When a siren rushes past, the pitch seems higher on approach and lower as it moves away. That apparent frequency shift is the Doppler effect, and it underpins police radar, weather Doppler systems, astronomy, and medical ultrasound.
Use the PDF for classwork, homework or revision. It includes key ideas, activities, questions, an extend task and success-criteria proof.
Why does a passing ambulance seem to drop in pitch the moment it goes by, even though the siren itself has not changed frequency at the source?
Type your prediction below. You will revisit it at the end.
Write your prediction in your book. You will revisit it at the end.
Wrong: Zero acceleration means an object is stationary.
Right: Zero acceleration means constant velocity — the object could be moving at constant speed in a straight line.
📚 Core Content
The source frequency stays the same, but the observed frequency changes because relative motion alters how the wavefronts arrive at the observer.
If the source moves towards the observer, each successive wavefront is emitted from a position slightly closer to the observer than the one before. This compresses the wavefronts in front of the source, shortening the effective wavelength. Because the wave speed in the medium is unchanged, a shorter wavelength means a higher observed frequency. If the source moves away, the wavefronts are more spread out, the effective wavelength increases, and the observed frequency drops.
A moving observer experiences a similar shift for a different reason: the observer changes the rate at which they encounter wavefronts. Moving towards the source means passing through wavefronts faster, raising the observed frequency. Moving away means encountering them more slowly, lowering the frequency. In both cases, the wave speed in the medium depends only on the properties of the medium — it does not change because of the motion.
The direction of relative motion decides whether the observed frequency rises or falls.
Imagine a source moving through still air. In front of it, the wave crests are squeezed together like the coils of a compressed spring. The observer in front receives more crests per second, so $f' > f$. Behind the source, the wave crests are stretched out like a relaxed spring. The observer behind receives fewer crests per second, so $f' < f$. The faster the source moves, the more dramatic the compression and stretching, and the larger the frequency shift.
The exact moment the source passes the observer is the transition point: the observed frequency drops sharply from above $f$ to below $f$. This is the classic drop in pitch you hear when an ambulance passes by on the street.
The moving-source and moving-observer situations use related but different equations because the physics of the shift is different in each case.
For a moving source, the source motion changes the physical spacing of the wavefronts in the medium. The new wavelength is $\lambda' = (v \pm v_s)/f$, so the observed frequency becomes $f' = f \times v/(v \pm v_s)$. For a moving observer, the wavelength in the medium is unchanged, but the observer’s motion changes the relative speed of the wavefronts. The observer meets wavefronts at speed $v \pm v_o$, giving $f' = f \times (v \pm v_o)/v$.
The sign conventions are designed so that approaching motion always produces a higher observed frequency. For the moving-source equation, approaching means using the minus sign in the denominator (making it smaller, so $f'$ increases). For the moving-observer equation, approaching means using the plus sign in the numerator (making it larger, so $f'$ increases). If your chosen sign makes $f'$ decrease for approaching motion, you have picked the wrong sign.
Doppler shifts are useful because motion becomes measurable through frequency change, enabling technologies that range from everyday road safety to cutting-edge astronomy.
In medical ultrasound, high-frequency sound waves are reflected off moving blood cells. The frequency shift of the reflected waves reveals blood velocity, which cardiologists use to diagnose heart-valve problems or arterial blockages. In police speed detection, a radar gun emits microwaves and measures the shift of the wave reflected from a moving vehicle. Because the wave reflects off the moving car, the total shift is roughly double the single-shift value for the same speed. In weather radar, meteorologists measure the Doppler shift of raindrops to determine wind speed and direction inside storms.
In astronomy, the light from distant galaxies is red-shifted — its wavelength is stretched toward the red end of the spectrum because the galaxies are receding from us. The greater the red-shift, the faster the recession. This relationship, known as Hubble’s law, provided the first strong evidence that the universe is expanding.
When both the source and the observer move, the two effects combine into a single equation that captures both shifts at once.
The general Doppler equation for sound in a medium is:
$f' = f \times \dfrac{v \pm v_o}{v \mp v_s}$
In the numerator, use plus when the observer moves towards the source and minus when moving away. In the denominator, use minus when the source moves towards the observer and plus when moving away. Notice that the signs in the numerator and denominator are independent — they do not have to be the same. The NSW HSC typically tests only one moving object at a time, but understanding the combined case deepens your intuition for the sign conventions.
| Motion | Numerator sign | Denominator sign |
|---|---|---|
| Observer towards source | + | — |
| Observer away from source | − | — |
| Source towards observer | — | − |
| Source away from observer | — | + |
The standard Doppler equations assume the source speed is less than the wave speed in the medium.
If a source moves faster than the wave speed — for example, a supersonic aircraft moving faster than the speed of sound — the wavefronts pile up on top of each other and form a shock wave, known as a sonic boom. In this regime, the simple Doppler formula no longer applies because the wavefronts cannot outrun the source. Similarly, if the observer moves faster than the wave speed, the observer outruns the wavefronts and the observed frequency becomes undefined in the simple model.
For all HSC problems, you can safely assume that both source and observer speeds are much smaller than the wave speed, so the standard equations are valid. This assumption is built into the derivation of the equations and is worth stating when explaining your reasoning.
Visual Break — Decision Flowchart
✏️ Worked Examples
Scenario: A siren of frequency 500 Hz moves towards a stationary observer at 20 m/s. The speed of sound is 340 m/s. Find the observed frequency and explain why the pitch sounds higher.
If the source were moving away, the denominator would use a plus sign and the observed frequency would be lower than 500 Hz. Calculate the exact value and explain the physical meaning.
Scenario: A stationary horn produces 400 Hz. An observer moves towards it at 10 m/s. The speed of sound is 340 m/s. Find the observed frequency and compare the size of this shift to the shift produced by moving the source at the same speed.
If the observer moved away from the source, the numerator would use a minus sign and the observed frequency would decrease. Calculate the new frequency and explain why the shift is smaller than the source-moving case.
Scenario: An ambulance siren of frequency 600 Hz drives away from a stationary pedestrian at 15 m/s. The speed of sound in air is 340 m/s. Find the observed frequency.
The ambulance stopped and the pedestrian now walked away from it at 15 m/s. Which equation would you use, and would the observed frequency be the same as 575 Hz? Calculate to check.
🏃 Activities
For each case below, decide whether the observed frequency should increase or decrease.
Write the correct Doppler equation for a moving source and for a moving observer, then explain what changes physically in each case.
Explain in one or two sentences how a speed camera or Doppler radar system can use frequency shift to detect motion.
A car horn produces a steady 500 Hz. A cyclist rides towards the stationary car at 8 m/s. The speed of sound is 340 m/s.
Earlier you were asked why a passing siren seems to drop in pitch even though the source does not change its own frequency.
The full answer: the source frequency stays the same, but relative motion changes the spacing of the wavefronts reaching the observer. Approaching motion compresses them and raises the observed frequency; receding motion stretches them and lowers it.
Now revisit your prediction. What is the key distinction between source frequency and observed frequency?
Annotate your prediction in your book with what you now understand differently.
Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?
✅ Check Your Understanding
1. The Doppler effect refers to an apparent change in:
2. If a source moves towards an observer, the observed frequency is:
3. In the moving-source Doppler equation, an approaching source uses:
4. For a moving observer heading towards a stationary source, the observer speed is used:
5. Which is a real-world application of the Doppler effect?
6. A passing siren seems lower in pitch after it goes by because the source is now:
7. Explain why an approaching source produces a higher observed frequency. 3 MARKS
8. A 600 Hz siren moves towards a stationary observer at 30 m/s. Take the speed of sound as 340 m/s. Find the observed frequency. 3 MARKS
9. Distinguish the moving-source and moving-observer Doppler equations, and explain one technological use of the effect. 4 MARKS
1. B — the observed frequency changes because of relative motion.
2. A — approaching motion raises the observed frequency.
3. D — use a minus sign in the denominator for an approaching source.
4. C — the observer speed appears in the numerator with a plus sign when moving towards the source.
5. B — weather Doppler radar measures motion from frequency shift.
6. A — receding motion lowers the observed frequency and pitch.
Q7 (3 marks): An approaching source produces a higher observed frequency because the emitted wavefronts are compressed in front of the source. This makes the observed wavelength shorter. Since the wave speed in the medium stays the same, a shorter wavelength means a higher observed frequency.
Q8 (3 marks): Use $f' = f \times \dfrac{v}{v - v_s}$. So $f' = 600 \times \dfrac{340}{340 - 30} = 600 \times \dfrac{340}{310} \approx 658\ \text{Hz}$.
Q9 (4 marks): For a moving source, use $f' = f \times \dfrac{v}{v \pm v_s}$ because the source changes the spacing of the wavefronts. For a moving observer, use $f' = f \times \dfrac{v \pm v_o}{v}$ because the observer changes how quickly the wavefronts are encountered. One application is Doppler radar, which measures vehicle or weather-system motion from the frequency shift of reflected waves.
Sprint through questions on the Doppler effect and frequency shifts. Pool: lessons 1–12.
Tick when you have finished the activities and checked the answers.