Year 11 Physics Module 3: Waves 40 min Lesson 12 of 18

The Doppler Effect

When a siren rushes past, the pitch seems higher on approach and lower as it moves away. That apparent frequency shift is the Doppler effect, and it underpins police radar, weather Doppler systems, astronomy, and medical ultrasound.

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Think First

Why does a passing ambulance seem to drop in pitch the moment it goes by, even though the siren itself has not changed frequency at the source?

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Key Relationships — This Lesson

$f' = f \times \dfrac{v}{v \pm v_s}$  |  $f' = f \times \dfrac{v \pm v_o}{v}$
f' = observed frequency f = source frequency v = wave speed vs = source speed vo = observer speed
Approaching source: use minus in denominator   |   Receding source: use plus in denominator   |   Observer towards source: use plus in numerator

f'
Formula Reference — Doppler Effect

$f' = f \times \dfrac{v}{v \pm v_s}$
Moving Source
Use minus when the source moves towards the observer, plus when it moves away.
Use when: the source is moving and the observer is stationary.
Common trap: approaching source means higher observed frequency, so the denominator must get smaller.
$f' = f \times \dfrac{v \pm v_o}{v}$
Moving Observer
Use plus when the observer moves towards the source, minus when moving away.
Use when: the observer is moving and the source is stationary.
Common trap: do not swap the source-speed and observer-speed versions. The sign logic lives in different places.

Know

  • What the Doppler effect is
  • That approaching motion raises observed frequency
  • That receding motion lowers observed frequency
  • The equations for moving source and moving observer cases

Understand

  • Why wavefronts bunch up in front of a moving source
  • Why stretched wavefronts behind the source reduce observed frequency
  • Why the sign conventions matter
  • How Doppler-based technologies use frequency shifts

Can Do

  • Predict whether observed pitch increases or decreases
  • Choose the correct Doppler equation
  • Apply the correct sign convention
  • Connect the effect to real-world examples

Misconceptions to Fix

Wrong: Zero acceleration means an object is stationary.

Right: Zero acceleration means constant velocity — the object could be moving at constant speed in a straight line.

📚 Core Content

Key Terms
That apparent frequency shiftthe Doppler effect, and it underpins police radar, weather Doppler systems, astronomy, and medical ultrasound
the sourcemoving and the observer is stationary
approaching sourcehigher observed frequency, so the denominator must get smaller
the observermoving and the source is stationary
Zero accelerationan object is stationary
rate at which workdone or energy is transferred; P = W/t
01What Changes in the Doppler Effect?

What Changes in the Doppler Effect?

The source frequency stays the same, but the observed frequency changes because relative motion alters how the wavefronts arrive at the observer.

If the source moves towards the observer, each successive wavefront is emitted from a position slightly closer to the observer than the one before. This compresses the wavefronts in front of the source, shortening the effective wavelength. Because the wave speed in the medium is unchanged, a shorter wavelength means a higher observed frequency. If the source moves away, the wavefronts are more spread out, the effective wavelength increases, and the observed frequency drops.

A moving observer experiences a similar shift for a different reason: the observer changes the rate at which they encounter wavefronts. Moving towards the source means passing through wavefronts faster, raising the observed frequency. Moving away means encountering them more slowly, lowering the frequency. In both cases, the wave speed in the medium depends only on the properties of the medium — it does not change because of the motion.

Real-World Anchor Emergency services in Sydney use Doppler radar to track storm cells moving across the harbour. The frequency shift of reflected microwaves reveals both the speed and direction of rain-bearing winds, helping meteorologists issue timely warnings.
02Approaching vs Receding

Approaching vs Receding

The direction of relative motion decides whether the observed frequency rises or falls.

Imagine a source moving through still air. In front of it, the wave crests are squeezed together like the coils of a compressed spring. The observer in front receives more crests per second, so $f' > f$. Behind the source, the wave crests are stretched out like a relaxed spring. The observer behind receives fewer crests per second, so $f' < f$. The faster the source moves, the more dramatic the compression and stretching, and the larger the frequency shift.

The exact moment the source passes the observer is the transition point: the observed frequency drops sharply from above $f$ to below $f$. This is the classic drop in pitch you hear when an ambulance passes by on the street.

Approaching

  • Wavefronts bunch together
  • Observed wavelength is shorter
  • Observed frequency is higher
  • Pitch seems higher

Receding

  • Wavefronts spread out
  • Observed wavelength is longer
  • Observed frequency is lower
  • Pitch seems lower
Real-World Anchor Astronomers observe red-shift in light from distant galaxies — the wavelengths are stretched because the sources are moving away from us. This was key evidence for the expansion of the universe.
03Two Common Doppler Cases

Two Common Doppler Cases

The moving-source and moving-observer situations use related but different equations because the physics of the shift is different in each case.

For a moving source, the source motion changes the physical spacing of the wavefronts in the medium. The new wavelength is $\lambda' = (v \pm v_s)/f$, so the observed frequency becomes $f' = f \times v/(v \pm v_s)$. For a moving observer, the wavelength in the medium is unchanged, but the observer’s motion changes the relative speed of the wavefronts. The observer meets wavefronts at speed $v \pm v_o$, giving $f' = f \times (v \pm v_o)/v$.

The sign conventions are designed so that approaching motion always produces a higher observed frequency. For the moving-source equation, approaching means using the minus sign in the denominator (making it smaller, so $f'$ increases). For the moving-observer equation, approaching means using the plus sign in the numerator (making it larger, so $f'$ increases). If your chosen sign makes $f'$ decrease for approaching motion, you have picked the wrong sign.

Common Misconceptions

The Doppler effect changes the speed of the wave in the medium.
The wave speed $v$ in the medium depends only on the properties of the medium (e.g. air temperature), not on the motion of the source or observer. Only wavelength and observed frequency change.
If the source moves away, the observed frequency is lower because the wave speed decreased.
The wave speed stays constant. The observed frequency drops because the wavefronts are stretched farther apart behind the source, increasing the effective wavelength while wave speed remains unchanged.
You can use the same sign in both the numerator and denominator when both move.
The sign conventions are independent. In the numerator, + means observer moves towards source. In the denominator, means source moves towards observer. They do not have to match.
Self-check if the source approaches, the observed frequency should increase. If your sign choice makes it decrease, you have chosen the wrong sign.
Wave Protocol — Doppler sign check
Step 1 — Identify who is moving (source, observer, or both)
Step 2 — Write the correct base equation before substituting numbers
Step 3 — Choose the sign that makes f' higher for approaching motion
Step 4 — Substitute values and confirm the result is physically sensible
04Technology and Science Applications

Technology and Science Applications

Doppler shifts are useful because motion becomes measurable through frequency change, enabling technologies that range from everyday road safety to cutting-edge astronomy.

In medical ultrasound, high-frequency sound waves are reflected off moving blood cells. The frequency shift of the reflected waves reveals blood velocity, which cardiologists use to diagnose heart-valve problems or arterial blockages. In police speed detection, a radar gun emits microwaves and measures the shift of the wave reflected from a moving vehicle. Because the wave reflects off the moving car, the total shift is roughly double the single-shift value for the same speed. In weather radar, meteorologists measure the Doppler shift of raindrops to determine wind speed and direction inside storms.

In astronomy, the light from distant galaxies is red-shifted — its wavelength is stretched toward the red end of the spectrum because the galaxies are receding from us. The greater the red-shift, the faster the recession. This relationship, known as Hubble’s law, provided the first strong evidence that the universe is expanding.

Real-World Anchor Police speed guns in NSW emit microwave radiation and measure the frequency shift of the reflected wave from a moving vehicle. Because the wave reflects off the moving car, the total shift is roughly double the single-shift value for the same speed, allowing very accurate speed measurements.
05Combined Motion and the General Equation

Combined Motion and the General Equation

When both the source and the observer move, the two effects combine into a single equation that captures both shifts at once.

The general Doppler equation for sound in a medium is:

$f' = f \times \dfrac{v \pm v_o}{v \mp v_s}$

In the numerator, use plus when the observer moves towards the source and minus when moving away. In the denominator, use minus when the source moves towards the observer and plus when moving away. Notice that the signs in the numerator and denominator are independent — they do not have to be the same. The NSW HSC typically tests only one moving object at a time, but understanding the combined case deepens your intuition for the sign conventions.

MotionNumerator signDenominator sign
Observer towards source+
Observer away from source
Source towards observer
Source away from observer+
Key exam move Before substituting numbers, write the equation with the signs filled in, then do a quick sanity check — approaching motion should always give a higher $f'$.
Wave Protocol — Doppler calculation
Step 1 — List all given values: f, v, v_s, v_o
Step 2 — Select the correct equation and write it with the appropriate signs
Step 3 — Substitute carefully and calculate f'
Step 4 — Compare f' to f and explain the result in words
06When the Doppler Equation Breaks Down

When the Doppler Equation Breaks Down

The standard Doppler equations assume the source speed is less than the wave speed in the medium.

If a source moves faster than the wave speed — for example, a supersonic aircraft moving faster than the speed of sound — the wavefronts pile up on top of each other and form a shock wave, known as a sonic boom. In this regime, the simple Doppler formula no longer applies because the wavefronts cannot outrun the source. Similarly, if the observer moves faster than the wave speed, the observer outruns the wavefronts and the observed frequency becomes undefined in the simple model.

For all HSC problems, you can safely assume that both source and observer speeds are much smaller than the wave speed, so the standard equations are valid. This assumption is built into the derivation of the equations and is worth stating when explaining your reasoning.

Key exam move In Doppler problems, always begin by stating that $v_s < v$ and $v_o < v$, which justifies the use of the standard Doppler equation.

Visual Break — Decision Flowchart

Relative motion problem Who is moving? Source Observer Moving source f' = f × v/(v ± v_s) Moving observer f' = f × (v ± v_o)/v Approaching? Minus in denominator → higher f' Approaching? Plus in numerator → higher f' Always check the sign against the physical meaning

✏️ Worked Examples

Worked Example 1 Type 12 — Moving Source

Problem Setup

Scenario: A siren of frequency 500 Hz moves towards a stationary observer at 20 m/s. The speed of sound is 340 m/s. Find the observed frequency and explain why the pitch sounds higher.

Solution

1
$f' = f \times \dfrac{v}{v - v_s}$
Use the moving-source equation with a minus sign because the source approaches.
2
$f' = 500 \times \dfrac{340}{340 - 20}$
Substitute the values.
3
$f' = 500 \times \dfrac{340}{320} \approx 531\ \text{Hz}$
The observed frequency is higher than the source frequency, which matches the physical expectation.

What would change if...

If the source were moving away, the denominator would use a plus sign and the observed frequency would be lower than 500 Hz. Calculate the exact value and explain the physical meaning.

Worked Example 2 Type 12 — Moving Observer

Problem Setup

Scenario: A stationary horn produces 400 Hz. An observer moves towards it at 10 m/s. The speed of sound is 340 m/s. Find the observed frequency and compare the size of this shift to the shift produced by moving the source at the same speed.

Solution

1
$f' = f \times \dfrac{v + v_o}{v}$
Use the moving-observer equation with a plus sign because the observer moves towards the source.
2
$f' = 400 \times \dfrac{340 + 10}{340}$
Substitute the values.
3
$f' = 400 \times \dfrac{350}{340} \approx 412\ \text{Hz}$
Again the observed frequency is higher, as expected for approaching motion. The shift (12 Hz) is smaller than the shift for a moving source at the same speed because the denominator effect is stronger than the numerator effect.

What would change if...

If the observer moved away from the source, the numerator would use a minus sign and the observed frequency would decrease. Calculate the new frequency and explain why the shift is smaller than the source-moving case.

Worked Example 3 Type 12 — Moving Source Away

Problem Setup

Scenario: An ambulance siren of frequency 600 Hz drives away from a stationary pedestrian at 15 m/s. The speed of sound in air is 340 m/s. Find the observed frequency.

Solution

1
$f' = f \times \dfrac{v}{v + v_s}$
Use the moving-source equation with a plus sign because the source is receding.
2
$f' = 600 \times \dfrac{340}{340 + 15}$
Substitute the given values.
3
$f' = 600 \times \dfrac{340}{355} \approx 575\ \text{Hz}$
The observed frequency is lower than the source frequency, matching the physical expectation for a receding source.

What would change if...

The ambulance stopped and the pedestrian now walked away from it at 15 m/s. Which equation would you use, and would the observed frequency be the same as 575 Hz? Calculate to check.

Copy into your books

Approaching vs Receding

  • Approaching → higher observed frequency
  • Receding → lower observed frequency
  • Wave speed in medium stays constant
  • Only wavelength and observed frequency change

Moving Source

  • $f' = f \times \dfrac{v}{v \pm v_s}$
  • Towards observer: minus in denominator
  • Away from observer: plus in denominator
  • Source motion changes wavefront spacing

Moving Observer

  • $f' = f \times \dfrac{v \pm v_o}{v}$
  • Towards source: plus in numerator
  • Away from source: minus in numerator
  • Observer motion changes encounter rate

Key Exam Moves

  • Pick the correct equation first
  • Check the sign by asking: does approaching give higher f'?
  • Always state the physical meaning in words
  • Connect the result to a real-world technology

🏃 Activities

Activity 1 — Pattern A

Sign Convention Sort

Predict whether the observed frequency increases or decreases.

For each case below, decide whether the observed frequency should increase or decrease.

  1. Moving source towards observer.
  2. Moving source away.
  3. Observer moving towards source.
  4. Observer moving away.
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Activity 2 — Pattern B

Equation Match

Write the correct Doppler equation and explain the physics.

Write the correct Doppler equation for a moving source and for a moving observer, then explain what changes physically in each case.

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Activity 3 — Pattern C

Technology Link

Connect the Doppler effect to a real-world technology.

Explain in one or two sentences how a speed camera or Doppler radar system can use frequency shift to detect motion.

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Activity 4 — Pattern D

Traffic Speed Scenario

Apply the Doppler effect to a road-safety context.

A car horn produces a steady 500 Hz. A cyclist rides towards the stationary car at 8 m/s. The speed of sound is 340 m/s.

  1. Write the correct Doppler equation for this situation.
  2. Calculate the observed frequency heard by the cyclist.
  3. Explain what would happen to the observed frequency if the cyclist passed the car and rode away at the same speed.
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Interactive: Doppler Effect Simulator
Interactive: Doppler Effect Classifier
Revisit Your Thinking

Earlier you were asked why a passing siren seems to drop in pitch even though the source does not change its own frequency.

The full answer: the source frequency stays the same, but relative motion changes the spacing of the wavefronts reaching the observer. Approaching motion compresses them and raises the observed frequency; receding motion stretches them and lowers it.

Now revisit your prediction. What is the key distinction between source frequency and observed frequency?

Annotate your prediction in your book with what you now understand differently.

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Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

✅ Check Your Understanding

Multiple Choice

6 MARKS

1. The Doppler effect refers to an apparent change in:

A
Wave speed due only to reflection
B
Observed frequency due to relative motion
C
Amplitude due to diffraction
D
Medium density due to resonance

2. If a source moves towards an observer, the observed frequency is:

A
Higher than the source frequency
B
Lower than the source frequency
C
Always zero
D
Unchanged in all cases

3. In the moving-source Doppler equation, an approaching source uses:

A
A plus sign in the denominator
B
A minus sign in the numerator
C
A plus sign in the numerator
D
A minus sign in the denominator

4. For a moving observer heading towards a stationary source, the observer speed is used:

A
With a minus sign in the denominator
B
With a plus sign in the denominator
C
With a plus sign in the numerator
D
Not used at all

5. Which is a real-world application of the Doppler effect?

A
Only resonance tubes
B
Weather Doppler radar
C
Only total internal reflection
D
Only static mirrors

6. A passing siren seems lower in pitch after it goes by because the source is now:

A
Moving away, so the observed frequency decreases
B
Moving away, so the wave speed becomes zero
C
Stationary, so the source frequency disappears
D
Approaching, so the observed frequency increases

Short Answer

10 MARKS

7. Explain why an approaching source produces a higher observed frequency. 3 MARKS

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8. A 600 Hz siren moves towards a stationary observer at 30 m/s. Take the speed of sound as 340 m/s. Find the observed frequency. 3 MARKS

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9. Distinguish the moving-source and moving-observer Doppler equations, and explain one technological use of the effect. 4 MARKS

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Comprehensive Answers

Multiple Choice

1. B — the observed frequency changes because of relative motion.

2. A — approaching motion raises the observed frequency.

3. D — use a minus sign in the denominator for an approaching source.

4. C — the observer speed appears in the numerator with a plus sign when moving towards the source.

5. B — weather Doppler radar measures motion from frequency shift.

6. A — receding motion lowers the observed frequency and pitch.

Short Answer — Model Answers

Q7 (3 marks): An approaching source produces a higher observed frequency because the emitted wavefronts are compressed in front of the source. This makes the observed wavelength shorter. Since the wave speed in the medium stays the same, a shorter wavelength means a higher observed frequency.

Q8 (3 marks): Use $f' = f \times \dfrac{v}{v - v_s}$. So $f' = 600 \times \dfrac{340}{340 - 30} = 600 \times \dfrac{340}{310} \approx 658\ \text{Hz}$.

Q9 (4 marks): For a moving source, use $f' = f \times \dfrac{v}{v \pm v_s}$ because the source changes the spacing of the wavefronts. For a moving observer, use $f' = f \times \dfrac{v \pm v_o}{v}$ because the observer changes how quickly the wavefronts are encountered. One application is Doppler radar, which measures vehicle or weather-system motion from the frequency shift of reflected waves.

🏎️
Speed Race

Race Through the Doppler Effect!

Sprint through questions on the Doppler effect and frequency shifts. Pool: lessons 1–12.

Mark lesson as complete

Tick when you have finished the activities and checked the answers.