Maths Extension 1 Year 11 - Module 4 - Lesson 7
Properties of Combinations & Pascal's Identity
Name
Date
Class
1. Lesson focus
Combination properties and Pascal identity. Use symmetry nCr=nC(n−r) and Pascal's identity nCr=(n−1)C(r−1)+(n−1)Cr.
Success criteria
- Apply the lesson method accurately in a routine example.
- Show each algebraic or domain step and check the result.
- Explain why the method and restrictions fit the question.
2. Worked practice
2. Use Pascal's identity to evaluate 7C2+7C3.
3. Find the sum of the entries in row 5 of Pascal's triangle, starting row 0.
3. Challenge
Use Pascal's identity to find 9C4 from entries in row 8.
4. Multiple choice
By symmetry, 9C2 equals which combination?
A. 9C2+1
B. 9C7
C. 8C2
D. 9P7
Worked answer key
Compare each step with your working. Keep stated intervals, domains and restrictions in your final answer.
1. Evaluate 8C3 and use symmetry to state 8C5.
8C3=56; by symmetry 8C5=56.
2. Use Pascal's identity to evaluate 7C2+7C3.
7C2=21 and 7C3=35; their sum is 56=8C3.
3. Find the sum of the entries in row 5 of Pascal's triangle, starting row 0.
The row sum is 2⁵=32; entries 1,5,10,10,5,1 sum to 32.
Challenge. Use Pascal's identity to find 9C4 from entries in row 8.
9C4=8C3+8C4=56+70=126.
Multiple choice. By symmetry, 9C2 equals which combination?
Correct answer: B. For fixed n, nCr=nC(n−r), so 9C2=9C7.
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