Year 12 Chemistry Module 6 — Acid/Base Reactions ⏱ ~45 min Lesson 1 of 19 IQ1

Acid-Base Models — Arrhenius to Brønsted-Lowry

Every model of acids and bases in history was overturned by one molecule that didn't fit — and the model we use today still has limits scientists are pushing against.

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Think First

Ammonia (NH₃) is one of the most important industrial chemicals on Earth — used to make the fertilisers that feed roughly half the global population. But here's the problem: dissolve ammonia in water and the solution is unmistakably basic. Litmus turns blue. pH climbs above 7. Every test confirms it is a base. According to one of the most famous acid-base theories in the history of chemistry, that should be impossible — because ammonia contains no hydroxide ions whatsoever.

Question 1: Before reading on, write down your best guess — what do you think a substance needs to contain or do in order to make a solution basic?

Question 2: The same problem applies to this gas-phase reaction: HCl(g) + NH₃(g) → NH₄Cl(s). No water, no ions in solution — yet chemists call this an acid-base reaction. How do you think that's possible?

Hold your answers. You will come back to test them — and almost certainly revise them — at the end of this lesson.

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Key Relationships — This Lesson

Arrhenius acid → produces H⁺ in aqueous solution
e.g. HCl → H⁺ + Cl⁻ (in water) Limitation: aqueous solutions only; cannot explain NH₃ as a base
Arrhenius base → produces OH⁻ in aqueous solution
e.g. NaOH → Na⁺ + OH⁻ (in water) Limitation: cannot classify NH₃ — it has no OH⁻
Brønsted-Lowry acid → proton (H⁺) donor in any reaction
Works in aqueous AND non-aqueous contexts e.g. HCl + H₂O → H₃O⁺ + Cl⁻ (HCl donates H⁺ to H₂O)
Brønsted-Lowry base → proton (H⁺) acceptor in any reaction
e.g. NH₃ + H₂O ⇌ NH₄⁺ + OH⁻ (NH₃ accepts H⁺ from H₂O)
Conjugate base = acid − H⁺  |  Conjugate acid = base + H⁺
Pairs always on opposite sides of the equation, differ by exactly one H⁺
H⁺(aq) + H₂O(l) → H₃O⁺(aq)  (hydronium ion)
Bare H⁺ cannot exist in water — instantly bonds to H₂O H⁺(aq) and H₃O⁺(aq) represent the same species
No calculation formulas this lesson — models and definitions are conceptual. All formulas in this panel describe relationships and processes, not calculations.

Choose how you work — type your answers below or write in your book.

📖 Know

  • The four acid-base models: Lavoisier, Davy, Arrhenius, Brønsted-Lowry
  • Each model's definition of an acid and base
  • The specific limitation that caused each model to be replaced
  • What H₃O⁺ (hydronium ion) is and why we write it

💡 Understand

  • Why ammonia is a base in Brønsted-Lowry but cannot be classified by Arrhenius
  • Why the gas-phase reaction HCl + NH₃ → NH₄Cl is an acid-base reaction under Brønsted-Lowry
  • The inverse strength relationship between conjugate pairs
  • When to write H⁺ vs H₃O⁺ and why it matters in extended responses

✅ Can Do

  • Identify the Brønsted-Lowry acid and base in any given equation
  • Identify both conjugate acid-base pairs from a full ionic equation
  • Evaluate a student claim about acid-base models using specific examples
  • Write balanced ionic equations showing proton transfer with correct arrow notation
Key Terms — scan these before reading
Arrhenius acidA substance that produces H⁺ ions when dissolved in water.
Brønsted-Lowry acidA proton (H⁺) donor in an acid-base reaction.
Brønsted-Lowry acidA proton (H⁺) donor in an acid-base reaction.
Brønsted-Lowry baseA proton (H⁺) acceptor in an acid-base reaction.
Conjugate acid-base pairTwo species differing by one H⁺ that interconvert.
pHThe negative logarithm of hydronium ion concentration.

Every scientific model is replaced not when scientists grow bored of it, but when a single observation appears that it cannot explain — the history of acid-base theory shows this process operating three times in just over a century.

The story begins with Antoine Lavoisier in the late 1700s, who proposed that all acids contain oxygen. Given the acids he studied — sulfuric (H₂SO₄), nitric (HNO₃), phosphoric (H₃PO₄) — this was a reasonable induction. His model was overturned in 1810 when Humphry Davy demonstrated conclusively that hydrochloric acid (HCl) is strongly acidic yet contains no oxygen whatsoever. Davy's revision was straightforward: the essential ingredient is not oxygen but hydrogen — acids must contain hydrogen.

This improved model survived longer but still lacked a definition for bases, and it could not explain which hydrogen-containing compounds were acidic (CH₄ contains hydrogen but is not acidic). In 1884, Svante Arrhenius produced the first rigorous quantitative model: an acid produces H⁺ in aqueous solution, and a base produces OH⁻ in aqueous solution. This model worked beautifully for common laboratory acids and alkali metal hydroxides, and it underpinned the first quantitative treatments of neutralisation. Its limitation was structural: it was locked to aqueous solution and to OH⁻-containing bases. It could not explain ammonia (no OH⁻), could not describe gaseous acid-base reactions, and could not account for the basicity of carbonate or bicarbonate ions.

In 1923, Johannes Brønsted and Thomas Lowry independently proposed the model that resolves all of these cases: an acid is a proton donor, and a base is a proton acceptor, in any reaction in any medium.

Lavoisier

Acid defined as: Contains oxygen
Base defined as:
Fatal limitation: HCl is acidic, contains no oxygen

Davy

Acid defined as: Contains hydrogen
Base defined as:
Fatal limitation: No definition for bases; CH₄ has H but is not acidic

Arrhenius

Acid defined as: Produces H⁺ in aqueous solution
Base defined as: Produces OH⁻ in aqueous solution
Fatal limitation: Aqueous only; NH₃ has no OH⁻ yet is basic; cannot explain HCl(g) + NH₃(g) → NH₄Cl(s)

Brønsted-Lowry

Acid defined as: Proton (H⁺) donor
Base defined as: Proton (H⁺) acceptor
Fatal limitation: Cannot account for Lewis acid-base reactions without proton transfer (e.g. BF₃ + F⁻ → BF₄⁻)
HSC TipIn any extended response comparing or evaluating acid-base models, you must state each model's definition AND its specific limitation. Writing only the definition earns partial marks. The limitation is worth as many marks as the definition in most marking guidelines.
Common ErrorStudents say Arrhenius was "wrong" or "disproved." He was not — his model correctly describes every strong acid and strong base in aqueous solution and is still used for basic pH calculations. The correct language is: his model is "limited to aqueous systems" or "cannot account for bases that do not contain OH⁻." A model that is incomplete is not the same as a model that is incorrect.
InsightThe gaseous reaction HCl(g) + NH₃(g) → NH₄Cl(s) is a complete acid-base reaction producing a salt — yet it occurs with no water, no solvent, and no ions in solution at any stage. Arrhenius cannot classify either reactant in this reaction. Brønsted-Lowry handles it without modification: HCl donates a proton to NH₃, producing NH₄⁺ and Cl⁻. The model works because it describes what actually happens — a proton transfer — rather than what ions appear in solution.
Lavoisier 1780s Acids contain O Broken by: HCl Davy 1810 Acids contain H No base definition Arrhenius 1884 H⁺ / OH⁻ in H₂O H⁺/OH⁻ in water Broken by: NH₃ Brønsted-Lowry 1923 Proton transfer H⁺ donor/acceptor Any medium HSC MODEL Use this one

Acid-Base Model Timeline — each model replaced by the one anomaly it could not explain

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Brønsted-Lowry Acids and Bases — Proton Transfer at the Molecular Level

Model before formula — picture the proton moving before writing any equation

Before writing any equation, picture what is physically happening: a proton — a bare hydrogen nucleus — detaches from one species and bonds to another, and that single event is the entire definition of a Brønsted-Lowry acid-base reaction.

In the Brønsted-Lowry model, every acid-base reaction is a proton transfer event. The species that releases the proton is the acid; the species that receives it is the base. These roles are defined by what happens in the specific reaction, not by the identity of the substance in isolation — the same molecule can be an acid in one reaction and a base in another.

Consider HCl dissolving in water: HCl donates H⁺ to H₂O, making HCl the acid and H₂O the base. The product H₃O⁺ forms because water has accepted the proton. Since HCl ionises completely, we write a single forward arrow (→):

HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)

Now consider ammonia dissolving in water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. Here, water donates H⁺ to NH₃ — water is now the acid and NH₃ is the base. The OH⁻ does not come from NH₃; it is the water molecule's remains after it donated its proton. This is why ammonia is a base in the Brønsted-Lowry model: it accepts a proton from water, releasing OH⁻ as a consequence of the water's proton donation — not because ammonia itself contains OH⁻. Since NH₃ only partially ionises, we write the equilibrium arrow (⇌):

NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

The two reactions above also demonstrate that water is amphoteric — it can act as either an acid or a base depending on its reaction partner. This property of water is central to understanding pH, Kw, and buffer systems in later lessons.

HCl + H₂O → H₃O⁺ + Cl⁻

What the acid does: HCl loses H⁺ → Cl⁻
Acid: HCl
What the base does: H₂O gains H⁺ → H₃O⁺
Base: H₂O

NH₃ + H₂O ⇌ NH₄⁺ + OH⁻

What the acid does: H₂O loses H⁺ → OH⁻
Acid: H₂O
What the base does: NH₃ gains H⁺ → NH₄⁺
Base: NH₃

CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻

What the acid does: CH₃COOH loses H⁺
Acid: CH₃COOH
What the base does: H₂O gains H⁺ → H₃O⁺
Base: H₂O
HSC TipWhen asked to identify a Brønsted-Lowry acid and base, always explicitly state which proton is transferred, which species it moves FROM, and which species it moves TO. "HCl is the acid" is incomplete. "HCl is the Brønsted-Lowry acid because it donates a proton (H⁺) to water, forming H₃O⁺" is complete and earns full marks.
Common Error"Ammonia is a base because it produces OH⁻ in solution." This is the Arrhenius explanation and it is incomplete — worse, it implies NH₃ contains OH⁻, which it does not. The Brønsted-Lowry explanation is: NH₃ is a base because it accepts a proton from water. The OH⁻ produced is the remains of the water molecule after it donated its proton to NH₃.
Reactants Products H Cl HCl O H H H₂O with lone pair proton transferred O H H H H₃O⁺ Cl⁻ Brønsted-Lowry acid donates H⁺ Water acts as base and accepts H⁺

Brønsted-Lowry proton transfer: HCl donates H⁺ and water accepts it, forming H₃O⁺ and Cl⁻.

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Conjugate Acid-Base Pairs — Identifying and Using Them

Differ by exactly one H⁺ · Always on opposite sides of the equation

Every Brønsted-Lowry acid-base reaction produces a new acid and a new base on the product side — and these conjugate species are always related to their parent by exactly one proton, nothing more.

When a Brønsted-Lowry acid donates a proton, the species it becomes is its conjugate base — it has one fewer H and one more negative charge than the original acid. When a Brønsted-Lowry base accepts a proton, the species it becomes is its conjugate acid — it has one more H and one less negative charge than the original base.

A conjugate acid-base pair consists of two species on opposite sides of the equation that differ by exactly one proton.

Consider the full equation: CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻

A crucial strength relationship flows from this pairing: a strong acid has a very weak conjugate base (if an acid donates its proton very readily, the resulting conjugate base has very little tendency to accept it back). Conversely, a weak acid has a relatively stronger conjugate base. This inverse relationship governs which direction an acid-base equilibrium favours, and it underpins buffer theory in L13.

ReactionAcid (left)Conjugate base (right)Base (left)Conjugate acid (right)
HCl + H₂O → H₃O⁺ + Cl⁻HClCl⁻H₂OH₃O⁺
NH₃ + H₂O ⇌ NH₄⁺ + OH⁻H₂OOH⁻NH₃NH₄⁺
CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻CH₃COOHCH₃COO⁻H₂OH₃O⁺
HCO₃⁻ + H₂O ⇌ H₂CO₃ + OH⁻H₂OOH⁻HCO₃⁻H₂CO₃
HPO₄²⁻ + H₂O ⇌ H₂PO₄⁻ + OH⁻H₂OOH⁻HPO₄²⁻H₂PO₄⁻
MethodTo find a conjugate base: remove one H⁺ and add one negative charge. To find a conjugate acid: add one H⁺ and remove one negative charge. Check your answer by verifying the formula differs by exactly H⁺ and that the species appear on opposite sides of the equation.
Common ErrorStudents list two species on the SAME side of the equation as a conjugate pair — for example, calling CH₃COOH and H₂O a conjugate pair because both appear on the left. Conjugate pairs are always one species from the left AND one from the right. Another common error: identifying SO₄²⁻ as the conjugate base of H₂SO₄. This is wrong — the conjugate base of H₂SO₄ is HSO₄⁻ (remove only one proton at a time).
InsightThe strength relationship between conjugate pairs has a direct consequence for equilibrium direction. An acid-base reaction always proceeds to favour the weaker acid and weaker base — the equilibrium lies on the side of the weaker pair. HCl + H₂O → H₃O⁺ + Cl⁻ proceeds to completion (→) because HCl is a far stronger acid than H₃O⁺, and H₂O is a far stronger base than Cl⁻.
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H⁺ in Water — Why We Write H₃O⁺ and When It Matters

The hydronium ion · Band 5–6 molecular-level explanations require H₃O⁺

Writing H⁺(aq) is a chemist's shorthand that hides a physical reality — a bare proton cannot exist in water for even a fraction of a nanosecond before bonding to a water molecule, and understanding this is essential for any molecular-level explanation.

A hydrogen ion, H⁺, is simply a proton — a hydrogen atom stripped of its single electron, leaving behind only the nucleus. A bare proton has an extraordinarily high charge density and is one of the most reactive species in chemistry. In aqueous solution, a free H⁺ ion immediately forms a coordinate covalent bond with a lone pair on a water molecule, producing the hydronium ion:

H⁺(aq) + H₂O(l) → H₃O⁺(aq)

The lifetime of a free H⁺ ion in water is estimated at less than 10⁻¹³ seconds — it effectively does not exist as an isolated species. This is why Brønsted-Lowry equations for aqueous acid reactions correctly show H₃O⁺ as the product rather than H⁺ alone.

In HSC contexts, H⁺(aq) is an accepted shorthand used extensively in calculations — it represents the same species as H₃O⁺(aq). However, in any question asking you to explain what happens at the molecular or ionic level when an acid dissolves in water, writing H₃O⁺ and explaining the proton transfer to water is required for Band 5–6 responses.

Acceptable notation
H⁺(aq) or H₃O⁺(aq)
H₃O⁺ preferred
H₃O⁺ required
H⁺ acceptable
Why
Both represent the same species; H⁺ is shorthand
Shows water acting as base (proton acceptor) — the full mechanism
Demonstrates understanding of proton transfer to water
Arrhenius model predates H₃O⁺ notation; context-dependent
HSC TipIn extended response questions asking you to describe what happens "at the molecular level" or "using the Brønsted-Lowry model" when an acid dissolves in water, you must explicitly state that H⁺ bonds to H₂O to form H₃O⁺ and identify water as the proton acceptor (Brønsted-Lowry base). Writing only "HCl → H⁺ + Cl⁻" omits the role of water and will not earn full marks.
Common ErrorStudents write HCl → H⁺ + Cl⁻ in a Brønsted-Lowry context. This equation shows dissociation in isolation — it does not show the proton transfer to water that the Brønsted-Lowry model requires. The correct Brønsted-Lowry equation is HCl + H₂O → H₃O⁺ + Cl⁻, which shows HCl donating H⁺ to H₂O (the base), producing H₃O⁺ (the conjugate acid of water) and Cl⁻ (the conjugate base of HCl).
Arrhenius model Brønsted-Lowry model H⁺ OH⁻ acid/base described by ions present in water works well for HCl and NaOH in aqueous solution NH₃ H₂O H⁺ transfer explains why NH₃ is a base without containing OH⁻ focus: ions produced focus: proton donation and acceptance

Arrhenius describes acids and bases by the ions they produce in water. Brønsted-Lowry explains acid-base behaviour by proton transfer, so it can handle NH₃ and non-aqueous reactions.

🌍 Real-World Anchor — The Chemistry Behind Feeding the World

Why Ammonia's Basicity Changed Acid-Base Chemistry Forever

Ammonia (NH₃) is the chemical that broke Arrhenius's model — and understanding why it is basic is not just a theoretical curiosity. The Haber process synthesises NH₃ from N₂ and H₂ at high temperature and pressure. This ammonia is then reacted with sulfuric acid in a Brønsted-Lowry acid-base reaction: NH₃ + H₂SO₄ → (NH₄)₂SO₄ (ammonium sulfate — a major nitrogen fertiliser). Without Brønsted-Lowry's insight that NH₃ accepts protons (rather than producing OH⁻), chemists would have struggled to explain and optimise the reactions that produce the fertilisers feeding approximately half the global population today.

The gas-phase reaction HCl(g) + NH₃(g) → NH₄Cl(s) — white solid ammonium chloride forming as a smoke when the gases mix — was the definitive experimental proof that acid-base reactions do not require water. It was observations like this that made Arrhenius's aqueous-only model untenable and drove Brønsted and Lowry to develop their proton-transfer framework.

⚠️ Common Misconceptions — Module 6 Lesson 1

"Arrhenius was proved wrong." — Arrhenius was not wrong — he was incomplete. His model correctly predicts the behaviour of strong acids and bases in aqueous solution and is still used in pH calculations. The correct language is "limited to aqueous systems" or "cannot account for bases without OH⁻."

"NH₃ is a base because it contains OH⁻." — NH₃ contains no OH⁻ whatsoever. It is a base because it accepts a proton (H⁺) from water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. The OH⁻ in solution comes from the water molecule that donated its proton to NH₃, not from NH₃ itself.

"HCl dissociates as HCl → H⁺ + Cl⁻ (using Brønsted-Lowry)." — In the Brønsted-Lowry model, you must show the proton transfer to water: HCl + H₂O → H₃O⁺ + Cl⁻. Writing HCl → H⁺ + Cl⁻ in a Brønsted-Lowry context omits water's role as the proton acceptor (base) and will not earn full marks in extended responses.

"SO₄²⁻ is the conjugate base of H₂SO₄." — Remove only one proton at a time. The conjugate base of H₂SO₄ is HSO₄⁻ (H₂SO₄ − H⁺). SO₄²⁻ is the conjugate base of HSO₄⁻. A conjugate pair always differs by exactly one H⁺.

"Conjugate pairs are two species on the same side of the equation." — Conjugate pairs are always one species from the left AND one from the right, related by the loss or gain of exactly one H⁺. Species on the same side are not conjugate pairs.

✏️ Worked Examples

Worked Example 1 — Identifying conjugate pairs and roles in a full equation

For the reaction HPO₄²⁻ + H₂O ⇌ H₂PO₄⁻ + OH⁻, identify (a) the Brønsted-Lowry acid and base on the left side; (b) the conjugate acid and conjugate base on the right side; (c) both conjugate pairs.

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(a) Identify which species donates a proton. Compare left and right: H₂O (left) → OH⁻ (right). H₂O has lost one H⁺ to become OH⁻. Therefore H₂O is the Brønsted-Lowry acid. HPO₄²⁻ (left) → H₂PO₄⁻ (right). HPO₄²⁻ has gained one H⁺ to become H₂PO₄⁻. Therefore HPO₄²⁻ is the Brønsted-Lowry base.

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(b) Identify conjugate species on the right. Conjugate acid = the base after it gains a proton = H₂PO₄⁻ (HPO₄²⁻ + H⁺). Conjugate base = the acid after it loses a proton = OH⁻ (H₂O − H⁺).

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(c) State both conjugate pairs explicitly. Conjugate pair 1 — H₂O (acid, left) and OH⁻ (conjugate base, right): differ by one H⁺, on opposite sides ✓. Conjugate pair 2 — HPO₄²⁻ (base, left) and H₂PO₄⁻ (conjugate acid, right): differ by one H⁺, on opposite sides ✓.

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Verification: Check charges balance. Left: −2 + 0 = −2. Right: −1 + (−1) = −2 ✓. Check atoms balance: P: 1 = 1 ✓; H: (1+2) = 3 left, (2+1) = 3 right ✓; O: (4+1) = 5 left, (4+1) = 5 right ✓.

Answer: (a) Acid = H₂O; Base = HPO₄²⁻. (b) Conjugate acid = H₂PO₄⁻; Conjugate base = OH⁻. (c) Pair 1: H₂O / OH⁻. Pair 2: HPO₄²⁻ / H₂PO₄⁻.

Worked Example 2 — Evaluating model limitations with a real reaction

(a) Explain why the Arrhenius model cannot describe HCl(g) + NH₃(g) → NH₄Cl(s). (b) Using Brønsted-Lowry, identify the acid, base, conjugate acid, and conjugate base, and write the proton-transfer equation. (c) Explain at the molecular level why NH₃ acts as a base in this reaction.

1

(a) Why Arrhenius fails: The Arrhenius model defines an acid as a substance that produces H⁺ in aqueous solution, and a base as a substance that produces OH⁻ in aqueous solution. This reaction occurs entirely in the gas phase — there is no solvent, no aqueous solution, and no ions produced in water. Furthermore, NH₃ contains no OH⁻ — it cannot satisfy the Arrhenius definition of a base under any circumstances. The Arrhenius model is therefore completely inapplicable to this reaction.

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(b) Brønsted-Lowry analysis: Identify the proton transfer: HCl → Cl⁻ (HCl loses H⁺) → HCl is the acid; Cl⁻ is the conjugate base. NH₃ → NH₄⁺ (NH₃ gains H⁺) → NH₃ is the base; NH₄⁺ is the conjugate acid.

HCl(g) + NH₃(g) → NH₄⁺(aq) + Cl⁻(aq) → NH₄Cl(s)

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(c) Molecular-level explanation: The nitrogen atom in NH₃ has a lone pair of electrons. When HCl and NH₃ molecules collide with sufficient energy in the gas phase, the lone pair on N forms a coordinate covalent bond with the H of HCl — the proton transfers from Cl to N. This leaves Cl with the bonding electrons as Cl⁻, and produces NH₄⁺. NH₃ acts as a Brønsted-Lowry base because it accepts the proton via its lone pair — no OH⁻ is involved at any stage.

Answer: (a) Arrhenius requires aqueous solution and OH⁻ for bases — neither applies here. (b) Acid = HCl; conjugate base = Cl⁻; base = NH₃; conjugate acid = NH₄⁺. Equation: HCl(g) + NH₃(g) → NH₄Cl(s). (c) NH₃ accepts H⁺ via its nitrogen lone pair — Brønsted-Lowry base by proton acceptance, no OH⁻ involved.

Worked Example 3 — Band 6 Extended Response: Model Comparison

(6 marks) A chemistry student states: "The Arrhenius model and the Brønsted-Lowry model are essentially the same — they both just describe acids producing H⁺ and bases producing OH⁻ in water." Evaluate this statement using at least two specific chemical examples.

1

Identify what the student got partially right: For strong acids and bases in aqueous solution, both models give identical predictions. HCl in water — Arrhenius: produces H⁺; Brønsted-Lowry: donates H⁺ to water producing H₃O⁺. Both correctly identify HCl as an acid. NaOH in water — Arrhenius: produces OH⁻; Brønsted-Lowry: OH⁻ is the base (it accepts H⁺). The student is not entirely wrong for this class of substances.

2

Where the models diverge — Example 1 (NH₃): Arrhenius cannot classify NH₃ as a base — it contains no OH⁻ and produces none directly. The Arrhenius model would predict NH₃ is not a base, contradicting experimental evidence. Brønsted-Lowry correctly identifies NH₃ as a base: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, where NH₃ accepts H⁺ from water. The OH⁻ comes from water, not from NH₃. The two models make different predictions — Arrhenius fails here.

3

Where the models diverge — Example 2 (gas phase): HCl(g) + NH₃(g) → NH₄Cl(s) is a complete acid-base reaction producing a salt. Arrhenius cannot describe it at all — no aqueous solution exists. Brønsted-Lowry describes it straightforwardly: HCl donates H⁺ to NH₃ in the gas phase. The models are NOT equivalent in scope — Brønsted-Lowry is a broader framework.

4

Evaluate the key conceptual difference: Arrhenius defines acids and bases by what ions they produce in water — a macroscopic, product-based definition. Brønsted-Lowry defines acids and bases by what they do — proton transfer — a mechanistic, process-based definition that applies in any medium. Brønsted-Lowry also explains WHY bases make solutions basic: by accepting H⁺ from water, they leave OH⁻ behind. Both models also have their own limitations — Brønsted-Lowry cannot describe Lewis acid-base reactions (e.g. BF₃ + F⁻ → BF₄⁻) that involve no proton transfer.

Answer: The statement is an oversimplification. For aqueous strong acid-base reactions both models agree — but they diverge for NH₃ (Arrhenius fails; Brønsted-Lowry correctly identifies NH₃ as a proton acceptor) and for non-aqueous reactions (Arrhenius cannot apply; Brønsted-Lowry applies universally). The models differ in scope, in their definition of bases, and in mechanistic depth. Both retain limitations beyond which a further model (Lewis) is required. 6 marks: 1 mark for agreement in aqueous strong acids/bases; 2 marks for NH₃ divergence with equation; 2 marks for gas-phase reaction divergence; 1 mark for evaluating mechanistic difference.

📓 Copy Into Your Books

The Four Models

  • Lavoisier: acids contain O — broken by HCl
  • Davy: acids contain H — no base definition
  • Arrhenius: acid → H⁺(aq); base → OH⁻(aq) — aqueous only, NH₃ fails
  • Brønsted-Lowry: acid = H⁺ donor; base = H⁺ acceptor — any medium

Conjugate Pairs — Rules

  • Conjugate base = acid − H⁺ (one fewer H, one more −)
  • Conjugate acid = base + H⁺ (one more H, one fewer −)
  • Always on opposite sides of the equation
  • Always differ by exactly one H⁺
  • Strong acid → very weak conjugate base

H⁺ vs H₃O⁺

  • H⁺(aq) = H₃O⁺(aq) — same species, shorthand vs full
  • Calculations: either notation acceptable
  • Brønsted-Lowry equations: prefer H₃O⁺
  • Molecular-level extended responses: H₃O⁺ required
  • Bare H⁺ cannot exist in water — bonds to H₂O instantly

Arrow Notation — Critical

  • Strong acid/base: complete ionisation (e.g. HCl + H₂O → H₃O⁺ + Cl⁻)
  • Weak acid/base: partial ionisation (e.g. CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻)
  • Using → for a weak acid is a critical error — check every equation

🧪 Activities

🔬 Activity 1 — Sort + Classify

Classifying Reactions Under Each Model

For each reaction below: (A) State whether Arrhenius can classify it as an acid-base reaction. (B) State whether Brønsted-Lowry can classify it. (C) Identify the Brønsted-Lowry acid and base where applicable.

ReactionArrhenius can classify?BL can classify?BL acid / BL base
HNO₃(aq) + H₂O(l) → H₃O⁺(aq) + NO₃⁻(aq)Your answerYour answerYour answer
NH₃(g) + HCl(g) → NH₄Cl(s)Your answerYour answerYour answer
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)Your answerYour answerYour answer
CH₃COOH(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃COO⁻(aq)Your answerYour answerYour answer
BF₃ + F⁻ → BF₄⁻Your answerYour answerYour answer
🔍 Activity 2 — Conjugate Pair Identification

Finding Conjugate Pairs in Unfamiliar Equations

For each equation, identify both conjugate acid-base pairs. State which species is the acid and which is the base on the left side. Verify your pairs differ by exactly one H⁺.

  1. H₂SO₄(aq) + H₂O(l) → H₃O⁺(aq) + HSO₄⁻(aq)
    Identify both conjugate pairs. Why is the conjugate base HSO₄⁻ and NOT SO₄²⁻?
  2. HCO₃⁻(aq) + OH⁻(aq) → CO₃²⁻(aq) + H₂O(l)
    Identify the Brønsted-Lowry acid and base. Does HCO₃⁻ always act as an acid, or can it also be a base?
  3. H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻(aq)
    Identify both conjugate pairs. What does the ⇌ symbol tell you about H₂PO₄⁻?
  4. Write the Brønsted-Lowry equation for HF dissolving in water. Identify the acid and both conjugate pairs. Should you use → or ⇌? (Ka of HF = 6.8 × 10⁻⁴)
Interactive — Acid-Base Model Classifier
Interactive: Acid Base Theories Interactive
Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

❓ Multiple Choice

01

Test Your Knowledge

EvaluateBand 4

1. A student claims: "NH₃ is a base because it produces OH⁻ ions when dissolved in water." Which response best evaluates this claim?

A
Correct — NH₃ contains OH⁻ that is released when it dissolves
B
Correct — producing OH⁻ in water is the definition of a base in all models
C
Partially correct — NH₃ solutions do contain OH⁻, but the OH⁻ comes from water donating H⁺ to NH₃, not from OH⁻ in NH₃ itself; the Brønsted-Lowry explanation is that NH₃ acts as a proton acceptor
D
Incorrect — NH₃ is not a base because it contains no OH⁻
B
Correct — producing OH⁻ in water is the definition of a base in all models
C
Partially correct — NH₃ solutions do contain OH⁻, but the OH⁻ comes from water donating H⁺ to NH₃, not from OH⁻ in NH₃ itself; the Brønsted-Lowry explanation is that NH₃ acts as a proton acceptor
D
Incorrect — NH₃ is not a base because it contains no OH⁻
ApplyBand 3

2. In the reaction HCO₃⁻ + OH⁻ → CO₃²⁻ + H₂O, which species is the Brønsted-Lowry acid and what is its conjugate base?

A
Acid = OH⁻; conjugate base = H₂O
B
Acid = HCO₃⁻; conjugate base = CO₃²⁻
C
Acid = CO₃²⁻; conjugate base = HCO₃⁻
D
Acid = H₂O; conjugate base = OH⁻
B
Acid = HCO₃⁻; conjugate base = CO₃²⁻
C
Acid = CO₃²⁻; conjugate base = HCO₃⁻
D
Acid = H₂O; conjugate base = OH⁻
UnderstandBand 3

3. Which of the following correctly identifies a limitation of the Brønsted-Lowry model that is NOT shared by the Arrhenius model?

A
Brønsted-Lowry cannot explain why HCl is an acid in water
B
Brønsted-Lowry cannot explain acid-base reactions in non-aqueous solutions
C
Brønsted-Lowry cannot account for acid-base reactions that involve electron pair donation without proton transfer, such as BF₃ reacting with F⁻
D
Brønsted-Lowry incorrectly predicts that NH₃ is a base
UnderstandBand 3

Select the option that correctly identifies a limitation of the Brønsted-Lowry model that is NOT shared by the Arrhenius model?

A
Brønsted-Lowry cannot explain why HCl is an acid in water
B
Brønsted-Lowry cannot explain acid-base reactions in non-aqueous solutions
C
Brønsted-Lowry cannot account for acid-base reactions that involve electron pair donation without proton transfer, such as BF₃ reacting with F⁻
D
Brønsted-Lowry incorrectly predicts that NH₃ is a base
ApplyBand 3

4. Which equation correctly represents the Brønsted-Lowry ionisation of hydrofluoric acid (HF, a weak acid) in water?

A
HF(aq) + H₂O(l) ⇌ H₃O⁺(aq) + F⁻(aq)
B
HF(aq) + H₂O(l) → H₃O⁺(aq) + F⁻(aq)
C
HF(aq) ⇌ H⁺(aq) + F⁻(aq) [using Brønsted-Lowry]
D
HF(aq) + H₂O(l) ⇌ H₂F⁺(aq) + OH⁻(aq)
B
HF(aq) + H₂O(l) → H₃O⁺(aq) + F⁻(aq)
C
HF(aq) ⇌ H⁺(aq) + F⁻(aq) [using Brønsted-Lowry]
D
HF(aq) + H₂O(l) ⇌ H₂F⁺(aq) + OH⁻(aq)
AnalyseBand 5

5. A student writes the following in an extended response: "HCl is a Brønsted-Lowry acid. It ionises as HCl → H⁺ + Cl⁻." Which of the following best describes what is incomplete about this response?

A
The arrow notation should be ⇌ because HCl is a weak acid
B
The equation should show H⁺ combining with Cl⁻ to form HCl on the right
C
The student should have used the Arrhenius model instead as HCl is in aqueous solution
D
The equation does not show the proton transfer to water — in the Brønsted-Lowry model, the equation must include H₂O as the proton acceptor (base), producing H₃O⁺ as the conjugate acid: HCl + H₂O → H₃O⁺ + Cl⁻
AnalyseBand 5

A student writes the following in an extended response: "HCl is a Brønsted-Lowry acid. It ionises as HCl → H⁺ + Cl⁻." Which of the following is most accurately described by what is incomplete about this response?

A
The arrow notation should be ⇌ because HCl is a weak acid
B
The equation should show H⁺ combining with Cl⁻ to form HCl on the right
C
The student should have used the Arrhenius model instead as HCl is in aqueous solution
D
The equation does not show the proton transfer to water — in the Brønsted-Lowry model, the equation must include H₂O as the proton acceptor (base), producing H₃O⁺ as the conjugate acid: HCl + H₂O → H₃O⁺ + Cl⁻

✍️ Short Answer

02

Extended Questions

UnderstandBand 3

6. (a) State the Arrhenius definitions of an acid and a base. (b) Explain why the Arrhenius model cannot classify ammonia (NH₃) as a base. (c) Write the Brønsted-Lowry equation that correctly explains why NH₃ produces a basic solution in water. Identify the acid and base in your equation. 5 MARKS

ApplyBand 4

7. For the reaction: H₂PO₄⁻(aq) + CO₃²⁻(aq) ⇌ HPO₄²⁻(aq) + HCO₃⁻(aq)

(a) Identify both conjugate acid-base pairs. (b) Identify the Brønsted-Lowry acid and base on the left side. (c) Verify that your identified conjugate pairs each differ by exactly one H⁺ and appear on opposite sides of the equation. 4 MARKS

EvaluateBand 5

8. Real-World Application: The industrial synthesis of ammonium sulfate fertiliser [(NH₄)₂SO₄] involves reacting ammonia gas with sulfuric acid: 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)

(a) Using the Brønsted-Lowry model, explain why this is classified as an acid-base reaction. Identify the proton donor and proton acceptor. (2 marks)
(b) A student says this reaction cannot be described by Arrhenius. Is this correct? Explain your reasoning with reference to the specific definitions involved. (3 marks) 5 MARKS

03

Revisit Your Thinking

Go back to your Think First response at the top of this lesson. Now that you've studied the Brønsted-Lowry model:

✅ Comprehensive Answers

🔬 Activity 1 — Sort + Classify

Row 1 (HNO₃ + H₂O): Arrhenius: Yes — HNO₃ produces H⁺ in aqueous solution. BL: Yes — HNO₃ donates H⁺ to H₂O. BL acid = HNO₃; BL base = H₂O. Arrow = → (strong acid, complete ionisation).

Row 2 (NH₃ + HCl gas): Arrhenius: No — no aqueous solution, and NH₃ has no OH⁻. BL: Yes — HCl donates H⁺ to NH₃. BL acid = HCl; BL base = NH₃.

Row 3 (NaOH + HCl): Arrhenius: Yes — NaOH produces OH⁻; HCl produces H⁺. BL: Yes — HCl is the acid (or H₃O⁺ if you write HCl + H₂O first); OH⁻ is the base. This can be written as H₃O⁺ + OH⁻ → 2H₂O in net ionic form.

Row 4 (CH₃COOH + H₂O): Arrhenius: Yes — CH₃COOH produces H⁺ in water. BL: Yes — CH₃COOH donates H⁺ to H₂O. BL acid = CH₃COOH; BL base = H₂O. Arrow = ⇌ (weak acid).

Row 5 (BF₃ + F⁻): Arrhenius: No — no H⁺ or OH⁻ involved. BL: No — no proton transfer; F⁻ donates an electron pair to BF₃ (Lewis acid-base, not Brønsted-Lowry). This reaction requires the Lewis model.

🔍 Activity 2 — Conjugate Pair Identification

1. H₂SO₄ + H₂O → H₃O⁺ + HSO₄⁻: Pair 1: H₂SO₄ (acid) / HSO₄⁻ (conjugate base) — differ by one H⁺. Pair 2: H₂O (base) / H₃O⁺ (conjugate acid) — differ by one H⁺. Conjugate base is HSO₄⁻ not SO₄²⁻ because you can only remove one proton at a time — the conjugate base of H₂SO₄ is HSO₄⁻; SO₄²⁻ is the conjugate base of HSO₄⁻.

2. HCO₃⁻ + OH⁻ → CO₃²⁻ + H₂O: BL acid = HCO₃⁻ (donates H⁺ to OH⁻ → CO₃²⁻). BL base = OH⁻ (accepts H⁺ → H₂O). HCO₃⁻ can also act as a base (e.g. HCO₃⁻ + H₂O ⇌ H₂CO₃ + OH⁻ — in that reaction it accepts H⁺). HCO₃⁻ is amphiprotic — can donate OR accept H⁺ depending on the reaction partner (covered in L07).

3. H₂PO₄⁻ + H₂O ⇌ H₃O⁺ + HPO₄²⁻: Pair 1: H₂PO₄⁻ (acid) / HPO₄²⁻ (conjugate base). Pair 2: H₂O (base) / H₃O⁺ (conjugate acid). The ⇌ tells us H₂PO₄⁻ is a weak acid — it only partially donates its proton.

4. HF in water: HF(aq) + H₂O(l) ⇌ H₃O⁺(aq) + F⁻(aq). Arrow = ⇌ because Ka = 6.8 × 10⁻⁴ — HF is a weak acid (partially ionises). Pair 1: HF / F⁻. Pair 2: H₂O / H₃O⁺.

❓ Multiple Choice

1. C — NH₃ solutions do contain OH⁻ (the observation is correct), but the explanation is incomplete and misleading. The OH⁻ comes from water donating H⁺ to NH₃ (water acts as the acid), not from OH⁻ inside NH₃. The Brønsted-Lowry explanation is that NH₃ is a proton acceptor.

2. B — HCO₃⁻ loses one H⁺ to become CO₃²⁻ — it donates a proton, so it is the acid. CO₃²⁻ is its conjugate base. Option A reverses acid/base roles.

3. C — Lewis acid-base reactions (electron pair transfer without proton transfer) extend beyond Brønsted-Lowry. Arrhenius doesn't attempt to describe such reactions either — but the question asks for a limitation specific to Brønsted-Lowry. Options A and D are incorrect (Brønsted-Lowry handles both). Option B is the Arrhenius limitation, not Brønsted-Lowry.

4. A — HF is a weak acid (Ka = 6.8 × 10⁻⁴), so ⇌ is correct. The Brønsted-Lowry equation must include H₂O as the proton acceptor, producing H₃O⁺. Option B uses → (wrong for a weak acid). Option C omits water (not a Brønsted-Lowry equation). Option D is chemically incorrect.

5. D — The critical omission is that the Brønsted-Lowry model requires showing the proton transfer to water. "HCl → H⁺ + Cl⁻" is a dissociation equation, not a Brønsted-Lowry equation. The correct form is HCl + H₂O → H₃O⁺ + Cl⁻. Option A is wrong — HCl is a strong acid, → is correct. Options B and C are wrong.

📝 Short Answer Model Answers

Q6 (5 marks): (a) Arrhenius acid: a substance that produces H⁺ ions in aqueous solution [1]. Arrhenius base: a substance that produces OH⁻ ions in aqueous solution [1]. (b) Arrhenius cannot classify NH₃ as a base because NH₃ contains no OH⁻ ions and does not produce OH⁻ directly — it has the formula N₁H₃ with no oxygen present [1]. (c) NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq) [1]. Acid = H₂O (donates H⁺ to NH₃); Base = NH₃ (accepts H⁺ from H₂O). The OH⁻ in solution comes from the water molecule that donated its proton, not from NH₃ [1].

Q7 (4 marks): (a) Pair 1: H₂PO₄⁻ (acid, left) and HPO₄²⁻ (conjugate base, right) [1]. Pair 2: CO₃²⁻ (base, left) and HCO₃⁻ (conjugate acid, right) [1]. (b) BL acid on left = H₂PO₄⁻ (loses H⁺ → HPO₄²⁻); BL base on left = CO₃²⁻ (gains H⁺ → HCO₃⁻) [1]. (c) Pair 1: H₂PO₄⁻ has formula H₂PO₄⁻; HPO₄²⁻ has formula HPO₄²⁻ — differ by one H and one negative charge = one H⁺ ✓. On opposite sides of equation ✓. Pair 2: CO₃²⁻ / HCO₃⁻ — differ by one H⁺; on opposite sides ✓ [1].

Q8 (5 marks): (a) This is a Brønsted-Lowry acid-base reaction because a proton (H⁺) is transferred from H₂SO₄ to NH₃ [1]. Proton donor (acid) = H₂SO₄; proton acceptor (base) = NH₃ [1]. (b) Partially correct [1]. Arrhenius defines an acid as producing H⁺ in aqueous solution — H₂SO₄ satisfies this [1]. However, Arrhenius defines a base as producing OH⁻ in aqueous solution. NH₃ contains no OH⁻ and cannot be classified as an Arrhenius base. So the Arrhenius model CAN classify H₂SO₄ as an acid but CANNOT classify NH₃ as a base, making the Arrhenius framework incomplete (not totally inapplicable) for this reaction [1].

Science Jump

Acid-Base Models — Arrhenius to Brønsted-Lowry

Climb platforms, hit checkpoints, and answer questions on Acid-Base Models — Arrhenius to Brønsted-Lowry. Quick recall from lessons 1–1.

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