Year 11 Physics Module 3: Waves 40 min Lesson 10 of 18

Sound Intensity, the Decibel Scale and Beats

Why does music sound quieter as you move away from a speaker, why does a 10 dB increase matter so much, and why do two nearby notes sometimes produce a pulsing wah-wah effect? This lesson links sound intensity, logarithmic decibels, and beats.

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Think First

If one workplace is measured at 90 dB and another at 100 dB, is the second place only “a little bit” more intense? Predict before we unpack what decibels actually mean.

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Key Relationships — This Lesson

$I \propto \dfrac{1}{r^2}$  |  $\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}$  |  $f_{\text{beat}} = |f_1 - f_2|$
I = intensity r = distance from source fbeat = beat frequency
Decibels: logarithmic scale   |   +10 dB: 10× more intense   |   Beats: slow amplitude variation from close frequencies

dB
Formula Reference — Sound Intensity and Beats

$I \propto 1/r^2$
Inverse Square Law for Sound
Intensity decreases with the square of distance from a point source.
Use when: comparing sound intensity at different distances.
Common trap: doubling distance does not halve intensity. It reduces intensity to one quarter.
$f_{\text{beat}} = |f_1 - f_2|$
Beat Frequency
Use the absolute difference between the two nearby frequencies.
Use when: two similar notes interfere and produce pulsing loudness.
Common trap: beats come from similar frequencies, not wildly different ones.

Know

  • The inverse square law for sound intensity
  • That the decibel scale is logarithmic
  • That +10 dB means 10 times more intense
  • That beats come from superposition of similar frequencies

Understand

  • Why sound intensity drops rapidly with distance
  • Why decibel differences are not simple linear steps
  • Why beats are heard as changing loudness rather than a new steady note
  • How these ideas connect to hearing safety and tuning instruments

Can Do

  • Compare intensities at different distances
  • Interpret simple decibel changes qualitatively
  • Calculate beat frequency
  • Explain how beats help with instrument tuning

Misconceptions to Fix

Wrong: Momentum is not conserved in collisions with friction.

Right: Momentum is always conserved in isolated systems; friction is an external force, so the system must include the surface.

📚 Core Content

Key Terms
WorkThe product of force and displacement in the direction of the force; W = Fd.
EnergyThe capacity to do work, measured in joules (J).
Kinetic EnergyThe energy of motion; KE = ½mv².
Potential EnergyStored energy due to position or configuration.
PowerThe rate at which work is done or energy is transferred; P = W/t.
Conservation of EnergyThe principle that energy cannot be created or destroyed, only transformed.
01Sound Intensity and Distance

Sound Intensity and Distance

As sound spreads out from a source, the same acoustic energy must cover an ever-larger surface area, so the energy arriving at each unit of area falls with distance.

For a point source in free space, the wavefronts form concentric spheres. The surface area of a sphere is $4\pi r^2$, so the intensity $I$ — power per unit area — obeys $I = P/(4\pi r^2)$. This is the physical origin of the inverse square law. If you double your distance from the source, the sphere’s area quadruples and intensity becomes one quarter. If you triple the distance, the area grows nine-fold and intensity drops to one ninth.

This rapid drop explains why a whisper across a large classroom is inaudible, why stage speakers are angled toward the audience, and why sound barriers are judged by how much they increase the effective distance between a noise source and a listener.

Distance changeIntensity changeMeaning
Double distance1/4 intensityMuch quieter than many people expect
Triple distance1/9 intensityLarge drop in received intensity
Half distance4× intensityMuch more intense near the source
Real-World Anchor Road workers in Sydney measure traffic noise at set distances from motorways to ensure compliance with environmental standards. A sound barrier that doubles the effective distance from the road can reduce the received intensity to one quarter, making a measurable difference to nearby residents.
Wave Protocol — inverse-square intensity problems
Step 1 — Confirm the source behaves as a point source (radiates evenly in all directions)
Step 2 — Write the proportionality $I \propto 1/r^2$ or the ratio $\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}$
Step 3 — Solve for the unknown intensity or distance and check the answer makes physical sense
Step 4 — State the physical meaning in a full sentence (e.g. “the intensity at 2 m is nine times greater than at 6 m”)
02The Decibel Scale

The Decibel Scale

Decibels are logarithmic, so equal steps on the dB scale do not represent equal linear changes in intensity. Instead, each 10 dB interval marks a tenfold multiplication of intensity.

The decibel scale is base-10 logarithmic. A 10 dB increase means the sound intensity is exactly 10 times greater. A 20 dB increase means 100 times the intensity, and a 30 dB increase means 1000 times the intensity. This compresses an enormous range of physical intensities into manageable numbers. The threshold of hearing is defined as 0 dB, which is not the absence of sound but the faintest pressure variation a typical human ear can detect — about $10^{-12}\ \text{W/m}^2$.

Because the human ear itself responds roughly logarithmically to intensity, the decibel scale also matches our subjective sensation of loudness better than a linear scale would. That is why a modest-looking decibel jump can correspond to a dramatic rise in the actual energy reaching the ear.

Common Misconceptions

A 10 dB increase means the sound is twice as intense.
A 10 dB increase corresponds to 10 times the intensity, not double. The phrase “twice as loud” is a perceptual description, but physically the energy flux increases by a factor of 10.
0 dB means no sound at all.
0 dB is the threshold of hearing — the faintest sound a typical human ear can detect. There are still pressure oscillations; they are just below the average detection limit.
Doubling the distance from a source halves the decibel level.
Doubling the distance quarters the intensity, which corresponds to a drop of about 6 dB, not a halving of decibels. Decibels follow a logarithmic rule, not a simple proportion.
Health Anchor This is why hearing-safety rules matter in noisy workplaces and concerts. A modest-looking decibel jump can correspond to a large rise in intensity reaching the ear.
Real-World Anchor At major Sydney venues, sound levels at the front of stage can exceed 110 dB. Earplugs rated for 20 dB reduction drop the intensity by a factor of 100 — the difference between safe exposure for hours and potential damage in minutes.
03Beats

Beats

Beats are periodic changes in loudness caused by the superposition of two sound waves with slightly different frequencies.

When two waves travel through the same medium at the same time, they interfere according to the principle of superposition. At moments when the crests align, the amplitudes add constructively and the sound grows louder. A short time later, the crest of one wave meets the trough of the other, producing partial cancellation and a quieter sound. This loud-soft-loud pattern repeats at the beat frequency, which is the absolute difference between the two source frequencies.

Mathematically, if two waves are $y_1 = A\sin(2\pi f_1 t)$ and $y_2 = A\sin(2\pi f_2 t)$, their sum can be rewritten as an amplitude-modulated wave. The envelope of that wave oscillates at $\frac{1}{2}|f_1 - f_2|$, so the loudness — which depends on amplitude squared — waxes and wanes at $|f_1 - f_2|$. If the frequencies differ by more than about 10–15 Hz, the ear begins to perceive them as two separate tones rather than a single wavering note.

Constructive Part

  • Waves line up more closely
  • Amplitude increases
  • Sound seems louder

Destructive Part

  • Waves misalign more
  • Amplitude decreases
  • Sound seems quieter
Real-World Anchor Orchestral musicians tune to an A at 440 Hz. If a violin string is at 442 Hz, the player hears 2 beats per second. Slowing the beats to zero confirms the string is perfectly in tune with the reference pitch.
Wave Protocol — beat-frequency problems
Step 1 — Confirm the two frequencies are close enough to produce audible beats (typically within ~15 Hz)
Step 2 — Write $f_{\text{beat}} = |f_1 - f_2|$ and substitute the values
Step 3 — Describe what you would hear in words (e.g. “the loudness waxes and wanes 4 times each second”)
Step 4 — Connect the result to a tuning or musical context
04Why Musicians Listen for Beats

Why Musicians Listen for Beats

If two notes are close but not identical, beats are heard. As the frequencies get closer together, the beat frequency decreases and the pulsation slows down.

When tuning an instrument, the musician’s goal is to make the beats disappear or become so slow that they are imperceptible. That tells the player that the two frequencies are effectively identical. Piano tuners have used this principle for centuries: they strike a reference tuning fork and the piano string simultaneously, then adjust the string’s tension until the wavering sound vanishes.

In an ensemble, players constantly listen for beats between their own instrument and others. By making tiny pitch adjustments — often less than a hertz — they eliminate beats and produce a blended, unified tone. This is especially critical in choirs and string quartets where just a few cents of detuning can create an unpleasant roughness.

Real-World Anchor Didgeridoo players sometimes produce harmonic overbeats by simultaneously vocalising and playing, using the beat effect to create rhythmic pulsations inside the sustained drone.
05Decibels, Intensity and Human Perception

Decibels, Intensity and Human Perception

Intensity and loudness are not the same thing. Intensity is a physical measure of power per unit area, while loudness is the subjective sensation interpreted by the brain.

Because the ear responds roughly logarithmically, a tenfold increase in intensity is perceived as only about a doubling of loudness. This is why the decibel scale is so useful: it translates physical measurements into numbers that match what we actually experience. A rock concert at 110 dB is not just “a bit louder” than normal conversation at 60 dB; it is $10^5$ times more intense, yet it feels perhaps 16–32 times as loud.

Intensity ratioDecibel changePerceived change
0 dBReference level
10×+10 dBAbout 2× as loud
100×+20 dBAbout 4× as loud
1000×+30 dBAbout 8× as loud
Key exam move When comparing decibel levels, always convert to intensity ratios using powers of 10. A 30 dB difference means an intensity ratio of $10^3 = 1000$, not a ratio of 30.

Visual Break — Decision Flowchart

Sound problem What is changing? Distance Two frequencies Inverse square law I ∝ 1/r² Beat frequency f_beat = |f₁ − f₂| Decibels change? +10 dB → 10× intensity Tuning context? Slower beats → closer match Always state the physical meaning, not just the number

✏️ Worked Examples

Worked Example 1 Type 10 — Intensity

Problem Setup

Scenario: A listener at an outdoor concert in Sydney moves from 2 m to 6 m from a loudspeaker. Compare the sound intensity at the two positions and explain what this means for hearing exposure.

Solution

1
Use $\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}$
Intensity from a point source is inversely proportional to the square of distance.
2
$\dfrac{I_1}{I_2} = \dfrac{6^2}{2^2} = \dfrac{36}{4} = 9$
The closer position receives much greater intensity because the same power is spread over a smaller area.
3
Interpretation
The intensity at 2 m is 9 times the intensity at 6 m. Moving back reduces the acoustic power reaching the ear dramatically.

What would change if...

If the distance only doubled (from 2 m to 4 m), the intensity would become one quarter, not one half. Explain why the inverse-square law means that small distance changes near the source produce large intensity differences.

Worked Example 2 Type 10 — Beats

Problem Setup

Scenario: A piano tuner strikes a tuning fork of frequency 256 Hz and a slightly out-of-tune piano string. The tuner hears a beat frequency of 4 Hz. Determine the possible frequencies of the string and describe what the tuner should do next.

Solution

1
$f_{\text{beat}} = |f_1 - f_2|$
Use the absolute difference between the two nearby frequencies.
2
$4 = |256 - f_{\text{string}}|$
Rearrange to find the two possible string frequencies.
3
$f_{\text{string}} = 256 \pm 4$ → $252\ \text{Hz}$ or $260\ \text{Hz}$
The string could be either slightly flat or slightly sharp relative to the tuning fork.
4
Next step: adjust string tension and listen for slower beats
As the string approaches 256 Hz, the beat frequency will decrease. When beats disappear, the string is in tune.

What would change if...

If the two frequencies moved closer together, the beats would become slower. If the frequencies matched exactly, the beats would disappear and the sound would become a steady, pure tone.

Worked Example 3 Type 10 — Decibel Change

Problem Setup

Scenario: A factory floor measures 85 dB. After installing new machinery, the level rises to 95 dB. Calculate the factor by which the sound intensity has increased.

Solution

1
$\Delta dB = 95 - 85 = 10\ \text{dB}$
Find the decibel difference between the two levels.
2
Intensity ratio $= 10^{\Delta dB/10} = 10^{10/10} = 10^1 = 10$
Each 10 dB step corresponds to a tenfold increase in intensity.
3
The intensity is 10 times greater.
A 10 dB rise means 10× the energy flux, which significantly changes exposure risk and hearing-protection requirements.

What would change if...

The level instead rose from 85 dB to 105 dB. What would the intensity ratio be, and why does a 20 dB increase correspond to 100× intensity?

Copy into your books

Inverse Square Law

  • Intensity from a point source spreads over a sphere
  • $I \propto 1/r^2$
  • Doubling distance → intensity becomes $1/4$
  • Use ratio $\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}$

The Decibel Scale

  • Logarithmic scale based on powers of 10
  • +10 dB means 10× the intensity
  • +20 dB means 100× the intensity
  • 0 dB = threshold of hearing, not silence

Beats and Tuning

  • Beats arise from superposition of close frequencies
  • $f_{\text{beat}} = |f_1 - f_2|$
  • Slower beats → frequencies are closer together
  • Zero beats → frequencies are matched

Key Exam Moves

  • Always convert decibel differences to intensity ratios using $10^{\Delta dB/10}$
  • Check that your answer makes physical sense
  • State the physical meaning, not just the number
  • Connect beat frequency to what you would hear

🏃 Activities

Activity 1 — Pattern A

Distance and Intensity Check

Apply the inverse square law to a real concert setup.

A listener stands 4 m from a stage speaker. They then move to 8 m away.

  1. Write the inverse-square ratio that relates the two distances.
  2. Calculate the factor by which the intensity changes.
  3. Explain why the intensity does not simply halve when the distance doubles.
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Activity 2 — Pattern B

Decibel Meaning

Explain the logarithmic nature of decibels in your own words.

Write one paragraph explaining why a 10 dB increase should never be described as “just 10% more intense.” Use the words logarithmic, intensity ratio, and factor of 10.

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Activity 3 — Pattern C

Tuning by Beats

Connect beat frequency to instrument tuning.

A violinist plays a string alongside a 440 Hz tuning fork and hears 3 beats per second.

  1. What are the two possible frequencies of the violin string?
  2. Describe what the violinist should do to bring the string into tune.
  3. Explain why zero beats mean the frequencies are matched.
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Activity 4 — Pattern D

Concert Sound Limit

Combine decibels and distance in a safety context.

At a Sydney concert, the sound level is measured as 100 dB at 10 m from the stage speakers.

  1. Calculate the approximate sound level at 20 m from the speakers, assuming spherical spreading. (Hint: intensity drops by a factor related to distance.)
  2. By what factor does the intensity drop when moving from 10 m to 20 m?
  3. Explain why earplugs that reduce the level by 20 dB are recommended for front-row positions.
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Interactive: Beat Frequency Generator
Interactive: Decibel Calculator
Revisit Your Thinking

Earlier you were asked whether 100 dB is only a little more intense than 90 dB.

The full answer: the decibel scale is logarithmic, so a 10 dB increase means 10 times greater intensity, not a 10% increase. This is why decibel changes can carry major real-world consequences for hearing safety.

Now revisit your prediction. What was misleading about treating decibels like a simple linear scale?

Annotate your prediction in your book with what you now understand differently.

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Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

✅ Check Your Understanding

Multiple Choice

6 MARKS

1. If distance from a point sound source doubles, intensity becomes:

A
Half as large
B
Four times as large
C
One quarter as large
D
Twice as large

2. A 10 dB increase corresponds to a sound that is:

A
2 times as intense
B
10 times as intense
C
10% more intense
D
Always perceived as exactly 10 times louder

3. Beats are caused by:

A
Superposition of two sound waves with slightly different frequencies
B
Reflection from a wall only
C
A single wave travelling through a vacuum
D
Only standing waves in pipes

4. Two sounds have frequencies 300 Hz and 306 Hz. The beat frequency is:

A
606 Hz
B
153 Hz
C
300 Hz
D
6 Hz

5. Beats are heard as a periodic change in:

A
Wavelength
B
Sound speed
C
Amplitude or loudness
D
Medium density

6. If a musician hears slower beats while tuning, it means the two frequencies are:

A
Moving further apart
B
Getting closer together
C
Both becoming zero
D
Becoming louder

Short Answer

10 MARKS

7. Explain why sound intensity decreases with distance from a point source. 3 MARKS

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8. A listener moves from 3 m to 9 m from a speaker. Compare the intensities at the two positions. 3 MARKS

Answer in your book
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9. Two notes of 440 Hz and 444 Hz are played together. Calculate the beat frequency and explain how this helps a musician tune an instrument. 4 MARKS

Answer in your book
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Comprehensive Answers

Multiple Choice

1. C — doubling distance reduces intensity to one quarter.

2. B — +10 dB means 10 times the intensity.

3. A — beats come from superposition of nearby frequencies.

4. D — $|300 - 306| = 6\ \text{Hz}$.

5. C — the loudness rises and falls periodically.

6. B — slower beats mean the frequencies are getting closer.

Short Answer — Model Answers

Q7 (3 marks): As sound spreads away from a point source, the same energy is distributed across a larger and larger area. This means less intensity reaches each unit area as distance increases. That is why sound intensity follows the inverse square law.

Q8 (3 marks): Use $\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}$. So $\dfrac{I_1}{I_2} = \dfrac{9^2}{3^2} = \dfrac{81}{9} = 9$. The intensity at 3 m is 9 times the intensity at 9 m.

Q9 (4 marks): $f_{\text{beat}} = |440 - 444| = 4\ \text{Hz}$. So the loudness changes 4 times each second. A musician uses beats when tuning because slower beats mean the played note is getting closer to the reference frequency. When the beats disappear, the notes are effectively matched.

⚔️
Boss Battle

Boss Battle — Sound Intensity!

Challenge the boss using your knowledge of sound intensity, the decibel scale and beats. Pool: lessons 1–10.

Mark lesson as complete

Tick when you have finished the activities and checked the answers.