Year 11 Maths Advanced Module 1 ⏱ ~40 min Lesson 2 of 15

Function Notation & Evaluation

How does a taxi meter know what to charge? It follows a simple rule: a fixed cost plus a rate for every kilometre travelled. In mathematics, we write this rule using function notation — and it opens the door to everything from economics to engineering.

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Think First

A taxi charges a $3 flag fall plus $2 for every kilometre travelled. How much would a 5 km trip cost? How much would a 10 km trip cost? Can you write a general rule using $C$ for cost and $d$ for distance?

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📐

Formula Reference — This Lesson

$f(a)$
Replace every $x$ in the rule with $a$, then simplify
$\displaystyle \frac{f(a+h) - f(a)}{h}$
Difference quotient — average rate of change of $f$ from $a$ to $a+h$
Key insight: When substituting algebraic expressions, always use brackets. This prevents sign errors.
📖 Know

Key Facts

  • How to evaluate $f(a)$ for numerical and algebraic inputs
  • The meaning of the difference quotient
  • How to interpret function notation in real-world contexts
💡 Understand

Concepts

  • That $f(x)$ describes a rule, not a multiplication
  • Why brackets are essential when substituting negatives or algebraic terms
  • How functions model relationships like cost, distance, and temperature
✅ Can Do

Skills

  • Evaluate functions for numerical inputs, negative inputs, and zero
  • Evaluate functions for algebraic inputs such as $f(x+h)$ and $f(a)$
  • Set up and interpret functions in real-world contexts
  • Simplify and evaluate the difference quotient for linear and quadratic functions

Misconceptions to Fix

Wrong: The domain of a function is always all real numbers.

Right: The domain depends on the function; rational functions exclude values that make the denominator zero.

Key Terms
Why bracketsessential when substituting negatives or algebraic terms
functionalways all real numbers
The processalways the same: replace every instance of the independent variable with the given value, then simplify using the correc
The function rulethe recipe, and the input is the ingredient you're using
Negative inputsa common source of errors
bracketsyour best defence against mistakes
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Evaluating Functions

To evaluate a function means to find the output for a given input. The process is always the same: replace every instance of the independent variable with the given value, then simplify using the correct order of operations.

Think of it like following a recipe. The function rule is the recipe, and the input is the ingredient you're using. If the recipe says "double the amount and subtract 3," then with an input of 5 you get $2(5) - 3 = 7$. The recipe doesn't change — only the ingredient does.

Numerical Inputs

Suppose $f(x) = x^2 - 3x + 2$. To find $f(4)$:

  • Replace $x$ with $4$: $f(4) = (4)^2 - 3(4) + 2$
  • Simplify: $16 - 12 + 2 = 6$

Negative Inputs

Negative inputs are a common source of errors. Always use brackets:

  • $f(-2) = (-2)^2 - 3(-2) + 2$
  • Simplify: $4 + 6 + 2 = 12$

Without brackets, $(-2)^2$ can easily become $-2^2 = -4$, which is incorrect. The bracket protects the sign.

Algebraic Inputs

Functions can also be evaluated for algebraic expressions. If $f(x) = 2x + 1$, then:

  • $f(a) = 2a + 1$
  • $f(x+h) = 2(x+h) + 1 = 2x + 2h + 1$

Again, brackets are your best defence against mistakes. Every $x$ in the original rule must be replaced by the entire expression in parentheses.

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Functions in Context & The Difference Quotient

Function notation becomes powerful when we use it to model real situations. A taxi fare might be written as $C(d) = 3 + 2d$, where $C$ is the cost in dollars and $d$ is the distance in kilometres. The notation tells us instantly what the variables represent and how they are related.

Context functions often use descriptive names. $C(t)$ might mean "cost after $t$ minutes." $T(h)$ might mean "temperature after $h$ hours." The letter inside the brackets is always the input, and the letter before the brackets names the function (or the output quantity).

The Difference Quotient

The difference quotient measures the average rate of change of a function over an interval:

$$\frac{f(a+h) - f(a)}{h}$$

This expression appears throughout calculus. For now, think of it as the average slope of the function between the points $x = a$ and $x = a+h$. If the difference quotient is constant for all values of $a$ and $h$, the function is a straight line.

THE FUNCTION MACHINE x = 3 f(x) = 2x + 5 Rule machine f(3) = 11 One input → apply the rule → exactly one output

Worked Example 1 — Numerical & Algebraic Evaluation

Stepwise
If $f(x) = 2x^2 - 3x + 1$, find $f(2)$, $f(-1)$, and $f(a)$.
  1. 1
    Substitute $x = 2$
    f(2) = 2(2)^2 - 3(2) + 1
  2. 2
    Simplify
    f(2) = 8 - 6 + 1 = 3
  3. 3
    Substitute $x = -1$ using brackets
    f(-1) = 2(-1)^2 - 3(-1) + 1
  4. 4
    Simplify
    f(-1) = 2(1) + 3 + 1 = 6
  5. 5
    Substitute $x = a$
    f(a) = 2a^2 - 3a + 1
✓ Answer $f(2) = 3$, $f(-1) = 6$, $f(a) = 2a^2 - 3a + 1$

Worked Example 2 — Function in Context

Stepwise
A taxi charges a fare according to the rule $C(d) = 5 + 1.8d$, where $C$ is the cost in dollars and $d$ is the distance in kilometres. Find the cost of a 15 km trip and a 30 km trip. Interpret the meaning of $C(0)$.
  1. 1
    Identify the function and variables
    $C(d) = 5 + 1.8d$ means cost depends on distance. $5$ is the fixed flag fall and $1.8d$ is the variable charge.
  2. 2
    Evaluate $C(15)$
    C(15) = 5 + 1.8(15) = 5 + 27 = 32
  3. 3
    Evaluate $C(30)$
    C(30) = 5 + 1.8(30) = 5 + 54 = 59
  4. 4
    Evaluate $C(0)$
    C(0) = 5 + 1.8(0) = 5
  5. 5
    Interpret $C(0)$
    $C(0) = 5$ means the cost is $5 even if the taxi travels 0 km. This represents the fixed booking or flag-fall fee.
✓ Answer $C(15) = \\$32$, $C(30) = \\$59$, and $C(0) = \\$5$ (the flag fall)

Worked Example 3 — The Difference Quotient

Stepwise
For $f(x) = x^2 + 2x$, find $\dfrac{f(x+h) - f(x)}{h}$ in simplified form.
  1. 1
    Find $f(x+h)$
    f(x+h) = (x+h)^2 + 2(x+h) = x^2 + 2xh + h^2 + 2x + 2h
  2. 2
    Find $f(x)$
    f(x) = x^2 + 2x
  3. 3
    Subtract
    f(x+h) - f(x) = (x^2 + 2xh + h^2 + 2x + 2h) - (x^2 + 2x)
  4. 4
    Simplify the numerator
    = 2xh + h^2 + 2h
  5. 5
    Divide by $h$
    \frac{2xh + h^2 + 2h}{h} = 2x + h + 2
✓ Answer $\dfrac{f(x+h) - f(x)}{h} = 2x + h + 2$
⚠️

Common Mistakes — Don't Lose Easy Marks

Treating $f(x)$ as $f$ multiplied by $x$
This is the most common error in function notation. $f(x)$ means "the function $f$ evaluated at $x$" — it is not an algebraic product. Writing $f(3) = 3f$ or expanding $f(x+1) = f \cdot (x+1)$ shows a fundamental misunderstanding.
✓ Fix: Read $f(x)$ aloud as "$f$ of $x$." The parentheses contain the input, just like $g(2)$ or $h(a+b)$.
Forgetting brackets with negative or algebraic inputs
If $f(x) = x^2$ and you want $f(-2)$, writing $-2^2$ gives $-4$ because the exponent only applies to the $2$. The correct substitution is $(-2)^2 = 4$.
✓ Fix: Always write brackets around substituted values before simplifying: $f(-2) = (-2)^2$.
Only replacing the first occurrence of $x$
In $f(x) = x^2 - 3x + 1$, some students substitute correctly for the first $x$ but leave the second one unchanged, writing $f(a) = a^2 - 3x + 1$.
✓ Fix: Replace every instance of the variable in the rule. Count them before you simplify.
Errors when expanding $(x+h)^2$
A classic algebraic slip is writing $(x+h)^2 = x^2 + h^2$. The middle term $2xh$ is missing.
✓ Fix: Memorise the identity $(x+h)^2 = x^2 + 2xh + h^2$. It appears constantly in difference quotient problems.

📓 Copy Into Your Books

📖 Function Notation Rules

  • $f(x)$ means "$f$ of $x$" — the output when the input is $x$
  • $f$ is the name of the function; $x$ is the input
  • Other common names: $g(x)$, $h(x)$, $C(t)$, $T(h)$

🔢 Evaluation Checklist

  • Write brackets around every substituted value
  • Replace every instance of the variable
  • Follow BODMAS/PEMDAS carefully
  • Watch for sign errors with negatives

🌍 Context Interpretation

  • $C(d) = 5 + 1.8d$ → cost in dollars for $d$ kilometres
  • $f(0)$ often represents a fixed fee, initial value, or starting point
  • The coefficient of the variable is the rate of change

📐 Difference Quotient

  • $\displaystyle \frac{f(a+h) - f(a)}{h}$ measures average rate of change
  • If this is constant for all $a$ and $h$, the function is linear
  • Always expand $(a+h)^2$ fully: $a^2 + 2ah + h^2$

📝 How are you completing this lesson?

🔍 Activity 1 — Calculate + Interpret

Evaluate and Explain

Evaluate each function for the given input. Show your substitution step before simplifying.

  1. 1 If $f(x) = 4x - 5$, find $f(3)$ and $f(-2)$.

    Type your answer:

    Answer in your workbook.

    Answer in your workbook
  2. 2 If $g(x) = x^2 - 3x + 2$, find $g(0)$ and $g(1)$.

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    Answer in your workbook
  3. 3 If $h(x) = 2x^2 + x - 1$, find $h(a)$ and $h(x+h)$ in expanded form.

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    Answer in your workbook.

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🌍 Activity 2 — Functions in Context

Real-World Rules

For each scenario, write the function using appropriate notation, then answer the question.

  1. 1 A gym charges a $20 joining fee plus $15 per week. Write a function $C(w)$ for the total cost after $w$ weeks, and find the cost for 12 weeks.

    Type your answer:

    Answer in your workbook.

    Answer in your workbook
  2. 2 The temperature of a cooling object is given by $T(t) = 100 - 5t$, where $T$ is in degrees Celsius and $t$ is in minutes. Find $T(10)$ and explain what it means in context.

    Type your answer:

    Answer in your workbook.

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  3. 3 A phone plan costs $P(m) = 30 + 0.5m$ dollars for $m$ minutes of international calls. What does $P(0)$ represent? What is the rate per minute?

    Type your answer:

    Answer in your workbook.

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Revisit Your Thinking

Earlier you were asked: A taxi charges a $3 flag fall plus $2 for every kilometre travelled. How much would a 5 km trip cost? How much would a 10 km trip cost? Can you write a general rule?

A 5 km trip costs $3 + 2(5) = \\$13, and a 10 km trip costs $3 + 2(10) = \\$23. The general rule is $C(d) = 3 + 2d$, where $C$ is the cost in dollars and $d$ is the distance in kilometres. This is a function because each distance input produces exactly one cost output. The $3$ is a constant (the flag fall) and the $2$ is the rate of change per kilometre — ideas that will follow you through calculus and beyond.

Now revisit your initial response. What did you get right? What has changed in your thinking?

Look back at your initial response in your book. Annotate it with what you now understand differently.

Annotate your initial response in your book
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Revisit Your Initial Thinking

Look back at what you wrote in the Think First section. What has changed? What did you get right? What surprised you?

MC

Multiple Choice

5 random questions from a replayable lesson bank — feedback shown immediately

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Extended Questions

UnderstandBand 3

8. Explain the difference between $f(x)$ and $f \times x$. Use a specific example with $f(x) = 2x + 3$ to illustrate your answer. 2 MARKS

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ApplyBand 3

9. Consider the function $f(x) = x^2 - 4x + 3$. (a) Find $f(2)$. (b) Find $f(-1)$. (c) Find $f(a+1)$ in simplified form. Show all working. 4 MARKS

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AnalyseBand 5

10. The difference quotient $\dfrac{f(a+h) - f(a)}{h}$ measures the average rate of change of a function. (a) For $f(x) = 2x + 3$, show that the difference quotient equals $2$. (b) Explain what this result tells you about the graph of $f(x) = 2x + 3$. 4 MARKS

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✅ Comprehensive Answers

🔍 Activity 1 — Calculate + Interpret Model Answers

1. $f(3) = 4(3) - 5 = 12 - 5 = 7$; $f(-2) = 4(-2) - 5 = -8 - 5 = -13$

2. $g(0) = (0)^2 - 3(0) + 2 = 2$; $g(1) = (1)^2 - 3(1) + 2 = 1 - 3 + 2 = 0$

3. $h(a) = 2a^2 + a - 1$; $h(x+h) = 2(x+h)^2 + (x+h) - 1 = 2(x^2 + 2xh + h^2) + x + h - 1 = 2x^2 + 4xh + 2h^2 + x + h - 1$

🌍 Activity 2 — Functions in Context Model Answers

1. $C(w) = 20 + 15w$; $C(12) = 20 + 15(12) = 20 + 180 = \\$200$

2. $T(10) = 100 - 5(10) = 50^\circ$C. After 10 minutes, the object has cooled to $50^\circ$C.

3. $P(0) = 30 + 0.5(0) = 30$. This represents the fixed monthly cost of $30 before any international calls are made. The rate per minute is $0.50.

❓ Multiple Choice

1. A — $f(4) = 3(4) - 7 = 5$

2. B — The cost is $5 plus $1.50 for every kilometre travelled.

3. B — $f(-3) = (-3)^2 + 2(-3) = 9 - 6 = 3$

4. B — $f(x+h) = 2(x+h) + 1 = 2x + 2h + 1$

5. B — The expression is the difference quotient.

📝 Short Answer Model Answers

Q8 (2 marks): $f(x)$ is function notation meaning "the output of function $f$ when the input is $x$" [1]. In contrast, $f \times x$ means the variable $f$ multiplied by $x$. For example, with $f(x) = 2x + 3$, we have $f(4) = 2(4) + 3 = 11$, which is completely different from $f \times 4$ [1].

Q9 (4 marks):

(a) $f(2) = (2)^2 - 4(2) + 3 = 4 - 8 + 3 = -1$ (b) $f(-1) = (-1)^2 - 4(-1) + 3 = 1 + 4 + 3 = 8$ (c) $f(a+1) = (a+1)^2 - 4(a+1) + 3 = a^2 + 2a + 1 - 4a - 4 + 3 = a^2 - 2a$

Award 1 mark each for (a), (b), and method in (c); 1 mark for correct simplified form in (c).

Q10 (4 marks):

(a) $f(a+h) = 2(a+h) + 3 = 2a + 2h + 3$ $\frac{f(a+h) - f(a)}{h} = \frac{(2a + 2h + 3) - (2a + 3)}{h} = \frac{2h}{h} = 2$

(b) The difference quotient equals 2 for all values of $a$ and $h$ [1]. This tells us that the average rate of change is constant [1], which means the graph of $f(x) = 2x + 3$ is a straight line with a slope of 2 [1].

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Speed Race

Race Through Function Notation!

Sprint through questions on function notation and evaluation. Pool: lessons 1–2.

Mark lesson as complete

Tick when you've finished all activities and checked your answers.