
L12 — Temperature Effect

4. Which of the following correctly describes the effect of increasing temperature on the Maxwell-Boltzmann energy distribution?

A The curve shifts to the left and the peak becomes higher and narrower
B The curve shifts to the right, the peak becomes lower and broader, and the area under the curve increases
C The curve shifts to the right, the peak becomes lower and broader, and the area under the curve remains the same
D The activation energy decreases and the curve shifts to the right
L12 — Catalyst Mechanism

5. A catalyst increases the rate of a reaction by:

A Increasing the temperature of the reaction mixture
B Providing an alternative reaction pathway with a lower activation energy
C Increasing the concentration of reactant particles
D Shifting the Maxwell-Boltzmann distribution to higher energies
L12 — Homogeneous vs Heterogeneous

6. Platinum (solid) catalyses the oxidation of carbon monoxide (gas) in a catalytic converter. This is an example of:

A Homogeneous catalysis
B Heterogeneous catalysis
C Thermal catalysis
D Acid-base catalysis
L11–L12 — Applying Rate Concepts

7. The rate of a reaction at 40°C is approximately four times the rate at 20°C. Which explanation is most consistent with collision theory?

A The activation energy doubled as the temperature doubled
B The proportion of particles exceeding Eₐ approximately doubled with each 10°C rise, giving a fourfold rate increase over 20°C
C The concentration of the reactants doubled at higher temperature
D The Maxwell-Boltzmann curve became twice as tall at 40°C, exposing more particles
L12 — Catalyst & ΔH

8. Which of the following correctly explains why adding a catalyst does not change ΔH?

A Catalysts increase both the forward and reverse activation energies by equal amounts
B Catalysts provide an alternative pathway to the same reactants and products; the energy difference between them is unchanged
C Catalysts lower both Eₐ and ΔH by the same proportion
D Catalysts change the kinetic energy of particles but not the thermodynamic stability of the products
L12 — Catalyst Poisoning

9. A catalytic converter becomes less effective when the car uses leaded petrol. Which explanation is correct?

A Lead increases the activation energy of the catalysed reactions
B Lead reacts with CO to form a product that clogs the exhaust system
C Lead compounds coat the platinum surface and block active sites, preventing reactant molecules from adsorbing
D Lead changes the platinum catalyst from a solid to a liquid phase
L11–L12 — Synthesis

10. Equal masses of marble chips (CaCO₃) react with excess HCl at 20°C and at 40°C. Which statement correctly describes the outcome?

A The 40°C reaction produces more CO₂ in total because the rate is higher
B Both reactions produce equal amounts of CO₂ in total; the 40°C reaction has a steeper initial gradient and reaches completion first
C The 20°C reaction produces more CO₂ because the reaction proceeds more slowly and completely
D Both reactions produce equal amounts of CO₂; the 20°C reaction has a steeper initial gradient because fewer particles are excited

Short Answer — 9 marks

L11 — Rate & Collision Theory

SA1. Define reaction rate and explain, using collision theory, why the rate of the reaction CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g) decreases over time even if temperature is held constant. (3 marks)

1 mark: reaction rate = change in concentration/mass/volume per unit time; 1 mark: as reaction proceeds, [HCl] decreases → fewer H⁺ ions per unit volume; 1 mark: collision frequency between H⁺ and CaCO₃ surface decreases → fewer effective collisions per second → rate decreases

Saved
L12 — Maxwell-Boltzmann & Catalysts

SA2. Explain, with reference to a Maxwell-Boltzmann energy distribution diagram, how a catalyst increases the rate of a reaction at constant temperature. In your answer: (a) describe what changes on the diagram when the catalyst is added; (b) explain why this leads to more effective collisions per second; (c) explain why ΔH is unchanged. (3 marks)

1 mark: catalyst lowers Eₐ → a new (lower) Eₐ line is drawn to the left on the same unchanged distribution curve; 1 mark: larger area to the right of the new (catalysed) Eₐ → greater proportion of particles now exceed the lower threshold → more effective collisions per second; 1 mark: ΔH unchanged because reactants and products are identical in both pathways — catalyst only lowers the barrier height, not the starting or finishing energy levels

Saved
L12 — Catalytic Converter Application

SA3. A car’s catalytic converter converts toxic nitrogen oxide (NO) to harmless nitrogen and oxygen. (a) Write the balanced equation for this reaction. (b) Explain why this reaction is an example of heterogeneous catalysis. (c) Explain why the converter does not reduce NO emissions in the first 30–60 seconds after the car is started. (3 marks)

1 mark: 2NO(g) → N₂(g) + O₂(g) [check: N 2=2; O 2=2 ✓]; 1 mark: heterogeneous because catalyst (solid Pt/Pd) is in a different phase from the reactants (gaseous NO); reaction proceeds by surface adsorption; 1 mark: at startup the Pt surface is below operating temperature (~300–400°C) and cannot effectively adsorb and activate NO molecules — the catalytic cycle cannot begin until the converter warms up

Saved
  • Q1 — C: Rate = Δvolume / Δt = 48 mL / 4 min = 12 mL/min.
  • Q2 — B: An effective collision requires BOTH (1) kinetic energy ≥ Eₐ (sufficient energy to break bonds and reach the transition state) AND (2) correct orientation (the reactive parts of the molecules must face each other). Temperature and concentration are factors that influence the frequency of collisions meeting these conditions, but they are not themselves the conditions.
  • Q3 — B: Eₐ is a fixed energy threshold marked as a vertical line on the x-axis of the Maxwell-Boltzmann diagram. Only particles whose kinetic energy places them to the right of this line can react. The area under the curve to the right of Eₐ represents the fraction of reactive particles.
  • Q4 — C: At higher temperature: the distribution shifts rightward (higher average energy), the peak decreases in height and broadens, and the area under the curve remains equal (same number of particles in the system). Option B is wrong — the total area is constant, not increased. Option D is wrong — temperature does not change Eₐ, which is a property of the reaction.
  • Q5 — B: A catalyst provides an alternative reaction pathway with a lower activation energy. This means a greater proportion of collisions at the same temperature have sufficient energy to be effective → rate increases. The catalyst is not consumed and does not change the temperature.
  • Q6 — B: Heterogeneous catalysis: the catalyst (solid Pt) is in a different phase from the reactants (gaseous CO and O₂). The reaction proceeds by the gas molecules adsorbing onto the platinum surface, reacting there, then desorbing as CO₂.
  • Q7 — B: The 10°C rule: for many reactions near room temperature, rate approximately doubles per 10°C rise. A 20°C increase → approximately 2 × 2 = 4-fold increase. This occurs because the M-B distribution shifts such that the area beyond Eₐ roughly doubles per 10°C. The curve does not become taller (option D) — area is constant.
  • Q8 — B: A catalyst provides an alternative pathway involving a lower-energy transition state, but the same reactants produce the same products. Because ΔH is determined by the energy difference between reactants and products (which are identical in both pathways), ΔH is unchanged. The catalyst only lowers the peak height (Eₐ), not the reactant or product energy levels.
  • Q9 — C: Catalyst poisoning: lead compounds (from leaded petrol) coat the active sites on the platinum surface, blocking reactant molecules (CO, O₂, NO) from adsorbing. With active sites blocked, the heterogeneous catalytic cycle cannot proceed. This is why leaded petrol was banned in most countries — it destroys catalytic converters.
  • Q10 — B: Rate determines how quickly the reaction proceeds, not how much product is formed in total. The total amount of CO₂ depends on the amount of CaCO₃ used (equal masses = same moles). Both reactions produce the same total CO₂. At 40°C, a higher proportion of HCl particles exceed Eₐ → more effective collisions per second → steeper initial rate gradient → reaction completes first.

SA1: Reaction rate is the change in concentration, mass, or volume of a reactant or product per unit time (e.g. mol/L/s, g/s, mL/s). As the reaction proceeds, HCl is consumed — its concentration decreases over time. With fewer H⁺ ions per unit volume in solution, the average distance between H⁺ ions and the CaCO₃ surface increases, so collisions between H⁺ and the solid surface occur less frequently. The proportion of those collisions that are effective (energy ≥ Eₐ and correct orientation) is unchanged at constant temperature. Therefore the number of effective collisions per second decreases → rate decreases. This continues until CaCO₃ or HCl is fully consumed and the rate reaches zero.

SA2: (a) When a catalyst is added at constant temperature, the Maxwell-Boltzmann distribution curve is unchanged — the same spread of particle energies exists at the same temperature. A second vertical line is drawn to the left of the original Eₐ line, at a lower energy value (Eₐ(cat)). This represents the lower activation energy of the catalysed pathway. (b) The area under the distribution curve to the right of Eₐ(cat) is larger than the area to the right of Eₐ(uncat). This means a greater proportion of particles now have sufficient kinetic energy to undergo effective collisions. At the same temperature and collision frequency, more effective collisions occur per second → rate increases. (c) ΔH is unchanged because the catalyst provides an alternative reaction mechanism that still starts from the same reactants and ends with the same products. ΔH = energy of products − energy of reactants; since both are fixed (same chemical species), the energy difference is the same in both the catalysed and uncatalysed pathways. The catalyst only changes the height of the energy barrier (Eₐ), not the energy levels of reactants or products.

SA3: (a) 2NO(g) → N₂(g) + O₂(g). [Check: left = 2N, 2O; right = 2N, 2O ✓]. (b) This is heterogeneous catalysis because the catalyst (solid platinum or palladium) is in a different physical phase from the reactants (gaseous NO). The mechanism involves: (1) gaseous NO molecules adsorbing onto the solid platinum surface at active sites; (2) reaction on the surface, breaking N–O bonds and forming N–N and O–O bonds; (3) desorption of N₂ and O₂ products into the gas phase. The platinum surface is regenerated and not consumed. (c) Heterogeneous catalysis requires reactant gas molecules to adsorb onto the catalyst surface and be activated. Below the operating temperature (~300–400°C), the platinum surface does not have sufficient thermal energy to facilitate effective adsorption of NO molecules — the molecules cannot bind to the active sites and the catalytic cycle cannot begin. Therefore NO passes through the cold converter unreacted, and emissions remain high until the converter warms up (typically within 30–90 seconds of starting the engine).

Track Your Score

Multiple Choice (Q1–10) / 10
Short Answer (SA1–3) / 9
Total — / 19

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